Annotations that overlap
What I do:
I have LabVIEW 2011. I create several random number generated XY plots.
I created annotations to show the most distant point in each plot.
What is going on:
When the last points in each plot are close, the names and the arrows overlap.
I want to be able to solve this problem.
I thought about keeping a collection of positions of each annotation Y which is created and ordering them from the average of each parcel.
Someone think of a better idea?
Interesting questions. The answer depends on what you really want to achieve. For example, if the number of parcels is greater than H/h, where H is the height of your pixel chart (the black box) and h is the height of an annotation string, then whatever the solution that you have to position your annotations, they will overlap, unless you spread them as well horizontally...
Assuming that you will ever be in this situation, you might find the min Y and Y max in your chart, display and follow one of these two conventions:
(1) list n Chart1 chart annotations, giving annotation n (= 0,..., N-1), a Label Offset.Y = max Y - (n + 1) (max, Y - min Y) /(N+1) - last Y
(this can be messy).
(2) list the annotations of the Y final largest in the smallest Y final.
Discover the file code.
Tags: NI Software
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Hi all
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Published by: Frank Kulash, October 3, 2012 18:08
Additional explanation -
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I need to prepare a request for the removal of the leaves that overlap to a denunciation of employee leave and return leaves without records with overlap. It works well in cases where leave overlapps leave immediately above or below the recording of leave sorting based from the date as below:
The above code returns a correct as result:with t as ( select 1 employee_num, to_date('01.09.2008','dd.mm.yyyy') gone_effdt, to_date('29.10.2008','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.10.2008','dd.mm.yyyy') gone_effdt, to_date('29.04.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.04.2009','dd.mm.yyyy') gone_effdt, to_date('01.05.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('01.06.2009','dd.mm.yyyy') gone_effdt, to_date('01.07.2009','dd.mm.yyyy') return_effdt from dual ) SELECT employee_num,MIN(gone_effdt) gone_effdt,MAX(return_effdt) return_effdt FROM (SELECT employee_num, gone_effdt, return_effdt,MAX(rn) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) max_rn FROM ( SELECT a.*, CASE WHEN lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) < gone_effdt OR lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) IS NULL THEN ROW_NUMBER() OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) END rn FROM T a ) ) GROUP BY employee_num, max_rn ORDER BY gone_effdt;
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This gives the output as:with t as ( select 1 employee_num, to_date('01.09.2008','dd.mm.yyyy') gone_effdt, to_date('29.10.2008','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('05.11.2008','dd.mm.yyyy') gone_effdt, to_date('11.02.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.10.2008','dd.mm.yyyy') gone_effdt, to_date('29.04.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.04.2009','dd.mm.yyyy') gone_effdt, to_date('01.05.2009','dd.mm.yyyy') return_effdt from dual ) SELECT employee_num,MIN(gone_effdt) gone_effdt,MAX(return_effdt) return_effdt FROM (SELECT employee_num, gone_effdt, return_effdt,MAX(rn) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) max_rn FROM ( SELECT a.*, CASE WHEN lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) < gone_effdt OR lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) IS NULL THEN ROW_NUMBER() OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) END rn FROM T a ) ) GROUP BY employee_num, max_rn ORDER BY gone_effdt;
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Kindly help with pointers to the achievement of the above output.EMPLOYEE_NUM GONE_EFFDT RETURN_EFFDT 1 01.09.2008 01.05.2009
Thanks in advance.How about this?
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But I suspect that there is a simpler solution (probably as suggested above marwin)
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Via mijn web brouwzer mozilla firefox kom ik op intranet werkgeverEnglish om 00:00 iets wordt finished you question zou iets als Français like send later plug-ins Jan
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