change the location of the PivotTable columns

Similar Questions

• Change the first column seen in the datagrid by code?

  Hello

  Is anyway to change the first column in a DataGrid using action script? I mean, for example, think I have 10 columns, only 3 are seen (0,1,2). I just want to have a button to change the first column view. Thus, for example, if I press it, 1.2, and third column will be those that is displayed in the datagrid control. I need to emulate the same thing that the scroll bar when you drag in a datagrid, but instead of letting the scroll bar does that automatically, I want to "scroll" datagrid manually.

  Moreover, is anyway through datagrid children and hide the scrollbar manually?

  Thanks in advance,

  Aron.

  horizontalScrollPolicy

• Editable interactive report. To change the list column dropdown type filter.

  Hi all, I thought I had posted this, but I can't find my post, so apologies if it turns up to twice more...

  XE SUMMIT 4.2 11.2

  Ive created an editable interactive report... Everything works very well, and I have several Text, LOV and selection list columns...

  However when I now click on a column header to filter, sort etc drop-down list is the same format as the column itself. So if for example, I have a text box, then the drop-down list is also text boxes, if the column is a column LOV, the filter drop-down list is a list of fields LOV. (Im assuming this is correct behavior, because it simply inherits the column parent..)   So, I would change the lists to a list of standard display so that they are in order and can be used...

  I think so? I know I have to do, which is either to substitute the function that generates the dropdown filter... or probably more simply, write a bit of JS/JQuery that modify data for drop-down lists.  Im still to learn, some help would be appreciated...

  I think so. (and please correct me if I'm talkiing... garbage)   I need to find each of the appearance of the DIV with the ID that corresponds to the drop-down list box, and then loop through each entry and change the structure...

  Currently the source for drop-down fields resembles the following (for a text field...). :

  < div id = "apexir_rollover_content" >

  < a href = "javascript:void (false); ">

  < input type = "text" value = "24489" maxlength = size "2000" = "6" name = 'f06' > < / input >

  < /a >

  < a href = "javascript:void (false); ">

  < input type = "text" value = "N1021" maxlength = "2000" size = "6" name = 'f06' > < / input >

  < /a >

  < / div >

  How could I 1) browse each occurrence of div id = "apexir_rollover_content" on my page, so I found out about each other, how would I go through the list and change the line above an input to a standard list item text...? Or is there a simpler way to do it?

  Kind regards

  Richard

  Hello

  Problem was on your process to GET the VALUES of LOV.

  You did not bind the variable values of cursor.

  I created another process for your page that manages LOV BUDGET_CAT

  Kind regards

  Jari

• Impossible to change the table column heading alignment in 11.1.1.5

  11.1.1.5 work.
  
  I want to align to right one of my headers of columns in the Table view. I'm going in the criteria, the column properties tab. Format of the column and clicking the Format icon next to the column heading box. I'm on the column properties dialog box, change the background color, adding a border and right Horizontal alignment setting. See the table in the results, I see the background color of the column heading, and I see the border. However, the column header text is always aligned to the left.
  
  What Miss me it please?

  Hi Mark,

  You do not have lack of what, whether Oracle has missed this basic functionality! This is a bug :-(

  Bug 12696084: FORMAT HEADINGS > HORIZONTAL ALIGNMENT does NOT WORK IN THE TABLE OR the PIVOT VIEW

  Rgds,
  DpKa

• Hide the PivotTable columns

  Hello

  I'm trying to hide the columns of the pivot table DYNAMIC.

  I want to show specific to the table columns.

  The values(ABC,PQR,XYZ) come from the unique column.

  

  For 2015, I want to show the PQR for 2014, I want to just show ABCand ABC and XYZ.

  Thank you

  Mayur_A

  

  Check your filter logic. Take a look at the above example on SampleApp406: ' Stockplus Inc. ' and 'Tescare Ltd' for 2010 were given, but because of the filter in 2010 only "Genmind Corp" is returned from the database and therefore the pivot see the value of this single column for 2010.

• Dynamically change the Lable column

  Hello
  I'm looking for some help in the report of the apex. I have a requirement where I want to show the name of the month as the column title. That change dynamically. below I have elabrated my requirement.
  
  Report of Novemeber
  Customer name Nov Oct Aug Jul Jun Sep
  99 99 99 99 99 99 XXXXXXXXXXXXX
  99 99 99 99 99 99 XXXXXXXXXXXXX
  
  
  December report
  Customer name Dec Nov Oct Aug Jul Sep
  99 99 99 99 99 99 XXXXXXXXXXXXX
  99 99 99 99 99 99 XXXXXXXXXXXXX
  
  
  I can dynamicallly change column lable shown above?
  
  Thanks in advance

  Set the field Type in the report attributes to PL/SQL and create a body of the function that generates and returns a string delimited by a colon that contains the required headers.

  See + {message identifier: = 10642248} + for an example.

• change the selected column puts loop nested in the hash join

  Hi all
  
  If "select * from...". «I "select table.* of...» "then plan changes.
  

  PLAN_TABLE_OUTPUT
  ----------------------------------------------------------------------------------------------------------------------------------------
  SQL_ID  a4fgvz5w6b0z8, child number 0
  -------------------------------------
  select * from ofertas ofe, ofertas_renting ofer where ofer.codigodeempresa = ofe.codigodeempresa    AND ofer.numerooferta =
  ofe.numerooferta    AND ofe.captacion = '1'
  
  Plan hash value: 3056192218
  
  ----------------------------------------------------------------------------------------------------------------------------------------
  | Id  | Operation          | Name            | Starts | E-Rows | Cost (%CPU)| A-Rows |   A-Time   | Buffers |  OMem |  1Mem | Used-Mem |
  ----------------------------------------------------------------------------------------------------------------------------------------
  |*  1 |  HASH JOIN         |                 |      1 |  23766 |  4032   (2)|  27421 |00:00:00.96 |    5444 |  9608K|  1887K|   10M (0)|
  |*  2 |   TABLE ACCESS FULL| OFERTAS         |      1 |  23969 |  1324   (2)|  27421 |00:00:00.14 |    2140 |       |       |          |
  |   3 |   TABLE ACCESS FULL| OFERTAS_RENTING |      1 |  71297 |   937   (2)|  72385 |00:00:00.22 |    3304 |       |       |          |
  ----------------------------------------------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     1 - access("OFER"."CODIGODEEMPRESA"="OFE"."CODIGODEEMPRESA" AND "OFER"."NUMEROOFERTA"="OFE"."NUMEROOFERTA" AND
                SYS_OP_DESCEND("OFER"."NUMEROOFERTA")=SYS_OP_DESCEND("OFE"."NUMEROOFERTA"))
     2 - filter("OFE"."CAPTACION"='1')
  
  
  22 filas seleccionadas.
  
  PLAN_TABLE_OUTPUT
  ----------------------------------------------------------------------------------------------------------------------------------------
  SQL_ID  2410uqu059fgw, child number 0
  -------------------------------------
  select ofe.* from ofertas ofe, ofertas_renting ofer where ofer.codigodeempresa = ofe.codigodeempresa
  AND ofer.numerooferta = ofe.numerooferta    AND ofe.captacion = '1'
  
  Plan hash value: 4206210976
  
  ----------------------------------------------------------------------------------------------------------------
  | Id  | Operation          | Name               | Starts | E-Rows | Cost (%CPU)| A-Rows |   A-Time   | Buffers |
  ----------------------------------------------------------------------------------------------------------------
  |   1 |  NESTED LOOPS      |                    |      1 |  23766 |  1333   (3)|  27421 |00:00:00.58 |   33160 |
  |*  2 |   TABLE ACCESS FULL| OFERTAS            |      1 |  23969 |  1324   (2)|  27421 |00:00:00.27 |    3910 |
  |*  3 |   INDEX UNIQUE SCAN| PK_OFERTAS_RENTING |  27421 |      1 |     0   (0)|  27421 |00:00:00.26 |   29250 |
  ----------------------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     2 - filter("OFE"."CAPTACION"='1')
     3 - access("OFER"."CODIGODEEMPRESA"="OFE"."CODIGODEEMPRESA" AND
                "OFER"."NUMEROOFERTA"="OFE"."NUMEROOFERTA")
  
  
  22 filas seleccionadas.

  Why change if the cost to access the complete table OFFERS is identical in the two plans?
  
  Thank you very much.
  
  Joaquin Gonzalez
  
  Published by: Joaquín González on November 4, 2008 17:32

  Joaquín González wrote:
  Hello

  Perhaps the reason for Blevel = 0 is?

  "This is."
  some common cases that could result in a variation between the basic formula and the
  "result:

  ...

  "Index where the blevel is set to 1 (the index goes directly from the root block in the).
  leaf blocks). The optimizer ignores effectively the blevel if each column in the index
  appears in a predicate of equality. "

  Joaquin,

  you're referring to the chapter "access Simple B-tree", it is a nested loop operation, so this does not apply. You can see that the 'Simple B-tree access' refers to a cost of 1, you have tested yourself.

  I think that it is a special case, if you have a nested loop operation that uses access unique index as the source of the inner line, then the cost of access unique index is simply BLEVEL - 1. You might get a different cost if access additional table of rowid is involved, which is usually the case. But even in this case access to the unique index is always encrypted in BLEVEL - 1, and access the table by rowid is usually encrypted to 1 by iteration.

  You can see on page 313 (chapter "Nested Loop") that Jonathan has used an example involving a unique index scan that also has a cost of 0.

  Kind regards
  Randolf

  Oracle related blog stuff:
  http://Oracle-Randolf.blogspot.com/

  SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
  http://www.sqltools-plusplus.org:7676 /.
  http://sourceforge.NET/projects/SQLT-pp/

• Change the number columns individually

  I've never used any kind of spreadsheet before, but now I need to build a five-column table, and 300 lines and numbers appears as one of the easiest programs I've seen. The only feature that I have not found is a way to vary the width of individual columns. Is there a way?

  It can be done, and I just learned how. Numbers of resembles the spreadsheet for me.

• Change the Date column tabular database of dd/mm/yyyy to dd/mm/yyyy

  Hi, I use Jdeveloper 11 G with an Oracle database.
  
  My table is empty now, but I am importing some excellent columns inside and dates to throw errors because you have some dates like 14/09/2012, which means the month is out of reach even if it is not.
  
  This seems to be a simple thing to do, but I was unable to find how online.
  
  Help, please

  Table import stuff using SQL Developer - most things in JDeveloper db is in reality.

  What you need to do is to indicate what date format is for incoming data - which allows us to build the inserts properly to the Import Wizard.

  Here's a tutorial to take you through the steps
  http://www.thatjeffsmith.com/archive/2012/04/how-to-import-from-Excel-to-Oracle-with-SQL-Developer/

  Special attention to this screenshot
  http://thatjeffsmith.wpengine.com/wp-content/uploads/2012/04/excel_copy9.PNG

  You want to enter the date format, because it is in the spreadsheet.

• When I imported e-mail addresses into TB, they landed in the nickname column and I can't manually change the addresses of 1000!

  Is there a way I can change the nickname column to e-mail addresses? If I try to import the address book again (I on a different flash drive), I'm afraid I'll have 2 copies and it's going to go even more complicated.

  Remove any address book and do the import again, but this time align the data with the correct address book fields.

• How to change the data type of a column after the creation of the table

  It comes to my table desc

  SQL > desc job1

  Name                                      Null?    Type

  ----------------------------------------- -------- ----------------------------

  JOB_CODE NOT NULL VARCHAR2 (3)

  JOB_CLASS VARCHAR2 (30)

  CHG_HOUR NUMBER (5.2)

  OVERTIMECHARGE NOT NULL NUMBER

  I want to change column CHG_HOUR to store numbers up to 12 digits in length (including the decimal points).

  I tried the following and it did not help

  SQL > alter table job1 change column chg_hour number (6.6);

  ALTER table job1 change column chg_hour number (6.6)

  *

  ERROR on line 1:

  ORA-01735: invalid option of ALTER TABLE

  SQL > alter table job1 change chg_hour number (6.6);

  ALTER table job1 change chg_hour number (6.6)

  *

  ERROR on line 1:

  ORA-01438: value larger than the precision specified for the column

  where I'm going wrong?

  Hello

  I want to change the CHG_HOUR column to store numbers up to 12 digits in length (including the decimal points).

  I tried the following and it did not help

  ALTER table job1 change chg_hour number (12.6);

• How to change the % of cost of full column

  Mr President.
  
  I want to change the cost column % complete, but unable to change it. any way to do it.
  
  Thank you
  Imad

  As I mentioned earlier, you cannot manually change the full value in % of the cost. It is calculated.

  If you use a unique resource for fees, have you tried to change the percent complete units? You can export to Excel (through resource assignments) and then change the values and import to P6.

• How can I change the size of the text column universally?

  I have created a book of a customer to ID CS4. The client decided that he would like a more narrow column of text throughout the book. (Each chapter of the book is its own file). I thought that this could be accomplished by going on the master pages, change margins and reapply the master pages, but it does not work. It does not change the text column, but the image containing the text does not change with it. Except changing the image manually, is there a way to change the existing dimensions of text column universally in a chapter? (I hope I'm being clear on what I'm asking.)

  This would have worked "as what" If the executives were on master pages, I think, but always possible even without master frames if executives adjustment the margins of the page. The secret is 'layout adjustment' which must be turned on before making changes in the margin.

  Go to the Layout > setting layout... and turn on, then make your changes on the master page. No doubt, you're ready for oversets that the adjustment of the width of the frame is likely to cause.

  Peter

• APEX do not allow to change the lines of the columns that are the primary key?

  I have pictures:
  http://img508.imageshack.us/my.php?image=21269582oe8.jpg
  
  
  Book (id_book - 'Primary key', title, year); book_author (id_author id_book - 'Primary key', - 'Primary key'); author (id_author - "Primary key", name)
  
  
  
  I created a new page-> Form-> form of 'author' table because I want to add new authors, modification and deletion. During the creation of this page, I have chosen column 'id_author' as '1 primary key column' and everything is OK (I can't edit the 'id_author' column - this column is autoincrement and I can change the 'name' column).
  
  BUT I also created a new page-> Form-> table for table "book_author" because I like to write numbers like id_book and id_author, change and remove them (so add relations between tables: book, book_author and author). During the creation of this page, I have chosen column 'id_book' as '1 primary key column' and 'id_author' as 'column primary key 2'. And on the Web site, I can't edit these fields. And I can not add also new line because I see in each new line: (null).
  
  http://img444.imageshack.us/my.php?image=11324615yk9.jpg
  
  APEX do not allow to change the lines of the columns that are the primary key? It's stupid... What can I do?
  
  Edited by: user10731158 2008-12-20 11:40

  Column unique and not meaningful if you ever want to update. In the case of your example, you need to add an ID column in the intersection of book_author table. Honestly, I was so blown away (and pleasantly surprised) by the absence of rebuttal and the "thx" I advanced and set up an example of how I would define the book_author table:

  create table  book_author
     (id varchar2(32),
      book_id varchar2(32),
       author_id varchar2(32),
       modified_on     date,
       modified_by varchar2(255),
       constraint book_author_pk primary key (id),
       constraint book_auth_book_fk foreign key (book_id) references books(id),
       constraint book_auth_author_fk foreign key (author_id) references authors(id)
       )
  /
  
  create unique index book_author_uq on book_author (book_id,author_id)
  /
  
  create or replace trigger  biu_book_author before insert or update on book_author
  for each row
  begin
       if inserting then
            :new.id := sys_guid();
       end if;
       modified_on := sysdate;
       modified_by := nvl(v('APP_USER'),user);
  end;
  /
  

  Good luck
  Tyler

• Trying to create a Section to multiple columns with Sections of the single column before and after

  Is there a way to create a section break that is not default to a new page after I created columns on a page.  I created the columns and under them, I want to return to the normal formatting for the rest of the single page.  See picture attached.

  Any rejection of Pages v5 has a break of presentation which was present in the Pages ' 09 v4.3. This will allow you to transition to several columns and back to single column on the same page. In the v5 Pages, you can insert 3 text boxes and change the 3-column layout in the Middle text box. You use the toolbar item Insert to inject column breaks when you want to start a new list in the next column. I'll show this screenshot below.

  You can fake your layout in Pages v5 using 3 text boxes and setting 3 columns in the Central text area. Better to show the mode of provision for this and in a text box, the column outlines are not displayed. After each column list, you then choose column break the Insert point toolbar menu to move to the next column, add a list, repeat. Each column will expand downwards. Click on the following to enlarge.

  Pages ' 09 v4.3 using layout breaks Pages using 3 text boxes V5.6.1