How to use Substr and Instr to get data from a file

Hi I have a script

I get a file like this

1.20, ram, sales

I get a file as these data as a column

I want to divide these data into 4 different columns as

1 20 sales of ram

Hello

This query will help you.

Select

SUBSTR (C1, 0, INSTR(C1,',')-1).

SUBSTR (C1, INSTR (C1, ',') + 1, INSTR(C1,',',1,2)-INSTR(C1,',',1,1)-1),

SUBSTR (C1, INSTR(C1,',',1,2) + 1, INSTR(C1,',',1,3)-INSTR(C1,',',1,2)-1).

SUBSTR (C1, INSTR(C1,',',1,3) + 1, INSTR(C1,',',1,4)-INSTR(C1,',',1,3)-1)

SUBSTR (C1, INSTR(C1,',',1,3) + 1)

BeO

Select 1, 20, ram, C1 double sales

)

Remember that a comma is not really safe as field separator

Post edited by: DecaXD

Tags: Business Intelligence

Similar Questions

How to use substr and instr, where the line of input Multi text

Hi all
with
data in the form of)
Select ' Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..' double val
Union of all the
Select 'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Plaza Falke' of the double
)
Select
regexp_substr (shipping_instructions, "[^ #] +' 1, 1") name
, regexp_substr (shipping_instructions, "[^ #] +' 1, 2") address
, regexp_substr (shipping_instructions, "[^ #] +' 1, 3") city
, regexp_substr (shipping_instructions, "[^ #] +' 1, 4") State
, regexp_substr (shipping_instructions, "[^ #] +' 1, 5") zip
, regexp_substr (shipping_instructions, "[^ #] +' 1, 6") County
FROM (select REGEXP_REPLACE (val, ' \.)) () [^.])', ' #\1 ") data shipping_instructions)
(1)'Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..'
(2)'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Falke Plaza. »
"Mary America. 1234 Southridge Park Dr. Samna Lorie. MO.31234..'
NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Married America 1234 Southridge Park Dr.    Samna Lorie MO 31234 NULL VALUE
"Bill Johnson. Apartment 3B. Sterling. VA. 20166. Falke Plaza 3... "
NAME ADDRESS CITY ZIP County SATE
----------------      -----------------        -------       -----        ---         --------
Bill Johnson apartment 3B Sterling, WILL 20166 3 Falke Plaza.
Problem
---------
(1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.
How to solve this problem?
(2) another possible to fix the code, I want to use substr and InStr.
(3) who is the best approach?
Conditions:
--------------
(1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »
This means it combined all the similar name, address, city, State, zip
(2) we insreted in the table separately.
=========================
/ * Use Substr and Instr * /.
=========================
I used substr and instr, but I'm getting the money results (no point in the address).
"America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234 NULL VALUE
But I need the results (no point in the address)
NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234 NULL VALUE

Hello

994122 wrote:

Hello

(1) how do to do this, use the substr and instr functions?

Thank you

You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

WITH got_delimited_string AS

(

SELECT REGEXP_REPLACE (val

, '\. ([^ .]| $)'

, '#\1'

) AS delimited_string

FROM the data

)

got_pos AS

(

SELECT delimited_string

, INSTR (delimited_string, "#", 1, 1) AS pos_1

, INSTR (delimited_string, "#", 1, 2), pos_2

, INSTR (delimited_string, "#", 1, 3) AS pos_3

, INSTR (delimited_string, "#", 1, 4) AS pos_4

, INSTR (delimited_string, "#", 1, 5) AS pos_5

, INSTR (delimited_string, "#", 1, 6) AS pos_6

OF got_delimited_string

)

SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

, '.'

)                                                           AS zip

SUBSTR (delimited_string, pos_5 + 1, pos_6 - (pos_5 + 1)) AS the County

OF got_pos

ORDER BY delimited_string

;

data of cutting using substring and instring, and storage in a new table

Hi all

I have an emp_address 2tables, address as below:
---------------------------------------------------------------
create the table emp_address (emp_id varchar2 (10), address varchar2 (100));

Insert into EMP_ADDRESS
(EMP_ID, ADDRESS)
Values
('101', 'street1 fremont CA 94538');
Insert into EMP_ADDRESS
(EMP_ID, ADDRESS)
Values
("102", "Street.2 fremont, CA 94537');
COMMIT;

create the address table (emp_id varchar2 (10), street varchar2 (20), city varchar2 (15), State varchar2 (10), zip varchar2 (10));

-----------------------------------------------------------------------------
Emp_address data as below:

emp_id address

street1 101 fremont CA 94538

102 fremont, CA 94537 Street.2

------------------------------------------------------------------------------
now I read data emp_address and split the data of the address column and record these data in the address table like as below

emp_id Street City State Zip Code
street1 101 fremont, ca 94538
102 fremont, ca 94537 Street.2

-------------------------------------------------------------------

I'm trying to divide these data using substring and instring. Actually my problem was between the data a few times I have 1tab or 2tabs and sometimes 3tab. If the number of tab spaces is not constant.

So can u help me in this case.

Thanks in adavnce

position of reference BluShadow

WITH emp_address AS (SELECT   '101' emp_id,
                              'street1 fremont CA 94538' address
                     FROM     DUAL
                     UNION ALL
                     SELECT   '102',
                              'street2  fremont CA 94537'
                     FROM     DUAL),
    emp_address_list_temp AS
      (SELECT       emp_id,
                    SUBSTR (
                      address,
                      DECODE (LEVEL,
                              1, 1,
                              INSTR (address, ' ', 1, LEVEL - 1) + 1
                             ),
                      DECODE (
                        INSTR (address, ' ', 1, LEVEL),
                        0,
                        LENGTH (address),
                        INSTR (address, ' ', 1, LEVEL)
                        - DECODE (LEVEL,
                                  1, 0,
                                  INSTR (address, ' ', 1, LEVEL - 1)
                                 )
                        - 1
                      )
                    )
                      address,
                    LEVEL rn
       FROM         emp_address
       CONNECT BY   LEVEL <=
                      LENGTH (address) - LENGTH (REPLACE (address, ' ')) + 1
       GROUP BY     emp_id, address, LEVEL),
    emp_address_list AS
      (SELECT   emp_id,
                address,
                ROW_NUMBER () OVER (PARTITION BY emp_id ORDER BY rn) rn
       FROM     emp_address_list_temp
       WHERE    TRIM (address) IS NOT NULL)
SELECT     emp_id,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 1)
             street,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 2)
             city,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 3)
             state,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 4)
             zip
FROM       emp_address_list e1
GROUP BY   emp_id

using substr and instr

Hi all
create table abc (str varchar2 (10))
insert into abc values ('ABC - DEF')
Insert into abc values('ABC/DEF')
Insert into abc values ('ABC DEF')
Insert into abc values('ABC.) DEF')
insert into abc values ('ABC DEF')
I need to put as ABCDEF for all values, if possible using sustr and instr
Thank you

Three ways:

Select replace (str, translate(str,'~ABCDEFGHIJKLMNOPQRSTUVWXYZ','~')) in abc; -assuming a single character is there in your data...

-generic way to remove all of the other characters keeping uppercase alphabets

SELECT TRANSLATE (str, ' ~' |) TRANSLATE (str, ' ~ ABCDEFGHIJKLMNOPQRSTUVWXYZ ',' ~'), ' ~') of ABC;

-Using regular expressions

Select regexp_replace(str,'[^[:alpha:]]') in abc;

See you soon,.

Manik.

A string into the text and numbers using SUBSTR and INSTR

I have the sample data. I know it's terrible database designed for a combination of text and numbers in the same field, but I can't change the business process.
That's what I have so far:
```
set linesize 5000

WITH table_data
     AS (SELECT 'R: JASON BOURNE 12341560' str FROM DUAL UNION ALL
         SELECT 'R: FATS DOMINO 23432342' str FROM DUAL UNION ALL
         SELECT 'R: MARTIN LUTHER KING 3334156' str FROM DUAL UNION ALL
         SELECT 'R: TOM CRUISE 6547123' str FROM DUAL UNION ALL
         SELECT 'R: TOMMY DE GROOT 1212124' str FROM DUAL UNION ALL
         SELECT 'R: GRIM REAPER 1345245' str FROM DUAL UNION ALL
         SELECT 'R: DOCTOR DEATH THE FIRST SMITH 24356178' str FROM DUAL)
SELECT str
     , TRIM(SUBSTR(str, INSTR(str, ' ', 1, 1), INSTR (str, ' ', 1, 2) - INSTR (str, ' ', 1, 1))) first_name
     , REPLACE(SUBSTR(str, INSTR (str, ' ', 1, 2)+1, 999), SUBSTR(str,LENGTH(str)-6,7), '') last_name
     , SUBSTR(str,LENGTH(str)-6,7) emp_num
  FROM table_data;

STR                                      FIRST_NAME    LAST_NAME                 EMP_NUM
---------------------------------------- -----------------------------------------------
R: JASON BOURNE 12341560                 JASON         BOURNE 1                  2341560
R: FATS DOMINO 23432342                  FATS          DOMINO 2                  3432342
R: MARTIN LUTHER KING 3334156            MARTIN        LUTHER KING               3334156
R: TOM CRUISE 6547123                    TOM           CRUISE                    6547123
R: TOMMY DE GROOT 1212124                TOMMY         DE GROOT                  1212124
R: GRIM REAPER 1345245                   GRIM          REAPER                    1345245
R: DOCTOR DEATH THE FIRST SMITH 24356178 DOCTOR        DEATH THE FIRST SMITH 2   4356178

7 rows selected.
```
I need to:
1 extract the first name - which is always the first name after the 'r' - I've got that little works very well.
2 extract the name - should be the last word before the number, if e.g. for the last night, I wish only that 'SMITH' and 'KING' for the 3rd line and "GROOT" for the 5th line.
3. remove the number at the end, regardless of the length - some of the examples above are 8 long numbers so my attempt above does not work.
I can't use any REGEXP or REGEXP_SUBSTR because they are not registered in the EUL I'm using discoverer, I can only use INSTR AND SUBSTR.
I was wondering if someone might be able to help please?
Any advice much appreciated.
Thank you

AW, go on them, as it's Christmas, I'm feeling generous...

SQL > ed
A written file afiedt.buf

1. WITH table_data (SELECT "r: JASON BOURNE 12341560' DOUBLE UNION ALL STR ')
2. SELECT "r: FATS DOMINO 23432342' str OF DOUBLE UNION ALL.
3. SELECT "r: MARTIN LUTHER KING 3334156' str OF DOUBLE UNION ALL.
4. SELECT "r: TOM CRUISE 6547123' str OF DOUBLE UNION ALL.
5. SELECT "r: TOMMY GROOT 1212124' str OF DOUBLE UNION ALL.
6. SELECT "r: GRIM REAPER 1345245' str OF DOUBLE UNION ALL.
7. SELECT "r: DOCTOR DEATH FIRST SMITH 24356178' FROM DUAL str.
8                     )
9 select substr (str, 1, instr(str,' ')-1) as a first name
10, substr (substr (str, 1, instr(str,' ',-1)-1), instr (substr (str, 1, instr(str,' ',-1)-1),' ', 1) + 1) as last_name
11, substr (str, instr (str, ' ',-1) + 1) as emp_num
12 years of (select replace (str,'R: ') as str)
table_data 13
14*        )
SQL > /.

FIRST_NAME LAST_NAME EMP_NUM
---------------------------------------- ---------------------------------------- ----------------------------------------
JASON BOURNE 12341560
FATS                                     DOMINO                                   23432342
MARTIN                                   KING                                     3334156
TOM                                      CRUISE                                   6547123
TOMMY                                    GROOT                                    1212124
GRIM                                     REAPER                                   1345245
DOCTOR SMITH 24356178

7 selected lines.

Help on using substr and instr functions
Hello

I'm trying to go back to the first three letters of the first word and all the last word in a description field. For example, if the description is 'grilled steak' the query should return "steak gri. That's what I have so far:

SELECT SUPPLIER_ID, PRODUCT_CODE, SUBSTR (DESCRIPTION, 1, 3). ' ' || SUBSTR (DESCRIPTION, INSTR (DESCRIPTION, ' ', 3)) AS A DESCRIPTION
OF L_FOODS;

Unfortunately, if the first word is the final word, it returns something like "sod soda." Does anyone have any advice or suggestions? Any help would be appreciated.
Hi and welcome to the forum!

It is always helpful if you identify your version of Oracle. The solution below depends on 10.1 and upward.

What you could do is include a conditional around your instr/substr functions that checks the number of spaces between words. If it is greater or equal two one then there are at least two words. For example:
```
WITH test_data AS
(
     SELECT 'grilled steak' AS DESCRIPTION FROM DUAL UNION ALL
     SELECT 'large pepperoni pizza' AS DESCRIPTION FROM DUAL UNION ALL
     SELECT 'soda' AS DESCRIPTION FROM DUAL
)
SELECT     (CASE
          WHEN LENGTH(REGEXP_REPLACE(TRIM(DESCRIPTION),'[^[:space:]]','')) > 0
          THEN SUBSTR(DESCRIPTION,1,3) || SUBSTR(DESCRIPTION,INSTR(DESCRIPTION,' ',-1))
          ELSE SUBSTR(DESCRIPTION,1,3)
     END) AS DESCRIPTION
FROM     test_data
```
Results
```
SQL> /

DESCRIPTION
-----------------------
gri steak
lar pizza
sod
```
: EDITION:

I also wanted to add this:
```
SUBSTR(DESCRIPTION, INSTR(DESCRIPTION, ' ', 3))
```
May not return the expected results. If your description field contains more than two words he will return all remaining words not only the LAST Word. See my solution above for what I believe is the correct version.

HTH!

Use Substr and InStr
I have created table:

create table wekaRules_productmgr)
The rule ID number,
WekaRule varchar2 (500),
VARCHAR2 (250) antecedent.
VARCHAR2 (250) resulting.
);

The table contains the following data with insert statements:

INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
VALUES (1, ' PM_PRICE_REDUCTION_TYPE = None 9828 == > PM_COUPON_TYPE = None 9828 conf: (1) lift: (1.06) conv: (576.86)') lev: (0.05) [576];

INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
VALUES (2, ' PM_AD_TYPE = None 9684 == > PM_PRICE_REDUCTION_TYPE = None 9684 conf: (1) lift: (1.12) conv: (1063.13)') lev: (0.1) [1063];

INSERT INTO wekaRules_productmgr (ID rule, WekaRule)
VALUES (3, ' PM_AD_TYPE = None 9684 == > PM_COUPON_TYPE = None 9684 conf: (1) lift: (1.06) conv: (568.41)') lev: (0.05) [568];

The values for the last two columns in the wekaRules_productmgr table is contained in the string values for each statement. For example, in the # 1 folder, the values are (from left to right):
history = PM_PRICE_REDUCTION_TYPE = None
result = PM_COUPON_TYPE = None

I need to find a way to analyze the values in each record and update in the appropriate table columns. So to case # 1, I need to update columns with the values given above, such as the records would look like:

Rule ID History Resulting
1 PM_PRICE_REDUCTION_TYPE = None PM_COUPON_TYPE = None
2 PM_AD_TYPE = None PM_PRICE_REDUCTION_TYPE = None
3 PM_AD_TYPE = None PM_COUPON_TYPE = None

I have tried this solution, but cannot very well:

UPDATE wekaRules_productmgr SET history =
(SELECT SUBSTR (wekarule, 1, (INSTR(wekarule,' ',1,1)-1)) 'history')
OF wekaRules_productmgr);

I also have a similar one for the suite. Does anyone have any suggestions? Any help is appreciated. Thank you!
I saw there is anonther detachment of you the same theme. If this can help you:
```
 SELECT
       regexp_substr(wekarule,'[a-zA-Z_]+ *= *[a-zA-Z_]+',1,1) antecedent,
       regexp_substr(wekarule,'[a-zA-Z_]+ *= *[a-zA-Z_]+',1,2) consequent,
       LTRIM(REGEXP_SUBSTR(wekarule, 'conf:$[^$]+'), 'conf:(') conf,
       LTRIM(REGEXP_SUBSTR(wekarule, 'lift:$[^$]+'), 'lift:(') lift,
       LTRIM(REGEXP_SUBSTR(wekarule, 'lev:$[^$]+'), 'lev:(') lev,
       LTRIM(REGEXP_SUBSTR(wekarule, 'conv:$[^$]+'), 'conv:(') conv
FROM   wekaRules_productmgr;
```
Published by: hm on 11.10.2010 11:29

How to use a memmory stick to get photos from one computer to another

I have an old computer with a lot of pictures on and I would like to put them on this computer I can do this with a memmory stick If Yes, how I'm new to computers so I need it to be simple

I have an old computer with a lot of pictures on and I would like to put them on this computer I can do this with a memmory stick If Yes, how I'm new to computers so I need it to be simple

Yes, you can very easily. Connect the memory stick on the old computer. Now copy the files of the rto to compute the memory stick. You can do this in several ways, but the easiest is to copy - paste and drag-and - drop. (If you don't know how to do those, post back for more information).

Once the files on the memory stick, remove it from the old computer and plug it into a new one. Do copy-and - paste or drag-and - drop from the memory stick to the new computer.

Also, note that it is possible that your memory stick is not big enough for all the photos, so you may need to do this in several batches.

Combination of substring and instring in RTF - dynamic signature images url

I am unable to use a combination of substring and instring in RTF model.
I have a BUYER_LAST_NAME column, which has a Jean Dupont value. I like to shoot 'john' on this channel.
I tried to create a variable using <? xdoxslt:set_variable($_XDOCTX,_'new_name',_'')? >
So I want to do a get variable using substr and InStr.
<? xdoxslt:get_variable (substring _XDOCTX, BUYER_LAST_NAME, $(DOCUMENT_BUYER_LAST_NAME, 1, instring(BUYER_LAST_NAME,' ')-1))? >
The command above does not work as a substring and instring aren't xdoxslt operations.
I tried to do this using xdofx: <? xdofx:substr (BUYER_LAST_NAME, 1, Instr(BUYER_LAST_NAME,' ')-1)? >
The above work, but I don't know how to make a variable defined using xdofx. Please help me on this.
Published:
I want to use this field in a dynamic signature display. But I can't call substring-before command as part of the url.
URL: {(concat('${OA_MEDIA}','/purchase_order/signatures/',.//BUYER_FIRST_NAME,'_',.//BUYER_LAST_NAME,'.jpg')}
I want to change the BUYER_LAST_NAME here.

I'm working on

URL: {concat (' ${OA_MEDIA} ',' / purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, "_",. / /, '.jpg')}

But it does not work.

->

URL: {concat (' ${OA_MEDIA} ','/ purchase_order/signatures /',. / / DOCUMENT_BUYER_FIRST_NAME, '_', substring-before(.//DOCUMENT_BUYER_LAST_NAME, ' '), '.jpg')}

who is working for me

Substr and InStr
Hi all

I have a table where a column has a data character in the format below:

* '00003434' *.
* '00123' *.
* '0000045' *.

If I want to eliminate all zeros on the left, how can I do using substr and instr? or is there an easier way?

Thank you

KK
Try again with

Select ltrim ('00003434 ', ' 0') of double;

substr and instr - get all the characters after the last.

I have a few fields tbl as follows
ABC, 123, xyz, 234
123, ggg, ppp, rrr
SSS/bbb/444/a
BB/11
XX/bb/f
I want to choose any characters after the last.
so the above might give
234
RRR
one
11
f
played with substr and instr but have not been able to figure it out yet. He should get one after last chain / no matter where / is or how they are.
Here is an example
Select
substr ("123/dd/gg ', instr (substr (" 123/dd/gg ', instr ("123/dd/gg ', ' /'") + 1 "), ' / ') + 3")
of the double

substr ("123/dd/gg ', instr('123/dd/gg','/',-1,1) + 1")

SUBSTR and INSTR function
Hi gurus,

I have the data as follows:

data
-----------------------------------------------------------------------------------------------------------------------
' BIDIE01H / TXT:ZUNE = HA011, CellIndex = 144 /CAI:452 - 01-32201-47001 / CAI:45201F7dc9b79a'
' BIDIE01H / TXT:ZUNE = HA111, CellIndex = 124 /CAI:452 - 01-32201-471 / CAI:45201F7dc9b79b'

and I'm writing a SQL results:

CAI
---------
452 01-32201-47001
452 01-32201-471

Any idea to do? I tried around with SUBSTR and INSTR functions but not yet sucessed.

Thank you
Alex
something like:
```
with my_tab as (select 'BIDIE01H/TXT:ZUNE=HA011, CellIndex=144 /CAI:452-01-32201-47001/CAI:45201F7dc9b79a' col1 from dual union all
                select 'BIDIE01H/TXT:ZUNE=HA111, CellIndex=124 /CAI:452-01-32201-471/CAI:45201F7dc9b79b' col1 from dual)
-- end of mimicking your data: USE SQL below:
select substr(col1, instr(col1, '/CAI:', 1) + 5, instr(col1, '/CAI:', 1, 2) - instr(col1, '/CAI:', 1) - 5 ) CAI
from my_tab

CAI
--------------------------------------------------------------------------------
452-01-32201-47001
452-01-32201-471     
```

How to use Ssh and Https for PC8164 PC5524

Hello!

How to use SSH and Https to connect to PC8164 and PC5524?

Kind regards!

For SSH configuration, we want to watch the 1651 page controls, user guide.

(config) #crypto console key generate rsa

RSA key generation started, it may take a few minutes...

Complete RSA key generation.

#crypto console key (config) generate dsa

DSA key generation started, it may take a few minutes...

DSA key generation complete.

Console (config) #ip ssh server

For HTTPS orders, we look at page 255, 1770-1778, CLI Guide.

generate a crypto certificate of console (config) # 1

Console (config-crypto-cert) #key - generate

output console(config-crypto-CERT) #.

Console (config) # ip http secure-certificate 1

Console (config) # ip http secure server

How to use cut and paste to import photos

How can I use cut and paste to import pictures from a SD card on Windows 7? Windows 7 has no AutoPlay.

It works in the same way as for any file:
1. Use Windows Explorer to open the folder on the SD card where your photos reside.
2. Mark the pictures you want to copy.
3. Press Ctrl + X to cut (or right click / cut)
4. Use Windows Explorer to open the folder on the hard drive where you keep your photos.
5. Press Ctrl + V to paste (or right click / Paste)

Need help with Substr and Instr

I have a request
Select msg
from table_a
She returned as log messages below
Continued in logid = > 241153 < for oid = > 1621 <, GoC = > 795, bday = > 01.04.2013 <
If the message contains logid = > then I want to display
Continued in logid = > 241151 <
for example
case
When the msg like ' % logid = > %'
then
I tried the combinations of substr and instr, but cannot make it work
Any help appreciated
Gus

SQL >-samples:

SQL > with t as

2 (choose "continued in logid-online 241153< for="" oid="">1621<, gdc="">795, bday-online 01.04.2013")<;' str="" from="" dual="" union="">

3 select "continued in pid-online 241153< for="" oid="">1621<, gdc="">795, bday-online 01.04.2013"<;' str="" from="">

4)

5. Select case-sensitive

6 when instr (str, 'logid') > 0

7 then substr (str

8, instr (str, ' > ', 1, 1) + 1

9, instr(str, '<', 1,="" 1)-instr(str,="" '="">', 1, 1)-1

10 )

11 another null - or what you want / need

12 end str

13 t;

STR

------------------------------------------------------------------------

241153

2 selected lines.

How to use Substr and Instr to get data from a file

Similar Questions

Maybe you are looking for