Access to the value of the application using javascript

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  JBM_In_Aus wrote:
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  -------------------------------------------------------------------
  http://deneskubicek.blogspot.com/
  http://www.Opal-consulting.de/training
  http://Apex.Oracle.com/pls/OTN/f?p=31517:1
  -------------------------------------------------------------------

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  I'm editing a form where a text field is to be filled using an On-Demand application process. The process is called with an OnChange.
  
  Application process:
  

  declare
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  In the attributes of HTML Form selection list element:
  
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  Thank you
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  Hello

  visit the similar to the below application process

  declare
    l_CCSS_STATUS varchar2(100);
    l_COPAY varchar2(100)
  begin
  
    select CCSS_STATUS , COPAY into l_CCSS_STATUS , l_COPAY from PATIENT
      where ID = :P11_PATIENT_ID;
    //notice this line.... how the response is send
    htp.prn(l_CCSS_STATUS || ',' || l_COPAY);
  EXCEPTION
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  l_CCSS_STATUS := 'Inactive';
    htp.prn(l_CCSS_STATUS);
  end;
  

  and javascript call you to something similar to below.

  function myAjaxCall()
  {
     var ajaxRequest = new htmldb_Get( null , &APP_ID. , 'APPLICATION_PROCESS=myAppProcess',0);
     ajaxRequest.add('P11_PATIENT_ID' , $v('P11_PATIENT_ID'))
     //notice the below line.. use of split function
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     $s( 'P11_CCSS_STATUS' , ajaxResult[0]);
        $s( 'P11_COPAY' , ajaxResult[1]);
  }
  

  Example: http://apex.oracle.com/pls/apex/f?p=12060:110

  Kind regards
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  Application to import?
  
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• How to lock access to the application user interface?

  Hello

  Our user interface application is configured to start automatically in the background when the BlackBerry is turned on.

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  If the device is configured with ShowUserInterface = 1, the user interface does not appear to the user until the user clicks on the icon of the application. If the user closes or closes the application then it will continue to run in the background and maintain its condition.

  By clicking on the application icon again will open the application in its state of the screen.

  If the device is configured with ShowUserInterface = 0, then the user interface does not appear even when the driver click on the application icon.

  Please help how to achieve this?

  A code snippet

  public class MyApplication extends UiApplication
  {
      private Configuration config;
  
      private BackGroundThread _thread;
  
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      public MyApplication() {
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              _thread.start(); // start the thread
  
          } else {
              if (config.isShowUserInterface()) {
                  pushScreen(new LoginScreen());
              } else {
                  // what to do here?
              }
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      }
  }
  

  When the user clicks on the icon of the application and config.isShowUserInterface () = false in this case I'm not pushing any screen of the application. It is for me only IU lost Focus error.

  Any help will be appreciated.

  Thank you

  Look at acceptsForeground().  I think that you can simply return config.isShowUserInterface ().

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  Hello

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  Hi all

  My requirement is "validation of the incoming request using schemetron leader (.sch) as a mediator."

  for the above prescription, I tried like below:

  The contribution of the Ombudsman to improve and output should write in the file adapter.

  I created the file schemetron for the validation of the entry application which is indicated below:

  <? XML version = "1.0" encoding = "UTF-8"? >

  " < scheme xmlns =" http://www.ASCC.NET/XML/Schematron "> "

  < name of the pattern 'validation of the sal' = >

  < context rule = "Employee/Employedetails" >

  < assert test = 'sal > 15000' > salary should be greater than 15000 < / statement >

  < / rule >

  < / pattern >

  < / schema >

  My diagram is as follows:

  
  

  < xsd: element name = "Employee" >

  < xsd: complexType >

  < xsd: SEQUENCE >

  < xsd: element name = "Employedetails" maxOccurs = "unbounded" >

  < xsd: complexType >

  < xsd: SEQUENCE >

  < xsd: element name = "empname" type = "xsd: String" / >

  < xsd: element name = "depno" type = "xsd: String" / >

  < xsd: element name = "sal" type = "xsd: int" / >

  < / xsd: SEQUENCE >

  < / xsd: complexType >

  < / xsd: element >

  < / xsd: SEQUENCE >

  < / xsd: complexType >

  < / xsd: element >

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  Appreciate your help.

  
  

  
  

  Kind regards

  Teja
  

  Hi Alain,

  Thank you for spending your valuable time.

  After providing the full xpath.it is not able to validate the sal.

  I tried with another sample taking different schema and adding @namespace in schematron file

  My schema file

  http://www.w3.org/2001/XMLSchema.

  "xmlns ="http://www.example.org"

  "targetNamespace ="http://www.example.org"

  elementFormDefault = "qualified" >

  S chemetron file to validate the application of entry which is indicated below:

  http://www.ASCC.NET/XML/Schematron">

  http://www.example.org prefix' = 'a' / >

  SAL must be greater than 10000

  The schematron file works fine and sal is having validated according to the provided entries.

  Kind regards

  Teja.