data of cutting using substring and instring, and storage in a new table

Similar Questions

• How to use substr and instr, where the line of input Multi text

  Hi all

  with

  data in the form of)

  Select ' Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..' double val

  Union of all the

  Select 'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Plaza Falke' of the double

  )

  Select

  regexp_substr (shipping_instructions, "[^ #] +' 1, 1") name

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 2") address

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 3") city

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 4") State

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 5") zip

  , regexp_substr (shipping_instructions, "[^ #] +' 1, 6") County

  FROM (select REGEXP_REPLACE (val, ' \.)) () [^.])', ' #\1 ") data shipping_instructions)

  (1)'Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..'

  (2)'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Falke Plaza. »

  "Mary America. 1234 Southridge Park Dr. Samna Lorie. MO.31234..'

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Married America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  "Bill Johnson. Apartment 3B. Sterling. VA. 20166. Falke Plaza 3... "

  NAME ADDRESS CITY ZIP County SATE

  ----------------      -----------------        -------       -----        ---         --------

  Bill Johnson apartment 3B Sterling, WILL 20166 3 Falke Plaza.

  Problem

  ---------

  (1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.

  How to solve this problem?

  (2) another possible to fix the code, I want to use substr and InStr.

  (3) who is the best approach?

  Conditions:

  --------------

  (1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »

  This means it combined all the similar name, address, city, State, zip

  (2) we insreted in the table separately.

  =========================

  / * Use Substr and Instr * /.

  =========================

  I used substr and instr, but I'm getting the money results (no point in the address).

  "America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

  
  

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234  NULL VALUE

  But I need the results (no point in the address)

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  Hello

  994122 wrote:

  Hello

  (1) how do to do this, use the substr and instr functions?

  Thank you

  You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

  Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

  WITH got_delimited_string AS

  (

  SELECT REGEXP_REPLACE (val

  , '\. ([^ .]| $)'

  , '#\1'

  ) AS delimited_string

  FROM the data

  )

  got_pos AS

  (

  SELECT delimited_string

  , INSTR (delimited_string, "#", 1, 1) AS pos_1

  , INSTR (delimited_string, "#", 1, 2), pos_2

  , INSTR (delimited_string, "#", 1, 3) AS pos_3

  , INSTR (delimited_string, "#", 1, 4) AS pos_4

  , INSTR (delimited_string, "#", 1, 5) AS pos_5

  , INSTR (delimited_string, "#", 1, 6) AS pos_6

  OF got_delimited_string

  )

  SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

  SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

  SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

  SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

  REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

  , '.'

  )                                                           AS zip

  SUBSTR (delimited_string, pos_5 + 1, pos_6 - (pos_5 + 1)) AS the County

  OF got_pos

  ORDER BY delimited_string

  ;

• How to use Substr and Instr to get data from a file

  Hi I have a script

  I get a file like this

  1.20, ram, sales

  I get a file as these data as a column

  I want to divide these data into 4 different columns as

  1 20 sales of ram

  Hello

  This query will help you.

  Select

  SUBSTR (C1, 0, INSTR(C1,',')-1).

  SUBSTR (C1, INSTR (C1, ',') + 1, INSTR(C1,',',1,2)-INSTR(C1,',',1,1)-1),

  SUBSTR (C1, INSTR(C1,',',1,2) + 1, INSTR(C1,',',1,3)-INSTR(C1,',',1,2)-1).

  SUBSTR (C1, INSTR(C1,',',1,3) + 1, INSTR(C1,',',1,4)-INSTR(C1,',',1,3)-1)

  SUBSTR (C1, INSTR(C1,',',1,3) + 1)

  BeO

  Select 1, 20, ram, C1 double sales

  )

  Remember that a comma is not really safe as field separator

  Post edited by: DecaXD

• A string into the text and numbers using SUBSTR and INSTR

  I have the sample data. I know it's terrible database designed for a combination of text and numbers in the same field, but I can't change the business process.

  That's what I have so far:

  set linesize 5000
  
  WITH table_data
       AS (SELECT 'R: JASON BOURNE 12341560' str FROM DUAL UNION ALL
           SELECT 'R: FATS DOMINO 23432342' str FROM DUAL UNION ALL
           SELECT 'R: MARTIN LUTHER KING 3334156' str FROM DUAL UNION ALL
           SELECT 'R: TOM CRUISE 6547123' str FROM DUAL UNION ALL
           SELECT 'R: TOMMY DE GROOT 1212124' str FROM DUAL UNION ALL
           SELECT 'R: GRIM REAPER 1345245' str FROM DUAL UNION ALL
           SELECT 'R: DOCTOR DEATH THE FIRST SMITH 24356178' str FROM DUAL)
  SELECT str
       , TRIM(SUBSTR(str, INSTR(str, ' ', 1, 1), INSTR (str, ' ', 1, 2) - INSTR (str, ' ', 1, 1))) first_name
       , REPLACE(SUBSTR(str, INSTR (str, ' ', 1, 2)+1, 999), SUBSTR(str,LENGTH(str)-6,7), '') last_name
       , SUBSTR(str,LENGTH(str)-6,7) emp_num
    FROM table_data;
  
  STR                                      FIRST_NAME    LAST_NAME                 EMP_NUM
  ---------------------------------------- -----------------------------------------------
  R: JASON BOURNE 12341560                 JASON         BOURNE 1                  2341560
  R: FATS DOMINO 23432342                  FATS          DOMINO 2                  3432342
  R: MARTIN LUTHER KING 3334156            MARTIN        LUTHER KING               3334156
  R: TOM CRUISE 6547123                    TOM           CRUISE                    6547123
  R: TOMMY DE GROOT 1212124                TOMMY         DE GROOT                  1212124
  R: GRIM REAPER 1345245                   GRIM          REAPER                    1345245
  R: DOCTOR DEATH THE FIRST SMITH 24356178 DOCTOR        DEATH THE FIRST SMITH 2   4356178
  
  7 rows selected.
  

  I need to:

  1 extract the first name - which is always the first name after the 'r' - I've got that little works very well.

  2 extract the name - should be the last word before the number, if e.g. for the last night, I wish only that 'SMITH' and 'KING' for the 3rd line and "GROOT" for the 5th line.

  3. remove the number at the end, regardless of the length - some of the examples above are 8 long numbers so my attempt above does not work.

  I can't use any REGEXP or REGEXP_SUBSTR because they are not registered in the EUL I'm using discoverer, I can only use INSTR AND SUBSTR.

  I was wondering if someone might be able to help please?

  Any advice much appreciated.

  Thank you

  AW, go on them, as it's Christmas, I'm feeling generous...

  SQL > ed
  A written file afiedt.buf

  1. WITH table_data (SELECT "r: JASON BOURNE 12341560' DOUBLE UNION ALL STR ')
  2. SELECT "r: FATS DOMINO 23432342' str OF DOUBLE UNION ALL.
  3. SELECT "r: MARTIN LUTHER KING 3334156' str OF DOUBLE UNION ALL.
  4. SELECT "r: TOM CRUISE 6547123' str OF DOUBLE UNION ALL.
  5. SELECT "r: TOMMY GROOT 1212124' str OF DOUBLE UNION ALL.
  6. SELECT "r: GRIM REAPER 1345245' str OF DOUBLE UNION ALL.
  7. SELECT "r: DOCTOR DEATH FIRST SMITH 24356178' FROM DUAL str.
  8                     )
  9 select substr (str, 1, instr(str,' ')-1) as a first name
  10, substr (substr (str, 1, instr(str,' ',-1)-1), instr (substr (str, 1, instr(str,' ',-1)-1),' ', 1) + 1) as last_name
  11, substr (str, instr (str, ' ',-1) + 1) as emp_num
  12 years of (select replace (str,'R: ') as str)
  table_data 13
  14*        )
  SQL > /.

  FIRST_NAME LAST_NAME EMP_NUM
  ---------------------------------------- ---------------------------------------- ----------------------------------------
  JASON BOURNE 12341560
  FATS                                     DOMINO                                   23432342
  MARTIN                                   KING                                     3334156
  TOM                                      CRUISE                                   6547123
  TOMMY                                    GROOT                                    1212124
  GRIM                                     REAPER                                   1345245
  DOCTOR SMITH 24356178

  7 selected lines.

• using substr and instr

  Hi all

  create table abc (str varchar2 (10))

  insert into abc values ('ABC - DEF')

  Insert into abc values('ABC/DEF')

  Insert into abc values ('ABC DEF')

  Insert into abc values('ABC.) DEF')

  insert into abc values ('ABC DEF')

  I need to put as ABCDEF for all values, if possible using sustr and instr

  Thank you

  Three ways:

  Select replace (str, translate(str,'~ABCDEFGHIJKLMNOPQRSTUVWXYZ','~')) in abc;  -assuming a single character is there in your data...

  -generic way to remove all of the other characters keeping uppercase alphabets

  SELECT TRANSLATE (str, ' ~' |) TRANSLATE (str, ' ~ ABCDEFGHIJKLMNOPQRSTUVWXYZ ',' ~'), ' ~') of ABC;

  -Using regular expressions

  Select regexp_replace(str,'[^[:alpha:]]') in abc;

  See you soon,.

  Manik.

• Use Substr and InStr

  I have created table:
  
  create table wekaRules_productmgr)
  The rule ID number,
  WekaRule varchar2 (500),
  VARCHAR2 (250) antecedent.
  VARCHAR2 (250) resulting.
  );
  
  The table contains the following data with insert statements:
  
  INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
  VALUES (1, ' PM_PRICE_REDUCTION_TYPE = None 9828 == > PM_COUPON_TYPE = None 9828 conf: (1) lift: (1.06) conv: (576.86)') lev: (0.05) [576];
  
  INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
  VALUES (2, ' PM_AD_TYPE = None 9684 == > PM_PRICE_REDUCTION_TYPE = None 9684 conf: (1) lift: (1.12) conv: (1063.13)') lev: (0.1) [1063];
  
  INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
  VALUES (3, ' PM_AD_TYPE = None 9684 == > PM_COUPON_TYPE = None 9684 conf: (1) lift: (1.06) conv: (568.41)') lev: (0.05) [568];
  
  The values for the last two columns in the wekaRules_productmgr table is contained in the string values for each statement. For example, in the # 1 folder, the values are (from left to right):
  history = PM_PRICE_REDUCTION_TYPE = None
  result = PM_COUPON_TYPE = None
  
  
  I need to find a way to analyze the values in each record and update in the appropriate table columns. So to case # 1, I need to update columns with the values given above, such as the records would look like:
  
  Rule ID History Resulting          
  1 PM_PRICE_REDUCTION_TYPE = None PM_COUPON_TYPE = None
  2 PM_AD_TYPE = None PM_PRICE_REDUCTION_TYPE = None
  3 PM_AD_TYPE = None PM_COUPON_TYPE = None
  
  I have tried this solution, but cannot very well:
  
  UPDATE wekaRules_productmgr SET history =
  (SELECT SUBSTR (wekarule, 1, (INSTR(wekarule,' ',1,1)-1)) 'history')
  OF wekaRules_productmgr);
  
  I also have a similar one for the suite. Does anyone have any suggestions? Any help is appreciated. Thank you!

  I saw there is anonther detachment of you the same theme. If this can help you:

   SELECT
         regexp_substr(wekarule,'[a-zA-Z_]+ *= *[a-zA-Z_]+',1,1) antecedent,
         regexp_substr(wekarule,'[a-zA-Z_]+ *= *[a-zA-Z_]+',1,2) consequent,
         LTRIM(REGEXP_SUBSTR(wekarule, 'conf:\([^\)]+'), 'conf:(') conf,
         LTRIM(REGEXP_SUBSTR(wekarule, 'lift:\([^\)]+'), 'lift:(') lift,
         LTRIM(REGEXP_SUBSTR(wekarule, 'lev:\([^\)]+'), 'lev:(') lev,
         LTRIM(REGEXP_SUBSTR(wekarule, 'conv:\([^\)]+'), 'conv:(') conv
  FROM   wekaRules_productmgr;
  

  Published by: hm on 11.10.2010 11:29

• Help on using substr and instr functions

  Hello
  
  I'm trying to go back to the first three letters of the first word and all the last word in a description field. For example, if the description is 'grilled steak' the query should return "steak gri. That's what I have so far:
  
  SELECT SUPPLIER_ID, PRODUCT_CODE, SUBSTR (DESCRIPTION, 1, 3). ' ' || SUBSTR (DESCRIPTION, INSTR (DESCRIPTION, ' ', 3)) AS A DESCRIPTION
  OF L_FOODS;
  
  Unfortunately, if the first word is the final word, it returns something like "sod soda." Does anyone have any advice or suggestions? Any help would be appreciated.

  Hi and welcome to the forum!

  It is always helpful if you identify your version of Oracle. The solution below depends on 10.1 and upward.

  What you could do is include a conditional around your instr/substr functions that checks the number of spaces between words. If it is greater or equal two one then there are at least two words. For example:

  WITH test_data AS
  (
       SELECT 'grilled steak' AS DESCRIPTION FROM DUAL UNION ALL
       SELECT 'large pepperoni pizza' AS DESCRIPTION FROM DUAL UNION ALL
       SELECT 'soda' AS DESCRIPTION FROM DUAL
  )
  SELECT     (CASE
            WHEN LENGTH(REGEXP_REPLACE(TRIM(DESCRIPTION),'[^[:space:]]','')) > 0
            THEN SUBSTR(DESCRIPTION,1,3) || SUBSTR(DESCRIPTION,INSTR(DESCRIPTION,' ',-1))
            ELSE SUBSTR(DESCRIPTION,1,3)
       END) AS DESCRIPTION
  FROM     test_data
  

  Results

  SQL> /
  
  DESCRIPTION
  -----------------------
  gri steak
  lar pizza
  sod
  

  : EDITION:

  I also wanted to add this:

  SUBSTR(DESCRIPTION, INSTR(DESCRIPTION, ' ', 3))
  

  May not return the expected results. If your description field contains more than two words he will return all remaining words not only the LAST Word. See my solution above for what I believe is the correct version.

  HTH!

• Comparison of the two bays and by generating a new table. ???

  Hi guys

  can someone solve this problem. Please...

  I have two tables, a table of strings and other's selectedLayers array with the same source names(a,b,c) selected in the aftermath.

  Now I want to generate the new table by using the string in [mySelectedComps]. source.name.

  For example

  var callName = [' a b "," "];

  var mySelectedComps = app.project.activeItems.selectedLayers; (eg.i chose a, b, c of comps in afx)

  var newArray = [];

  
  

  If ([callName][] mySelectedComps. source.nameof ==) {}

  newArray.push ();

  }

  How iterate two tables at the same time or how to compare an element in an array Array1 with all elements of array2 until it returns true/false.and, then proceed to the next item in the table 1. ??

  I think that you just need nested loops, something like this (untested):

  for (var i = 0; i)< myselectedcomps.length;="">

  for (var j = 0; j)< callname.length;="">

  If (callName [j] is {mySelectedComps [i].source.name)}

  newArray.push (mySelectedComps [i]);

  break;

  }

  }

  }

  Dan

• Insertion of the calculated values and values into a new table. How?

  Hi guys. Had a slight dilemma here. My problem is that:
  
  1. I have an average of two values (in the same column) for the 2 different lines (which is 7 days before the event and the other which is 14 days). I need to insert a new table
  
  WITH
  
  2. the data in some of the other columns of the lines of these two values I have on average.
  
  So, for example, I have the source table table S, with the values of Company_Name, Date, name of the Emp, salary, Date. I have to calculate the average salary, corresponding to the date criteria I described before. So I have to insert into another table (the average value) while keeping other data (Date, name of the Emp) etc.
  
  This is really confusing me. I think that the mix of simple db and sql pl theory is to play with my head.
  
  I know that the scenario is a bit confused, so please ask any questions! I'll check this thread very frequently!

  Frankly speaking, I'm lost.

  Please post some samples of entry and your required output in a formatted way.

  Kind regards.

  LOULOU.

• Substr and InStr

  Hi all
  
  I have a table where a column has a data character in the format below:
  
  * '00003434' *.
  * '00123' *.
  * '0000045' *.
  
  If I want to eliminate all zeros on the left, how can I do using substr and instr? or is there an easier way?
  
  Thank you
  
  KK

  Try again with

  Select ltrim ('00003434 ', ' 0') of double;

• Combination of substring and instring in RTF - dynamic signature images url

  I am unable to use a combination of substring and instring in RTF model.

  I have a BUYER_LAST_NAME column, which has a Jean Dupont value. I like to shoot 'john' on this channel.

  I tried to create a variable using <? xdoxslt:set_variable($_XDOCTX,_'new_name',_'')? >

  So I want to do a get variable using substr and InStr.

  <? xdoxslt:get_variable (substring _XDOCTX, BUYER_LAST_NAME, $(DOCUMENT_BUYER_LAST_NAME, 1, instring(BUYER_LAST_NAME,' ')-1))? >

  The command above does not work as a substring and instring aren't xdoxslt operations.

  I tried to do this using xdofx: <? xdofx:substr (BUYER_LAST_NAME, 1, Instr(BUYER_LAST_NAME,' ')-1)? >

  The above work, but I don't know how to make a variable defined using xdofx. Please help me on this.

  Published:

  I want to use this field in a dynamic signature display. But I can't call substring-before command as part of the url.

  URL: {(concat('${OA_MEDIA}','/purchase_order/signatures/',.//BUYER_FIRST_NAME,'_',.//BUYER_LAST_NAME,'.jpg')}

  I want to change the BUYER_LAST_NAME here.

  I'm working on

  URL: {concat (' ${OA_MEDIA} ',' / purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, "_",. / /, '.jpg')}

  But it does not work.

  ->

  URL: {concat (' ${OA_MEDIA} ','/ purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, '_', substring-before(.//DOCUMENT_BUYER_LAST_NAME, ' '), '.jpg')}

  who is working for me

• RegExp_. Using substr

  Hi - I need to extract the string after the last ' / ' and everything before the last ' / '. Possible to do using substr and instr but I would like to know how this can be done using regexp_substr.

  for example: / Merchants/Retail/ShopBrand/Home/Holidays/Bed

  My requirement is to extract 'Reads', which is after the last ' / ' and '' / Merchants/Retail/ShopBrand/Home/Holidays which is before the last ' / '.

  Help, please

  Could you give the explanation as well to '. * /', '' ?

  We receive all the strings until the last ' / ' and substituting null

  And my second (not a Cleaver) option would be:

  SELECT REGEXP_REPLACE(REGEXP_SUBSTR('/Merchants/Retail/ShopBrand/Home/Holidays/Bed', '.*/'), '.$', '') FIRST_REQUIREMENT FROM DUAL;
  

  Here, we remove the last character. Take a look at the documentation to go further: http://docs.oracle.com/database/121/ADFNS/adfns_regexp.htm#ADFNS1003

  Kind regards.

• How to extract 1 ASA and put them in the new table

  Hello

  Can someone tell me how to extract a table and put in the new table. (eg. I have a table with no 1 to 1000, I would extract only 1, 30, 60, 90,...)  ?

  Please advise me.

  Thank you

  concerning

  
  

• Question to load data using sql loader in staging table, and then in the main tables!

  Hello

  I'm trying to load data into our main database table using SQL LOADER. data will be provided in separate pipes csv files.

  I have develop a shell script to load the data and it works fine except one thing.

  Here are the details of a data to re-create the problem.

  Staging of the structure of the table in which data will be filled using sql loader

  create table stg_cmts_data (cmts_token varchar2 (30), CMTS_IP varchar2 (20));

  create table stg_link_data (dhcp_token varchar2 (30), cmts_to_add varchar2 (200));

  create table stg_dhcp_data (dhcp_token varchar2 (30), DHCP_IP varchar2 (20));

  DATA in the csv file-

  for stg_cmts_data-

  cmts_map_03092015_1.csv

  WNLB-CMTS-01-1. 10.15.0.1

  WNLB-CMTS-02-2 | 10.15.16.1

  WNLB-CMTS-03-3. 10.15.48.1

  WNLB-CMTS-04-4. 10.15.80.1

  WNLB-CMTS-05-5. 10.15.96.1

  for stg_dhcp_data-

  dhcp_map_03092015_1.csv

  DHCP-1-1-1. 10.25.23.10, 25.26.14.01

  DHCP-1-1-2. 56.25.111.25, 100.25.2.01

  DHCP-1-1-3. 25.255.3.01, 89.20.147.258

  DHCP-1-1-4. 10.25.26.36, 200.32.58.69

  DHCP-1-1-5 | 80.25.47.369, 60.258.14.10

  for stg_link_data

  cmts_dhcp_link_map_0309151623_1.csv

  DHCP-1-1-1. WNLB-CMTS-01-1,WNLB-CMTS-02-2

  DHCP-1-1-2. WNLB-CMTS-03-3,WNLB-CMTS-04-4,WNLB-CMTS-05-5

  DHCP-1-1-3. WNLB-CMTS-01-1

  DHCP-1-1-4. WNLB-CMTS-05-8,WNLB-CMTS-05-6,WNLB-CMTS-05-0,WNLB-CMTS-03-3

  DHCP-1-1-5 | WNLB-CMTS-02-2,WNLB-CMTS-04-4,WNLB-CMTS-05-7

  WNLB-DHCP-1-13 | WNLB-CMTS-02-2

  Now, after loading these data in the staging of table I have to fill the main database table

  create table subntwk (subntwk_nm varchar2 (20), subntwk_ip varchar2 (30));

  create table link (link_nm varchar2 (50));

  SQL scripts that I created to load data is like.

  coil load_cmts.log

  Set serveroutput on

  DECLARE

  CURSOR c_stg_cmts IS SELECT *.

  OF stg_cmts_data;

  TYPE t_stg_cmts IS TABLE OF stg_cmts_data % ROWTYPE INDEX BY pls_integer;

  l_stg_cmts t_stg_cmts;

  l_cmts_cnt NUMBER;

  l_cnt NUMBER;

  NUMBER of l_cnt_1;

  BEGIN

  OPEN c_stg_cmts.

  Get the c_stg_cmts COLLECT in BULK IN l_stg_cmts;

  BECAUSE me IN l_stg_cmts. FIRST... l_stg_cmts. LAST

  LOOP

  SELECT COUNT (1)

  IN l_cmts_cnt

  OF subntwk

  WHERE subntwk_nm = l_stg_cmts (i) .cmts_token;

  IF l_cmts_cnt < 1 THEN

  INSERT

  IN SUBNTWK

  (

  subntwk_nm

  )

  VALUES

  (

  l_stg_cmts (i) .cmts_token

  );

  DBMS_OUTPUT. Put_line ("token has been added: ' |") l_stg_cmts (i) .cmts_token);

  ON THE OTHER

  DBMS_OUTPUT. Put_line ("token is already present'");

  END IF;

  WHEN l_stg_cmts EXIT. COUNT = 0;

  END LOOP;

  commit;

  EXCEPTION

  WHILE OTHERS THEN

  Dbms_output.put_line ('ERROR' |) SQLERRM);

  END;

  /

  output

  for dhcp

  
  

  coil load_dhcp.log

  Set serveroutput on

  DECLARE

  CURSOR c_stg_dhcp IS SELECT *.

  OF stg_dhcp_data;

  TYPE t_stg_dhcp IS TABLE OF stg_dhcp_data % ROWTYPE INDEX BY pls_integer;

  l_stg_dhcp t_stg_dhcp;

  l_dhcp_cnt NUMBER;

  l_cnt NUMBER;

  NUMBER of l_cnt_1;

  BEGIN

  OPEN c_stg_dhcp.

  Get the c_stg_dhcp COLLECT in BULK IN l_stg_dhcp;

  BECAUSE me IN l_stg_dhcp. FIRST... l_stg_dhcp. LAST

  LOOP

  SELECT COUNT (1)

  IN l_dhcp_cnt

  OF subntwk

  WHERE subntwk_nm = l_stg_dhcp (i) .dhcp_token;

  IF l_dhcp_cnt < 1 THEN

  INSERT

  IN SUBNTWK

  (

  subntwk_nm

  )

  VALUES

  (

  l_stg_dhcp (i) .dhcp_token

  );

  DBMS_OUTPUT. Put_line ("token has been added: ' |") l_stg_dhcp (i) .dhcp_token);

  ON THE OTHER

  DBMS_OUTPUT. Put_line ("token is already present'");

  END IF;

  WHEN l_stg_dhcp EXIT. COUNT = 0;

  END LOOP;

  commit;

  EXCEPTION

  WHILE OTHERS THEN

  Dbms_output.put_line ('ERROR' |) SQLERRM);

  END;

  /

  output

  for link -.

  coil load_link.log

  Set serveroutput on

  DECLARE

  l_cmts_1 VARCHAR2 (4000 CHAR);

  l_cmts_add VARCHAR2 (200 CHAR);

  l_dhcp_cnt NUMBER;

  l_cmts_cnt NUMBER;

  l_link_cnt NUMBER;

  l_add_link_nm VARCHAR2 (200 CHAR);

  BEGIN

  FOR (IN) r

  SELECT dhcp_token, cmts_to_add | ',' cmts_add

  OF stg_link_data

  )

  LOOP

  l_cmts_1: = r.cmts_add;

  l_cmts_add: = TRIM (SUBSTR (l_cmts_1, 1, INSTR (l_cmts_1, ',') - 1));

  SELECT COUNT (1)

  IN l_dhcp_cnt

  OF subntwk

  WHERE subntwk_nm = r.dhcp_token;

  IF l_dhcp_cnt = 0 THEN

  DBMS_OUTPUT. Put_line ("device not found: ' |") r.dhcp_token);

  ON THE OTHER

  While l_cmts_add IS NOT NULL

  LOOP

  l_add_link_nm: = r.dhcp_token |' _TO_' | l_cmts_add;

  SELECT COUNT (1)

  IN l_cmts_cnt

  OF subntwk

  WHERE subntwk_nm = TRIM (l_cmts_add);

  SELECT COUNT (1)

  IN l_link_cnt

  LINK

  WHERE link_nm = l_add_link_nm;

  IF l_cmts_cnt > 0 AND l_link_cnt = 0 THEN

  INSERT INTO link (link_nm)

  VALUES (l_add_link_nm);

  DBMS_OUTPUT. Put_line (l_add_link_nm |) » '||' Has been added. ") ;

  ELSIF l_link_cnt > 0 THEN

  DBMS_OUTPUT. Put_line (' link is already present: ' | l_add_link_nm);

  ELSIF l_cmts_cnt = 0 then

  DBMS_OUTPUT. Put_line (' no. CMTS FOUND for device to create the link: ' | l_cmts_add);

  END IF;

  l_cmts_1: = TRIM (SUBSTR (l_cmts_1, INSTR (l_cmts_1, ',') + 1));

  l_cmts_add: = TRIM (SUBSTR (l_cmts_1, 1, INSTR (l_cmts_1, ',') - 1));

  END LOOP;

  END IF;

  END LOOP;

  COMMIT;

  EXCEPTION

  WHILE OTHERS THEN

  Dbms_output.put_line ('ERROR' |) SQLERRM);

  END;

  /

  output

  control files -

  DOWNLOAD THE DATA

  INFILE 'cmts_data.csv '.

  ADD

  IN THE STG_CMTS_DATA TABLE

  When (cmts_token! = ") AND (cmts_token! = 'NULL') AND (cmts_token! = 'null')

  and (cmts_ip! = ") AND (cmts_ip! = 'NULL') AND (cmts_ip! = 'null')

  FIELDS TERMINATED BY ' |' SURROUNDED OF POSSIBLY "" "

  TRAILING NULLCOLS

  ('RTRIM (LTRIM (:cmts_token))' cmts_token,

  cmts_ip ' RTRIM (LTRIM(:cmts_ip)) ")". "

  for dhcp.

  
  

  DOWNLOAD THE DATA

  INFILE 'dhcp_data.csv '.

  ADD

  IN THE STG_DHCP_DATA TABLE

  When (dhcp_token! = ") AND (dhcp_token! = 'NULL') AND (dhcp_token! = 'null')

  and (dhcp_ip! = ") AND (dhcp_ip! = 'NULL') AND (dhcp_ip! = 'null')

  FIELDS TERMINATED BY ' |' SURROUNDED OF POSSIBLY "" "

  TRAILING NULLCOLS

  ('RTRIM (LTRIM (:dhcp_token))' dhcp_token,

  dhcp_ip ' RTRIM (LTRIM(:dhcp_ip)) ")". "

  for link -.

  DOWNLOAD THE DATA

  INFILE 'link_data.csv '.

  ADD

  IN THE STG_LINK_DATA TABLE

  When (dhcp_token! = ") AND (dhcp_token! = 'NULL') AND (dhcp_token! = 'null')

  and (cmts_to_add! = ") AND (cmts_to_add! = 'NULL') AND (cmts_to_add! = 'null')

  FIELDS TERMINATED BY ' |' SURROUNDED OF POSSIBLY "" "

  TRAILING NULLCOLS

  ('RTRIM (LTRIM (:dhcp_token))' dhcp_token,

  cmts_to_add TANK (4000) RTRIM (LTRIM(:cmts_to_add)) ")" ""

  SHELL SCRIPT-

  If [!-d / log]

  then

  Mkdir log

  FI

  If [!-d / finished]

  then

  mkdir makes

  FI

  If [!-d / bad]

  then

  bad mkdir

  FI

  nohup time sqlldr username/password@SID CONTROL = load_cmts_data.ctl LOG = log/ldr_cmts_data.log = log/ldr_cmts_data.bad DISCARD log/ldr_cmts_data.reject ERRORS = BAD = 100000 LIVE = TRUE PARALLEL = TRUE &

  nohup time username/password@SID @load_cmts.sql

  nohup time sqlldr username/password@SID CONTROL = load_dhcp_data.ctl LOG = log/ldr_dhcp_data.log = log/ldr_dhcp_data.bad DISCARD log/ldr_dhcp_data.reject ERRORS = BAD = 100000 LIVE = TRUE PARALLEL = TRUE &

  time nohup sqlplus username/password@SID @load_dhcp.sql

  nohup time sqlldr username/password@SID CONTROL = load_link_data.ctl LOG = log/ldr_link_data.log = log/ldr_link_data.bad DISCARD log/ldr_link_data.reject ERRORS = BAD = 100000 LIVE = TRUE PARALLEL = TRUE &

  time nohup sqlplus username/password@SID @load_link.sql

  MV *.log. / log

  If the problem I encounter is here for loading data in the link table that I check if DHCP is present in the subntwk table, then continue to another mistake of the newspaper. If CMTS then left create link to another error in the newspaper.

  Now that we can here multiple CMTS are associated with unique DHCP.

  So here in the table links to create the link, but for the last iteration of the loop, where I get separated by commas separate CMTS table stg_link_data it gives me log as not found CMTS.

  for example

  DHCP-1-1-1. WNLB-CMTS-01-1,WNLB-CMTS-02-2

  Here, I guess to link the dhcp-1-1-1 with balancing-CMTS-01-1 and wnlb-CMTS-02-2

  Theses all the data present in the subntwk table, but still it gives me journal wnlb-CMTS-02-2 could not be FOUND, but we have already loaded into the subntwk table.

  same thing is happening with all the CMTS table stg_link_data who are in the last (I think here you got what I'm trying to explain).

  But when I run the SQL scripts in the SQL Developer separately then it inserts all valid links in the table of links.

  Here, she should create 9 lines in the table of links, whereas now he creates only 5 rows.

  I use COMMIT in my script also but it only does not help me.

  Run these scripts in your machine let me know if you also get the same behavior I get.

  and please give me a solution I tried many thing from yesterday, but it's always the same.

  It is the table of link log

  link is already present: dhcp-1-1-1_TO_wnlb-cmts-01-1

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-02-2

  link is already present: dhcp-1-1-2_TO_wnlb-cmts-03-3
  link is already present: dhcp-1-1-2_TO_wnlb-cmts-04-4

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-05-5

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-01-1

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-05-8
  NOT FOUND CMTS for device to create the link: wnlb-CMTS-05-6
  NOT FOUND CMTS for device to create the link: wnlb-CMTS-05-0

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-03-3

  link is already present: dhcp-1-1-5_TO_wnlb-cmts-02-2
  link is already present: dhcp-1-1-5_TO_wnlb-cmts-04-4

  NOT FOUND CMTS for device to create the link: wnlb-CMTS-05-7

  Device not found: wnlb-dhcp-1-13

  IF NEED MORE INFORMATION PLEASE LET ME KNOW

  Thank you

  I felt later in the night that during the loading in the staging table using UNIX machine he created the new line for each line. That is why the last CMTS is not found, for this I use the UNIX 2 BACK conversion and it starts to work perfectly.

  It was the dos2unix error!

  Thank you all for your interest and I may learn new things, as I have almost 10 months of experience in (PLSQL, SQL)

• SUBSTR and INSTR function

  Hi gurus,
  
  I have the data as follows:
  
  data
  -----------------------------------------------------------------------------------------------------------------------
  ' BIDIE01H / TXT:ZUNE = HA011, CellIndex = 144 /CAI:452 - 01-32201-47001 / CAI:45201F7dc9b79a'
  ' BIDIE01H / TXT:ZUNE = HA111, CellIndex = 124 /CAI:452 - 01-32201-471 / CAI:45201F7dc9b79b'
  
  
  and I'm writing a SQL results:
  
  CAI
  ---------
  452 01-32201-47001
  452 01-32201-471
  
  Any idea to do? I tried around with SUBSTR and INSTR functions but not yet sucessed.
  
  Thank you
  Alex

  something like:

  with my_tab as (select 'BIDIE01H/TXT:ZUNE=HA011, CellIndex=144 /CAI:452-01-32201-47001/CAI:45201F7dc9b79a' col1 from dual union all
                  select 'BIDIE01H/TXT:ZUNE=HA111, CellIndex=124 /CAI:452-01-32201-471/CAI:45201F7dc9b79b' col1 from dual)
  -- end of mimicking your data: USE SQL below:
  select substr(col1, instr(col1, '/CAI:', 1) + 5, instr(col1, '/CAI:', 1, 2) - instr(col1, '/CAI:', 1) - 5 ) CAI
  from my_tab
  
  CAI
  --------------------------------------------------------------------------------
  452-01-32201-47001
  452-01-32201-471