All_source research directories

I would get the names of the packages that returns a list of directory. I tried to interview the ALL_SOURCE and was able to get the name of the directories, hard coding

select *
from all_source
Where upper(text) like '%XXHRMS_DIR%'
OR upper(text) like '%XXARUPLOAD%'
and type='PACKAGE BODY';

I have the list of directories of 10-15 and instead of hard coding the directory names, it will be possible to use a subquery that would return the object_name of object where the object_type is DIRECTORY using regexp_like.

SELECT  *
    FROM all_source
   WHERE     REGEXP_LIKE (UPPER (TEXT), '^.[XXAPUPLOAD.|.XXFA_DIR].')
         AND TYPE = 'PACKAGE BODY'

The query above with REGEXP_LIKE does not - it returns all the package names and I do not know how to use a subquery to replace the ALL_OBJESTS.object_name instead of hard coding the names of directory one by one.

Expected results: the output should be the names of package body that returns the set of directories in the code.

SELECT *.

From all_source

WHERE REGEXP_LIKE (UPPER (TEXT),'XXAPUPLOAD |) XXFA_DIR')

AND TYPE = 'PACKAGE BODY '.

Returns all the rows in all package ALL_SOURCE where line upprecased contains XXAPUPLOAD or XXFA_DIR. And what follows will find all lines in all package ALL_SOURCE where line upprecased contains text corresponding to an object directory ALL_DIRECTORIES uppercase name.

SELECT *.

FROM ALL_SOURCE,.

        All THE_DIRECTORIES

WHERE REGEXP_LIKE (UPPER (TEXT), UPPER (DIRECTORY_NAME))

AND TYPE = 'PACKAGE BODY '.

SY.

Tags: Database

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