Ask for help with the query group by

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• What is the correct way to ask for help with the forum, rather than product, questions?

  I can't find the right way to ask a question about the forums themselves.

  PAGulley said

  I can't find the right part of the forum to ask questions about the forum itself and its features. I wonder what the right place and the way is to get help with the forum system itself. I can find the place to ask questions about specific Mozilla products very well.

  Look up where it says contributor tools and select Contributor Forums. Make sure that you scroll to the top or you'll get a bar with different links instead,

  The forum is https://support.mozilla.org/forums where you question would be better in the SUMO community discussions.

• ask for help with the 3210, can not see the hp software, can't sweep

  Can someone help me with this, I have a 2.66 ghz processor mac intel core 2 duo, the osx running version 10.6.7 and scanner no longer works after update to latest software to 10.6.7.  I tried to download the software of hp hp upgrade, and then when it works not tried to download apple software update for hp.  Nothing works.  I can't activate a scan of the computer, the software icons have disappeared.  And I can't activate the printer, just shows 'no scan options '.  The computer allows printing, I can find a printer icon with the option of mac system preferences.  very frustrating hours pass, no solution, thank you very much, david.

  I was able to solve the problem by talking to a person capable of mac online, a person named kelly in oregon, basically, we did a software update (she waited w / me through 15 minutes of downloading), and mac program "image capture" is now effective for me for scanning documents.  I think I can have earlier been confused by the fact that the screenshot is a new program, I had been looking for hp scanning software and finder contains more than all the entries of "hp".  Image capture seems to work.  (FYI, we had briefly discussed to insert the original disc, but chose to not not to this since it does not say that it's usable in mac os 10.6 and since we had the opportunity to see if the system works after installing the downloaded software updates).

• Help with the query GROUP BY?

  Why the habit of this work? When I run the code with the first where clause it works fine.
  

  select diffrating, count (diffrating) 
  from IT220_HOLIDAYDETAILS
  where diffrating = 'A'
  GROUP BY diffrating

  It returns the result that there is a diffirating marked "A".
  
  However, when I try to add other clauses he says "no data found"?
  

  select diffrating, count (diffrating) 
  from IT220_HOLIDAYDETAILS
  where diffrating = 'A'
  and diffrating = 'B'
  and diffrating = 'C'
  and diffrating = 'D'
  and diffrating = 'E'
  GROUP BY diffrating

  How can this be when he came 'A' data in the first place? Surely, it should return 'A' as a negative because it worked before?
  
  What I want is to count all results for each diffrating and return them. Any reason, why it does not work?
  
  Thanks in advance!

  It returns nothing because you try to select a diffrating whose value has, b, c, d and e at the same time.

  select diffrating, count (diffrating)
  from IT220_HOLIDAYDETAILS
  GROUP BY diffrating
  

  is not already display what you want?

• Can you tell me how I can ask for help with the following question of Indesign: I am a new user of Indesign and creative Member Cloud.  I was using the fall of the window/Pages to the bottom of the window to view my pages alphabetically or by page number

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  Your help will be appreciated,

  Don Unwin

  [Personal information]

  All I had to do was to click on the links and information in the drop-down list.

• Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?

  Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?

  It does not ask the cloud your computer admin password password!

• Help with the query to select only one record from the result set in double

  Hello

  Please help with the query. Version of Oracle database we use is 10g R2.

  I have a vision that is duplicated IDS, but they are used across the different functions. See below examples of data. Please help me with a query to select only one record (based on ID regardless of the area) from the bottom of the result set of duplicate records. For what is the point of view is there unique records, given the combination of the fields ID, Org, DF, dry, Sub-Sec

  ID	Org	DF	Sec	Sub-Sec

  
  (163)CQCPDMCPDMHD(163)PCENGENGENG(163)CQASICASICIS8888TSTACTACTAC(163)TSHEHESW6789CQINFOINFOFOS6789PCSECSYSSECSYSINFO16789TSSECSYSSECSYSINFO29009PCBMSBMSBMS1

  My result set must eliminate the duplicate identifiers regardless of whoever we choose of the result set. (I mean without distinction Org, DF, s, Sub-s). My expected result set should be.

  ID	DSB

  
  DF
  SEC
  Sub-Sec
  (163)CQCPDMCPDMHD8888TSTACTACTAC6789CQINFOINFOFOS9009PCBMSBMSBMS1

  
  

  Thank you

  Orton
  

  Hello

  This sounds like a job for ROW_NUMBER:

  WITH got_r_num AS

  (

  SELECT id, DSB, df, s, sub_sec org

  ROW_NUMBER () OVER (PARTITION BY ID.

  ORDER BY org

  ) AS r_num

  OF view_x

  )

  SELECT id, DSB, df, sub_sec s,

  OF got_r_num

  WHERE r_num = 1

  ;

  He is a Top - N query example, where you choose the elements of N (N = 1 in this case) from the top of an ordered list.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) to your sample data and the results desired from these data.  (I know that you said that you were a view selection.  Just for this thread, pretending it is a picture and post simple CREATE TABLE and INSERT statements to simulate your point of view).
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.  (I didn't quite understand the explanation above.  I don't know why you want to

  ID ORG DF DRY SUB_SEC

  --      ---     --      ---     -------

  1234 CQ DPRK DPRK HD

  and is not

  1234 IS CQ ASIC, ASIC

  or

  TS 1234 IT IT SW

  or

  1234 CQ ASIC ASIC HD

  )
  If you change the query at all, post your modified version.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002

• need help with the query, thx

  Hello
  I need a little help with the query I have to write;
  the table has 4 columns:

  col1               col2         col3       col4
  emp_name     empl_id    salary      year
  
  content of data:
  
  col1               col2         col3       col4
  smith             12           1200      1999
  smith             12           1340      2000
  smith             12           1500      2001
  jones             13           1550      1999 
  jones             13           1600      2000
  aron              14           1200      2002

  what I am asking is the following result: salary according to the latest available year
  i.e.

  smith         12         1500        2001
  jones         13         1600        2000
  aron          14         1200        2002

  ID appreciate some guidance on how to achieve
  Thank you
  Rgds

  select *from
  (select col1, col2,col3, col4,row_number() over(partition by col1 order by col4 desc)  rn  from 
  ) where rn=1
  

• Help with the query

  Hi, can someone help me with the query. I try to display comm based on calculation below

  SAL < 5000 then 10%

  5000 - 10000 then 15%

  > 10000 then 20%

  This is the query

  DECLARE

  v_comm number (7.2);

  v_Name emp.ename%type;

  v_empno emp.empno%type;

  v_sal emp.sal%type;

  BEGIN

  SELECT ename, empno, sal IN

  v_Name, v_empno, v_sal

  EMP;

  v_comm: = (IF v_sal < v_sal*.10 then 5000;)

  ELSIF v_sal between 5001 AND 10000 THEN v_sal*.15;

  Of ANOTHER v_sal > 10001 THEN v_sal*.20;

  END IF ;);

  dbms_output.put_line(v_Name||) e with empno' | v_empno | "win a comm' | v_comm);

  END; /

  also tried

  DECLARE

  v_comm number (7.2);

  v_Name emp.ename%type;

  v_empno emp.empno%type;

  v_sal emp.sal%type;

  BEGIN

  SELECT ename, empno, sal IN

  v_Name, v_empno, v_sal

  EMP;

  IF v_sal < v_comm then 5000: = v_sal*.10;

  ELSIF v_sal between 5001 AND 10000 THEN v_comm: = v_sal*.15;

  Of ANOTHER v_sal > 10001 THEN v_comm: = v_sal*.20;

  END IF ;);

  dbms_output.put_line(v_Name||) e with empno' | v_empno | "win a comm' | v_comm);

  END;

  /

  Hello

  Look at the syntax of the IF in the PL/SQL manual.  Comapre to the instruction BOX and also the expression BOX.

  Perhaps, instead of an IF statement

  v_comm: = (IF v_sal<5000 then="">

  ELSIF v_sal between 5001 AND 10000 THEN v_sal*.15;

  ELSE v_sal > 10001 THEN v_sal*.20;

  END IF ;);

  you wanted to write an expression BOX, like this:

  v_comm: = BOX

  WHEN v_sal< 5000                ="" then="" v_sal="" *="">

  WHEN v_sal BETWEEN 5001 AND 10000 THEN v_sal *.15

  WHEN v_sal > 10001 THEN v_sal *.20

  END;

  Or perhaps cela:

  v_comm: = v_sal * CASE

  WHEN v_sal<=  5000="" then="">

  WHEN v_sal<= 10000="" then="">

  OF AUTRE.20

  END;

  You can also use a CASE expression in the SELECT statement.

• Need help with the query. Help, please

  Hey everyone, need your help.  Thank you in advance.  In my view, there is function Pivot.  Just do not know how to use this function.  I have the query that works.  The result is:

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 dental plan pre-tax amount 29,65

  11-111-1111 Vlad 16505 01/04/2013 dental pre-tax 5 August 13 Plan level EE + SP

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Option TOP dental plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax dental care plan pay the value

  11-111-1111 16505 Vlad 01/04/2013 dental pre-tax 5 August 13 Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 amount pre-tax medical Plan of 5 August 13 149

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Medical Plan level EE + SP

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan medical Option MED

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 plan pre-tax pay value

  11-111-1111 16505 Vlad 01/04/2013 5 August 13 pre-tax Medical Plan period Type

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 pre-tax Plan PPO medical Plan

  11-111-1111 Vlad 16505 01/04/2013 5 August 13 Vision Plan amount 5.94 pre-tax

  But I need the result to be

  Amount of SSN ID name item level Option PayValue period Type

  11-111-1111 Vlad 16505 01/04/2013 null null high of 5 August 13 pre-tax Dental Plan 29,65 EE + SP

  11-111-1111 Vlad 16505 01/04/2013 null null MED 5 August 13 149 medical plan pre-tax EE + SP

  11-111-1111 Vlad 16505 01/04/2013 Vision Plan before taxes of 5 August 13

  Select distinct
  ' 11-111-1111 "as ssn,
  WOMEN'S WEAR. Employee_number,
  "Vlad" as EMPLOYEE_FULL_NAME,
  TO_CHAR (papf.start_date, "MM/DD/YYYY") as Date_Of_Hire
  a.effective_start_date,
  PETF.element_name,
  pivf. Name,
  peevf.screen_entry_value

  Of
  PER_all_PEOPLE_F women's wear
  per_assignments_f A
  pay_element_types_f petf
  pay_element_links_f pelf
  PAY_ELEMENT_ENTRIES_F penf
  PAY_ELEMENT_ENTRY_VALUES_F peevf
  pay_input_values_f pivf
  WHERE
  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")
  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID
  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)
  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)
  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)
  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID
  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID
  AND papf.employee_number IS NOT NULL
  AND A.assignment_type = 'E '.
  AND A.person_id = papf.person_id
  and papf.effective_end_date > sysdate
  and a.effective_end_date > sysdate
  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)
  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)
  and a.assignment_id = 42643
  and a.assignment_status_type_id = '1'
  order of petf.element_name;

  Change with your query

  SELECT * FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  PIVOT (MAX (screen_entry_value) FOR (name) TO ("Amount" AS 'Amount', 'level' AS 'level', 'Option High' AS 'High Option', 'Pay the value' AS 'Value to pay', 'Period of Type' AS 'Type period'))

  order by element_name;

  (GOLD)

  SELECT ssn,

  Employee_number,

  employee_full_name,

  date_of_hire,

  effective_start_date,

  element_name,

  Max (decode (Name, 'Amount', screen_entry_value)) 'amount. "

  Max (decode (Name, 'Level', screen_entry_value)) 'level ',.

  MAX (DECODE (name, "High Option", screen_entry_value)) "High Option",

  MAX (DECODE (name, 'Value of pay', screen_entry_value)) 'value of pay. "

  MAX (DECODE (name, 'Period Type', screen_entry_value)) 'period of Type '.

  FROM (select distinct)

  ' 11-111-1111 "as ssn,

  WOMEN'S WEAR. Employee_number,

  "Vlad" as employee_full_name,

  TO_CHAR (papf.start_date, "MM/DD/YYYY") as date_of_hire

  a.effective_start_date,

  PETF.element_name,

  pivf. Name,

  peevf.screen_entry_value

  Of

  PER_all_PEOPLE_F women's wear

  per_assignments_f A

  pay_element_types_f petf

  pay_element_links_f pelf

  PAY_ELEMENT_ENTRIES_F penf

  PAY_ELEMENT_ENTRY_VALUES_F peevf

  pay_input_values_f pivf

  WHERE

  PETF.element_name ('Dental Plan before taxes', 'Medical Plan before taxes', "Vision Plan before taxes")

  and petf. ELEMENT_TYPE_ID = pelf. ELEMENT_TYPE_ID

  and (trunc (sysdate) BETWEEN pelf. EFFECTIVE_START_DATE AND pelf. EFFECTIVE_END_DATE)

  and (pelf. ELEMENT_LINK_ID = penf. ELEMENT_LINK_ID and a.assignment_id = penf. ASSIGNMENT_ID)

  and (trunc (sysdate) BETWEEN penf. EFFECTIVE_START_DATE AND penf. EFFECTIVE_END_DATE)

  and penf. ELEMENT_ENTRY_ID = peevf. ELEMENT_ENTRY_ID

  and peevf. INPUT_VALUE_ID = pivf. INPUT_VALUE_ID

  AND papf.employee_number IS NOT NULL

  AND A.assignment_type = 'E '.

  AND A.person_id = papf.person_id

  and papf.effective_end_date > sysdate

  and a.effective_end_date > sysdate

  and (trunc (sysdate) BETWEEN women's wear. EFFECTIVE_START_DATE AND women's wear. EFFECTIVE_END_DATE)

  and a.effective_start_date = (select MAX (effective_start_date) from PER_ASSIGNMENTS_f where assignment_id = a.assignment_id)

  and a.assignment_id = 42643

  and a.assignment_status_type_id = '1')

  GROUP BY ssn, employee_number, employee_full_name, date_of_hire, effective_start_date, NOM_ELEMENT

  order by element_name;

• Need help with the query using the aggregation

  If I have a table, defined as follows:
  
  CREATE TABLE range_test
  (
  range_id NUMBER (20) NOT NULL,
  rank of char (1) NOT NULL,
  lower_bound_of_range NUMBER (5.2) NOT NULL,
  upper_bound_of_range NUMBER (5.2) NOT NULL,
  received_date_time_stamp SYSTIMESTAMP NOT NULL DEFAULT TIMESTAMP
  );
  
  And I wanted to query the table to find the range associated with the last line inserted for each 'class' (for example 'A', 'B', 'C', etc.), how would I go about this?
  
  I want something like the following, but I know that it will not work right:
  
  SELECT
  grade,
  lower_bounding_of_range,
  upper_bounding_of_range,
  Max (received_date_time_stamp)
  Of
  range_test GROUP BY received_date_time_stamp;
  
  Thanks for your help... I am frustrated with this one and I think that it should be possible without having to use the PL/SQL (i.e. the functions of SQL aggregation or subqueries should work).

  Perhaps something along the lines of...

  SQL> ed
  Wrote file afiedt.buf
  
    1  select deptno, empno, ename, hiredate
    2  from emp
    3* order by deptno, empno
  SQL> /
  
      DEPTNO      EMPNO ENAME      HIREDATE
  ---------- ---------- ---------- --------------------
          10       7782 CLARK      09-JUN-1981 00:00:00
          10       7839 KING       17-NOV-1981 00:00:00
          10       7934 MILLER     23-JAN-1982 00:00:00
          20       7369 SMITH      17-DEC-1980 00:00:00
          20       7566 JONES      02-APR-1981 00:00:00
          20       7788 SCOTT      19-APR-1987 00:00:00
          20       7876 ADAMS      23-MAY-1987 00:00:00
          20       7902 FORD       03-DEC-1981 00:00:00
          30       7499 ALLEN      20-FEB-1981 00:00:00
          30       7521 WARD       22-FEB-1981 00:00:00
          30       7654 MARTIN     28-SEP-1981 00:00:00
          30       7698 BLAKE      01-MAY-1981 00:00:00
          30       7844 TURNER     08-SEP-1981 00:00:00
          30       7900 JAMES      03-DEC-1981 00:00:00
  
  14 rows selected.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  select deptno, empno, ename, hiredate
    2  from (
    3        select deptno, empno, ename, hiredate
    4              ,row_number() over (partition by deptno order by hiredate desc) as rn
    5        from emp
    6       )
    7  where rn = 1
    8* order by deptno, empno
  SQL> /
  
      DEPTNO      EMPNO ENAME      HIREDATE
  ---------- ---------- ---------- --------------------
          10       7934 MILLER     23-JAN-1982 00:00:00
          20       7876 ADAMS      23-MAY-1987 00:00:00
          30       7900 JAMES      03-DEC-1981 00:00:00
  
  SQL>
  

• need help with the query: (Frank)

  Hi Frank,.
  
  I have the oracle 8 database.
  I have the following table with the data structure:
  
  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID
  

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES
  

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part
  
  for this I used the following query, but it gives the result worng...
  
  can help me please in this way to get this...
  

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren') 
  group by sid having count(pid) >= 2

  Hello

  Jojo wrote:
  Hi Frank,.

  It would be nice if someone with a different name helped you? Do not restrict yourself by addressing someone in particular in your subject line or the first message.

  I have the oracle 8 database.
  I have the following table with the data structure:

  TABLE P (PID, PNAME, COLOR)
  PRIMARY KEY: PID

  PID     Pname    Color
  p1...........          Red
  P2.................    green
  p3...............       blue
  p4 ..................   red
  

  CAT TABLE (SID, PID, COST)
  KEY: SID MAIN + PID
  KEY REFERENCE: SID REFERENCE S.SID
  PID P.PID REFERENCES

  Sid        Pid       COst....
  S1        P1
  S2        P2
  S3        P3
  S1      P4
  S2       p1
  S3        p1
  

  now my question is:
  I want to find the SIDS of suppliers that provide a red and a green part

  for this I used the following query, but it gives the result worng...

  can help me please in this way to get this...

  select sid from cat
  where pid in (select pid from p where color= 'red'
            union
            select pid from p where color = 'gren')
  group by sid having count(pid) >= 2
  

  You don't like what is the number of lines with a pid; If you had 20 rows all said 'p1', that would be good enough. The number of distinct colors of the whole ('red', 'green') is what is important.
  Avoid the UNION when there is a simple alternative. The UNION tends to be slow.

  You can use a join instead, like this:

  SELECT       c.sid
  FROM       cat     c
  ,            p
  WHERE       p.pid          = c.pid
  AND       p.color       IN ('red', 'green')
  GROUP BY  c.sid
  HAVING       COUNT (DISTINCT p.color)     = 2
  ;
  

  If you would care to post CREATE TABLE and INSERT statements for the sample data and the results that you want from this data, then I could test this.

  Published by: Frank Kulash, January 10, 2011 15:25

• Help with the query to create hourly statistics

  Hello!

  I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

  I need to create a query to display the number of jobs running for all hours during the last two weeks.

  A job can run for more than an hour.

  
  

  I tried to define what it means for a job during an interval:

  
  

  Job.Start_date < = Interval.end AND Job.Finish_date > = Interval.start

  
  

  Can help you with this query?

  
  

  Thank you!

  Mihai
  

  
  

  Hi, Mihai,

  User810719-Oracle wrote:

  Hello!

  I have an array of jobs. Each task has a start_date and a column end_date. end_date can be null if the job is still running.

  I need to create a query to display the number of jobs running for all hours during the last two weeks.

  A job can run for more than an hour.

  I tried to define what it means for a job during an interval:

  Job.Start_date <= interval.end="" and="" job.finish_date="">= Interval.start...

  You gave essentially the solution yourself.  You just need to outside join your jobs table to a table (or, in the example below, a result set that acts like a table) containing 1 row for each interval.  You can use NVL to equate finish_dates with an effective DATE NULL, so they will be counted:

  WITH intervals AS

  (

  SELECT TRUNC (SYSDATE, 'HH') - ((LEVEL-1)/24) AS interval_start

  , TRUNC (SYSDATE, 'HH') - ((LEVEL-2)/24) AS interval_end

  OF the double

  CONNECT BY LEVEL<= 14="" *="">

  )

  SELECT i.interval_start

  EARL of (j.start_date) AS jobs_running

  Intervals I have

  LEFT OUTER JOIN jobs j WE j.start_date<=>

  AND NVL (j.finish_date

  i.interval_end

  ) > = i.interval_start

  ;

  If you would care to post a small example of data (CREATE TABLE and INSERT statements) and the results desired from this data, I was able to test this.

  Simplify the problem for display.  Do what you are interested only for the past 6 hours, not the last 2 weeks.  We will find a solution that can easily adapt to any number or intervals.

• Need help with the query string manipulation

  Hello
  
  With the help of 10.1.0.4.2
  
  Given a table called PREFIX_CODES that contains a column called PREFIX_CODE
  with the following data:
  
  PREFIX_CODE - VARCHAR2 (20)
  -------------------
  AAA
  BENAMER
  CARTER
  
  and another table called SUBSCRIBERS with a column called SUBSCRIBER_ID
  with the following data:
  
  SUBSCRIBER_ID - VARCHAR2 (30)
  ---------------------
  BBBB-123456
  AAA-444444
  DD-2222222
  EEEE-888888
  
  Is there a query that will pull all the SUBSCRIBER_ID that begin with
  each of the PREFIX_CODES? The following query is not valid, but it
  This will give you an idea of what I'm trying to do:
  
  SELECT SUBSCRIBER_ID
  SUBSCRIBERS
  WHERE AS SUBSCRIBER_ID (SELECT PREFIX_CODE |) » %'
  OF PREFIX_CODES)
  
  Using the data from above, I would like that the query to return:
  
  BBBB-123456
  AAA-444444
  
  Thanks for your help!

  Hello

  Welcome to the forum!

  You were on the right track. To find if a given subscriber corresponds to any prefix_code, you can do an EXISTS subquery:

  SELECT     subscriber_id
  FROM     subsribers     s
  WHERE     EXISTS ( SELECT  NULL
                    FROM      prefix_codes
             WHERE      s.subscriber_id     LIKE prefix_code || '%'
              )
  ;
  

  This will tell you if at least a prefix code. It won't tell you exactly how many, or what they were.
  Your message, I'm guessing that there may be more than one, and you can deduct the subscriber_id itself, then the above query should work for you.

• Help with the query to return the last possible value

  Can someone please help me to create a query for the situation below?
  
  Table: TABLEA
  Columns:
  FACID VARCHAR2 (10),
  DEPTID VARCHAR2 (10),
  CHARGENUMBER NUMBER (10)
  
  I have the following data:
  
  A, B, 1
  A, B, 2
  C, D, 3
  C, D, 4
  
  I will return the following:
  
  A, B, 2
  C, D, 4
  
  In other words, I would return the last possible CHARGENUMBER for FACID and DEPTID.
  The table has no index, and it is responsible for a worksheet in that order.
  
  Thank you very much!

  Hello

  If you have a TIMESTAMP column, called entry_dt, you can use a Top - N query like this to find the last x entries.

  WITH  got_rnum  AS
  (
       SELECT  my_table.*
       ,     RANK () OVER (ORDER BY entry_dt DESC)     AS rnum
       FROM     my_table
  )
  SELECT     *     -- or list all columns except rnum
  FROM     got_rnum
  WHERE     rnum     <= x
  ;
  

  It is very common to have a trigger to ensure that columns like entry_dt are met.

  If you have only one statement that inserts with hundreds of lines, they can all have the same entry_dt. (The value of SYSTIMESTAMP is constant throughout a statement, even if it takes a few seconds).
  The above query uses RANK, so if you tell him you want the last 10 entries, it can return more than 10, because it includes all lines with exactly the same entry_dt as the 10th. If you want to exactly 10 rows returned, even if there is a tie for 10th place, then use ROW_NUMBER instead of RANK; the rest of the query is the same.