ADF: How to fill a column in a table with a specific color

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  I have a table with more than 10 million rows and there is a column called 'number_zaq', I want to update this column on line frist from 2000 and + 1 for the next all ranks.

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• How to make the column in the table with the formula

  Hi all..
  This is my class
  

  public class MyNumber{
       private int num;
  
       public int getNum(){
            return num;
       }
  
       public void setNum( int num){
            this.num = num;
       }
  }

  Consider that designing a table with FXML Editor (Builder scene in this case)
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  private TableView tab;
  private TableColumn<MyNumber, Integer> tabColInput;
  private TableColumn tabColOutput;
  
  tab.setEditable(true);
  tabColInput.setEditable(true);
  
  tabColInput.setCellValueFactory( new PropertyValueFactory<Person,Integer>("num") );
  tabColInput.setCellFactory(TextFieldTableCell.forTableColumn());
  tabColInput.setOnEditCommit(
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          @Override
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  Problem:
  I want to tabColOutput to always show the result for tabColInput multiplied by 2
  
  for example:
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  When I change a line in tabColInput to 3, tabColOutput show 6
  
  Could someone advice me how do?
  
  PS: I'm not native English, so I'm sorry if I tell it fake ^^

  You're up-to-date data are probably not ObservableValues as properties, so the TableView cannot update dynamically as modification of data items.

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• Oracle how to multiply two columns of different tables and results

  Oracle how to multiply two columns of different tables and get the result in the third column?
  
  I want to multiply all the lines of the quantinty column in the table of quantity with the relevant lines of the table of prices price column and get the result of multiplying in the third column. What should I use procedure trigerr? OR IS IT POSSIBLE HOW TO DO IT PLEASE HELP :D
  
  Edited by: 994229 2013-03-15 12:44

  /* Formatted on 3/15/2013 3:51:08 PM (QP5 v5.185.11230.41888) */
  CREATE TABLE mytable1
  AS
     (SELECT 1 id, 5 VALUE FROM DUAL
      UNION ALL
      SELECT 2, 7 FROM DUAL
      UNION ALL
      SELECT 3, 8 FROM DUAL);
  
  CREATE TABLE mytable2
  AS
     (SELECT 1 id, 4 VALUE FROM DUAL
      UNION ALL
      SELECT 2, 12 FROM DUAL
      UNION ALL
      SELECT 10, 12 FROM DUAL);
  
    SELECT id,
           mytable1.VALUE,
           mytable2.VALUE,
           mytable1.VALUE * mytable2.VALUE product
      FROM mytable1 FULL OUTER JOIN mytable2 USING (id)
  ORDER BY id;
  

  ID     VALUE     VALUE_1     PRODUCT
  1     5     4     20
  2     7     12     84
  3     8
  10          12     
  

• How the values to insert into the table with the command insertion

  Dear all
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  Please help me its urgent

  Hello

  If the block is based on your database table, just committed the shape, then changes will be applied to the database.

  François

• How to get the title of a table with FDK?

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• How to select all text in a table with a single click cell?

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• How to fill a column with numbers and maintain when adding or deleting lines?

  So far, I've discovered two ways to fill a column with the number:

  1. Enter '1' in a single cell, '2' in the one below, select both, and then use the yellow dot to drag down - it will do the rest.

  2 create a formula such as 'A2 + 1' and drag also.

  However, in both cases it will work if I manually this continues to do for each newly added line at the bottom. Now, that alone would not be that big of a problem if it wasn't for the fact that I'm working with a table where the lines can be added among other rows in the future.

  Having said that, could someone please tell me how to create a column with a number that will increase automatically? I mean - if I add a new line between line 56 and 57, I want the new line to have a '57"in it, and the" old 57 "would now be"58"and so on." " I don't want to drag the whole column, which can be hundreds if not more than a thousand lines.

  Try to put this in the cells in the column:

  = ROW()

  In the formula, you can add or subtract a number if necessary to get the starting number that you need.

  SG

• In DataGrid, how to fill a column with zeros (0) records?

  Is there a simple way, in a DataGrid, for fill the records in a column with zeros (0)?

  I have a DataGrid with two columns: colA and colB.  ColA records values from a RemoteObject call.  I need auto-fill (AutoFill) recordings in colB with zeros.  How is that possible?

  Thank you!

  If you need to 0 in the dataprovider, once pass you the loop of result of the data provider and add a dynamic property with value = 0;

  Something like that

  var dp:ArrayCollection = event.result as ArrayCollection collection;

  for (each var item: Object in PD)
  {
  item.demoValue = 0;
  }

  Create a new datagrid column, set demoValue as datafield.

  If it is just for display, add a new column, put an itemrenderer with label = '0 '.

• How to hide the column in a table in the adf.

  I created the table of the ADF and surround it in the collection of panels, the data in the table from the bean to support variable. Depending on the State, there are a few columns that must hide with the user. I used visible = "false", where the false value will come from backing bean. However the user to the table always have the ability to display the column. Is there any one to hide the column with the user at all times. Fixing the code example:

  < af:column sortable = "false" headerText = "column1" id = "c13" visible = "false" >

  "" < af:outputText value = "{row.columns1} ' id ="ot13"/ >

  < / af:column >

  Hello

  Use the rendered property?

  Concerning

• How to dynamically add columns to the table

  Hi all

  I'm new to ADF and need help on sub condition.

  We have created a ViewObject on the EMPLOYEE table that has under columns:

  EMP_ID,

  EMP_NAME,

  DEPARTMENT,

  COST_CENTER,

  BUSINESS_UNIT

  COUNTRY

  GCODE

  We need to create a page in the ADF with employee table to show only below the columns

  EMP_ID,

  EMP_NAME,

  DEPARTMENT,

  COST_CENTER

  Later, if necessary user should be able to add other columns to the page dynamically.

  Can you please advice on how to implement this feature.

  Thank you.

  Kind regards

  Vidya

  Hello.

  There could be a simple solution, which is to use the component PanelCollection.

  Drag ' drop your VO to a page and create a Table with all the attributes.

  For columns that emp_id, emp_name, cost_center, set the Visible property to false.

  Put the PanelCollection component on your page and drag your table inside.

  When you run the page you will see the view menu in the upper left corner of the table above. You can show/hide columns in this menu.

• How to create the column of the table for long-form Master detail relationship

  Apex 4.1

  Oracle 11g

  I created a form master detail and see the main table hotel_list and table hotel_mapping as detailed below.

  Hotel_list

  ID HOTEL_NAME

  1 Holiday Inn

  Hotel Hilton 2

  Hotel_mapping

  ID HOTEL_NAME MAPPING_NAME

  1 Inn Holiday Inn Select hotel

  2 holiday hotel Holiday Inn Select

  3 hotel Holiday Inn Holiday Inn Hotel

  4 Hilton Hotel Hilton Hotel chain

  Hotel Hilton 5 HiltonHotel

  Table Hotel_name Hotel_list is a linked table Hotel_mapping

  When I add a line to the Hotel_mapping table for the selected row in the hotel_list table, mapping_name of column is null, therefore impossible to create the relationship between the main table and the secondary table.

  I would like to know, how to create the relationship?

  Thank you very much

  Best regards

  Yong Huang,

  simple step see creating a form detailed master with APEX - Assistant Master retail

  and check how to maintain the relationship between two tables,

  simple return the packaged application «Sample of Masters details»

  and try to understand this concept...

  In your example, use Hotel_list.ID as a foreign key in the table Hotel_mapping

  and maintain the relationship with the column ID...

  and choose the display type of the column Hotel_list.ID in table Hotel_mapping as List(Query Based LOV) select.

  otherwise the best way is to create sample on oracle.apex.com

  I hope this helps...

  Leave.

• How to match columns from two tables with

  Hello:
  I have two tables as below:
  
  Table1::(Base Table)
  Country | Prefix | Prefix_Length
  Travel | 001 | 3
  CountryB. 0012 | 4
  PaysC | 00443 | 5
  CountryD | 0091 | 4
  
  :(Detail Table) table2
  The population | Area | Prefix
  500 | AreaA | 0015921
  1000 | AreaB | 00122
  400. AreaC. 00443743
  300. ALIS | 0091333
  100. AreaA | 001
  
  I need to match these two tables with prefix columns (whose length is not fixed in the two tables: but it starts with 00 in the two tables). Two different countries the prefix may be similar up to a certain length. Thus, Prefix_Length can be used to determine (exactly) how much time should be taken in the search of Table2.
  
  Output:
  Country | Prefix | Area | Population
  Travel | 001 | AreaA | 600
  CountryB. 0012 | AreaB | 1000
  PaysC | 00443 | AreaC. 400
  CountryD | 0091 | ALIS | 300
  
  Please help me with your valuable comments.
  
  -Tender

  Try this

  with base_table as (
                      select 'CountryA' country,'001' prefix,3 prefix_length from dual union all
                      select 'CountryB','0012',4 from dual union all
                      select 'CountryC','00443',5 from dual union all
                      select 'CountryD','0091',4 from dual
                     ),
     detail_table as (
                      select 10 no_of_call,'0015921' prefix from dual union all
                      select 3,'00122' from dual union all
                      select 50,'00443743' from dual union all
                    select 50,'00443643' from dual union all
                      select 300,'0091333' from dual union all
                      select 60,'001' from dual
                     ) 
  
  SELECT  country,
          prefix,sum(no_of_call)
     FROM (
           select  country,
          b.prefix,no_of_call,
          decode(no_of_call,lead(no_of_call,1,0) over(partition by no_of_call order by b.prefix,no_of_call),'y','n') y_or_no
    from  base_table b,
          detail_table d
    where b.prefix = substr(d.prefix,1,prefix_length))
    where y_or_no !='y'
    group by  country,
          prefix
    order by country,
          prefix;
  

  Published by: Vi on 20 February 2012 01:07