Behavior of the PriorityQueue using Java 6

Hello

I have a code for test PriorityQueue ordering of items with it below is the natural order.

Out of SOP1 is clear to me.

I was expecting
SOP2 as: [a, b, d]
SOP3 as: [a, b, c and d]

Import Java.util;
Class PQTest {}
Public Shared Sub main (String... args) {}
PriorityQueue < String > pq = new PriorityQueue < String > ();

PQ. Add ("b");
PQ. Add ("d");
System.out.println (PQ); Output SOP1 [b, d]

PQ. Add ("a");
System.out.println (PQ); SOP2 output [a, d, b]

PQ. Add ("c");
System.out.println (PQ); SOP3 output [a, b, c, d]
}
}

Could someone shed some light?
Appreciate your help.

The method toString() of a PriorityQueue in no way reflect the order of the elements in the queue. Given that the PriorityQueue is based on a 'heap' (see http://download.oracle.com/javase/6/docs/api/java/util/PriorityQueue.html and http://www.cs.auckland.ac.nz/software/AlgAnim/heaps.html) the order that you see in the toString() is probably the physical order of the elements in the table used to back up the 'heap' which is not the logical order of queue.

Tags: Java

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