Balance sheet for a YEAR between two dates in the dashboard

Similar Questions

• List of years between two dates

  Hello

  I am new to Livecycle Designer and learning I will.

  I have a few questions related to the same question.

  1. is it possible to create a list of years between two dates, especially the exercises? (I'm in Australia so it's July 1 to June 30).

  for example

  User between two dates in date fields:

  (Start Date of the project field) July 1, 2012 and (end Date of the project field) 30 June 2015

  Have an auto list to fill out as below:

  (List)

  2013

  2014

  2015

  or ideally

  (List)

  2012/13

  2013/14

  2014/15

  linking this (if possible).

  2. is it possible to have to repeat the lines created automatically in a table for each of the fiscal years indicated in the list above?

  If either / both of them are possible help that someone could provide would be very appreciated.

  Thank you

  Ivan

  Hello

  Please find an example that shows what I think you would do here - https://workspaces.acrobat.com/?d=F9t-rLq3bapw2d-XY0dRuQ

  I ran a few test cases and did not include the error handling to keep the code as easy to read as possible.

  If you open the form and look at the code in the click event of the update button, then that's where all the magic happens.

  Hope this helps

  Malcolm

• Calculate the (age) years between two dates

  Nice day!

  I have not been able to find an answer, that I was able to use in the archives or online and would be very grateful for the help.  I'm working with Adobe Acrobat Pro XI (not LiveCycle) and I have very little experience with programming (for the most part, copy / paste).

  I need to create a text box that calculates the number of years between two dates entered, i.e. the age when the date of birth and death are given.  Also, would be nice if she was a Virgin until the two were provided.  Anyone would be able to give me the code I need to put in the custom calculation script?

  Once again, any help would be much appreciated!  Thank you and have a wonderful day!

  For the fields for Date of birth DOB and DOD for the Date of death and age in complete years both by using a'd-mmm-yyyy' date format you can use a custom calculation to the JavaScript for the field of age as:

  function GetField (cName) {}
  get the field with error trapping object;
  oField var = this.getField (cName);
  test error;
  if(oField == null) app.alert ("error during the" + cName, 1, 0);
  Returns the field object;
  return oField;
  } / / end GetField function;

  function {Scand (cFormat, cString)
  using date string format convert object date;
  convert string to date using format;
  Kai var = util.scand (cFormat, cString);
  the value null is an error of conversion;
  if(oDate == null) app.alert ("Conversion error" cString "by using the format" + cFormat, 1, 0);
  date of return;
  Return to oDate;
  } / / end Scand function;

  clear the value of the field;

  Event.Value ="";
  get data dob and dod;
  var oDOB = GetField ("DOB");
  Var o = GetField ("DOD");

  treat only if DOB and DOD have value and are not null;
  If (oDOB! = null & o! = null & oDOB.value! = "" & oDOD.value!) = "") {}

  convert the DOB and DOD to date objects.
  oDOB var = util.scand ("d-mmm-yyyy", oDOB.value);
  O var = util.scand ("d-mmm-yyyy", oDOD.value);

  get the difference over the years;
  var Age = oDOD.getFullYear () - oDOB.getFullYear ();

  adjust for month of previous DOD DOB;
  If (oDOD.GetMonth)< odob.getmonth())="">

  adjust the DOD before DOB date in the month of birth;

  If (oDOD.GetMonth () == oDOB.getMonth () & oDOD.getDate ())< odob.getdate())="">
  Set the value of the field;

  Event.Value = Age;
  }

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• Difference between two dates in the server behaviors

  Hello all,.

  I am trying to create a Recordset by using server behaviors and that I'm not an expert in php, I'm completely lost...

  The problem is this: I want to find in a table of all the records where the difference between today's date and date of creation (stored in this table, although course) is superior to, say 30 days. How can I specify the variable field?

  Thank you very much in advance for your help!

  You must use a sql like query below:

  SELECT * FROM table WHERE creationDate< date_sub(now(),="" interval="" 30="">

  'table' is the name of the table that you want to select the information of and 'creationDate' being the column 'date' in the database

• Number of days between two Dates in the Correct month

  I am trying to write a SELECT statement that returns the number of days spent on a project.
  
  Here's my problem. I have a table with several columns of date (start_date, end_date, etc.) as well as several other columns. Here is an example of the table.
  
  PROJECT... START_DATE... END_DATE
  123 ................. 1ST JANUARY 13... 15 JANUARY 13
  456 ................. 25 JANUARY 13... FEBRUARY 5, 13
  789 ................. 30 JANUARY 13... FEBRUARY 5, 13
  999 ................. 1ST FEBRUARY 13... FEBRUARY 8, 13
  
  I'm counting the number of days spent on projects in each month. For example, with the above data, I would come back...
  
  MONTHS... PROJECT_DAYS
  Jan ............. 24
  Feb ............. 18
  
  I tried to use a CASE statement, but I'm having a hard time to understand. Any help would be greatly appreciated!
  
  Published by: 987079 on February 8, 2013 13:12

  An option would be something like

    1  with project as (
    2    select 123 project_id, date '2013-01-01' start_date, date '2013-01-15' end_date from dual union all
    3    select 456, date '2013-01-25', date '2013-02-05' from dual union all
    4    select 789, date '2013-01-30', date '2013-02-05' from dual union all
    5    select 999, date '2013-02-01', date '2013-02-08' from dual
    6  ),
    7  all_days as (
    8    select start_date + level - 1 dt
    9      from (select min(start_date) start_date,
   10                   max(end_date) end_date
   11              from project)
   12   connect by level <= end_date - start_date + 1
   13  )
   14  select trunc(dt,'MM'),
   15         count(*)
   16    from all_days ad
   17         join project p on (ad.dt between p.start_date and p.end_date)
   18   group by trunc(dt,'MM')
   19*  order by trunc(dt,'MM')
  SQL> /
  
  TRUNC(DT,'MM')        COUNT(*)
  ------------------- ----------
  2013-01-01 00:00:00         24
  2013-02-01 00:00:00         18
  

  Justin

• Number of Saturdays between two dates

  Hello

  How can I get number of Saturdays between two dates, including the two dates?

  for example number of Saturdays between 09/05/2014 and 10/05/2014 is five

  Help, please

  I use oracle 10g

  SQL> with t
    2  as
    3  (
    4  select to_date('05/09/2014 ', 'dd/mm/yyyy') from_dt
    5       , to_date('05/10/2014 ', 'dd/mm/yyyy') to_dt
    6    from dual
    7  )
    8   select to_char(from_dt + (level-1), 'fmDay') day_
    9        , count(*) cnt
   10     from t
   11  connect
   12       by level <= to_dt - from_dt + 1
   13    group
   14       by to_char(from_dt + (level-1), 'fmDay');
  
  DAY_             CNT
  --------- ----------
  Saturday           5
  Thursday           4
  Tuesday            4
  Friday             5
  Wednesday          4
  Monday             4
  Sunday             5
  
  7 rows selected.
  
  SQL>
  

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben

• find the difference in days between two dates

  Hello world
  
  I'm trying to find out the difference in days between two dates and the execution of the query that I'm passing
  
  SELECT TO_char(sysdate, 'dd/mm/yyyy') - TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL
  
  the error I get is
  
  ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  Could someone please help.
  
  Thanks in advance

  user10636796 wrote:
  Hello world

  Thanks a lot for all the replies. I am trying to apply it in a statement to my table like this

  SELECT trunc (sysdate) - TO_char (date_last_recommended, ' dd/mm/yyyy') DAYS OF recommendation;

  SELECT trunc (sysdate) - TRUNC (date_last_recommended) DAYS OF recommendation;

• Dynamic action - Get the difference between two dates + times

  I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
  
  Here is what I got (this is apex 4.0):
  
  Two date pickers + two numbers fields (date/start/end times)
  
  I created a dynamic action on the page who fires on the point lose focus (above points).
  
  The real action for the DA is the body of the PL/SQL function:

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
    end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
    :P1_HOURS := end_date-start_date;
  End;

  When I change the values on the page, I get the following error:
  
  AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
  
  I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!

  Hi djston,

  because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
    end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
    RETURN (end_date-start_date)*24;
  End;
  

  and P1_REQUESTED_HOURS like 'item affected. "

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

  Published by: Patrick Wolf on January 17, 2011 10:54

• Calculate the number of days between two dates

  Hello

  Can someone help please change my formcalc script to calculate the number of working days between two date fields.  My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.

  If

  (HasValue (Start_Date1) & HasValue (End_Date1)) then

  $

  = Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1

  on the other

  ""

  endif

  Any help will be most appreciated.

  Thank you.

  Check...

  (1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.

  (2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.

  Steve

• Difference of two dates in the month

  I need to find the difference between two dates as the number of months:
  find the last day of the month of the two dates. subtract and give the difference in number of months.

  user637544 wrote:
  I need to find the difference between two dates as the number of months:
  find the last day of the month of the two dates. subtract and give the difference in number of months.

  Why not just use MONTHS_BETWEEN function? That does not help?

  SQL> SELECT sysdate FROM Dual;
  
  SYSDATE
  ---------
  01-JUN-09
  
  SQL> SELECT MONTHS_BETWEEN (SYSDATE,
    2                         TO_DATE ('01/01/2009', 'DD/MM/YYYY')
    3                        ) diff_in_months
    4    FROM DUAL;
  
  DIFF_IN_MONTHS
  --------------
               5
  
  SQL>
  

  You can also use the LAST_DAY function to get the last day of the month.

  SQL> SELECT LAST_DAY(sysdate) FROM Dual;
  
  LAST_DAY(
  ---------
  30-JUN-09
  
  SQL> SELECT MONTHS_BETWEEN (LAST_DAY(SYSDATE),
    2                         LAST_DAY(TO_DATE ('01/01/2009', 'DD/MM/YYYY'))
    3                        ) diff_in_months
    4    FROM DUAL;
  
  DIFF_IN_MONTHS
  --------------
               5
  
  SQL>
  

  Kind regards
  JO

  Published by: Joice John - added LAST_DAY function example

• Number of weeks between two dates that are in the same or different year

  Hello

  How to calculate the number of weeks between two dates?

  for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014
  

  
  

  Thanks in advance.

  lukx
  

  Hello

  Looks like your date range is incorrect.

  Please try the below.

  SQL >-front right

  SQL > select D2 - D1 "days."

  2 round ((D2-D1)/7.0) "weeks."

  3 round (Months_between (d1, d2), 0) 'months '.

  (select 4

  5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

  6 from two

  (7) date_range;

  Elapsed days weeks months

  ------------ --------- ---------

  46         7         1