Build the name of guard of the table of the last element, but not the others. Workaround solution?
Hello
Sorry if this has been posted before, I did the search first, but can't find anything.
Problem is that I have two configurations which are identical and must be ordered by a single vi. Given that they are the same, they are configured with the same sets of parameters so I decided to create a cluster of these and then build an array of clusters. In this way I need to use only a thread and if I need a given parameter I can get it easily from here (or so I thought) and also because I need to see if anything changes I can compare a thread instead of each of the parameters.
The gui has the list of parameters, then in the block diagram I group them appropiately, using "Bundle name" and then each bundle in a table by using "build the table. Problem is when I have the index in the array for the first place of the configuration and usage to unbundle the parameters I need, using "ungroup by name" (although if I use "Unbundle" the same thing happens) and lo and behol, the output names come from the configuration of the second, not the first.
Here's the curious thing, though, even if the names are all wrong, that the values are correct. I could live with that, but it's more boring it will be another very difficult user to understand the schema more this is just a proof of principle to test with two, eventually there will be eight or more and who's going to get really confusing.
Is there a way to get around this? Even if it is to change the names after unbundling.
Check the attached vi to see what I mean.
I think you forget an important point on the tables. The only thing that may be different between each element of a table is its value. The elements in the array must all share the same properties. This would therefore include the names of the different elements that make up the cluster that is a table element.
It seems that the last group that builds in the table is the one that defines the names of the items that are in the element of the cluster. You must give all elements of the array with the same name within the cluster. Or use a cluster of clusters rather than a table of cluster to create your data structure.
Tags: NI Software
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