Accuracy of currentTimeMillis

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  I tried my new Apple Watch series 2 in the pool today.  The pool at the University I work is 15 m wide and I did 30 laps.  I don't flip turn.  After my workout my watch said I did 55 laps in one less than 30 minutes.  After checking the part passing through and taking care that the hand (my watch is on), I touch the side with, I think two things.  First, it considers the key on one side a tower.  Is there a way to change this?  Second, you can improve the accuracy of the Tower, well than doubled in my case, taking care not to touch with the same hand that your watch.  Can it be formed or changed somehow?

  Also, when I started my training you only gave me the choice of the number of calories to burn.  Is there a way to set a number of towers, or do a training session open, instead?

  Hello

  When starting a swim practice, slide sideways on the screen of the goal to choose a different goal, including a workout open-ended.

  Watch OS is designed to improve the accuracy of the estimates for training of swimming over time automatically by analyzing the effectiveness of your race.

  If you want to share your comments with Apple about your problems with the application, you can do so here:

  https://www.Apple.com/feedback/watch.html

• Accuracy of the resting heart rate

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  Consumer Reports tested the sensor frequency heart Apple Watch against their dedicated Recommendations cardiofrequence-meter and have 'no difference' between their reading:

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  However, note that Apple Watch, heart rate sensor and the included applications are not medical devices and are intended only for fitness purposes. They are not designed or intended to be used in the diagnosis of disease or other conditions, or to cure, mitigation, treatment or prevention of the disease.

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• Degree of accuracy is to find the locations of friends?  If the location of a person is updated, the situation might be wrong or delay?

  Degree of accuracy is to find the locations of friends?  If the premises of a person is updated on my phone, could be wrong or delay of an hour or two?

  It is as accurate as the location information that becomes their phone. And which can vary wildly. GPS signals are subject to an intervention by buildings, trees, weather. The phone can get information about the location of a WiFi network that is inaccurate. Find My Friends is certainly not specific enough to be invoked in situations of life and death. Nor should it be used as "evidence" that children or spouses are lying to you.

• Find my iPad accuracy?

  I thought I would try the "Find my iPad" feature on and noticed the location who gave is nowhere near here where I live, the "place" was a few roads away.  Is it the highest level of accuracy can I expect from the function "Find my iPad", or is it possible to improve it?

  Thank you

  If it's only one wifi this is only an approximate location based on the database of address of router wifi Apple maintains. Depending on where you are and what are the wifi nodes in the database within the range, it can vary from quite accurate for quite inaccurate.

• Understand and improve the absolute accuracy

  Many sculptures absolute accuracy calculated the computation of absolute precision in the manuals of the user for the use of modules in series C the following entries:

  • TempChangeFromLastExternalCal = 70 * C
  
  
  • TempChangeFromLastInternalCal = 1 * C
  
  
  • Sigma/Std-dev = 3
  
  
  • # of samples = 100

  I have a few questions about these two values listed above TempChange

  1. Why such a low value of only 1 has the TempChangeFromLastInternalCal * C; modules are continually doing internal calibration automatically?
  
  
  2. Regarding TempChangeFromLastExternalCal, I read correctly that NEITHER is the calculation of accuracy, assuming that the material has seen a +/-70 * C delta temperature since the last time it was calibrated externally. that is calibrated to 25 * C, but runs at 95 * C?

  To improve the absolute accuracy, I'm curious to know if the following two statements would improve accuracy:

  1. The material exists in an environment temperature controlled with a + / delta 10 * C ambient temperature. Can I use the value of 10 for TempChangeFromLastExternalCal if it has been calibrated at room temperature outside?
  
  
  2. If I'm short so HAVE them + HAVE terminals and a channel not used by COM and the extent to which results can be subratcted of readings of all other channels, I essentially elimited the error of the formula of absolute precision shifting?

  For completeness, for absolute accuracy formulas are:

  Absolute accuracy = ± (VoltageReading * GainError + VoltageRange * OffsetError + NoiseUncertainity)
  GainError = ResidualAIGainError + GainTempco * TempChangeFromLastInternalCal + ReferenceTempco * TempChangeFromLastExternalCal
  OffsetError = ResidualAIOffsetError + OffsetTempco * TempChangeFromLastInternalCal + INL_Error
  NoiseUncertainity = (RandomNoise * sigma) /(# of samples)

  Hey Sean,

  Change in temperature refers to the temperature difference from the last time that you did these two calibrations and the current temperature unit. So if you did an internal and external calibration at 25 ° C, then you will find the difference between the current temperature and 25 ° C. This is valid for two years for external calibration (according to the data sheet) to answer your questions:

  (1) If you both internal as external calibrated at 25 ° c, and then assign TempChange 1 ° C if the environment is in a summer of 24 or 26 ° C.

  (2) if the room was 10 ° C when the measurement has been taken, both internal and external TempChanges is 15 ° C (because your calibration conducted at 25 ° C).

  (3) If you were doing an internal calibration at 10 ° C, then your internal TempChange would be 0 ° C and your external would be 15 ° C.

  Regarding tips, I do not have too. The best I can suggest is to use a lower range and a device that has a lower production, but I don't think that it would be viable for your application. The best try of course is calibrated as close as possible to the more uniform temperature.

  I found a VI that calculates the absolute accuracy of a device. Must be a lot of values, but it allows you to play with the values to see what you can afford. My calculations show you in your range, but be absolutely sure of these fluctuations.

  https://decibel.NI.com/content/docs/doc-9912

  Attached a photo of the values that I used to get this error. I'm sure that the devices are calibrated at 23 ° C. Here's the manual where I found the numbers that I used.

  http://www.NI.com/PDF/manuals/374231c.PDF

  Sorry for the confusion earlier, I hope that this post clears up a lot of information and if it's not please let me know.

  -KP

• NEITHER 9237 quarter bridge absolute accuracy

  Given a NI 9237 bridge completion Module with NI 9944 accessory Terminal strain gauges and 120 ohms with GF = 2.11, how calculate we precision of strain?

  I was told that the absolute accuracy for bridges of quarter is given by

  Absolute accuracy = (Gain error * reading) + (error offset * range) + noise + half bridge watchkeeping tolerance tolerance.

  Since I'm on the NI 9944, watchkeeping tolerance would be 500 uV/V (given by OR R & D). The tolerance of half bridge is given in the manual OR 9237 being 1.2 mV/V.

  (1) it has no value of 'Noise' of entry for bridges on watch in the NI 9237 manual; We use only the sound of half-bridge?

  (2) if I use a sample rate of 1,613 kech. / s (the rate guaranteed valid sampling for the NI 9237 module) and my system is always in his 1st year of use, always is my gain error 0.05%? It is worth noting that 0.05% applies to the 50 kech. / s ; If the gain error does not apply to my low sampling frequency, how can I find the error of gain?

  (3) if my maximum/minimum deformation measures around 600 EU (microstrains), how can I change my values "Reading" and "Range" in the equation for absolute accuracy above, if they need to be adjusted?

  (4) why the absolute accuracy for a quarter-bridge set up does not include the half bridge tolerance?

  (5) is the equation for the conversion of precision of voltage precision for quarter of a bridge, of the strain , where U is the precision of the voltage given by the equation of absolute accuracy above.

  Example of calculation using the values assumed for quarter-bridge:

  Error error/gain Offset = 0.05%

  Reading distance / = 25 mV/V

  Half bridge noise = 1.6 mV/V * 3

  Half bridge tolerance = 1.2 mV/V

  Tolerance of watchkeeping = 500 uV/V

  Absolute accuracy = (V/V 0.0005*.025) + (0.0005*.025 V/V) + ((1.6e-6) * 3 V/V) + (1.2e - 3 V/V) + (500-6 V/V) = 25 mV/V +/-1.73 mV/V

  Accuracy of the strain =-4(V/Vex) / GF (1 + 4 (V/Vex)) = - 4 * (25 mV/V +/-1.73 mV/V) / (2.11) * (1 + 4 * (25 mV/V +/-1.73 mV/V))

  How to simplify this precision of strain to get a reading + / range of precision?

  Thanks for any help.

  (2) if I use a sample rate of 1,613 kech. / s (the rate guaranteed valid sampling for the NI 9237 module) and my system is always in his 1st year of use, always is my gain error 0.05%? It is worth noting that 0.05% applies to the 50 kech. / s ; If the gain error does not apply to my low sampling frequency, how can I find the error of gain?

  This applies at a rate of 50 kech. / s. lower data rate can have up to 0.20% gain additional error reading.  This can be found on page 24 the unit operating instructions and specifications document

  You get to know how to calculate what percentage of Reading (Gain error) I'd get according to what sampling frequency use? Otherwise, I guess I could use the error of gain of 0.20% in the worst case scenario.

  Yes, I so calculate the error of Gain for the worst case scenario (0.2%)

  (5) is the equation for the conversion of precision of voltage precision for quarter of a bridge, of the strain , where U is the precision of the voltage given by the equation of absolute accuracy above.

  Yes, I think it's the correct equation.

  It is more a matter of math - since you will be in the form of a reading + / a range (for example 25 mV/V +/-1.73 mV/V), do you know how I simplify or interpret the accuracy of strain after its replacement by the U-value?

  Accuracy of the strain =-4(V/Vex) / GF (1 + 4 (V/Vex)) = - 4 * (25 mV/V +/-1.73 mV/V) / (2.11) * (1 + 4 * (25 mV/V +/-1.73 mV/V))

  Just reuse the worst cases to calculate positive and negative values on 1.73mV.

• Ammeter/voltmeter display indicator accuracy

  Hello

  I was wondering if there was a method to increase the displayed precision of ammeter and voltmeter indicator components (components AMMETER_V, AMMETER_H, VOLTMETER_V, VOLTMETER_H, etc.) such that it provides a similar level of precision displayed in one of the multimeter (Multisim 13.0) instrument? Thanks in advance for your help.

  Al

  Hi Al,.

  You cannot change the ammeter and voltmeter indicator output accuracy, that you can use instead is the probe. The probe is located on the toolbar of the Instrument.  When you double-click on the probe, and then select the 'Settings' tab, there is an option to configure the output precision.

  Watch this video to learn how to use the probe:

  http://www.YouTube.com/watch?v=xKEQ3EXEaP8

• Accuracy of the PXI-4110 and aid for the supply of the sweep of the voltage-2, 5V to 2, 5V

  Hello

  I want to know about the accuracy of PXI 4110 DC power. I use 4110 PXI to apply a voltage sweep-2, 5V to 2, 5V with a 0, 5V step using Labview, how can I do?

  Hi Khan,

  After reading my post, I realized I'd probably be a bit clearer on that last paragraph...

  Available for PXI-4110 voltage ranges are different for each channel, as shown in the first page of the specifications:

  CH0: 0 to + 6V

  CH1: 0 to + 20 v

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  I hope that clarifies the it!

  Chris G

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  Dear team,

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  Michal

  Hi Michal,

  I'm not sure I understand your question. Are you trying to calculate the accuracy of the SCXI-1100 module, but you do not have the data specification for the calculation, or you don't know how to calculate the accuracy?

  If you need performance data, you can consult the technical data sheet 1100 SCXI. If you want to calculate your accuracy of the device, I can recommend you following KB: How can I calculate absolute precision or the accuracy of the system?

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