Accurate count all in iteration

Similar Questions

• Count all Tables

  Hi all
  
  11.2.0.1
  OEL 6.4
  
  I want to count all the tables in our database to check that it is growing. (Well not really fast) ;)
  
  Some helpful Samaritan post me this pl/sql program:
  

  SQL> create table temptable (owner varchar2(30), table_name varchar2(30), row_co                      unt number, record_date date);
  
  Table created.
  
  SQL> declare
    2  counter number;
    3  cursor cur is select owner, table_name from dba_tables;
    4  begin
    5  for rec in cur loop
    6  execute immediate 'select count(*)  from '||rec.owner||'.'||rec.table_name                       into counter;
    7  insert into temptable values (rec.owner,rec.table_name,counter,sysdate);
  commit;
    8    9  counter := 0;
   10  end loop;
   11   end;
  / 12
  declare
  *
  ERROR at line 1:
  ORA-01031: insufficient privileges
  ORA-06512: at line 6

  I am already logged in as SYSTEM. :(
  
  
  
  If I use "SYS" I get different error.
  

  SQL> declare
    2  counter number;
    3  cursor cur is select owner, table_name from dba_tables;
    4  begin
    5  for rec in cur loop
    6  execute immediate 'select count(*)  from '||rec.owner||'.'||rec.table_name into counter;
    7  insert into temptable values (rec.owner,rec.table_name,counter,sysdate);
    8  commit;
    9  counter := 0;
   10  end loop;
   end;
   11   12  /
  declare
  *
  ERROR at line 1:
  ORA-00911: invalid character
  ORA-06512: at line 6

  Thank you very much
  zxy
  
  Published by: yxes2013 on 23.4.2013 18:34

  Hello

  He ran for me as SYS:

  declare
        counter     number;
        cursor cur is select  owner
                           ,          table_name
                from    dba_tables
                WHERE   NVL (iot_type, '?')     != 'IOT_OVERFLOW';
        sql_txt     VARCHAR2 (200);
    begin
        for rec in cur loop
               sql_txt := 'select count(*)  from "' || rec.owner || '"."' || rec.table_name || '"';
  --       dbms_output.put_line (sql_txt || ' = sql_txt');
            execute immediate  sql_txt   into counter;
            insert into temptable values (rec.owner,rec.table_name,counter,sysdate);
           commit;
           counter := 0;
       end loop;
  end;
  /
  

  There are some good questions above about this is a really smart thing to do. If it provides useful information and doesn't hurt too much of the performance of the system, that's fine; Otherwise, look for ways to identify the tables that you are most interested and only them, control by using the auditing tools provided by Oracle if possible. General database discussion forum may be a better place to ask how to do this.

• How to reset the counter at each iteration, and how to introduce a delay

  Hello world

  First of all I apologize for the basic level of my questions, I'm new with Labview...

  I'm counties of reading out of a USB-6008 labview chip using the DAQ assistant and I write the output to a file. The problem is that instead of giving me the number of levels for each iteration it gives me the sum of all this. How to make Wizard Reset to 0 data acquisition account on each iteration? I tried using a shift register, but it added a counter to my folder and nothing else...

  Thank you very much

  Sure thing. Sorry about that.

• Count only the iterations of duplicates? [SOLVED]

  Using Oracle 9i 9.2.0.6.0.
  
  This could be something simple that I am on, there are plenty of ways to find and count duplicates but I'm looking for a way to count only the number of iterations of a duplicate, it is and then group them if possible.
  
  For example, suppose that you have
  

  store   customer   product    date
    1          John          A         2008/05/01
  
    1          John          A         2008/05/01
  
  
    1          John          B         2008/05/01
  
  
    2          Bob           C         2008/05/01
  
  
    2          Bob           C         2008/05/01
  
  
    3          Mary          D         2008/05/01
  
  
    3          Mary          D         2008/05/01
  
  
    3          Mary          D         2008/05/01
  
  
    3          Joe            F         2008/05/01

  So I don't want to go back to the following:
  

  Store    Duplicates
    1               1
    2               1
    3               2

  I want to only count how many duplicates beyond the first row for each store, where a duplicate has the same store, the customer and the product. Then
  1 John A 2 Bob C, had one double, and Mary has 2.
  
  I've tried so far to use analytical functions to subtract the first value of each partition before doing a count or make a number from each partition but niether seems to work by a group of store.
  
  Published by: a little rabbit on September 18, 2008 13:03

  You can find the number for each group and subtract one, as follows.

  SQL> create table t ( store int, customer varchar2(10), product varchar2(1), d_ate date );
  
  Table created.
  
  SQL>
  SQL> insert all
    2     into t values ( 1, 'John', 'A', date '2008-05-01' )
    3     into t values ( 1, 'John', 'A', date '2008-05-01' )
    4     into t values ( 1, 'John', 'B', date '2008-05-01' )
    5     into t values ( 2, 'Bob',  'C', date '2008-05-01' )
    6     into t values ( 2, 'Bob',  'C', date '2008-05-01' )
    7     into t values ( 3, 'Mary', 'D', date '2008-05-01' )
    8     into t values ( 3, 'Mary', 'D', date '2008-05-01' )
    9     into t values ( 3, 'Mary', 'D', date '2008-05-01' )
   10     into t values ( 3, 'Joe',  'F', date '2008-05-01' )
   11  select null
   12  from   dual;
  
  9 rows created.
  
  SQL>
  SQL> select distinct
    2         store
    3  ,      cnt - 1 as duplicates
    4  from  (
    5         select store
    6         ,      customer
    7         ,      product
    8         ,      d_ate
    9         ,      count(*) over (partition by store, customer, product) as cnt
   10         from   t
   11        )
   12  where  cnt - 1 > 0;
  
       STORE DUPLICATES
  ---------- ----------
           2          1
           1          1
           3          2
  

  Concerning

• Create a virtual channel that increases a counter for each iteration of a cyclic load test

  We will be a long period of cyclic fatigue tests, and I wish I could keep track of which iteration we are on this block.  The current plan is to test for 10 hours at 15 Hz, and then stop test for 2 hours for an inspection of the structure.  Later tests will begin upward.  Each of these blocks of 10 hours can start at a number of 0, but I would like to follow the release of our cell so that when he sees a rising edge (with filtering to take account of any noise) it will increase a 1 meter.  Each sample will then save this number in a column in the data file.  It doesn't have to be perfect in the measurement on the forehead, he sees the new cycle, but there need to be specific in the way that it is not miss or as an additional cycle.

  Is something like this in Signal Express full?

  Yes, what you are proposing is possible with SignalExpress full. You can call LabVIEW signal express code, so call a LabVIEW VI, which contains your counter code is a way to do it. If want to do entirely in SignalExpress you can use DAQmx features by browsing up to add a step > acquire signals > DAQmx acquire and put in place a task entry counter to match your needs.

• count the signed iterations

  I'm counting iterations above and below 0 Volt applied (VAPP).  It is used as a Subvi inside a For loop.  One of them (the positive, I think) seems to work, the reset to zero for each series.  The other seems to add to the previous one, every moment of execution.

  For example, 6 intervals below and above zero returns 6 and 6 round, 6 and 12 the second time.  I know this is a hack, but I didn't know how to do better.

  Maybe try something like that. Reset if [i] = 0, for example.

• count all the columns in the tables belonged to the user

  I want to get a handle on the width of the collar of ALL tables owned by a user.
  I have this syntax to check individual tables:
  SELECT COUNT (*)
  Of user_tab_columns
  WHERE table_name = < tbl_name >;
  
  But, I did a DESC on the USER_TAB_COLUMNS and it is not an owner\user that I can use to get all the tbls.
  
  Any suggestions how I can get it to go through all the tables (I will be rolled up the output to a file)

  Hello

  USER_TAB_COLUMNS view is not the owner because all available information is on your own schema.

  The DBA_TAB_COLUMNS view has the same information more OWNER. Then, you can query the number of columns for each table of any user. For example:

  SELECT TABLE_NAME, COUNT(*)
  FROM DBA_TAB_COLUMNS
  WHERE OWNER = 'SCOTT'
  GROUP BY TABLE_NAME
  

  Or, for all schemas

  SELECT OWNER, TABLE_NAME, COUNT(*)
  FROM DBA_TAB_COLUMNS
  GROUP BY OWNER, TABLE_NAME
  ORDER BY OWNER, TABLE_NAME
  

  Kind regards
  Miguel

• count all values with a special WHERE clause in a select group?

  Hello
  
  I have the following table 1:
  
  code, month, value
  * 1,1,40 *.
  * 1,2,50 *.
  * 1,3,0 *.
  * 1,4,0 *.
  * 1,5,20 *.
  * 1,6,30 *.
  * 1,7,30 *.
  * 1,8,30 *.
  * 1,9,20 *.
  * 1,10,20 *.
  * 1,11,0 *.
  * 1,12,0 *.
  
  * 2,1,10 *.
  * 2,2,10 *.
  * 2,3,20 *.
  * 2,4,20 *.
  * 2,5,20 *.
  * 2,6,30 *.
  * 2,7,40 *.
  * 2,8,50 *.
  * 2,9,20 *.
  * 2,10,20 *.
  * 2,11,20 *.
  * 2,12,20 *.
  
  
  This is a table with 3 columns, first column is a code, second is the number of months, third, one is a value.
  Now, I want to select records for each code. For example, all records for the code = 1.
  I want to count how many values = 0 for this code = 1. After this count, I want to update the value with the number 0.
  
  For my example:
  Code 1, there are 4 fields with the value 0. So, I want to update all values from code 1 to 4.
  The second code = 2 there is no value = 0. So, I want to update the values of code2 to 0.
  
  This should be the result:
  code, month, value
  * 1,1,4 *.
  * 1,2,4 *.
  * 1,3,4 *.
  * 1,4,4 *.
  * 1,5,4 *.
  * 1,6,4 *.
  * 1,7,4 *.
  * 1,8,4 *.
  * 1,9,4 *.
  * 1,10,4 *.
  * 1,11,4 *.
  * 1,12,4 *.
  
  * 2,1,0 *.
  * 2,2,0 *.
  * 2,3,0 *.
  * 2,4,0 *.
  * 2,5,0 *.
  * 2,6,0 *.
  * 2,7,0 *.
  * 2,8,0 *.
  * 2,9,0 *.
  * 2,10,0 *.
  * 2,11,0 *.
  * 2,12,0 *.
  
  
  My question is:
  Is it possible in oracle to count in a select (or in an insert/update statement) all values = 0 for a group (in this example, named code) and make an update in the same statement for this group?
  
  I hope someone can give me a hint, if possible?
  
  Thank you very much.
  Best regards
  
  
  Tim

  something like that? NOT TESTED *.

  Setting a DAY Table1 a SET A.Value = (SELECT COUNT (B.ROWID) FROM Table1 B WHERE A.Code = B.Code AND B.Value = 0);

• Microsoft Windows 7 FreeCell Solitaire guard is no longer the accurate count of games won/lost

  I played FreeCell for a long time, accumulating a high percentage of victories on the losses.  Recently, this percentage has begun to drop for some unknown reason.  I recently gave my score score zero, has played only one match and won and had a percentage of 100%.  The next day, I played a second game won and my percentage fell to 66%.  It had harvested 3 games played.

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  Macdent salvation,

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  I suggest you to uncheck and check the functionality of the games inWindows enable or disable featuresand check if that helps:

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  Niall

• PIC count

  Hello!

  I think it's a very simple question and can be an easy solution, but I can't. I have square waves and I'm counting peaks (max and min) and sum them up with the add function. This structure is located in the loop while for when another iteration takes place automatically that it removes the previous values and begins to count all over again. I would like the program from peaks until I have press stop.

  I joined the program and the structure of the mention is in the lower part of it.

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  Swear

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• How to count separately files and folders

  I have a folder with many files and subfolders.

  How to count in the record the number of files and folders separately? Or count the total number of files but exclude the number of folder?

  The Finder, choose utilities go to menu, open the Script Editor and AppleScript editor and run code such as:

  Tell application "Finder".

  count all files in the folder ""path: to: file""

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