Flattening of the ranges that overlap
I have data that looks like this:(SKU, from_day, to_day)
(1, 1, 3)
(1, 2, 8)
(1, 7, 9)
(2, 2, 4)
(2, 6, 8)(1, 1, 9)
(2, 2, 4)
(2, 6, 8)I have three SKU 1 positions that were in place for a range of dates. The first element was there from day 1 to 3; the second days 2 to 8; the third days 7 to 9. These days this overlap, I would like to report on the maximum range of days that overlap - that is to say, that I had an element of SKU 1 present of the day 1 to day 9.
I have two SKU 2 elements that were present in the location for the date interval. The first element was there for days 2 to 4; the second from 6 to 8 days. Given that these days do not overlap, I need to report separately.
Can someone help me to write SQL that will accomplish this? It seems that I could use the syntax to CONNECT BY PRIOR, but I don't see how.
Hello
Here's one way:
WITH got_grp_start AS
(
SELECT sku, from_day, to_day
, CASE
WHEN from_day <= MAX (to_day) OVER ( PARTITION BY sku
ORDER BY from_day
RANGE BETWEEN UNBOUNDED PRECEDING
AND 1 PRECEDING
)
THEN 0
ELSE 1
END AS grp_start
FROM table_x
)
, got_grp AS
(
SELECT sku, from_day, to_day
, SUM (grp_start) OVER ( PARTITION BY sku
ORDER BY from_day
) AS grp
FROM got_grp_start
)
SELECT sku
, MIN (from_day) AS grp_from_day
, MAX (to_day) AS grp_to_day
FROM got_grp
GROUP BY sku
, grp
ORDER BY sku
, grp_from_day
;
This is an example of a problem of the English Channel , where consecutive lines (here, means consecutive in order of from_day) into groups, but there is nothing in any individual line which indicates which group belongs to this line; We must compare each row of other rows in the same score to determine if a new group (a ' handle') started this line or not. It's a little trickier than most other neck problems, because we had (I assume) data like this:
INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 1, 5);
INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 2, 3);
INSERT INTO table_x (sku, from_day, to_day) VALUES (9, 4, 6);
When deciding if a round begins with the 3rd rank, we cannot just look at the previous 1 row; To watch all the previous lines.
After that we have determined where each round begins, we use the analytical SUM function to see how many innings have already started, i.e. to which group each line belongs. Once we have the number of group, getting high and low group limits is just a matter of using MIN and MAX.
Published by: Frank Kulash, October 3, 2012 18:08
Additional explanation
Tags: Database
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(
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b.start_date
b.end_date
a.dat_col
, ROW_NUMBER () OVER (PARTITION BY a.id, a.dat_col)
ORDER BY b.start_date, b.end_date
) AS r_num
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, (
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Periods
) b
WHERE a.dat_col BETWEEN b.start_date
AND b.end_date
GROUP BY a.id, b.end_date, a.dat_col, b.start_date and b.id
)
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OF got_r_num
WHERE r_num = 1
ORDER BY start_date
;
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The above code returns a correct as result:with t as ( select 1 employee_num, to_date('01.09.2008','dd.mm.yyyy') gone_effdt, to_date('29.10.2008','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.10.2008','dd.mm.yyyy') gone_effdt, to_date('29.04.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.04.2009','dd.mm.yyyy') gone_effdt, to_date('01.05.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('01.06.2009','dd.mm.yyyy') gone_effdt, to_date('01.07.2009','dd.mm.yyyy') return_effdt from dual ) SELECT employee_num,MIN(gone_effdt) gone_effdt,MAX(return_effdt) return_effdt FROM (SELECT employee_num, gone_effdt, return_effdt,MAX(rn) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) max_rn FROM ( SELECT a.*, CASE WHEN lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) < gone_effdt OR lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) IS NULL THEN ROW_NUMBER() OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) END rn FROM T a ) ) GROUP BY employee_num, max_rn ORDER BY gone_effdt;
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This gives the output as:with t as ( select 1 employee_num, to_date('01.09.2008','dd.mm.yyyy') gone_effdt, to_date('29.10.2008','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('05.11.2008','dd.mm.yyyy') gone_effdt, to_date('11.02.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.10.2008','dd.mm.yyyy') gone_effdt, to_date('29.04.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.04.2009','dd.mm.yyyy') gone_effdt, to_date('01.05.2009','dd.mm.yyyy') return_effdt from dual ) SELECT employee_num,MIN(gone_effdt) gone_effdt,MAX(return_effdt) return_effdt FROM (SELECT employee_num, gone_effdt, return_effdt,MAX(rn) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) max_rn FROM ( SELECT a.*, CASE WHEN lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) < gone_effdt OR lag(return_effdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) IS NULL THEN ROW_NUMBER() OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) END rn FROM T a ) ) GROUP BY employee_num, max_rn ORDER BY gone_effdt;
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Kindly help with pointers to the achievement of the above output.EMPLOYEE_NUM GONE_EFFDT RETURN_EFFDT 1 01.09.2008 01.05.2009
Thanks in advance.How about this?
with t as ( select 1 employee_num, to_date('01.09.2008','dd.mm.yyyy') gone_effdt, to_date('29.10.2008','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('05.11.2008','dd.mm.yyyy') gone_effdt, to_date('11.02.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.10.2008','dd.mm.yyyy') gone_effdt, to_date('29.04.2009','dd.mm.yyyy') return_effdt from dual union all select 1 employee_num, to_date('29.04.2009','dd.mm.yyyy') gone_effdt, to_date('01.05.2009','dd.mm.yyyy') return_effdt from dual ) SELECT employee_num,MIN(gone_effdt) gone_effdt,MAX(return_effdt) return_effdt FROM (SELECT employee_num, gone_effdt, return_effdt,MAX(rn) OVER (PARTITION BY employee_num ORDER BY gone_effdt, return_effdt) max_rn FROM ( SELECT a.*, CASE WHEN lag(maxdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, maxdt) < gone_effdt OR lag(maxdt) OVER (PARTITION BY employee_num ORDER BY gone_effdt, maxdt) IS NULL THEN ROW_NUMBER() OVER (PARTITION BY employee_num ORDER BY gone_effdt, maxdt) END RN FROM (SELECT employee_num, gone_effdt, RETURN_EFFDT, MAX(RETURN_EFFDT) OVER (PARTITION BY employee_num ORDER BY GONE_EFFDT) maxdt FROM T) a ) ) GROUP BY EMPLOYEE_NUM, MAX_RN ORDER BY GONE_EFFDT;But I suspect that there is a simpler solution (probably as suggested above marwin)
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Hi, I need to calculate the exact overlap between two battered.
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