Combination of substring and instring in RTF - dynamic signature images url

I am unable to use a combination of substring and instring in RTF model.

I have a BUYER_LAST_NAME column, which has a Jean Dupont value. I like to shoot 'john' on this channel.

I tried to create a variable using <? xdoxslt:set_variable($_XDOCTX,_'new_name',_'')? >

So I want to do a get variable using substr and InStr.

<? xdoxslt:get_variable (substring _XDOCTX, BUYER_LAST_NAME, $(DOCUMENT_BUYER_LAST_NAME, 1, instring(BUYER_LAST_NAME,' ')-1))? >

The command above does not work as a substring and instring aren't xdoxslt operations.

I tried to do this using xdofx: <? xdofx:substr (BUYER_LAST_NAME, 1, Instr(BUYER_LAST_NAME,' ')-1)? >

The above work, but I don't know how to make a variable defined using xdofx. Please help me on this.

Published:

I want to use this field in a dynamic signature display. But I can't call substring-before command as part of the url.

URL: {(concat('${OA_MEDIA}','/purchase_order/signatures/',.//BUYER_FIRST_NAME,'_',.//BUYER_LAST_NAME,'.jpg')}

I want to change the BUYER_LAST_NAME here.

I'm working on

URL: {concat (' ${OA_MEDIA} ',' / purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, "_",. / /, '.jpg')}

But it does not work.

->

URL: {concat (' ${OA_MEDIA} ','/ purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, '_', substring-before(.//DOCUMENT_BUYER_LAST_NAME, ' '), '.jpg')}

who is working for me

Tags: Business Intelligence

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  • How to use substr and instr, where the line of input Multi text

    Hi all

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    --------------

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    =========================

    / * Use Substr and Instr * /.

    =========================

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    Hello

    994122 wrote:

    Hello

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  • substr and instr - get all the characters after the last.

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  • substr and instr EQL

    Another question EQL. Is there an equivalent to substr and instr EQL?

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    http://docs.Oracle.com/CD/E29805_01/QueryLangRef.PDF

  • Substr and InStr

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            WHERE    e2.emp_id = e1.emp_id
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FROM       emp_address_list e1
GROUP BY   emp_id

  • SUBSTR and INSTR function

    Hi gurus,

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    data
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    and I'm writing a SQL results:

    CAI
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    Thank you
    Alex

    something like:

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-- end of mimicking your data: USE SQL below:
select substr(col1, instr(col1, '/CAI:', 1) + 5, instr(col1, '/CAI:', 1, 2) - instr(col1, '/CAI:', 1) - 5 ) CAI
from my_tab

CAI
--------------------------------------------------------------------------------
452-01-32201-47001
452-01-32201-471

  • A string into the text and numbers using SUBSTR and INSTR

    I have the sample data. I know it's terrible database designed for a combination of text and numbers in the same field, but I can't change the business process.

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WITH table_data
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         SELECT 'R: MARTIN LUTHER KING 3334156' str FROM DUAL UNION ALL
         SELECT 'R: TOM CRUISE 6547123' str FROM DUAL UNION ALL
         SELECT 'R: TOMMY DE GROOT 1212124' str FROM DUAL UNION ALL
         SELECT 'R: GRIM REAPER 1345245' str FROM DUAL UNION ALL
         SELECT 'R: DOCTOR DEATH THE FIRST SMITH 24356178' str FROM DUAL)
SELECT str
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     , REPLACE(SUBSTR(str, INSTR (str, ' ', 1, 2)+1, 999), SUBSTR(str,LENGTH(str)-6,7), '') last_name
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  FROM table_data;

STR                                      FIRST_NAME    LAST_NAME                 EMP_NUM
---------------------------------------- -----------------------------------------------
R: JASON BOURNE 12341560                 JASON         BOURNE 1                  2341560
R: FATS DOMINO 23432342                  FATS          DOMINO 2                  3432342
R: MARTIN LUTHER KING 3334156            MARTIN        LUTHER KING               3334156
R: TOM CRUISE 6547123                    TOM           CRUISE                    6547123
R: TOMMY DE GROOT 1212124                TOMMY         DE GROOT                  1212124
R: GRIM REAPER 1345245                   GRIM          REAPER                    1345245
R: DOCTOR DEATH THE FIRST SMITH 24356178 DOCTOR        DEATH THE FIRST SMITH 2   4356178

7 rows selected.

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    3. remove the number at the end, regardless of the length - some of the examples above are 8 long numbers so my attempt above does not work.

    I can't use any REGEXP or REGEXP_SUBSTR because they are not registered in the EUL I'm using discoverer, I can only use INSTR AND SUBSTR.

    I was wondering if someone might be able to help please?

    Any advice much appreciated.

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    AW, go on them, as it's Christmas, I'm feeling generous...

    SQL > ed
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    1. WITH table_data (SELECT "r: JASON BOURNE 12341560' DOUBLE UNION ALL STR ')
    2. SELECT "r: FATS DOMINO 23432342' str OF DOUBLE UNION ALL.
    3. SELECT "r: MARTIN LUTHER KING 3334156' str OF DOUBLE UNION ALL.
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    6. SELECT "r: GRIM REAPER 1345245' str OF DOUBLE UNION ALL.
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    8                     )
    9 select substr (str, 1, instr(str,' ')-1) as a first name
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    11, substr (str, instr (str, ' ',-1) + 1) as emp_num
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    table_data 13
    14*        )
    SQL > /.

    FIRST_NAME LAST_NAME EMP_NUM
    ---------------------------------------- ---------------------------------------- ----------------------------------------
    JASON BOURNE 12341560
    FATS                                     DOMINO                                   23432342
    MARTIN                                   KING                                     3334156
    TOM                                      CRUISE                                   6547123
    TOMMY                                    GROOT                                    1212124
    GRIM                                     REAPER                                   1345245
    DOCTOR SMITH 24356178

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  • Help on using substr and instr functions

    Hello

    I'm trying to go back to the first three letters of the first word and all the last word in a description field. For example, if the description is 'grilled steak' the query should return "steak gri. That's what I have so far:

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     SELECT 'large pepperoni pizza' AS DESCRIPTION FROM DUAL UNION ALL
     SELECT 'soda' AS DESCRIPTION FROM DUAL
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          THEN SUBSTR(DESCRIPTION,1,3) || SUBSTR(DESCRIPTION,INSTR(DESCRIPTION,' ',-1))
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    SQL> /

DESCRIPTION
-----------------------
gri steak
lar pizza
sod

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  • substring and instring

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    test@ORA10G>
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  3  --
  4  select x,
  5         substr(x,instr(x,':',1,1)+2,instr(x,' position now')-instr(x,':',1,1)-2) y,
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X                                             Y          Z
--------------------------------------------- ---------- ----------
robert alias: 09-047 position now: CLARK      09-047     CLARK

test@ORA10G>
test@ORA10G>

    isotope

  • using substr and instr

    Hi all

    create table abc (str varchar2 (10))

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    Insert into abc values ('ABC DEF')

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    Thank you

    Three ways:

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    See you soon,.

    Manik.

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    Hi I have a script

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    Hello

    This query will help you.

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    SUBSTR (C1, INSTR(C1,',',1,2) + 1, INSTR(C1,',',1,3)-INSTR(C1,',',1,2)-1).

    SUBSTR (C1, INSTR(C1,',',1,3) + 1, INSTR(C1,',',1,4)-INSTR(C1,',',1,3)-1)

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    Post edited by: DecaXD

  • How to make a combination substr and instr in javascrip

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    lukx

    Hi lukx,

    You can use the following javascript function:

    function processText(pString, pSearchString, pOccurrenceNum)
{
  var j = 0;
  for(var i = 0; i < pOccurrenceNum; i++)
  {
    j = pString.indexOf(pSearchString,j) + 1;
  }
  j = j - 1;
  return pString.substr(0,j);
}

    To treat, for example, the second example, you've shown, you would have to make the following call:

    processText("001.002.003.004.005", ".", 4)

    Maybe this isn't the best solution, but as I saw it in the JavaScript API that indexOf and lastIndexOf are only for the first and the last accident, that's why I included the loop for. I hope this helps.

    Kind regards

    Sergio

  • Problem with substr and instr

    create table ztest1 (descrr varchar2 (40));

    values in ztest1
    ===============

    123/09-00
    1234345/66-44
    1/8-00000
    345656676/555555555-222222

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    I am able to do first and last as
    123 00 null
    123345 44 null
    1 null 0000
    345656676 null 222222
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    can you please advise me where I am doing wrong.

    Select TRIM (SUBSTR (mck.descrr,
    1,
    INSTR (mck.descrr, "/")-1
    )
    ) 'type ',.
    TRIM (SUBSTR (mck.descrr,
    INSTR (mck.descrr, '-') + 1.
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    -1
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    INSTR (mck.descrr, '-',-1) + 1
    )
    ) "T"
    of ztest1 mck

    Thanks in advance.

    You are close with your attempt. You have to find the starting position of the /, then calculate the length between the / amd t he... So:

    SQL> l
  1  with mck as (
  2    select '123/09-00' descrr from dual union all
  3    select '1234345/66-44'  from dual union all
  4    select '1/8-00000'  from dual union all
  5    select '345656676/555555555-222222' from dual)
  6  select TRIM (SUBSTR (mck.descrr, 1, INSTR (mck.descrr, '/') - 1)) "type",
  7         TRIM (SUBSTR (mck.descrr, INSTR (mck.descrr, '/') + 1,
  8                       INSTR (mck.descrr, '-') - INSTR (mck.descrr, '/')-1)) "part2",
  9         TRIM (SUBSTR (mck.descrr, INSTR (mck.descrr, '-', -1) + 1)) "T"
 10* from mck
SQL> /

type                       part2                      T
-------------------------- -------------------------- --------------------------
123                        09                         00
1234345                    66                         44
1                          8                          00000
345656676                  555555555                  222222

    @Kim:
    "Regular expressions will be easier," well, that's a little matter to debate ;-) they can get real ugly looking very quickly.

    John

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