By subtracting the values in the same column?

Similar Questions

• Multiple values for the same column in the columns of diffétent in the same row?

  Hi all
  I wonder how you can display different values for the same column in different columns on the same line. For example, using a CASE statement, I can:
  
  CASE WHEN CODE IN ('1 ', ' 3') THEN COUNT (ID) AS 'Y '.
  CASE WHEN CODE NOT IN ('1 ', am') THEN COUNT (ID) AS "N".
  
  Yes, that will produce two columns but will produce null values to empty and also two separate registers.
  
  
  Any ideas?
  
  Thank you

  Are you sure that this code works for you?

  Select ID
           ,CASE WHEN MODE_CODE IN ('1', '3') THEN COUNT( No) END as "Fulltime"
           ,CASE WHEN MODE_CODE NOT IN ('1', '3') THEN COUNT( No ) END  as "Other"
  From table
  group by ID
  

  I guess the code above fails because MODE_CODE is not in your group by?

  My suggestion would be to put the CASE in the COUNT:

  Select ID
           ,COUNT(CASE WHEN MODE_CODE IN ('1', '3') THEN No END) as "Fulltime"
           ,COUNT(CASE WHEN MODE_CODE NOT IN ('1', '3') THEN No END)  as "Other"
  From table
  group by ID
  

  CASE expressions return no. when the respective conditions are true and NULL otherwise.
  COUNTY will have non-null values.

• By comparing the values in the same column

  Hello
  
  I have a requirement to do the following:
  
  The guest of the dashboard has two drop downs as 'Acct number 1' and others as 'Acct number 2 ". Both are the same column from the database. When two different values are chosen from the prompt, it should produce a report with the following 5 colomns, 'ACCT1', 'SALES AMOUNT ACCT1', "ACCT2", "SALES AMOUNT ACCT2", "DIFFERENCE".
  
  I tried to use a variable of presentation in the command prompt and it fills my column pther having the same value I have input for the first prompt.
  
  How can I do this? Thanks for your time and your help.

  Hello

  You can try it at the level of the report.

  * Ensure that you have set your guests with different effects. Suppose that the two PVs are acc1 and acc2.
  * Report, add below filter
  Account number is equal to @{acc1} {defualtvalue}
  OR
  Account number is equal to @{acc2} {defualtvalue}
  This will filter the report by the two account numbers.
  * Now apply below in your fx of all columns.

  "ACCT1: ' @{acc1} {defualtvalue}"
  ACCT1 SALES AMOUNT: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc1} {defualtvalue}'))
  "ACCT2: ' @{acc2} {defualtvalue}"
  ACCT2 SALES AMOUNT: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc2} {defualtvalue}'))
  DIFFERENCE: FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc1} {defualtvalue}'))-FILTER (with the HELP of SalesCol (AccountNumber = ' @{acc2} {defualtvalue}'))

  Thank you

• Select literal values in the same column

  Hello
  like the practice:
  
  Select 'A', 'B', 'C' for double
  will select these values in their own column on the same line, is there a simple way to select these values in the same column on lines without first their insertion into a table?
  
  Thank you

  SQL> select 'A' x from dual union
    2  select 'B' x from dual union
    3  select 'C' x from dual ;
  
  X
  -
  A
  B
  C
  

  A bit complicated:

  SQL> select chr(ascii('A')+level-1) x
    2  from dual
    3  connect by level <=3;
  
  X
  -
  A
  B
  C
  

  Other:

  SQL> select regexp_substr('ABC','[[:alpha:]]',1,level) x
    2  from dual
    3  connect by level <= length('ABC');
  
  X
  ---
  A
  B
  C
  

  Max
  http://oracleitalia.WordPress.com

  Published by: Massimo Ruocchio, February 12, 2010 17:55
  added a second

  Published by: Massimo Ruocchio, February 12, 2010 17:58
  Added the third

• an alphabet by typing in a cell gives drop down suggestions from previous hits on the same column. But how the drop down to choose the suggestions of the other columns and other sheets.

  an alphabet by typing in a cell gives drop down suggestions from previous hits on the same column. But how the drop down to choose the suggestions of the other columns and other sheets.

  Hi mdsavol,

  Your observations are accurate. The 'suggestions' are previous entries in the same column that correspond to what has been entered so far in the active cell. The only direct user control is to activate the function turn on or off in numbers preferences > general.

  There are other ways to include or exclude items of suggestions:

  • To remove typos in the suggestions list, the user must correct the typos in the cell above the active cell. If they are more in the list, they won't be presented as suggestions.
  • To include selections added to the list, the user must enter these suggestions in the individual cells above the active cell and column where they are wanted as suggestions.

  There was a request here a while there is a list of suggestion 'live' similar to those of some websites, which offers a descending list of possible entries as a type in an input box.

  The only way I see to reach a solution similar to what you have asked is to use as many lines at the top of the non-en-tete of the table section to list the items likely to repeat in your table, and then hide the lines. You'll need a list for each column where you want to use this feature with a list previously planted. Existing items will then require a likely hit up to three, then a click to choose from a list small enough to enter a value into a cell. News he will need to enter in full the first time, but after that it will be put on the list and answer the same thing as the terms preseeded.

  While your setting upward (or decide not to do), consider going on the menu of number (in numbers), choosing to provide feedback from numbers and writing a feature in Apple request. Describe what you want. Explain how he could help the average user numbers, and then hope for the best.

  Kind regards

  Barry

• Entries are concatenated in the same column in the excel file

  Hi, I really need help in this emergency. The problem is when I open the spreadsheet file after you run the program below, all the values that I believe are concatenated in the same column. However, there are 2 different analog inputs which I want in 2 different columns. I'm getting the 2 waveforms in the same graph, but when I open the excel file, it seems that the entries are concatenated in the same column. Someone knows how to fix this? Thank you very much.

  

  Hi Ben 64,.

  Thanks a lot again. I did as you said and I removed the dynamic data and logged files added directly to the results. I'm still checking if the program works as I can branch only when I return to work tomorrow. Tell me if you think it might be able to work this time. Thanks a lot again!

• Two or more SRID in the same column?

  Hello, I am working with Oracle Spatial, and I have a problem with the SRID.
  
  I have a column in a table with the SDO_GEOMETRY type and I need to create a Spatial Index to use. But to create a Spatial Index first, I need to insert metadata into the table incluied SRID: for example
  
  Insert in user_sdo_geom_metadata (table_name, column_name, srid, diminfo) values ('Spatial_Test', 'GEOMETRIA', 8307, SDO_DIM_ARRAY (SDO_DIM_ELEMENT('LONGITUDE',-180,180,0.5), SDO_DIM_ELEMENT ('LATITUDE',-90, 90, 0.5)));
  
  But I need to work with more than one SRID in this column. Is there anyway to have two or more SRID in the same column? How? and if I insert them, can they give any problem?
  
  Thank you very much.
  
  Good bye.

  ZeyKa,

  . . . . You can transform and store all your geometries in SRID 8307 and then turn to their original SRID when you SELECT them.

  -- "Example: Transform geometry from  to SRID 8307 for storage"
  -- "NOTE: Replace  and  with your values"
  INSERT INTO MyTable (ID, geometry,RenderSRID) VALUES (1, SDO_CS.TRANSFORM(,8307), );
  

  -- "Example: Transform stored geometry back to its "
  SELECT SDO_CS.TRANSFORM(geometry,RenderSRID) FROM MyTable WHERE ID = 1;
  

  Kind regards
  Noel

• Two guests on the same column

  Hi Experts,
  
  I'm defining two different guests (and associate them with the two variables of different presentation) on the same column. However, when I view the 2 guests on the same dashboard page, whenever I select a value for the first prompt, the same value is automatically selected for the second line.
  
  Is this a normal behavior? How to capture the two distinct values?
  
  Thank you
  Guillaume

  Hi William,.

  I think I forgot something.

  You must do the following steps:

  (1) add the column to the dashboard command prompt.
  (2) in the column "Show" change the option to 'results '.
  (3) in the column "Column" change the formula of the column to a name like «filter 1"»
  (4) this column value to the variable in the presentation, such as FILTER1.
  (5) change the label for the column.
  (6) assign the filter in your report to the presentation FILTER1 variable.

  Repeat step 1 to 6 for the second filter.

  Kind regards
  Stijn

• A target table is in charge of two different sources but the same columns, but a source is one database and another in a flat file.

  We all hope you are doing well.

  I have a business problem to implement in ODI 11 G. It's here. I'm trying to load a target table from two sources that have the same column names. But a source is to the file format and the other is in the Oracle database.

  That's what I think I'll create two mappings in the same interface by using the Union between the sources. But I don't know how the interface would connect to different logical architecture to connect to two different sources.

  Thank you

  SM

  You are on the right track, all in a single interface. Follow these steps

  (1) pull model of your data in the designer of the source file and your table model target to the target pane.

  (2) all relevant columns map

  (3) in the source designer to create a new dataset and choose as the UNION join type (this will create a separate tab in the source designer pane)

  (4) select the new dataset tab in the source designer pane and pull your source oracle table data model in the designer of the source. All columns that are relevant to the target card

  (5) make sure that your staging location is set to a relational technology i.e. in this case the target would be an ideal candidate because it is where the ODI will organize the data from source two files and oracle and perform the UNION before loading to the target

  If you want to watch some pretty screenshots showing the steps above, take a look at http://odiexperts.com/11g-oracle-data-integrator-part-611g-union-minus-intersect/

• Multiple constraints on the same column

  Hello experts, we can use Multiple forced on the same column in oracle as creating table, I want to add a key single and forced to check on the same column is this possible? Thanks in advance,

  If you want, seems to be possible

  CREATE TABLE t1

  (col1 VARCHAR2 (50))

  CONSTRAINT ck1 CHECK (col1 IN ('A', 'B', 'C'))

  CONSTRAINT PRIMARY KEY (col1) pk1

  );

• subtracting the two rows in the same column

  Hello
  I have the following table with about 6000 lines of different year_month, but I compare and subtract v
  Contribution of the Organization Year_month
  Kano 200000 JAN-2011
  KADUNA 300000 JAN-2011
  ABUJA 400000 JAN-2011
  Kano 300000 FEB-2011
  KADUNA 200000 FEB-2011
  ABUJA 600000 FEB 2012
  I want to choose a year_month runtime to subtract the contribution of the first contribution of the second year_month year_month and give me the result, as shown in the following table
  Difference of JAN - FEB 2011 - 2011 organization
  Kano 200000 300000-100000
  300000 200000 100000 KADUNA
  ABUJA 400000 200000 600000
  Here is my code back will too
  
  create or replace function "GET_MONTHLY_VALUE".
  (q_name in VARCHAR2,
  hmoCode in VARCHAR2)
  return VARCHAR2
  is
  number of C1;
  Start
  Select NHIS_CONTRIBUTION in c1 of CONTRIBUTION_MGT where upper (YEAR_MONTH) = upper (q_name) and upper (ORGANIZATION) = upper (hmoCode);
  
  return to c1;
  exception when NO_DATA_FOUND THEN
  Returns a null value.
  end;
  
  -a call to the function above:
  
  create or replace function process_cont_monthly return varchar
  
  is
  Cursor cont_cursor is select ORGANIZATION of CONTRIBUTION_MGT;
  Start
  for
  cont_rec loop cont_cursor
  First, select GET_MONTHLY_VALUE(:p26_month,cont_rec.ORGANIZATION) GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION) second,
  ABS (GET_MONTHLY_VALUE (:p26_month,cont_rec.ORGANIZATION)-GET_MONTHLY_VALUE(:p26_month2,cont_rec.ORGANIZATION)) difference
  of CONTRIBUTION_MGT;
  
  end loop;
  commit;
  end;
  I got totally confused and do not know what to do next
  Any help and the best guide is appreciated

  Analytics can also be used (assuming that you store dates as dates, ORDER BY working properly)

  create table t(org varchar2(10),mon date, cont number);
  insert into t(org,mon,cont) values ('Kano',to_date('201101','YYYYMM'),200000);
  insert into t(org,mon,cont) values ('KADUNA',to_date('201101','YYYYMM'),300000);
  insert into t(org,mon,cont) values ('Kano',to_date('201102','YYYYMM'),300000);
  insert into t(org,mon,cont) values ('KADUNA',to_date('201102','YYYYMM'),200000);
  commit;
  
  select * from t;
  ORG        MON                    CONT
  ---------- ---------------------- ----
  Kano       01-JAN-2011 00:00:00   200000
  KADUNA     01-JAN-2011 00:00:00   300000
  Kano       01-FEB-2011 00:00:00   300000
  KADUNA     01-FEB-2011 00:00:00   200000 
  
  select org,cont1 start_month,cont2 end_month,cont1-cont2 difference
    from (
          select org,mon,cont cont1,
                 lead(cont) over (partition by org order by mon) as cont2
          from t
          where  mon in (to_date('201101','YYYYMM'),to_date('201102','YYYYMM'))
          )
  where cont2 is not null;
  
  ORG        START_MONTH END_MONTH DIFFERENCE
  ---------- ----------- --------- ----------
  KADUNA          300000    200000     100000
  Kano            200000    300000    -100000 
  

• All unique combinations of values in the same column of a group?

  Hi friends
  
  I have a table t with data as follows
  

  CREATE TABLE T
  (order_number number,
  item_name varchar2(3))
   
  INSERT INTO T VALUES (1,'A1');
  INSERT INTO T VALUES (1,'A2');
  INSERT INTO T VALUES (1,'B1');
  INSERT INTO T VALUES (1,'B2');
  INSERT INTO T VALUES (1,'C1');
  INSERT INTO T VALUES (1,'C2');
  INSERT INTO T VALUES (2,'A4');
  INSERT INTO T VALUES (2,'B1');
  INSERT INTO T VALUES (2,'A3');
  INSERT INTO T VALUES (2,'B5');
  INSERT INTO T VALUES (2,'C1');
  INSERT INTO T VALUES (2,'C2');
  
  sql> SELECT ITEM_NAME, ORDER_NUMBER FROM T
  /
  
  
  item name   order number
  A1             1
  A2             1
  B1             1
  B2             1
  C1             1
  C2             1
  ...
  ...
  A4             2
  B1             2
  A3             2
  B5             2
  C1             2
  C2             2
  
  In my table, each 'item' can appear just once in each 'order number'. 
  I want to join each item name to all other item names (without any repitition), within the same order number. 
  
  
  My desired output is like below:
  
  item name     item name   order number
  A1            A2          1
  A1            B1          1
  A1            B2          1
  A1            C1          1
  A1            C2          1
  A2            B1          1    
  A2            B2          1
  A2            C1          1
  A2            C2          1
  B1            B2          1    
  B1            C1          1
  B1            C2          1
  B2            C1          1
  B2            C2          1
  C1            C2          1    
  
  ......
  ......
  ......

  There are 15 combinations so the number 1
  .. .nCr where n = 6 and r = 2 NCR Yes = 15.
  
  
  Note: x A1 A2 is ignored because already, A1, A2 came in the first row of my desired output. similar cases for others combinations should be ignored as well.
  
  
  I want to have the shortest possible of a query with more rapid execution to achieve this goal. Because in my real table 2000 there order numbers and each order number has 10 unique objects.
  
  I look forward to the answer.
  
  concerning
  Hamza
  
  Published by: Hamza on July 10, 2011 22:55
  
  Published by: Hamza on July 10, 2011 22:58

  with t as (
             select 'A1' item_name,1 order_number from dual union all
             select 'A2',1 from dual union all
             select 'B1',1 from dual union all
             select 'B2',1 from dual union all
             select 'C1',1 from dual union all
             select 'C2',1 from dual
            )
  -- end of on-the-fly data sample
  select  t1.item_name,
          t2.item_name,
          t1.order_number
    from  t t1,
          t t2
    where t1.order_number = t2.order_number
      and t1.item_name < t2.item_name
    order by t1.order_number,
             t1.item_name,
             t2.item_name
  /
  
  ITEM_NAME  ITEM_NAME  ORDER_NUMBER
  ---------- ---------- ------------
  A1         A2                    1
  A1         B1                    1
  A1         B2                    1
  A1         C1                    1
  A1         C2                    1
  A2         B1                    1
  A2         B2                    1
  A2         C1                    1
  A2         C2                    1
  B1         B2                    1
  B1         C1                    1
  
  ITEM_NAME  ITEM_NAME  ORDER_NUMBER
  ---------- ---------- ------------
  B1         C2                    1
  B2         C1                    1
  B2         C2                    1
  C1         C2                    1
  
  15 rows selected.
  
  SQL> 
  

  SY.
  P.S. It your order_number big enough index table, nom_element would be useful.

• How to make the comparison operation in the same column

  Hello

  here to fix vi I want to make the comparison of the 3rd column operation.

  I tried with different ways, but I didn't want to result.

  Please guide me how to compare the column value with the previous measured all 3rd.

  I want to compare the current value with the previous value, and if the current value is less, one of the previous then LED must be OFF.

  Thank you very much.

  Same basic idea, but less code...

  

• Filters in the way different on the same column

  http://img848.imageshack.us/i/screenshotwjk.PNG/
  
  If you take a look at the screen at the time there is view pivot that has about 10 columns one of them is the type of scene that always contains two values Foster Care child and current CPS, my requirement is if I click on the month column values if the month value is in the category Foster Care child, then he must pass three id filters , id of the person and if she has the current CPS then it must pass two filters case id and month is it possible if say me. I will be very happy if you can help out me.
  
  Thank you

  Already answered.

  Filters in the way different in the same report

• Print data online in the same column

  Hello
  
  In a tabular report I want to print a column (for example: Description,) in two lines in the same cell.
  Because the description is too long. Is this possible in report 6i. Or any other solution for this?
  
  Please answer.

  Hello
  For the Description of the value vertical elasticity EXPAND field. Then it will automatically adjust based on the data.

  -Clément