All unique combinations of values in the same column of a group?

Hi friends

I have a table t with data as follows

CREATE TABLE T
(order_number number,
item_name varchar2(3))
 
INSERT INTO T VALUES (1,'A1');
INSERT INTO T VALUES (1,'A2');
INSERT INTO T VALUES (1,'B1');
INSERT INTO T VALUES (1,'B2');
INSERT INTO T VALUES (1,'C1');
INSERT INTO T VALUES (1,'C2');
INSERT INTO T VALUES (2,'A4');
INSERT INTO T VALUES (2,'B1');
INSERT INTO T VALUES (2,'A3');
INSERT INTO T VALUES (2,'B5');
INSERT INTO T VALUES (2,'C1');
INSERT INTO T VALUES (2,'C2');

sql> SELECT ITEM_NAME, ORDER_NUMBER FROM T
/


item name   order number
A1             1
A2             1
B1             1
B2             1
C1             1
C2             1
...
...
A4             2
B1             2
A3             2
B5             2
C1             2
C2             2

In my table, each 'item' can appear just once in each 'order number'. 
I want to join each item name to all other item names (without any repitition), within the same order number. 


My desired output is like below:

item name     item name   order number
A1            A2          1
A1            B1          1
A1            B2          1
A1            C1          1
A1            C2          1
A2            B1          1    
A2            B2          1
A2            C1          1
A2            C2          1
B1            B2          1    
B1            C1          1
B1            C2          1
B2            C1          1
B2            C2          1
C1            C2          1    

......
......
......

There are 15 combinations so the number 1
.. .nCr where n = 6 and r = 2 NCR Yes = 15.

Note: x A1 A2 is ignored because already, A1, A2 came in the first row of my desired output. similar cases for others combinations should be ignored as well.

I want to have the shortest possible of a query with more rapid execution to achieve this goal. Because in my real table 2000 there order numbers and each order number has 10 unique objects.

I look forward to the answer.

concerning
Hamza

Published by: Hamza on July 10, 2011 22:55

Published by: Hamza on July 10, 2011 22:58

with t as (
           select 'A1' item_name,1 order_number from dual union all
           select 'A2',1 from dual union all
           select 'B1',1 from dual union all
           select 'B2',1 from dual union all
           select 'C1',1 from dual union all
           select 'C2',1 from dual
          )
-- end of on-the-fly data sample
select  t1.item_name,
        t2.item_name,
        t1.order_number
  from  t t1,
        t t2
  where t1.order_number = t2.order_number
    and t1.item_name < t2.item_name
  order by t1.order_number,
           t1.item_name,
           t2.item_name
/

ITEM_NAME  ITEM_NAME  ORDER_NUMBER
---------- ---------- ------------
A1         A2                    1
A1         B1                    1
A1         B2                    1
A1         C1                    1
A1         C2                    1
A2         B1                    1
A2         B2                    1
A2         C1                    1
A2         C2                    1
B1         B2                    1
B1         C1                    1

ITEM_NAME  ITEM_NAME  ORDER_NUMBER
---------- ---------- ------------
B1         C2                    1
B2         C1                    1
B2         C2                    1
C1         C2                    1

15 rows selected.

SQL>

SY.
P.S. It your order_number big enough index table, nom_element would be useful.

Tags: Database

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