substr and instr - get all the characters after the last.

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  Hi all

  with

  data in the form of)

  Select ' Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..' double val

  Union of all the

  Select 'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Plaza Falke' of the double

  )

  Select

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  , regexp_substr (shipping_instructions, "[^ #] +' 1, 6") County

  FROM (select REGEXP_REPLACE (val, ' \.)) () [^.])', ' #\1 ") data shipping_instructions)

  (1)'Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..'

  (2)'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Falke Plaza. »

  "Mary America. 1234 Southridge Park Dr. Samna Lorie. MO.31234..'

  NAME ADDRESS CITY ZIP County SATE

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  "Bill Johnson. Apartment 3B. Sterling. VA. 20166. Falke Plaza 3... "

  NAME ADDRESS CITY ZIP County SATE

  ----------------      -----------------        -------       -----        ---         --------

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  Problem

  ---------

  (1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.

  How to solve this problem?

  (2) another possible to fix the code, I want to use substr and InStr.

  (3) who is the best approach?

  Conditions:

  --------------

  (1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »

  This means it combined all the similar name, address, city, State, zip

  (2) we insreted in the table separately.

  =========================

  / * Use Substr and Instr * /.

  =========================

  I used substr and instr, but I'm getting the money results (no point in the address).

  "America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

  
  

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234  NULL VALUE

  But I need the results (no point in the address)

  NAME ADDRESS CITY ZIP County SATE

  ---------                  --------                                ------------           ------           -------    -- -----

  Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234  NULL VALUE

  Hello

  994122 wrote:

  Hello

  (1) how do to do this, use the substr and instr functions?

  Thank you

  You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

  Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

  WITH got_delimited_string AS

  (

  SELECT REGEXP_REPLACE (val

  , '\. ([^ .]| $)'

  , '#\1'

  ) AS delimited_string

  FROM the data

  )

  got_pos AS

  (

  SELECT delimited_string

  , INSTR (delimited_string, "#", 1, 1) AS pos_1

  , INSTR (delimited_string, "#", 1, 2), pos_2

  , INSTR (delimited_string, "#", 1, 3) AS pos_3

  , INSTR (delimited_string, "#", 1, 4) AS pos_4

  , INSTR (delimited_string, "#", 1, 5) AS pos_5

  , INSTR (delimited_string, "#", 1, 6) AS pos_6

  OF got_delimited_string

  )

  SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

  SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

  SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

  SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

  REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

  , '.'

  )                                                           AS zip

  SUBSTR (delimited_string, pos_5 + 1, pos_6 - (pos_5 + 1)) AS the County

  OF got_pos

  ORDER BY delimited_string

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