Adding a column to the table-> IR and form

The database has been changed to add a column to a table. It is desirable to update the form generated 'on a Table with a report. What I have to delete the pages and redo them with the new column or is it possible to get just the set DML to update? (change the report and the form is easy, it's that the DML is updated tha I can not understand.

Kind regards
Bill

Published by: BillArms_GS on Sep 12, 2012 10:55

Hi Bill,

out of the box, you get an "automatic line (DML) treatment.
If you ensure that the new column is the right column of the mapping database in the source section of the page element, then the DML is automagically picking up your new column.

Kind regards
Erik-jan

Tags: Database

Similar Questions

  • Query took too much time when adding new column to the table and the index set on this

    I added a new column to the table that contains thousands of records. and created the composite index with three columns (those newly added + two existing column)

    for the specifics. TBL table there are two columns col1, col2

    I added the new column col3 to TBL and created composit index (col1, col2, col3).

    Now for all the records in col3 is NULL. When I choose on this table, it takes too long...

    Any idea what my I do bad., I have check the query plan, it is using the index

    It is solved using collection of statistics using the

    DBMS_STATS. GATHER_TABLE_STATS

    @Top.Gun thanks for your review...

  • How to create the column of the table for long-form Master detail relationship

    Apex 4.1

    Oracle 11g

    I created a form master detail and see the main table hotel_list and table hotel_mapping as detailed below.

    Hotel_list

    ID HOTEL_NAME

    1 Holiday Inn

    Hotel Hilton 2

    Hotel_mapping

    ID HOTEL_NAME MAPPING_NAME

    1 Inn Holiday Inn Select hotel

    2 holiday hotel Holiday Inn Select

    3 hotel Holiday Inn Holiday Inn Hotel

    4 Hilton Hotel Hilton Hotel chain

    Hotel Hilton 5 HiltonHotel

    Table Hotel_name Hotel_list is a linked table Hotel_mapping

    When I add a line to the Hotel_mapping table for the selected row in the hotel_list table, mapping_name of column is null, therefore impossible to create the relationship between the main table and the secondary table.

    I would like to know, how to create the relationship?

    Thank you very much

    Best regards

    Yong Huang,

    simple step see creating a form detailed master with APEX - Assistant Master retail

    and check how to maintain the relationship between two tables,

    simple return the packaged application «Sample of Masters details»

    and try to understand this concept...

    In your example, use Hotel_list.ID as a foreign key in the table Hotel_mapping

    and maintain the relationship with the column ID...

    and choose the display type of the column Hotel_list.ID in table Hotel_mapping as List(Query Based LOV) select.

    otherwise the best way is to create sample on oracle.apex.com

    I hope this helps...

    Leave.

  • Add constant neumber way out of the table array and form

    I have two user input constant, e.g. 0.25 and 0.5

    I want to

    Add 0.25 (which will also be the first element of my table) 0.5 = 0.75

    then,

    I want to add 0.5 to the second element of my table, that is to say, 0.75 and write it as my third element = 1.25

    then add 0.5 to my third point, that is, 1.25 and write it as my fourth element and so on

    generating a table of a fixed number of items virtually 720 items that looks like this

    0.25

    0.75

    1.25

    1.75

    2.25

    .

    .

    .

    .

    .

    to the 720th element...

    Help, please

    Thank you...

    Avinash

    You could do something like this:

  • How to get only latest date and other columns in the table

    Hello
    Table
     
       id          name        date
      123        a             2/3/2010
      124        b            15/2/2010
      125        c             1/1/2010
      123        a             12/4/2010
      125        c             17/2/2010
    
     
    It's a table, id, name, date here is the composite key.
    I want to select id, name, and date so that date (e.g., 123 date 04/12/2010 be selected for the id) is selected for each id and each id and name should be selected once.
    So, what will be its application?
    Thank you
    select
       id,
       name,
       date
    from
    (
       select
          id,
          name,
          date,
          max(date) over (partition by id, name) as max_date
       from your_table
    )
    where date = max_date;
    

    Would do assuming you do not have duplicates (all 3 columns) in the table.

  • ADF 11g - adding serial No. sum of column/calculation of column in the table of the ADF.

    Hello

    -How can I add serial number of column in the table of the ADF.
    -What is the way to calculate the sum of a column at the end of the table. (Table of the ADF). That is to say.
    10
    20
    15
    ______
    45


    Niaz M

    Hello

    Here you have some links to blog posts how do the sum:
    http://apps.branislavnemec.com/blogs/faces/bjanko/blogs.jsp?blog=bjanko20070725180020
    http://Kuba.zilp.pl/?id=781

    Kind regards

    Branislav

    Published by: Branislav Nemec June 6, 2011 11:23

  • Impossible to extract the data of an additional column in the table advance

    Hello

    We have an obligation to add an extra column to the table of advanced search. In addition, we need sort the table using this additional column.

    Now, we have achieved the following:

    1. the required VO was already extended previously and the additional column (LAST_UPDATE_DATE) is already present in the definition of the EO. So, we just added the tag for LAST_UPDATE_DATE in YOUR XML in the form:

    < ViewAttribute

    Name = "LAST_UPDATE_DATE".

    IsPersistent = "false".

    Type = "Oracle.jbo.domain.date"

    ColumnType = "DATE".

    AliasName = 'LAST_UPDATE_DATE. '

    Expression = "LAST_UPDATE_DATE."

    SQLType = 'DATE' >

    < / ViewAttribute >

    2 added a new MessageStyledText column, and updated the following property:

    Prompt = LastUpdateDate. Discover the Instance = TaskPerzSumVO. Display attribute = LAST_UPDATE_DATE. Sort Allowed = true

    The field is now visible in table advance and whenever we seek, attaches the value as ' 1901-01-01'. While I checked manually in the respective table, we have the appropriate data. But in the front end we do not get the data in our additional column of table in advance. In addition, if we try to sort the table by clicking the column LAST_UPDATE_DATE, we get the NPE error. Spec of NullPointerException is as follows:

    # # 0 in detail

    1. java.lang.NullPointerException

    at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:989)

    Kindly help us to obtain the appropriate data in the additional column. Thank you!

    Kind regards

    Zahid

    Hi Zahid,

    This is the error:

    29000: unexpected exception caught: oracle.jbo.NoObjException, msg = Houston-25003: TaskEO.LAST_UPDATE_DATE object of type entity activity not found

    Tag entity by its use should have only name of EO and not the name of the attribute.

    Use instead under the tag:

    EntityUsage = "TaskEO".

    Also, I mentioned that rather tags manually, add it please try Wizard VO to add this attribute in EO attributes available list.

  • delete extra spaces in the column of the table

    How can Hi I remove extra spaces in the column of the table for example if the table column is store as "ÄAAAAA" how to remove this extra space

    This is the column I have what it takes to remove extra spaces
    select SUBTYPES  from tablesubtype;
    am in
    Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
    PL/SQL Release 11.2.0.3.0 - Production
    CORE Production 11.2.0.3.0
    AMT for Solaris: 11.2.0.3.0 - Production Version
    NLSRTL Version 11.2.0.3.0 - Production

    Published by: adf0994 on 03/12/2012 11:30

    Published by: adf0994 on 03/12/2012 11:42
    UPDATE tablesubtype
       SET SUBTYPES  = TRIM (SUBTYPES);
    

    RTRIM do it alone will not be enough coz it takes away only right spaces and NOT left those.
    I guess in your case do a PLATE will be more advantageous to be safe and avoid left spaces in the future.

    For the intermediate spaces... try this.

    UPDATE tablesubtype
       SET SUBTYPES  = REGEXP_REPLACE (SUBTYPES, ' ', '');
    

    Hope this helps,
    Vanessa B.

    Published by: Vanessa B December 3, 2012 14:33
    -added regexp

  • Unable to add a new column to the table of the LCD? Option, just usually add it.

    I have a form of LCD with a table in it. Im trying to simply add a new column to the table. The option is there, but the column appear just after clicking Add the column to the left. I selected a column, right click the space > insert > column to the left. But the habit intsert. The object table properties tab shows lines and colum numbers, but they are grey.

    See screenshots:

    http://www.emermed.NET/staging/forums...

    http://www.emermed.NET/staging/forums...

    It is a dynamic array, where a new line can be inserted using a button. Is that the dynamic nature of the question? ID hate to cancel all the flow dynamics and programming just to add a column, and then reapply them all.

    Thank you!

    Hello

    You do not add the columns in the object > palette (screenshot 2) of the Table. I suspect that the problem is that it is not enough on the page (in the content area) to add the column. In the screenshot 1, if you look at the width of the column highlighted from the space to the right of the table, you will see that a column can be added due to restrictions of space.

    Reduce the width of the column highlighted (temporarily), and then add a column. Once added, you can resize the columns to match the width of the page.

    Hope that helps,

    Niall

  • display / hide column of the table running

    Are there known issues with display / hide a column of the table at run time?

    I have a table that contains a column with a check box and another with a radio button.  If the user is allowed to select more than one row in the table (as indicated by a form variable), then I want to hide the column of radio and checkbox column.  If not, I want to show / hide the contrary.

    I show / hide the column header too.  When I preview the form, however, the data in the table appears "scoot" left and placed in the column that is hidden, so to speak.

    Here is a view of the design of the table:

    tableDesignView.jpg

    And a view of the execution of the table.  You can see the radio is hidden, but the "account number" column wants to crush in the (hidden) radio column,

    tableRunTimeView.jpg

    Here is the script, I'm very confident in this small snippet of code because the lines of account were filling wonderfully until I added the column of radio buttons and the script to show/hide.

    Put the account data in the table

    function

    setAccountData (objAccountRow, objAccountItem) //Pass in the line and data to complete line

    {

    stuff the line

    objAccountRow.accountNumber.rawValue

    = objAccountItem.accountNumber;

    objAccountRow.accountName.rawValue

    = objAccountItem.accountName;

    objAccountRow.accountBalance.rawValue

    = objAccountItem.accountBalance;

    display the check box or radio button, depending on the number of accounts they are allowed to select (as specified by the form variable)

    var searchNumAccounts = objFragment.resolveNode("searchNumAccounts").value; Variable //Form

        if (searchNumAccounts==1)

    { //show the column of radio buttons and hide the checkbox column }

    hideObject (objResultsSubform.accounts.HeaderRow.txtSelect);   <-it's exaggerated here, to hide the table for each row header column,...

    hideObject (objAccountRow.accountSelected);

    showObject (objResultsSubform.accounts.HeaderRow.txtRadioSelect);

    showObject (objAccountRow.radioSubform.radioGroup.selected);

    }

    on the other

    { //show the checkbox column and hide the column of radio }

    hideObject (objResultsSubform.accounts.HeaderRow.txtRadioSelect);

    hideObject (objAccountRow.radioSubform.radioGroup.selected);

    showObject (objResultsSubform.accounts.HeaderRow.txtSelect);

    showObject (objAccountRow.accountSelected);

    }

    }

    OK I got it. The table object implements a container to contain the fields. You hid the ok fields, but you then never reset the row in the table to have only two columns. I copied the parameter of the XML source so that I would have the exact width and then deleted the one I wanted to hide. Now everything works fine.

    See the example updated the.

    Paul

  • CSS: Pointing out the columns of the Table

    I want to use the border-bottom property to create underscore for the columns of the table. The complexity is when I try to create colspanned 'parent' or 'Super-colonnes' i.e. of the column heads that span 2 or more child/sub-headings heads. I need the underscore to stop a few pixels short of the next column, so that the user can see what child columns are included in the parent. When I tried to add white borders to the left and to the right, that he worked too good, in that not only it has created the space downstairs, he also created the space at the top (or bottom one above). Essentially the vertical borders to sit on top of the horizontal. Anyone can make sense what I said right? Any ideas how to get what I want (elegantly)?

    Thank you.

    Well, it was pretty easy. I just added the border-collapse attrib and set 'split' and now (white) borders left and right do not cut into the bottom border of the cell above.

    http://mysite.Verizon.NET/brentemerson/public/test_page0.html

  • How to use &lt; C:when test... inside the column in the table of the ADF

    I use ADF table with two columns
    in the first column, I check the Type of document is doc type so I have to use commondlink to download this file, otherwise I need to display only text.

    to this I added
    * < c:when test = "{boolean ($favoriteType eq 'doc')}" > *.
    that does not work.

    Please let me know how to use < C:when test... inside the column in the table of the ADF

    < tr:column sortProperty = "favoriteName" sortable = "true".
    headerText = "#{res ['favorite.favoritename ']}" "
    width = "500" noWrap = "false" >
    < c: choose >
    * < c:when test = "{boolean ($favoriteType eq 'doc')}" > *.
    < tr:commandLink actionListener = "#{bindings.downloadFile.execute} '"
    Text = "#{row.favoriteName} '"
    Disabled = "#{!}" Bindings.downloadFile.Enabled}"/ >
    < / c:when >
    < c: otherwise >
    < af:outputText value = "#{row.favoriteName}" / >
    < / c: otherwise >
    < / c: choose >
    < / tr:column >
    < tr:column sortProperty = "favoriteType" sortable = "true".
    headerText = "#{res ['favorite.favoriteType ']} ' rendering ="true">"
    < af:outputText value = "#{row.favoriteType}" id = "favoriteType" / > "
    < / tr:column >

    Hello

    I do not see, you use a Table of the ADF, but I see that you use Apache Trinidad. JSTL is executed analysis of time then that JSF is to render time, that's why it does not work what you see. Trinidad is a part of tr:switcher, and you can try this. Note that it doesn't ' r allow to change components by rank.

    Frank

  • How to remove columns from the table on the master 1-0?

    I have an array of 96 columns with strings. I also have the array of int 96-elemets (mask) with 1 and 0.

    What I want to do is to is to remove (or hide - but I read that it is not possible) all the columns with index corresponding to 0 in the mask table.

    example:

    columns in the table

    1 2 3 4 5

    mask

    0 1 0 0 1

    I want to remove the columns 1, 3 and 4 and leave only 2 and 5 in my table.

    How can I do?

    If I create loop for with i as the index of the column, when I do DeleteTableColumns() columns number decreases, and I get an error of range out of

    Or do I have an option to hide the unnecessary columns (not set their width to 1, it's very ugly-looking)?

    Please help me (())

    Hello rovnyart!

    1. removal of columns in the table:

    I suspect that the reason why you get the out-of-range error is due to fact that in your loop, you delete the columns in the table, you'll eventually end up by referring to a column that no longer exists, because the other columns before it have been deleted. While you remove each column of your table in the loop for example, the column index number will move, because you deleted the other columns in front of her.

    To resolve this, even if you delete a column in your loop, make sure that you take also into account that the index of the column is moved because of the removed columns.

    2 hide columns in table:

    You can use the ATTR_COLUMN_VISIBLE attribute to hide columns in the table:

    http://forums.NI.com/T5/LabWindows-CVI-idea-exchange/add-attr-column-visible-attribute-for-table-Col...

    http://zone.NI.com/reference/en-XX/help/370051Y-01/CVI/uiref/cviattrcolumnvisible_column/

    3 alternatives:

    Note that another alternative would also use a tree instead, control as the tree control also supports the hidable columns:

    http://forums.NI.com/T5/LabWindows-CVI/table-hide-column/TD-p/569773

    Best regards!

    -Johannes

  • How to create a status column in the table

    Hello everyone

    I am trying to create a column of the table status in frontview Panel. I enclose a picture with her to say clearly what I say.plz tell me how to create the active status column in the table.

    I want to show green for safety stock and red for safety stock below.


  • How to select lines if a column has the same first and last characters?

    Hello

    I have a scenario that one of the columns in the table of the student is having names student, (Ex) John, Mary, Donald, Ana, Maria. In this case how can we write a query to retrieve lines for the values if the first and the last character of the student of identical names? Production is expected to be Donald, Ana.

    Frank answers the question in the subject of your post, but looking at your examples, I think you wanted

    WHERE lower (SUBSTR (student_name, 1, 1)) - 1 character

    low = (SUBSTR (student_name,-1)) - last character

Maybe you are looking for