All the columns after first column null/white
Database: 10.2.0.1OS: Windows xp
I need your help in the future. I have a table whose columns varchar2 20. Table looks something like this:
-------------------------------------------------------------------------------------------------------------------------------------------------------------
Col1 Col2 Col3 Col4 Col5 Col6...Col20
-------------------------------------------------------------------------------------------------------------------------------------------------------------
In some operating systems, you can use a character in place of HOST such as "$" in Windows. On some platforms,
SQL*Plus removes the SQLTERMINATOR (a semicolon by default) before the HOST command A workaround for this
Power required (all columns after first null/white column for a given row)Output
On some platforms,
A workaround for this
I'm sorry, I'm not having the machine in this moment, which is why I'm not necessary validation create table and SAMPLES.I hope I'm clear in my question.
Thank you.
Hello
Assuming that you know a few suibstring who never appears in the data, you can get all the columns after the first NULL like this:
SELECT REPLACE ( REGEXP_SUBSTR ( '/' || col1 ||
'/' || col2 ||
'/' || col3 ||
...
'/' || col20 ||
, '//.*'
)
, '/'
-- , ' '
)
FROM table_x
;
As indicated, this returns the concatenated text, without any delimiter.
If you want the delimiter, omit to REPLACE them; Just use REGEXP_SUBSTR.
If you want a delimiter which may appear in the text, then a comment the argument 3 to REPLACE.
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------- ------ -------- ---------- ---------- ---------- ---------- ----------
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------------------------------- -------- ----
A VARCHAR2 (10)
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--- ---- ----- ------ -------
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What is your version of Oracle?
Can you explain why these lines are your expected results? For example if I have run the following query I see these results:
SQL> SELECT DA.ANAME 2 , DA.DB_ID 3 , DA.DC_ID 4 , DB.ABBB 5 , DC.ACCC 6 FROM DA 7 JOIN DB ON DA.DB_ID = DB.DB_ID 8 JOIN DC ON DC.DC_ID = DA.DC_ID 9 ORDER BY 1, 2, 3, 4, 5 10 / ANAME DB_ID DC_ID ABBB ACCC ---------- -------------------- -------------------- ---------- ---------- Apples 1 100 B1test C1test Apples 1 100 B1test C2test Apples 1 100 B1test C3test Apples 1 100 B2test C1test Apples 1 100 B2test C2test Apples 1 100 B2test C3test
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SQL> SELECT DA.ANAME 2 , DA.DB_ID 3 , DA.DC_ID 4 , DB.ABBB 5 , DC.ACCC 6 FROM DA 7 JOIN DC ON DC.DC_ID = DA.DC_ID 8 LEFT OUTER JOIN DB ON DA.DB_ID = DB.DB_ID AND SUBSTR(DB.ABBB,2,1) = SUBSTR(DC.ACCC,2,1) 9 ORDER BY 1, 2, 3, 4, 5 10 / ANAME DB_ID DC_ID ABBB ACCC ---------- -------------------- -------------------- ---------- ---------- Apples 1 100 B1test C1test Apples 1 100 B2test C2test Apples 1 100 C3test
Published by: Centinul on January 15, 2010 11:01
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