Calculation of time difference

Similar Questions

• calculation of time between two time as timestamp

  How can calculate two hour, START as the timestamp TIME in the data type, END TIME as of time also.

  select END_TIME-START_TIME from PROG_DLY_WORK
  

  Result

  + 01:50:00.000000 000000000

  How can get exactly the time spent as 01:50 ? and these calculated time must sum (elapsed_time) in another column.

  oracle as PaaS cloud environment

  Product	VERSION	STATUS
  NLSRTL	11.2.0.3.0	Production
  Oracle Database 11g Enterprise Edition	11.2.0.3.0	64 bit Production
  PL/SQL	11.2.0.3.0	Production
  AMT for Linux:	11.2.0.3.0	Production

  Time difference between two columns in hours

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24).

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

  Lag in minutes

  Start

  FOR REC IN (SELECT START_TIME, END_TIME, CALC_TIME CAL_ID)

  LOOP

  UPDATE CALc_TIME

  SET ELAPSED_TIME = round (())

  TO_DATE (to_char (REC. End_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")-

  TO_DATE (to_char (REC. Start_time, 'ddmmyyyyhh24miss'),

  "ddmmyyyyhh24miss")

  () * 24 * 60)

  WHERE CAL_ID = REC. CAL_ID;

  END LOOP;

  end;

• calculation of time under a form

  I have a form, I can't understand how to calculate time I have 6 boxes, in that I need to put some time and the box 7 would be the total time.

  This form is used to our fire department to show the trucks in road - to - stage time - to-another sure - to - left scene - to - service time... and then the total time in the final area I believe that subtract you all the time on the road in total. but I have no idea, I tried everything and can not understand.  I can download the form if you need.

  Thank you

  I have attached an updated version of your form.

  The time calculations are always a bit tricky, and it is one of the areas that I wish that Adobe would treat a little better.  In this case, I assumed that you are using 24-hour time formats.  Calculation of the difference is a bit tricky, since shopping can extend to midnight and the end time value will be smaller than the start time.  The simplest method is fairly rudimentary: calculate the hours and minutes separately and adjust if the time extend to midnight.

  In the attached form, I made the first column for you.  There are new javascript in the case to calculate cell TotalTime910.  You should be able to copy this script and paste it into the Calculate event to other cells TotalTime; the only change you'll need to do is to change when the startTime and endTime values are extracted.  For example, for the TotalTime911 cell, we will use the Row2.enroute911 and Row6.InService911 fields.

  Don't forget to change the drop-down list JavaScript language when you paste in each event.

  Also, I changed the models of cell for the cells in the column 910: null} | NUM 9999 {}.  This will display the values in the right format of 24 hours, for example 0200 at 02:00.  If it works for you, copy the model in other cells in the table.  I eliminated the zero {} template because it causes midnight you should see a white; It should be displayed as 0000.

  Finally, all this falls apart if you are on-site 24 hours. In this case you will need the date and time to make it work.  I hope that nothing in your town will burn so long.

• Convert time difference in seconds in hours, minutes, and seconds

  Hi all
  
  I used the following logic to calculate the time difference between 2 passes of time for all the individual lines.
  
  (floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24) |) ':' || MOD (Floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24 * 60), 60) |': ' | MOD (Floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24 * 60 * 60), 60))
  
  The user asked a column that displays the SUM of all the differences in time between the report.
  
  Any help much appreciated!
  
  
  Thank you
  Sweta

  Simply the sum of time_actioned - time_allocated, then do the same calculation you make on this sum.

  John

• calculate the time difference.

  Hello

  How to calculate the time difference by using javascript.

  Example 15.05 and18.35 difference is 2 h 30 min

  BTW: it isn't ~ 2h30min is 3h30min

  Maybe something like this works:

  // result is 3.300000000000002 ~ 3h 30min
  (parseFloat((18.35 - 15.05) / 3600) * 3600)
  

• "There is a time difference between the client and the server"

  Unit 4.0.3

  Everything worked very well, and all of a sudden, I'm not able to connect to the server unit using any domain account. When I enter the domain/name username/password, I get this error message:

  ************************************************

  The system is unable to log on due to the following error:

  There is a time difference between the client and the server.

  Try again or contact your system administrator.

  **************************************************

  I can use the same domain account (unityinstall) and the journal in other machines. I can connect the machine to the unit using a local account. There is no time difference between the DC server and unity.

  Need help,

  Thank you

  Partha

  Log on to your LOCAL computer using an account that has privileges

  At the command prompt, type the following:

  NET TIME ancien_mot_passe/set

  Found this on the MS site:

  Cannot open a session if the Date and time are not synchronized

  http://support.Microsoft.com/default.aspx?scid=kb;en-us;232386&product=Win2000

• A design of query for the conversion of time difference in days, hours, Minutes

  Hi all

  A design of query for the conversion of time difference of time in number of days remaining remaining hours minutes and rest in seconds. Made this one till now. Please suggest for all modifications, until now, it seems to work very well, kindly highlight for any anomaly.

  WITH DATA (startDAte, EndDate, Datediff) AS (SELECT to_date ('2015-10-01 10:00:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-20-01 03:00:49 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-10-01 10:00','yyyy-dd-mm hh24:mi:ss')-to_date('2015-20-01 03:00','yyyy-dd-mm hh24:mi:ss') FROM dual)

  UNION ALL SELECT to_date ('2015-10-01 10:00:39 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-20-01 03:00:40 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-10-01 10:00','yyyy-dd-mm hh24:mi:ss')-to_date('2015-20-01 03:00','yyyy-dd-mm hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 10:30:45 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 11:00:50 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 10:30','yyyy-dd-mm hh24:mi:ss')-to_date ('2015-11-01 11:00 ',' yyyy-mm-dd hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 09:00:50 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 10:00:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 09:00','yyyy-dd-mm hh24:mi:ss')-to_date ('2015-11-01 10:00 ',' yyyy-mm-dd hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 08:30:49 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 09:30:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 08:30','yyyy-dd-mm hh24:mi:ss')-to_date('2015-11-01 09:30','yyyy-dd-mm hh24:mi:ss') FROM dual

  )

  Select

  trunc ((EndDate-StartDate)) days.

  trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24) hours)

  trunc (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60) Minutes,))

  (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60 - trunc (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60)) * 60 seconds))))

  data;

  Thanks for the answers in advance.

  AHA!

  TO_TIMESTAMP expects a string as input, so it first makes an implicit conversion from DATE to a string, in the format of NSL_DATE_FORMAT.

  To convert the TIMESTAMP DATE independently NLS_DATE_FORMAT, use

  CAST ( AS TIMESTAMP)

• How to calculate the time difference

  Hi friends,

  I want to calculate and the sum of the time difference.

  I have two fields in a table. Inside and OUTSIDE. for example.

  OUT IN DIFFERENT

  01:46 15:30?

  01:47 15:45?

  02:50 17:30?

  I want less above figure and the result will appear in different column.

  Help, please

  Kind regards

  Hello

  Assuming that the two columns are the VARCHAR2 data type and "represent" the hours and minutes:

  WITH sample_data AS (SELECT ' 01:46 ' in_col, 15:30 ' out_col FROM DUAL)

  UNION ALL

  SELECT ' 01:47 ' 15:45 ' OF THE DOUBLE

  UNION ALL

  SELECT ' 02:50 ', 17:30 ' OF THE DOUBLE

  )

  SELECT in_col,

  out_col,

  TO_CHAR (TO_DATE ((TO_DATE(out_col, 'HH24:MI')-TO_DATE(in_col, 'HH24:MI')) * 86400, «SSSSS»), "HH24") differ))

  OF sample_data;

  SQL > WITH sample_data AS (SELECT ' 01:46 ' in_col, 15:30 ' out_col FROM DUAL)

  2. ANY TRADE UNION

  3. SELECT ' 01:47 ' 15:45 ' OF THE DOUBLE

  4 UNION ALL

  5. SELECT ' 02:50 ', 17:30 ' OF THE DOUBLE

  6                      )

  7. SELECT in_col,

  out_col 8,.

  9 to_char (TO_DATE ((TO_DATE(out_col, 'HH24:MI')-TO_DATE(in_col, 'HH24:MI')) * 86400, «SSSSS»), "HH24") differ))

  10 FROM sample_data;

  IN_COL OUT_COL DIFFER

  ------ ------- ------

  01:46 15:30 13:44

  01:47 15:45 13:58

  02:50 17:30 14:40

  SQL >

• Time difference calculate for changing value

  
  create table tbl ( id number, value1 varchar2(5), value2 varchar2(5), date_changed date);
  
  insert into tbl (id, value1, value2, date_changed)
  
  values (1,'N', 'RM', '16-DEC-2013');
  
  insert into tbl (id, value1, value2, date_changed)
  
  values (1,'RM', 'U', '17-DEC-2013');
  
  insert into tbl (id,value1,value2,date_changed)
  
  values (1,'S', 'N', '16-DEC-2013');
  
  
  
  
  
  
  

  I would like a report showing registration where value1 = RM and the value 2 = you and the time difference he had to change value2 = RM (this is the record where value1 = N and value2 = RM) to value1 = RM

  ID	value1	value2	time to change
  1	RM	U	1 days, 0 hours, 0 minutes, 0 seconds

  Can this be achieved? If so, how could I do that?

  Thanks Diana

  Try the below

  SELECT T1.ID id,.

  T1. Description MovieFrame,

  T1. Value1 value2,

  T2. Value2 value2,

  T2.date_changed - t1.date_changed | ' days '.

  EXTRACT (HOUR (TO_TIMESTAMP (t2.date_changed) - TO_TIMESTAMP (t1.date_changed))) | ' hour '.

  EXTRACT (MINUTE SINCE (TO_TIMESTAMP (t2.date_changed) - TO_TIMESTAMP (t1.date_changed))) | ' min '.

  EXTRACT (SECOND (TO_TIMESTAMP (t2.date_changed) - TO_TIMESTAMP (t1.date_changed))) | ' dry ' diff

  OF tbl_new t1, tbl_new t2

  WHERE t2.value2 = 'U '.

  AND t1.value2 = t2.value1

  AND t1.id = t2.id;

• selection of image based on exif time difference between images

  Hello

  I am a user of LR5. In a sequence of new pictures to import, I have a few Images that are taken with a time difference of less than 10 seconds. These images are part of a sequence for the stacking of pano. I want to select these images (or the value of a brand like a colored flag) with a single command. Is there a way to implement a script for LR or a way to do this?

  All advice welcome.

  thx a lot.

  kkd

  In the library, try 'Battery Auto capture time'

  

• How do the time difference between two dates?

  Hi all
  
  I use this query to get the time difference between two dates.
  
  Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;
  
  but do not get the correct result.
  
  Thank you

  Left KEY... Left Padding of tanks.

• How do you time differences in first 10 items?

  Hi, I was wondering how to make time differences in first 10 elements. I tried just clidking a picture then clicking on time warp and setting the time for 1 frame but I can't apply it to all of them. I also went to Edition, preferences, general and set of stills duration by default of 1 frame, but it doesn't matter.

  Any suggestions?

  Thank you

  I did a lot of videos broken down into first.

  There are several factors that probably need to test first. The largest exam is the interval of the stills shot, and then the 'look' that one wishes to achieve.

  For the most part, I'm going to Edit > preferences (before I import still Images) and change the time again to something around 3-5 frames. This is once again, after a few tests. Then I import still Images. I also put the duration of Transitions to be quite short, depending on how many images I have chosen.

  After importing, I ensure that the fixed image files are sorted numerically, select several files and drag those to the timeline. Then, I apply the default value (shortened to change preferences > General > video Transitions) to each Image.

  Usually, I start with maybe 10 Images and experiment with life still picture, until I'm comfortable with the look for this topic.

  Good luck and hope that helps.

  Hunt

• Is there an easy way to calculate the time difference?

  I am trying to find a way to calculate the time difference between

  here at a certain time

  var settime:Number = 02:35

  and

  now would be getDate();

  I tried something rediculus, but it does not work when I entered a date less than 24 hours, is there a class out there who can just this kind of things

  or y at - it something on the internet that could tell me the difference between different time

  Thank you

  My attempt

  var date: Date = new Date();

  Set timer to what would I like to call the function
  var lastcallH:Number = 22;
  var lastcallM:Number = 50;
  var lastcallS:Number = 0;

  Set up of the 24-hour clock
  var tHour:Number = 24;
  var tMinute:Number = 60;
  var tSecond:Number = 60;

  Get the current time
  var cHour:Number = date.getHours ();
  var cMinutes:Number = date.getMinutes ();
  var cSeconds:Number = date.getSeconds ();

  Set the first variable
  var fH:Number;
  var fM:Number;
  var fS: Number;

  A second set of Variable
  var sH: number;
  var sM:Number;
  var sS:Number;

  Final conversion for the Timer
  var finalMil:Number;

  Time variables that will need to be converted

  If (lastcallH < Thur)
  {
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);
  }
  ElseIf (cMinutes > 0 | cSeconds > 0) {}
  ++ Choir;
  ++ cMinutes;
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }
  else {}
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }

  sH = fH + lastcallH;
  sM = fM + lastcallM;
  sS = fS + lastcallM;

  If (< 0 sH: sM < 0 | sS < 0)
  {
  sH = sH * (-1);
  sM = sM * (-1);
  sS = sS * (-1);
  }
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);

  Allows you to implement a timer
  var yahooTime:Timer = new Timer (finalMil, repeat);
  var repeat: Number = 1;

  yahooTime.start ();

  yahooTime.addEventListener (TimerEvent.TIMER, displayCall);

  function displayCall(event:TimerEvent):void
  {
  trace ("well let's success");
  }

  your first trace() statement is almost certainly not what you want.

  dtDate2 is 08/08/2009

  and it's probably not what you want.  Flash months are zero-based.  That is to say, January corresponding to month 0 and December is the month 11.

• Time difference in hours

  Hello
  
  I have 2 dates in my picture of the '2008-12-22 12:20 ' format. Can you please help me to find the time difference in hours, excluding Saturdays and Sundays using SQL.
  
  Thanks for all your suggestions.
  
  Sharan.

  Hello Sharan,
  If I understand correctly you want to calculate the difference in hours between 2 dates, excluding Saturday and Sunday hours (a kind of working hours, if we worked 24 hours a day from Monday to Friday :)).

  If this is the case and you have two dates in two columns on the same record to take a look at the following query
  (Loulou gave a solution if you have dates on individual files):

  select id
        ,d1
        ,d2
        ,case
         when trunc(d1,'iw') != trunc(d2,'iw') -- dates in different week
         then
            ((trunc(d1,'iw')+5)-least(d1,trunc(d1,'iw')+5))*24 -- first_week
           +((trunc(d2,'iw'))-(trunc(d1,'iw')+7))/7*5*24       -- middle_weeks
           +(least(d2,trunc(d2,'iw')+5)-trunc(d2,'iw'))*24     -- last_week
         else -- dates in the same week
           (least(d2,trunc(d2,'iw')+5)-least(d1,trunc(d1,'iw')+5))*24
         end as working_hours
  from dates
  ;
  

  Below you can see an example (I guess that d1 is always less than d2):

  SQL> alter session set nls_language = 'AMERICAN';
  
  Session altered.
  
  SQL> alter session set nls_date_format = 'dd-mon-yyyy hh24:mi:ss';
  
  Session altered.
  
  SQL> create table dates (id number, d1 date, d2 date);
  
  Table created.
  
  SQL> insert into dates values (1,to_date('07012009 00:00:00','ddmmyyyy hh24:mi:ss'),to_date('20012009 00:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (2,to_date('08012009 12:00:00','ddmmyyyy hh24:mi:ss'),to_date('13012009 00:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (3,to_date('11012009 00:00:00','ddmmyyyy hh24:mi:ss'),to_date('18012009 12:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (4,to_date('10012009 09:00:00','ddmmyyyy hh24:mi:ss'),to_date('10012009 22:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (5,to_date('10012009 23:00:00','ddmmyyyy hh24:mi:ss'),to_date('17012009 12:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (6,to_date('12012009 23:00:00','ddmmyyyy hh24:mi:ss'),to_date('13012009 12:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (7,to_date('08012009 23:00:00','ddmmyyyy hh24:mi:ss'),to_date('10012009 12:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> insert into dates values (8,to_date('08012009 23:30:00','ddmmyyyy hh24:mi:ss'),to_date('10022009 12:00:00','ddmmyyyy hh24:mi:ss'));
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select id
    2        ,d1
    3        ,d2
    4        ,case
    5         when trunc(d1,'iw') != trunc(d2,'iw') -- dates in different week
    6         then
    7            ((trunc(d1,'iw')+5)-least(d1,trunc(d1,'iw')+5))*24 -- first_week
    8           +((trunc(d2,'iw'))-(trunc(d1,'iw')+7))/7*5*24       -- middle_weeks
    9           +(least(d2,trunc(d2,'iw')+5)-trunc(d2,'iw'))*24     -- last_week
   10         else -- dates in the same week
   11           (least(d2,trunc(d2,'iw')+5)-least(d1,trunc(d1,'iw')+5))*24
   12         end as working_hours
   13  from dates
   14  ;
  
          ID D1                   D2                   WORKING_HOURS
  ---------- -------------------- -------------------- -------------
           1 07-jan-2009 00:00:00 20-jan-2009 00:00:00           216
           2 08-jan-2009 12:00:00 13-jan-2009 00:00:00            60
           3 11-jan-2009 00:00:00 18-jan-2009 12:00:00           120
           4 10-jan-2009 09:00:00 10-jan-2009 22:00:00             0
           5 10-jan-2009 23:00:00 17-jan-2009 12:00:00           120
           6 12-jan-2009 23:00:00 13-jan-2009 12:00:00            13
           7 08-jan-2009 23:00:00 10-jan-2009 12:00:00            25
           8 08-jan-2009 23:30:00 10-feb-2009 12:00:00         540,5
  
  8 rows selected.
  
  SQL> 
  

  I hope having tested all cases.

  See you soon,.
  Davide

  Published by: davide gislon on gen / 11/2009 10:05

• Calculation of the time differences between several lines

  Hello
  
  I have a table as below:
  
  EVENT ID DATE
  1. start 05/03/2012-13:00
  1. stop the 15:00 05/04/2012
  1. start 09:00 05/07/2012
  1 stop on 05/09/2012 10:00
  Start 2 08/06/2012-08:00
  2 stop on 08/07/2012 10:00
  
  I would like to calculate the duration (in hours ideally) between 'Start' and 'Stop' for each ID, so having a set of lines:
  
  ID TimeSpan
  ---------------------
  1 75
  26 2
  
  I would appreciate any idea how to solve this, ideally as a SQL solution or maybe a function.
  
  Thank you very much!
  Tom

  The difference between two dates is a number, where 1 = 1 day. Multiply by 24 to get hours.

  Use the LAG, as stated above, to compare the date prior to the current date.

  create table T(TID, EVENT, TDATE) as select
  1, 'start', TO_DATE('03/05/2012 13:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'Stop',  TO_DATE('04/05/2012 15:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'start', TO_DATE('07/05/2012 09:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'Stop',  TO_DATE('09/05/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  2, 'start', TO_DATE('06/08/2012 08:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  2, 'Stop',  TO_DATE('07/08/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL;
  
  select tid, round(sum(hours)) hours from (
    select case
      when EVENT = 'Stop' then 24*(TDATE - LAG(TDATE) over(partition by TID order by TDATE))
      else 0 end hours,
    TID from T
  )
  group by tid;
  
  TID HOURS
  --- -----
    1    75
    2    26