Change the training Plan?

I don't see a place to change a learning plan once it was created, is it not possible? I created one to add in some way to a person when they are added to a certain group and did not want to specify a time period for completion (it's learning during the first). Now it's show days '0' to finish. Opens forever or never opened it's just what it means? Sounds weird, I know. Also, you can add several courses/activities for a training PLAN? I guess it's a PLAN that you might...

Thank you.

Hi Wendy,.

My apologies for the error of reading it.

You cannot change once created learning plans. However, you can disable. Also you can only add a course or learning or a program of Certification for a Learning Plan.

Even if you have set '0' to complete then also learning day will be able to take LP any time thereafter, and it will be shown in the dashboard. You can also set a deadline for this LP to make sure that the user takes the Learning Plan.

Kind regards

MILIN

Tags: Captivate Prime

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    PLAN_TABLE_OUTPUT

    ---------------------------------------------------------------------------------------------------------------
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    ---------------------------------------------------------------------------------------------------------------
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    {code}


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    {code}

    TKPROF: Release 10.2.0.3.0 - Production on Tue Jan 13 13:21:47 2009

    Copyright (c) 1982, 2005, Oracle. All rights reserved.

    Trace file: C:\oracle\product\10.2.0\admin\nautp02\udump\nautp02_ora_880.trc
    Sorting options: by default

    ********************************************************************************
    Count = number of times OIC procedure has been executed
    CPU = time in seconds cpu execution
    elapsed = elapsed time in seconds the execution
    disc = number of physical reads from disk buffers
    Query = number of buffers for a consistent reading
    current = number of buffers in current mode (usually for the update)
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    SELECT sdu.u_crop_group,
    SD. Name as sdg_name,
    ad.variety_name,
    ad.batch_number,
    B.SID as aliquot_name,
    Sau.u_box_code as box_code,
    Sau.u_box_position as box_position,
    t.Nom as test_name,
    r.original_result,
    PLT. Name as plate_name,
    Concat (chr (a.plate_row + 64), a.plate_column) as plate_position,
    au.u_replicate_number as replicate_number
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    lims_sys. Sample his.
    lims_sys.sample_user sau,
    lims_sys.aliquot has,
    to the lims_sys.aliquot_user,.
    lims_sys.test t,
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    PLT lims_sys.plate,
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    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Parse 1 0.00 0.00 0 0 0 0
    Run 1 1.15 1.16 0 0 0 0
    Fetch 1 8.53 16.10 227649 241266 0 500
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Total 3 9.68 17,27 227649 241266 0 500

    Chess in the library during parsing cache: 1
    Lack in the library during execution cache: 1
    Optimizer mode: ALL_ROWS
    The analysis of the user id: 97

    Rows Row Source operation
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    FILTER 21311 (cr = 241266 pr = 227649 pw = time 0 = 16246749 en)
    21311 HASH JOIN (cr = 241266 pr = 227649 pw = time 0 = 16225434 en)
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    21895 VIEW PLATE (cr = 316 pr = 0 pw = time 0 = 43825 US)
    21895 FILTER (cr = 316 pr = 0 pw = time 0 = 43823 US)
    21895 TRAY FULL ACCESS (cr = 316 pr = 0 pw = time 0 = 31 US)
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    21311 HASH JOIN (cr = 240576 pr = 227649 pw = time 0 = 16106174 en)
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    7876 NESTED LOOPS (cr = 377 pr = 0 pw = time 0 = 488287 en)
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    3406836 TABLE ACCESS FULL ALIQUOT_USER (cr = 7940 pr 7734 pw = time = 0 = 556 en)
    3406832 TABLE TEST FULL ACCESS (cr = 39236 pr 38315 pw = time = 0 = 3413192 en)
    3406832 TABLE ACCESS FULL RESULTS (cr = 107017 pr = 106053 pw = time 0 = 6848487 en)
    0 INDEX UNIQUE SCAN PK_OPERATOR_GROUP (cr = 0 pr = 0 pw = time 0 = 0 US)(object id 45769)
    0 INDEX UNIQUE SCAN PK_OPERATOR_GROUP (cr = 0 pr = 0 pw = time 0 = 0 US)(object id 45769)
    0 INDEX UNIQUE SCAN PK_OPERATOR_GROUP (cr = 0 pr = 0 pw = time 0 = 0 US)(object id 45769)
    0 INDEX UNIQUE SCAN PK_OPERATOR_GROUP (cr = 0 pr = 0 pw = time 0 = 0 US)(object id 45769)

    ********************************************************************************

    Select 'x '.
    Of
    Double


    call the query of disc elapsed to cpu count current lines
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Parse 1 0.00 0.00 0 0 0 0
    Run 1 0.00 0.00 0 0 0 0
    Fetch 1 0.00 0.00 0 0 0 1
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Total 3 0.00 0.00 0 0 0 1

    Chess in the library during parsing cache: 0
    Optimizer mode: ALL_ROWS
    The analysis of the user id: 97

    Rows Row Source operation
    ------- ---------------------------------------------------
    1 DOUBLE QUICK (cr = 0 pr = 0 pw = time 0 = 3 US)

    ********************************************************************************

    Start: id: = sys.dbms_transaction.local_transaction_id; end;


    call the query of disc elapsed to cpu count current lines
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Parse 1 0.00 0.00 0 0 0 0
    Run 1 0.00 0.00 0 0 0 1
    Fetch 0 0.00 0.00 0 0 0 0
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Total 2 0.00 0.00 0 0 0 1

    Chess in the library during parsing cache: 0
    Optimizer mode: ALL_ROWS
    The analysis of the user id: 97



    ********************************************************************************

    TOTALS FOR ALL NON RECURSIVE INSTRUCTIONS

    call the query of disc elapsed to cpu count current lines
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Parse 3 0.00 0.00 0 0 0 0
    Run 3 1.15 1.16 0 0 0 1
    Pick 2 8.53 16.10 227649 241266 0 501
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Total 8 9.68 17,27 227649 241266 0 502

    Chess in the library during parsing cache: 1
    Lack in the library during execution cache: 1


    TOTALS FOR ALL RECURSIVE INSTRUCTIONS

    call the query of disc elapsed to cpu count current lines
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Parse 30 0.00 0.00 0 0 0 0
    Run 30 0.00 0.00 0 0 0 0
    Get 30 0.00 0.00 0 40 0 10
    ------- ------ -------- ---------- ---------- ---------- ---------- ----------
    Total 90 0.00 0.00 0 40 0 10

    Chess in the library during parsing cache: 0

    3 the session user SQL statements.
    30 internal to SQL statements in session.
    33 SQL statements in session.
    ********************************************************************************
    Trace file: C:\oracle\product\10.2.0\admin\nautp02\udump\nautp02_ora_880.trc
    Compatibility of trace files: 10.01.00
    Sorting options: by default

    8 sessions in the trace file.
    3 SQL statements of the user in the trace file.
    30 internal SQL instructions in the trace file.
    33 SQL statements in the trace file.
    6 unique SQL statements in the trace file.
    633 lines in the trace file.
    23 seconds in the trace file.
    {code}

    ZI wrote:
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    I would interpret the results displayed differently.

    Execution which took 17 s according to the 241 266 coherent block played tkprof output gets but in order to do so he read 227 649 the disk blocks. Note that most of the table addressed by this query blocks were read through scanning of complete table that can take advantage of multiple blocks readings, for example if you unset the db_file_multiblock_read_count 10.2 (recommended) it usually try to read 1 MB with a read request, which are 128 blocks in case of standard block size 8 k. Due to several reasons not always the full size can be requested with each read request, lets say about 200 000 blocks could have been read by about 2,000 blocks multiple readings. Each read request would turn into a physical read, could you get an estimate approximate 25 MS per read times 2,000 applications-online 50 seconds (your system is running obviously better that the average assumed by ost g 10 base optimizer without collected statistics system workload, can be that some additional file caching system is involved).

    On the other hand, the execution plan that finished within 2 seconds completed 221 420 coherent block gets but did No physical reads at all. Note that most of the table blocks should be processed using one-piece random searches (ACCESS BY ROWID of the TABLE), according to the grouping of the indices factor, it could have been as many blocks that the lines have been returned to the range index scans. So you could have done with lets say more than 60,000 randomly accessed table blocks => until 60 000 monobloc required reading. So in the worst case, this may take 60 000 requests time 10ms by read-online 600 seconds, even if in reality at least some of the blocks will be stored in the buffer cache, so it should be less.

    It would be interesting to know how these two declarations with a cold buffer cache, so that both had to physical reads. I suppose the first is actually faster. Of course, if the second corresponds more to your typical situation that most of the blocks is in the buffer anyway, then it could be faster, because the blocks read by random access are more likely to stay in memory blocks read by complete sweep of the table, but in a true perspective of I/O the first is expected to be higher.

    Moreover, the change in the plan is probably caused by the fact that the additional predicate (DECODING) lowers the cardinality of the table of SDG_USER conduct so that LOOP IMBRIQUEE approach seems to be cheaper to the optimizer that the hash join/full scan table approach. Apparently the estimate is way off (by two orders of magnitude, in fact 100 instead of 1), then the plan is not really cheap, because it seems like the optimizer.

    By the way: two actual execution plans displayed in the output from tkprof are actually different from the displayed output of EXPLAIN the PLAN, so the statement has executed a little differently provided the facility to EXPLAIN the PLAN.

    Your PLAN_TABLE is old, since you are on 10g you should drop any PLAN_TABLEs that are in non - SYS diagrams, since 10 g already provides a global temporary Table as part of the default dictionary (SYS. Plan_table$ presentations via public synonym PLAN_TABLE).

    Kind regards
    Randolf

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    This is an open forum, not Adobe support... Click below to contact Adobe staff for help

    While the forums are open 24/7 you can't contact Adobe support at any time

    Chat support: Mon - Fri 05:00-19:00 (US Pacific Time)<=== note="" days="" and="">

    Don't forget to stay signed with your Adobe ID before accessing the link below

    Creative cloud support (all creative cloud customer service problems)

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