Calculation of log base 2 of 35 s new

I would like to calculate the necessary resolution for an ADC with analog input will accept a +/-10V swing with a background noise of 0.4mV. The counties of RMS are 20.0V/0.0004V = 50 000 points - just easy. To set the 50 000 RMS number of bits is: bits = log2 (50,000). How can I make my new imagination 35 s to calculate log base 2 of 50 000? Help is appreciated - thanks.

Hello

To calculate LOG2(A) use LOG (A) / log (2) or LN (A) /LN (2).

Here is a program to do this (run in RPN mode):

To use, type number and XEQ, then, ENTERED.

HTH

Tags: HP Tablets

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