Calculation of time

Could use a little help. I work on the calculation of a starting time for a hike. I have the time I want to end up like 17:00, the next cell contains the number of miles. I want to take the time of the end, subtract the number of miles / 2 and ending up with a start time.

Here is an example:

Cell A1: 17:00

Cell A2: 13

Cells A3: some math to convert time functions (A1 - (A2 / 2)) = 10:30

Make sense?

You can subtract a duration of a period

Enter the time in the cell B1

Enter the distance you plane to travel to B2

Enter the rate you plan to walk in cell B3

calculate the length of walk in cell B4 by using the formula:

= DURATION (0,0,B2÷B3)

now calculate the start time in cell B5 by using the formula:

B1−B4

Tags: iWork

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    oracle as PaaS cloud environment

    Product VERSION STATUS
    NLSRTL11.2.0.3.0Production
    Oracle Database 11g Enterprise Edition11.2.0.3.064 bit Production
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    Start

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    LOOP

    UPDATE CALc_TIME

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    end;

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  • Time sheet calculation of time fields (TimeIN + TimeOUT) - (BreakIN + BreakOUT)

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    I'm really a novice in the field of pdf script, I would like to ask if someone could help me make a calculation script of a time field with a TOTAL production WORKED HOURS in a day to a calculation of

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    TimeBreakIN: 20:00

    TimeBreakOUT: 21:00

    OUT time: 02:30

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    ACROBAT-PRO-QUESTION-1.jpg

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  • Calculation of time with FormCalc

    Hello!

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    It does not work. I mean, if I inform startTime = 10:00 and endTime = 11:00, the result is 23:00. How is it?

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    Greetings of the season!

    Marcos

    Hello

    Check this thread.

    It describes a solution for this kind of calculation.

    http://forums.Adobe.com/message/4054814#4054814

  • calculation of time under a form

    I have a form, I can't understand how to calculate time I have 6 boxes, in that I need to put some time and the box 7 would be the total time.

    This form is used to our fire department to show the trucks in road - to - stage time - to-another sure - to - left scene - to - service time... and then the total time in the final area I believe that subtract you all the time on the road in total. but I have no idea, I tried everything and can not understand.  I can download the form if you need.

    Thank you

    I have attached an updated version of your form.

    The time calculations are always a bit tricky, and it is one of the areas that I wish that Adobe would treat a little better.  In this case, I assumed that you are using 24-hour time formats.  Calculation of the difference is a bit tricky, since shopping can extend to midnight and the end time value will be smaller than the start time.  The simplest method is fairly rudimentary: calculate the hours and minutes separately and adjust if the time extend to midnight.

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  • Help with the calculations of time

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    CREATE TABLE AAA_CDR
    (ACCTTYPE (1) NUMBER, MSID VARCHAR2(20 BYTE), ACCOUNTSESSION_ID VARCHAR2(64 BYTE), BEGINNINGSESSION NUMBER (1),)
    SESSIONCONTINUE NUMBER (1), ACCT_MULTI_SESSION_ID VARCHAR2(64 BYTE), DATAOCTETCOUNTORIGINATING NUMBER (20), DATAOCTETCOUNTTERMINATING NUMBER (20), ACCTSESSIONTIME NUMBER (20));

    -SQL statement that produces these data:
    / * Select msid, accountsession_id, beginningsession, sessioncontinue, ACCTTYPE, acct_multi_session_id,.
    dataoctetcountoriginating, dataoctetcountterminating, acctsessiontime
    OF AAA_CDR
    where msid = "5C4CA98EAC4C."
    ORDER BY acct_multi_session_id, accountsession_id, accttype
    */

    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '190001E9', 1, 0, '100014E19775F169', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', '190001E9', 0, 0, '100014E19775F169', 47496, 182054, 70);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', ' 290001C 4', 1, 0, '100014E19E21F16C', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', ' 290001C 4', 0, 0, '100014E19E21F16C', 3278162, 17540714, 14152);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', 190001 FC', 1, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', 190001 FC', 0, 1, "100014E1A949316E", 682734, 2935111, 1553);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '190001FD', 0, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', '190001FD', 0, 1, "100014E1A949316E", 1821052, 9585090, 5368);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '190001FE', 0, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', '190001FE', 0, 1, "100014E1A949316E", 42012, 505004, 213);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '19000200', 0, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', 0, '19000200', 1, '100014E1A949316E', 50224, 144566, 729).
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '19000201', 0, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', 0, '19000201', 1, '100014E1A949316E', 62634, 378416, 392);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (1, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 0, 0, 0);
    Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
    Values (2, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 1457286, 9141033, 7574);
    commit;

    I need to calculate the sum (dataeoctetcountoriginating) + sum (dataoctetcountterminating) for each session
    It is average, but the beginning of the session and the end of the session, as below,
    for each ACCT_MULTI_SESSION_ID and MSID
    the beginning of the session is when the accttype = 1 and beginningsession = 1
    and the end of the session is at this time the accttype = 2 and SESSIONCONTINUE = 0


    1. collect the first accounting start CDR generated an event online for a user.
    Collect CDR AcctType is 1 and beginning of Session is 1 according to MSID. In
    also, see the value of the Acct-Multi-Session-ID field in the CDR.
    2. collect all Accountants stop CDRs generated during this event the user online.
    Collect CDR AcctType is 2 according to MSID and Acct-Multi-Session-ID.
    If the value of Session continues on a CD - r accounting stop is 0, it indicates that this CDR
    is the last CDR of accounting judgment that is generated during the event of the user's offline.
    3. calculate the total volume of the user during this event online.
    Add the values of the data fields Byte Count (termination) and data values
    Fields byte (native) Count in the accounts collected stop CDRs together to get
    the total volume of this event the user online.

    How can I find each session, then calculate the sum of this session?
    any help please

    Published by: user11309581 on July 13, 2011 22:01

    Is that what you are looking for:

    select
       acct_multi_session_id,
       max(ACCTSESSIONTIME)-min(ACCTSESSIONTIME)
    from AAA_CDR
    group by acct_multi_session_id
    

    According to the DDL and DML you provided, this is the output I see:

    ACCT_MULTI_SESSION_ID,MAX(ACCTSESSIONTIME)-MIN(ACCTSESSIONTIME)
    100014E19E21F16C,         14152
    100014E19775F169,         70
    100014E1A949316E,         7574
    
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    Hi all

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    endif

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    Thank you

    Gene-O

    Ok

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    endif

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    $ = full time

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  • Time of calculation relative to the size of the db

    Hello

    I have a database with versions and various scenarios. I have an estimate every night (not just an aggregation) that runs on a scenario and version. As other versions and scenarios have been created, the size of the database has grown up a bit, and the nightly calculation every time develops new scenario/version data sets are created. Has always been my understanding that education fix limit the number of blocks in the calculation, and in theory, existing data in other intersections not being set to should have nothing to do with the calculation time. However, this is not my experience. I even tested out in app development by erasing all the data in 8 of the other versions and scenarios and saw my time reduced by 27%. Does anyone know why this should be? It comes to me that we save more historical copies of the data, the computing time on the active data will grow and develop.

    We are currently implementing a BSO/ASO solution to reduce the data in the cube of the BSO, but I do not see why it should be necessary and want all overview of this.

    Thank you

    Sabrina

    You can be calculate on these blocks, but the charge of these operations increases grows the database

    Whenever he has to calculate on a block, it must go in the index file - find the location of the block in the .pag file, and then open the .pag file and integrate this memory block.

    I am not opposed to the segregation of historical data which is not often used and which moving a cube separated from a design perspective, and it probably would be a good idea if the cycle on your calcs time take forever.

    You can try and improve performance by changing the cache settings - but that is performance tuning and is beyond the scope of your original question.

    -Matt

  • Add 2nd HARD drive to Time Capsule - best practices?

    Hello

    I have an iMac running El Capitan at the end of 2012, supporting up to a 4th Gen 2 TB Time Capsule. The total size of my backup is 1.05 to. Incremental backups take the total space used on the TC to about 1.6 TB.

    Fear of the HARD drive TC will: phut that I, as a "belt and Suspenders" approach, yesterday signed a 2 TB Western Digital Elements HARD drive for the TC and other introduced Time Machine backups. He is currently conducting his first backup to the new HARD drive to the Mac OS extended (journaled) format.

    The iMac and the TC are connected via 200AV Homeplugs.

    I have two questions if you don't mind...

    Should I have copied the existing backups from the drive HARD internal TC for the new drive external HARD first, so that two backups are ongoing for the same item, with the same 'history', as they save in alternation? What is wise or even possible? As is stands, the new hard drive back up the iMac from scratch so if the TC HDD died, I'd lose all historical backups (they date back to March 2015), with just a very recent version on the new HARD drive.

    The progress of the backup on the new disk, while that connected to the TC, is slow. After that 11 hours I'm only 16 GB to 1.05 TB - it has not yet calculated the time remaining yet :-) I assumed connecting via Homeplug iMac would be more robust than the Wi - Fi for such a transfer of data. I appreciate there are several factors at play here - the size of the files, the indexing of the backup, the speed of the Homeplugs, age / my wiring standard, etc. etc.

    I would have been better connecting this direct drive new external DRIVE in the iMac, the first backup, then connect it to the TC to continue it's incremental backups replacing? Yet once, is it still possible?

    Thank you very much for any help. After spending only to Mac a few years back I love TM - I have never found a Windows backup system that has worked for me the way of TM.

    See you soon.

    Should I have copied the existing backups from the drive HARD internal TC for the new drive external HARD first, so that two backups are continue from the same point with the same "historical."

    IMHO you do it the correct way back up again.

    The story is not so important after a few weeks and months... If the computer was stolen for example... what you want to do is to restore the computer as is... and what you were doing last year is really little relevant... Even if the TC Gen4 goes wrong, the story is never likely to be lost by the TC Gen4... it just needs the disc removed to put in the work. But it's the current image of the computer which is always the most important.

    We found copy of the enormously successful backups. Although in this case it would have been possible to do an archive... always if you asked the question of what you need to do... Myself and several others here always recommend a new clean as backup being the most reliable method.

    I would have been better connecting this direct drive new external DRIVE in the iMac, the first backup, then connect it to the TC to continue it's incremental backups replacing? Yet once, is it still possible?

    This is a good question... EOP adapters can be very slow. Slower than wireless AV200 are a pretty old standard and the actual speed could be all about 30Mbps down... It might surprise you... and indeed there have been measured before.

    The problem is that Time Machine backs up differently on the local network FC drives... When you plug the USB key into the TC then it's a network drive and the backup will not be recognized.

    Pondini wrote a method to get around this.

    Here see Q18.

    http://pondini.org/TM/FAQ.html

    I have not tried... Bob Timmons that's regular shows here has and discovered that it was not reliable. In my view, that a backup is too important to fiddling so.

    However, leaving the USB drive plugged into the Mac and keep the local backup of very good sense. It is much faster and more reliable than the backups over the network.

    If you really want to have the backup on the WD drive plugged into the TC, then I recommend do you via ethernet... Remove the TC of the network if it is too far for a patch lead... you can save the current configuration (export from the main menu of airport utility), then plug it into the computer directly with a short patch lead... and the USB in the TC, the backup will be much more quick... less than one full day (24 hours) for 1 TB if all goes well. Once completed you can then put the TC via the USB back in the network location.

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