calculate the day of the year using the date.

Hi all
Can calculate us the day of the year using the date form? Is this possible? Please help me thanks in advance
Like this
30/08/2009-30/08/2010 after calculation - 365

Sarah

Published by: SarahSarahSarah on August 30, 2009 12:49 AM

Sarah.

: ins1.noday must be a part of number!

Create a function in forms like this:

function get_nodays ( f_dtm_start in date,
                      f_dtm_end   in date ) return number is
begin
if
  f_dtm_start is null OR
  f_dtm_end is null
then
  return ( null );
end if;
return ( trunc ( f_dtm_start ) - trunc ( f_dtm_end ) );
exception when others
then message ( sqlerrm || ' in function get_nodays occured.' );
return ( null );
end;

Call this function in the when-validate-point triggers on ins1. INSPERIOD and: ins1.end love

:ins1.noday := get_nodays ( :ins1.INSPERIOD, :ins1.end );

It is redundant to have the: noday as a cause of part of database
the value may by calculated every time using the values INSPERIOD and: end.

Tags: Oracle Development

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PDF Acroform Javascript (WIN): Calculate the Date of next Tuesday

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You just need to call this function, and then use the string that it returns. What

does not work, exactly?

PowerCLI does not calculate the Date year statement

Hello
I have a custom to attribute Date (JJ/MM/AAAA) in vCenter and I attempt to bring together WHAT VM before that date but does not my statement appear to account for the year. So if I put a date in the future for example 15/01/2012 the script lists than before the current date is incorrect and everything goes back beyond the date of the day but still in 2011 is not displayed is correct. Any ideas would be greatly appreciated.
$currentdate = get-Date
$currentdate = $currentdate. ToShortDateString()
Get - VM | Get-Annotation - CustomAttribute "Expires"? {$_. Value - the "$currentdate"} ' "
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See you soon!

Have you thought about converting the date you get the attribute. Try this

$currentdate = get-Date

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How to calculate the date interval

Hi Experts,

I'm looking for a way to calculate the interval between two dates. And get the result to the format "dd.mm.yyyy hh24:mi:ss.

select  sysdate - to_date('1.1.2000 12:00:00','dd.mm.yyyy hh24:mi:ss') from dual

Best practices for a problem like this?

Best regards
Igor

select trunc( months_between( day2, day1 ) / 12 ) years
     , mod( trunc( months_between( day2, day1 ) ), 12 ) months
     , numtodsinterval( day2 - add_months( day1, trunc( months_between( day2, day1 ) ) ), 'DAY' ) rest
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How to calculate the data according to the fiscal

I want to dispaly the result for  the accounting year from April to March for any accounting year (Accounting year is from April to March). 
I have a table INVOICE. 

CREATE TABLE INVOICE
(
  IN_NO       NUMBER,
  IN_DT       DATE,
  IN_DETAILS  VARCHAR2(20 BYTE)
)

I want to calculate display the result for accounting year from April 2010 to March 2011, and from April 2011 to MArch 2012.
What statement should i use to filter the data as above ?

Sanjay

user12957777 wrote:

I want to dispaly the result for  the accounting year from April to March for any accounting year (Accounting year is from April to March).
I have a table INVOICE. 

CREATE TABLE INVOICE
(
IN_NO       NUMBER,
IN_DT       DATE,
IN_DETAILS  VARCHAR2(20 BYTE)
)

I want to calculate display the result for accounting year from April 2010 to March 2011, and from April 2011 to MArch 2012.
What statement should i use to filter the data as above ?

Sanjay

You should now learn to use correctly

 tags

select to_char(add_months(in_dt,-3),'YYYY') FISCAL_YEAR FROM INVOICE;

Calculate the Date of the next
Hello

I have two dates:

Start date: December 18, 2007
End date: December 18, 2012

I would like to calculate the next payment date, using the example above, it would be December 18, 2010.

How can I achieve this in SQL by using the current date / month, keeping in mind, if sysdate is past the date, then the next payment date will follow month.

Thank you

Published by: sliderrules on December 15, 2010 08:50
Hello

Assuiming the due date is the same day of the month (if possible) as start_date:
```
SELECT  start_date
,     ADD_MONTHS ( start_date
             , CEIL ( MONTHS_BETWEEN ( SYSDATE     -- or maybe SYSDATE + 1
                                     , start_date
                            )
                 )
             )  AS next_payment_date
FROM    table_x
;
```
If you happen to run it on December 18, the expiry date should be December 18 or January 18?
The code above returns on 18 December. If you want Jnauary 18, replace SYSDATE SYSDATE + 1.

Assuiming that the due date is the same day of the month (if possible) as end_date, you could do something similar with the help of end_date.
Whatever it is, only one of the columns plays a role in this problem? What results would you if, for example. start_date was January 1, 2010 and July 20, 2012 end_date?

I hope that answers your question.
If not, post a small example of data (CREATE TABLE and INSERT statements) and also publish outcomes from these data. For the results, after what you want if it was executed on 15 December 2010 at noon.
Explain, using specific examples, how you get these results from these data.
Always tell what version of Oracle you are using.

Calculate the date of the first or last in a quarter
Hello

I have data of project with a start date and end date I need to calculate the number of days per quarter

project x: 15/03/06 - 15/05/06
15 days Q1 = Q2 = 45 days

I'm then going to calculate the percentages of resource. I can get the bt of the watch with a hack of a time to identify the first or the last day of a given quarter. Any help win my sincere admiration.

Sorry, misread the question. The district will rely on the company that you work for. If the end of his is the same as an end of year calendar (31 December), then the example below will be accurate. Change the dates according to the needs of the company.
You can hardcode the variables in your application.cfm page.
quarter1start = "01 - jan -";
quarter2start = '01 - apr -';
quarter3start = "01 - jul -";
quarter4start = '01 - oct -';

Programatically, the end of each quarter is always the day before the start of the next quarter.
I would add "year" to the equation dynamically, to keep in it before compatible.

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I use the following to try to establish the number of difference in days between the dates of two different recordsets. The result using test data should be 15, but I get 0. No code error message, but no accurate result either. I checked the date two values involved, and they send the data appropriate to the right format... just can't get the DateDiff function to work in the session... variable all help greatly apprciated.

Code:

< % Session("Lead") = DateDiff ([d], [rsSurvey.Fields.Item("tblShipDat"). Value], [rsOrder.Fields.Item("tblValDat"). % of value]) >
Thank you very much for any assistance... it was indeed the brackets surrounding table columns names that have crossed upwards. Correct solution:

< %="">< br="">Session("Lead") = DateDiff ("d", rsSurvey.Fields.Item("tblShipDat"). Value,< br="" >="" rsorder.fields.item("tblvaldat").="" valeur)="">< br="" >="" %="">

All entries are greatly appreciated. Really the non-professional coder help advance...

Kind regards

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How to calculate the date from sysdate

I try to get 12/09/2009-12:51:30 by subtracting the current date to sysdate.
I can get with this year, but I don't know how I can get to the date and the month preceding.
() Choose add_months (sysdate-36() of double) = 12/09/2010
Planned result 12/09/2010 13:23:30
Thank you for the help

I'm assuming that time is fixed if it is to see the example below.

SQL > select add_months (to_date (to_char(sysdate,'dd-mon-yyy') |)) (("" 12:51:30 ',' dd-MON-yyy hh: mi: ss AM "), - 36) prior_date
2 double;

PRIOR_DATE
-----------------------
12 - Oct - 2010 12:51:30

SQL >

split with day, month and year in a date

Hi all
I have this point of view
with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
--
-end of test data
--
SELECT id, dt
floor (months_between(sysdate,dt)/12) years
, floor (mod (months_between (sysdate, dt), 12)) months
-The day is ambiguous because of the number of days in a different month
-you could design your own algorithm to give the desired results, but it is a good approximation
, floor (sysdate-(add_months (dt, floor (months_between (sysdate, dt))) as dys
t
/
ID DT YEARS MONTHS DYS
---------- ----------- ---------- ---------- ----------
1-6 FEBRUARY 2010 5 8 22
2 29 NOVEMBER 2001 13 10 29
3-6 FEBRUARY 2011 4 8 22
4-10 OCTOBER 2011 4 0 18
As a result, 26 years old, 26 months, 91 days.

And subtract years, MONTHS and DYS as format
erase years, from 1 to 12 months and the days of the 1 to 30 as
91 days = 30 x 3 + 1 = > 1 day over 3 months
26 months + 3 months = 29 months = > 24 months + 5 months = 2 years + 5 months
and 26 years + 2 years = 28
desire to result: 28 years, 5 months and 1 day.
Is there a function that give me this result from the query above?
Kind regards
Gordan

Hello Gordan,.

I understand that you are the SUM of all the lines.

Here are two ideas:

-1 - using a date
(a) SUM (TRUNC (sysdate) - dt)
I would give you the total number of days.
(b) adding the number of days to, for example, DATE ' 1900-01-01' would give another date...
(c) simply subtract the years 1900 and it takes several years,
subtract 1 from the month (1-12 from January to December) and you have the number of months
subtract 1 from the day of the month (1-31) and you have the number of days.
It is of course 'approximate' as the months do not have the same number of days...

-2 - using only the number of days
Maybe you want something else, for example: the total number of days divided by 365.25 for many years, the recall divided by 30 to get the number of months, the reminder being the number of days.

(a) SUM (TRUNC (sysdate) - dt)

I would give you the total number of days.

(b) Division by 365.25 (le.25 is to take leap years into account, but you can choose for example "365")

(c) number of reminder of days (total - years * 365.25): divided by 30 is the number of months

(d) number reminder of days (total - years * 365.25 - months * 30): gives the number of days.

The following two options with your test data (by chance, this gives the same result in this case)

option 1:
with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
target_date AS
(SELECT DATE ' 1900-01-01' + SUM (TRUNC (sysdate) - t.dt) FROM t trgt)
in_pieces AS
(SELECT TO_NUMBER (TO_CHAR (td.trgt, 'YYYY')) - 1900 y
, TO_NUMBER (TO_CHAR (td.trgt, 'MM')) - 1 m
, TO_NUMBER (TO_CHAR (td.trgt, 'DD')) - 1 d
Target_date TD
)
SELECT "result: ' |"
TRIM (CASE WHEN ip.y = 0 THEN NULL
WHEN ip.y = 1 THEN "1 year"
Of OTHER TO_CHAR (ip.y) | "years".
END |
CASE WHEN ip.m = 0 THEN NULL
WHEN ip.m = 1 THEN "1 month"
Of OTHER TO_CHAR (ip.m) | 'months '.
END |
CASE WHEN ip.d = 0 THEN NULL
WHEN ip.d = 1 THEN "1 day"
Of OTHER TO_CHAR (ip.d) | 'days '.
END
)
Of in_pieces ip
;
result: 28 years, 4 months and 28 days

option 2:

with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
nb_days AS
(SELECT SUM (TRUNC (sysdate) - t.dt) n t)
, y AS
(SELECT Nb.n, FLOOR (nb.n / 365.25) y nb_days n. b.)
ym AS
(SELECT y.n, y.y, FLOOR ((y.n-y.y * 365,25) / 30) FROM a)
ymd AS
(SELECT ym.y, ym.m, ym.n - ym.y * 365.25 - ym.m * ym FROM 30 d)
SELECT "result: ' |"
TRIM (CASE WHEN ymd.y = 0 THEN NULL
WHEN ymd.y = 1 THEN "1 year"
Of OTHER TO_CHAR (ymd.y) | "years".
END |
CASE WHEN ymd.m = 0 THEN NULL
WHEN ymd.m = 1 THEN "1 month"
Of OTHER TO_CHAR (ymd.m) | 'months '.
END |
CASE WHEN ymd.d = 0 THEN NULL
WHEN ymd.d = 1 THEN "1 day"
Of OTHER TO_CHAR (ymd.d) | 'days '.
END
)
WAN
;
result: 28 years, 4 months and 28 days

Best regards

Bruno Vroman.

Get Excactly day after 60 years of timeStamp data
Hi all
I want to find excact date after 60 years of timeStamp data how do I get the result?

For example
"Given TimeStamp = ' 1940 - 05 - 01 00:00:00.0"

Result =' 00:00:00:0 2000-05-10'
which is exactly the date after 60 years of data date .thank you

Please help me.
Hello
Use the following syntax

Select to_char (add_months (sysdate,(60*12)), "yyyy-mm-dd hh24:mi:ss") of the double;

Add_months is the arithmetic function of date. It accepts 2 parameters, 1st date, 2nd month u want add u date passed as parameter 1.

Concerning

UMI

How to calculate the date fields while excluding Saturday and Sunday

Hi, I use Jdeveloper 11.1.3.4

I have an Oracle database and creates a table called holiday with 3 attributes:

user (VARCHAR)

(early)

end (date)

The idea is that you subtract the finish from the beginning and get a number of vacation days used. The thing is that the sum should exclude Saturday and Sunday.

Any way to do it?

/* Formatted on 6/1/2011 7:57:32 AM (QP5 v5.149.1003.31008) */
WITH t AS (  SELECT id,
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                    MAX (finish) finish,
                    SUM (dys) days_off
               FROM (SELECT id,
                            strt,
                            finish,
                            CASE
                               WHEN TO_CHAR (dy, 'day') LIKE 'saturday%' THEN 0
                               WHEN TO_CHAR (dy, 'day') LIKE 'sunday%' THEN 0
                               ELSE 1
                            END
                               dys
                       FROM vacations
                     MODEL
                        PARTITION BY (ID id)
                        DIMENSION BY (0 d)
                        MEASURES (POCETAK strt, KRAJ finish, POCETAK dy)
                        RULES
                           (dy [FOR d FROM 1 TO finish[0] - strt[0] INCREMENT 1] =
                                 (NVL (dy[CV () - 1], dy[CV ()]) + 1)))
           GROUP BY id
           ORDER BY id)
SELECT t.id,
       t.strt,
       t.finish,
       t.days_off,
       vacations.korisnik,
       SUM (
          CASE
             WHEN finish < TO_DATE ('01/07/2011', 'dd/mm/yyyy') THEN days_off
             ELSE 0
          END)
       OVER (PARTITION BY vacations.korisnik ORDER BY t.id)
          this_years_running_total,
       SUM (
          CASE
             WHEN finish < TO_DATE ('01/07/2011', 'dd/mm/yyyy') THEN days_off
             ELSE 0
          END)
       OVER (PARTITION BY vacations.korisnik)
          this_years_grand_total,
       SUM (
          CASE
             WHEN finish >= TO_DATE ('01/07/2011', 'dd/mm/yyyy')
             THEN
                days_off
             ELSE
                0
          END)
       OVER (PARTITION BY vacations.korisnik ORDER BY t.id)
          next_years_running_total,
       SUM (
          CASE
             WHEN finish >= TO_DATE ('01/07/2011', 'dd/mm/yyyy')
             THEN
                days_off
             ELSE
                0
          END)
       OVER (PARTITION BY vacations.korisnik)
          next_years_grand_total
  FROM t, vacations
 WHERE t.id = vacations.id

id                    strt               finish        daysoff          korisnik    thisyrruntot  thisyrtot   netyrruntot    nextyrtotal
1     5/25/2011     5/31/2011     5     Kantardzic     5     22     0     26
2     6/6/2011     6/13/2011     6     Kantardzic     11     22     0     26
5     6/1/2011     7/6/2011     26     Kantardzic     11     22     26     26
6     6/16/2011     6/30/2011     11     Kantardzic     22     22     26     26

Calculate the interval in days
Hi all!

I need your help.

I have an oracle sql table.

This is going to...

TABLENAME: RACE
DATE NAME
JANUARY 11, 12 JAMES
JAMES JANUARY 12, 12
JAMES JANUARY 14, 12
JAMES JANUARY 17, 12
JAMES 22 JANUARY 12

1 FEBRUARY 12 JOHN
FEBRUARY 11, 12 JOHN
JOHN 13 FEBRUARY 12
JOHN 14 FEBRUARY 12
28 FEBRUARY 12 JOHN
JOHN 1ST MARCH 12

HOW can I calculate the date total interval (difference) for James and John in days?
for example in this case total is 7 days for James (January 11, 12 to 12 January 12 is 0 days and 12 January 12 to January 14, 12 is 1 day and 14 January 12 to 17 January 12 is 2 days) and 24 days for John

Data for the date will be random and can be up to names and dates of difference 60 so I would like to calculate all the names of different... Thank you!
Is there anyway that I can query without listing all the date?

Yes, just use the lower part of the "Real application" comment, that is:
```
select max(dt)-min(dt)-count(*)+1 diff
,      nm
from   race
group by nm;
```
I used the WITH only clause to generate some testdata...

Calculate the time period
I want to calculate the date to end date of beginning period, but I have problem
For example, my start date is 'August 21, 2011' and my End Date is "August 21, 2012".
So I want to result as months of the year and days like this is "2 YEARS".
I wrote this command from pl/sql, but I figured it
"TWO YEARS AND SIX DAYS."
Please tell me how to calculate this period
I have enclosed my query

----------------- QUERY ----------------------
Declare
number of mtot_days;
number of mdays;
number of myears;
number of mmonths;
V_Month Varchar2 (10);
V_Year Varchar2 (10);
V_Days Varchar2 (10);
Start
break;
mtot_days: days = (: from_date,: to_date);
myears: = floor(mtot_days/365);
mmonths: = floor(mtot_days/30);
If mmonths = 12 then
mmonths: = 0;
end if;
Mdays: = mod(mtot_days,30);
If mmonths = 1 then
V_Month: = "MONTHS";
on the other
V_Month: = "MONTHS";
End If;

If myears = 1 then
V_Year: = "YEAR";
on the other
V_Year: = "YEARS";
End If;
If mdays = 1 then
V_Days: = "DAY";
on the other
V_Days: = "DAYS";
End If;

If myears = 0 and mmonths! = 0 and mdays! = 0 then
: period: = mmonths | ' ' || V_Month | «AND» | Mdays | ' ' || V_DAYS;
ELSIF
Mdays = 0 and mmonths! = 0 and myears! = 0 then
: period: = myears | ' ' || V_Year | «AND» | mmonths | ' ' || V_Month;
ELSIF
mmonths = 0 and myears! = 0 and mdays! = 0 then
: period: = myears | ' ' || V_Year | «AND» | Mdays | ' ' || V_Days;
ELSIF
myears = 0 and = 0 and mdays mmonths! = 0 then
: period: = mdays | ' ' || V_Days;
ELSIF
Mdays = 0 and = 0 and myears mmonths! = 0 then
: period: = myears | ' ' || V_Year;
ELSIF
Mdays = 0 and = 0 and mmonths myears! = 0 then
: period: = mmonths | ' ' || V_Month;
ELSIF
Mdays! = 0 and myears! = 0 and mdays! = 0 then
: period: = myears | » ' || V_Year | » ' || mmonths | » ' || V_Month | ' AND ' | Mdays | » ' || V_Days;
on the other
: period: not = "ANY TIME."
End If;

end;
not every month has 30 days. Use ADD_MONTHS() instead:
```
SET SERVEROUTPUT ON

DECLARE
   v_start DATE := TO_DATE('21-AUG-2011', 'DD-MON-RRRR');
   v_end DATE := TO_DATE('22-JUN-2014', 'DD-MON-RRRR');
   v_cnt_years NUMBER := 0;
   v_cnt_months NUMBER := 0;
   v_cnt_days NUMBER := 0;
   v_date DATE;
BEGIN
   v_date := v_start;

   WHILE ADD_MONTHS(v_date, 1) <= v_end
   LOOP
       v_date := ADD_MONTHS(v_date, 1);
       v_cnt_months := v_cnt_months + 1;
       IF v_cnt_months = 12 THEN
          v_cnt_years := v_cnt_years + 1;
          v_cnt_months := 0;
       END IF;
   END LOOP;
   v_cnt_days := v_end - v_date;
   --
   DBMS_OUTPUT.PUT_LINE(
       TO_CHAR(v_start, 'DD-MON-RRRR') || ' - ' ||
       TO_CHAR(v_end, 'DD-MON-RRRR') || ': ' ||
       v_cnt_years || ' Years, ' || v_cnt_months || ' Months, ' || v_cnt_days || ' Days');
END;
/
```
outpupt vor several ranges:
```
21-AUG-2011 - 20-AUG-2012: 0 Years, 11 Months, 30 Days

21-AUG-2011 - 21-AUG-2012: 1 Years, 0 Months, 0 Days

21-AUG-2011 - 22-AUG-2012: 1 Years, 0 Months, 1 Days

21-AUG-2011 - 22-JUN-2014: 2 Years, 10 Months, 1 Days
```
Published by: Serge the 25.03.2011 10:46

Choose the date
Hello

I need to select all dates between two dates. This selection is plu query subquery, return of rows of data per day (month or year) between two dates.
I use object and trunc (sysdate + rownum) for select dates.

Is it posible to optimize this somehow? For example, use the stored procedure that generates all the dates between the two parameters. Please tell me how to do it.

Thanks and greetings
Hello

CONNECTION BY and double is faster than ROWNUM and a large table.
Try this:
```
SELECT     p_from_date + LEVEL - 1
FROM     (
          SELECT     DATE '2009-10-01'     AS p_from_date
          ,     DATE '2010-07-01'     AS p_to_date
          FROM     dual
     )
CONNECT BY     LEVEL <= 1 + p_to_date
                        - p_from_date
```
If you build only a few hundred dates, then it would not significantly faster.

variable presentation changing the data type date to string the Calende
Hi gurus,

I'm having a strange problem. I have a Start date and end date fast that aren't on any column presentation for example (in the case where 1 = 0 DATE. DATE other cast ('2100-12-31 Date ') end).
Now, this prompt, I put 2 startdate and enddate variables presentation to use in my sql filter in the report.i use these variable to calculate the date for these 2 end dates and then I apply between it function with these 2 dates.
The question is when the dashboard is running for the first time the presentation variable takes the dates as the DATE "' 2009/14/10 and when I change the date and click on the go button, the variables is October 15, 2009" as strings anf so DATE in my SQL filter functions fails and error throughts VD.

All of the suggestions!
Nico explain already.

Select date '' 2009-12-15 of the double - TRUE
Select date of 2009 '-15-12' of the double - ORA-01843: not one month valid
Select date ' 10/2009/15 ' of double - ORA-01861: literal does not match the format string

DATE 'yyyy-mm-dd' does that have this format.

Concerning
Goran
http://108obiee.blogspot.com

calculate the day of the year using the date.

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