CommandBatch - unknow user type

Similar Questions

• In text box on form Web PC, get name based on the ID that the user types

  Hello world

  This is urgent. Please help.

  Is it possible that we can implement the following scenario:

  1. as a user types an ID (for example, student card) in a control textbox in a form Web of PCS, the student's name is recovered and populated accordingly?

  Can web service to be invoked as type us something in the text box within the SCP?

  Thank you very much.

  Nathan

  Hello again, Nathan,

  Creates a window should be easy.

  This page contains examples and templates that you can use with web forms:

  http://docs.Oracle.com/CD/E29542_01/user.1111/e15177/app_form_rule_examples.htm#BPMCU528

  Check the last section 'Search Popup'

  Also is there an example that explains how to call a web service from web forms and how to process the response:

  Employee search database using criteria

  If {(Search.clicked)

  eval ('x =' + http.get ("data/myqset/findEmployee? name = {name_s1} & type = {type_s1}

  ((& racfid = {id_s1} & email = {email_s1}'));

  Hope this helps

  See you soon

  José

• In a text box - Guidance Notes that disappears when the user types on?

  Hello

  I'm looking for a way to add Guidance Notes in a text box - that disappears when the user types on?

  Thank you very much

  GD

  See:

  95078.aspx https://Answers.acrobatusers.com/is-Add-Instructional-Text-Text-Field-disappear-clicked-Q1

• ProcessEntry (...) consistency: unknown user type: java.lang.Object

  Hello!
  
  I created a new class that extends the VersionedPutAll class. When I replace processEntry (...) method I get an exception:

  Exception in thread "main" (Wrapped: Failed request execution for DistributedCache service on Member(Id=1, Timestamp=2012-08-09 18:02:13.598, Address=192.168.1.1:8088, MachineId=49553, 
  Location=site:,machine:StBook,process:18387, Role=IntellijRtExecutionAppMain) (Wrapped) unknown user type: java.lang.Object) java.io.IOException: unknown user type: java.lang.Object

  The original VersionedPutAll works well. My class without processEntry (...) works well also. But the simple substitution of processEntry (...) as
  

  protected Object processEntry(InvocableMap.Entry entry, Map mapAll, boolean fInsert, boolean fReturn) {
      return new Object();
  }

  throws an exception.
  
  Does anyone know what is the problem? Thank you.
  
  

  public class ExtVersionedPutAll extends VersionedPutAll {
      private static final Object NO_RESULT = new Object();
  
      public ExtVersionedPutAll() {}
  
      public ExtVersionedPutAll(Map map) {
          super(map);
      }
  
      public ExtVersionedPutAll(Map map, boolean fAllowInsert, boolean fReturn) {
          super(map, fAllowInsert, fReturn);
      }
  
      protected Object processEntry(InvocableMap.Entry entry, Map mapAll, boolean fInsert, boolean fReturn) {
          Object oKey = entry.getKey();
          if(mapAll.containsKey(oKey)) {
              Versionable oValueCur = (Versionable)entry.getValue();
              Versionable oValueNew = (Versionable)mapAll.get(oKey);
              boolean fMatch;
              if(oValueCur == null) {
                  fMatch = fInsert;
              } else {
                  Comparable verCur = oValueCur.getVersionIndicator();
                  Comparable verNew = oValueNew.getVersionIndicator();
                  fMatch = verCur.compareTo(verNew) < 0;
              }
              if(fMatch) {
                  oValueNew.incrementVersion();
                  entry.setValue(oValueNew, false);
                  return NO_RESULT;
              } else {
                  return fReturn ? oValueCur : NO_RESULT;
              }
          } else {
              return NO_RESULT;
          }
      }
  }

  Exception in thread "main" (Wrapped: Failed request execution for DistributedCache service on Member(Id=1, Timestamp=2012-08-09 18:02:13.598, Address=192.168.1.1:8088, MachineId=49553,
   Location=site:,machine:StBook,process:18387, Role=IntellijRtExecutionAppMain) (Wrapped) unknown user type: java.lang.Object) java.io.IOException: unknown user type: java.lang.Object
       at com.tangosol.util.Base.ensureRuntimeException(Base.java:288)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.Grid.tagException(Grid.CDB:36)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache.onInvokeAllRequest(PartitionedCache.CDB:97)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache$InvokeAllRequest.onReceived(PartitionedCache.CDB:111)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.Grid.onMessage(Grid.CDB:34)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.Grid.onNotify(Grid.CDB:33)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.PartitionedService.onNotify(PartitionedService.CDB:3)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache.onNotify(PartitionedCache.CDB:3)
       at com.tangosol.coherence.component.util.Daemon.run(Daemon.CDB:42)
       at java.lang.Thread.run(Thread.java:662)
  Caused by: java.io.IOException: unknown user type: java.lang.Object
       at com.tangosol.io.pof.ConfigurablePofContext.serialize(ConfigurablePofContext.java:351)
       at com.tangosol.util.ExternalizableHelper.serializeInternal(ExternalizableHelper.java:2597)
       at com.tangosol.util.ExternalizableHelper.toBinary(ExternalizableHelper.java:211)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache$ConverterValueToBinary.convert(PartitionedCache.CDB:3)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache$Storage.invokeAll(PartitionedCache.CDB:63)
       at com.tangosol.coherence.component.util.daemon.queueProcessor.service.grid.partitionedService.PartitionedCache.onInvokeAllRequest(PartitionedCache.CDB:78)
       ... 7 more
  Caused by: java.lang.IllegalArgumentException: unknown user type: java.lang.Object
       at com.tangosol.io.pof.ConfigurablePofContext.getUserTypeIdentifier(ConfigurablePofContext.java:430)
       at com.tangosol.io.pof.ConfigurablePofContext.getUserTypeIdentifier(ConfigurablePofContext.java:419)
       at com.tangosol.io.pof.PofBufferWriter.writeUserType(PofBufferWriter.java:1671)
       at com.tangosol.io.pof.PofBufferWriter.writeObject(PofBufferWriter.java:1623)
       at com.tangosol.io.pof.ConfigurablePofContext.serialize(ConfigurablePofContext.java:345)
       ... 12 more

  The problem is that you try to return an instance of the EntryProcessor NO_RESULT and No_Result is of type Object. Coherence cannot serialize an ordinary object, so you get this error. You need to do something No_RESULT that can be serialized - object to primitive type or a custom class that is serializable POF.

  JK

• ESSBASE & PLANNING USER TYPE SETTING

  Hi all
  
  We use the ESsbase and planning implementation.
  
  some of our face to users as a matter of 'Not allowed access to Essbase' or 'not allowed access to the planning. When we looked for the reason, we found as the user not having the two 'Essbase & Planning' as access to applications in the EA-> Essbase Server-> Security
  
  So, on this basis, select us the users manually in HSS and select the two 'Essbase & Planning' as the type of user for them.
  
  It is all utilityto perform this task.
  
  First of all, I need to list users who have not 'Essbase & Planning' as user type
  
  Secondly, I would like to change their settings in order to access the applications...
  
  Any help is appreciated!
  
  Thank you!!
  
  Kind regards
  Rev

  You can use maxl to set the application type
  For example

  ALTER user user_name add application_access_type Essbase;

  or

  ALTER user user_name add application_access_type planning;

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• Account with a 'Normal user' Type.

  Program: User accounts.

  Question: when you try to create a user account I am able to do only a user Statndard & Aministrator account Types, but need a Normal user account type.

  Please help me find the solution to get the kind of Normal user account when creating a user.

  Sudhir Hervé.

  There is no such thing as a 'Normal' user account It is Standard and he is a Director. You want your regular to be the standard user accounts.

  User - recommended configuration (Vista and Win7) accounts

  You absolutely don't want to have only one user account. As XP and all other Windows 7, Vista, and modern operating systems are operating systems multi-user with integrated system of accounts as default Administrator and comments. These accounts should be left alone because they are part of the structure of the operating system.

  In particular, you do not want account only one user with administrator privileges on Vista and Windows 7 because the administrator account integrated (normally only used in emergencies) is disabled by default. If you use as an administrator for your daily work, and this account is corrupt, things will be difficult. It is not impossible to activate the built-in administrator to rescue things, but it may require more work you want to do. Better not to get into a bad situation at first.

  The user account that is for your daily work must be a Standard user, with the extra administrative user (call it something like 'CompAdmin' or 'Tech' or similar) only it for elevation purposes. As a user Standard is recommended for security reasons and will help protect your computer against infections. After you have created "CompAdmin", connect to it and change your normal user account Standard. Then log on to your regular account.

  If you want to go directly to the desktop and ignore the Welcome screen with the icons of the user accounts, you can do this:

  Start Orb > Search box > type: netplwiz [Enter]
  Click continue (or provide an administrator password) when you are prompted by UAC

  Uncheck "users must enter a user name and password to use this computer". Select a user account to connect automatically by clicking on the account you want to highlight and press OK. Enter the password for this user account (when it exists) when you are prompted. Leave blank if there is no password (null).

  MS - MVP - Elephant Boy computers - don't panic!

• Possible to use cast without creating a user type?

  RDBMS: 10.2.0.3.0
  TOAD 8.5.0.50
  
  I'm trying to use the collect() to turn this:
  

  part      category
  A1        gloves
  A1        hat
  A1        glasses

  in this:

  part       category
  A1         glove,hat,glasses

  When I run my sql in Toad, I get:

  select part, collect(category) my_category
  from my table
  where part = 'A1'
  
  part   my_category
  A1    (Dataset)

  I know that I need to use the Cast function, but the problem is that I don't have the rights to create a user-defined type. I tried to use a seeded as Varchar2 type, but I get a channel of communication for end of file ora-03113 error.

  select part, cast(collect(category) as VARCHAR2(500))
   -->ORA-03113

  Is it possible to use successfully collect and cast without the ability to create a user-defined type?
  
  -Tracy

  You can use sys.odcivarchar2list as for example in

  select deptno, cast(collect(ename) as sys.odcivarchar2list) enames from emp group by deptno
  /
  

• Unknow user accounts and Environment Variables.

  Hello I wonder if you can help me with a friends computer its system is a Dell Allienware with Windows 7 and for some strange reason, it keeps Hijacked and unknown about 3 user accounts are hide like him on his computer, please find some screenshots of this:

  That's what he said:

  "and if you notice one of the screenshots shows the USERS AUTHENTIFIES... as having read write and execute.
  When normally they should have just PERMISSIONS SPECIAL... which means they took authorities... and took over... used user accounts my own account from another pc or ipad combo... »

  [URL = http://imgbox.com/adgbu06s] [IMG] http://i.imgbox.com/adgbu06s.jpg [line] [url] [URL = http://imgbox.com/abn5L3ve] [IMG] http://i.imgbox.com/abn5L3ve.jpg [line] [url] [URL = http://imgbox.com/acetHWxc] [IMG] http://i.imgbox.com/acetHWxc.jpg [line] [url] [URL = http://imgbox.com/abhTHMjy] [IMG] http://i.imgbox.com/abhTHMjy.jpg [line] [url] [URL = http://imgbox.com/acsPk2yS] [IMG] http://i.imgbox.com/acsPk2yS.jpg [line] [url]

  So how can he take control?

  Also, here is its guid in Regedit: it's DELLSUCKS (it's his user account)

  I did it on the hijacked aircraft and there were 6 of them...
  3 of them are the pc... and the windows... etc.
  1 single user as admin... no idea why you want the screenshot of the user accounts.

  they have even edited the variables to change discs...  Temp was z:\temp not \\temp or folder or whatever it is
  even the exe and bat and others to run were all cleared... CPU changed... all that... fun

  [URL = http://imgbox.com/acfgbpKH] [IMG] http://i.imgbox.com/acfgbpKH.jpg [line] [url]

  The hijackers changed its certificates:

  That's what he said:
  now on the hijacked machine... where I circled and underlined... it says z:\windows and username was JOHNSMITH non-SYSTEM...
  etc.

  I could go on...
  on the top where it says temp... He said USERPROFILE he says z:\users\johnsmith etc.

  or in the end he just said-* and all the filters had * which means that all release to
  same firewall disabled all the rules and set up his own... even with Windows and controls the management of the ATI... all supported

  Any ideas of a fix on this one?

  Thank you

  Rob

  If I were a pirate, then I would do whatever to remain discreet. I would do my utmost to avoid attracting attention, for example by using an account name which comes out as the dog b... Or have you ever seen a thief walking the streets with a pinch bar and a large bunch of keys in the hands?

  What you see are the residues of the accounts that have been deleted in the past. You can remove these entries in the whitelists without fear.

• How can I do what a user types in the text entry box go to lms?

  Hello

  I have a few boxes of text entry for the unmarked short answer responseses - more of an exercise of reflection than anything else.

  However, I would text the learner types to be saved by the LMS.

  How to make that happen if it is not a real assessment?

  Thank you

  fantastic, thanks a lot!

• How to limit navigation directly via the URL when the user tries to type the page number and access this page in ORACLE APEX 4.2

  Hi all

  I developed an application where I have 6 pages and 5 tabs and based on the user role I posted the tabs for the user to access these pages.

  But when the user, who doesn't have access to the particular page (say, page 2), but still the user can navigate to it directly by typing the page number in the URL.

  I want to avoid such scenarios.

  eg: http://Apex.Oracle.com/f?p=110:2 , when the user type this in the address bar, it navigates the user to this page even if this particular user does not have access to this page.

  How to prevent the user to navigate through the URL, if the user tries to navigate directly through URLS rather than tabs, I have to give the error message.

  Version: ORACLE APEX 4.2

  Thank you

  Good reading this recent post

  Re: Authentication at the Page level

  All links to a page and the page itself must be secure.

  You can also consider the protection of session state to prevent tampering of the URL.

• Add the column to an existing table-based user-defined type

  Hello guys,.
  I am compiling my function that returns a type defined by the user based on an existing table. Throughout the process of initialization so my query returns an additional column - SCORE (1). Here is my package:
  
  create or replace
  PACKAGE STAFF_AGENCY_PKG AS
  
  TYPE TYPE_SEEKER_TABLE IS TABLE OF THE DRAW. SEEKER % ROWTYPE;
  FUNCTION GET_SEEKERS (IN_KEYWORD IN VARCHAR2)
  TYPE_SEEKER_TABLE RETURN PIPELINE;
  
  END STAFF_AGENCY_PKG;
  -------
  
  create or replace
  STAFF_AGENCY_PKG PACKAGE BODY
  AS
  
  FUNCTION GET_SEEKERS (IN_KEYWORD IN VARCHAR2)
  TYPE_SEEKER_TABLE RETURN PIPELINE
  IS
  R_TBL TYPE_SEEKER_TABLE; -to return
  BEGIN
  FOR R IN)
  SELECT Seeker.SEEKER_ID,
  Seeker.FIRSTNAME,
  Seeker.LASTNAME,
  Seeker.NATIONALITY,
  Seeker.ISELIGIBLE,
  Seeker.BIRTHDATE,
  Seeker.ISRECIEVEEMAILS,
  Seeker.HIGHESTDEGREE,
  Seeker.ETHNICITY,
  Seeker.GENDER,
  Seeker.ISDISABILITY,
  Seeker.DISABILITY,
  Seeker.CV,
  Seeker.PASSWORD,
  Seeker.PREFFERED_CITY,
  SEEKER. E-mail
  SEEKER. JOB_PREFERENCES_ID,
  SCORE (1)
  THE APPLICANT Seeker
  WHERE CONTAINS (CV, ' < query >)
  < textquery lang 'grammar' = 'context' = > ' |
  GET_RELATED_CATEGORIES (IN_KEYWORD) |
  ' < / textquery >
  < score datatype = "INTEGER" / >
  (< / query > ', 1) > 0
  )
  LOOP
  PIPE ROW (R); -Error (38,10): PLS-00382: expression is of the wrong type
  END LOOP;
  RETURN;
  
  END GET_SEEKERS;
  END STAFF_AGENCY_PKG;
  
  How do I change my user type to be sufficient?
  
  Oracle version 11.2.0.1.0
  Thanks in advance!

  >
  How do I change my user type to be sufficient?
  >
  You will need to create two new TYPEs. The one who has all the columns of the draw. The REQUESTOR table and the new column SCORE, then a TYPE which is an array of the first type.

  See example 12-22 using a Pipelined Table function for a Transformation in the PL/SQl language reference

  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28370/tuning.htm#i53120

  Here's the first part

  -- Define the ref cursor types and function
  CREATE OR REPLACE PACKAGE refcur_pkg IS
    TYPE refcur_t IS REF CURSOR RETURN employees%ROWTYPE;
    TYPE outrec_typ IS RECORD (
      var_num    NUMBER(6),
      var_char1  VARCHAR2(30),
      var_char2  VARCHAR2(30));
    TYPE outrecset IS TABLE OF outrec_typ;
   FUNCTION f_trans(p refcur_t)
        RETURN outrecset PIPELINED;
  END refcur_pkg;
  /
  
  CREATE OR REPLACE PACKAGE BODY refcur_pkg IS
    FUNCTION f_trans(p refcur_t)
     RETURN outrecset PIPELINED IS
      out_rec outrec_typ;
      in_rec  p%ROWTYPE;
    BEGIN
  

  Change

    TYPE outrec_typ IS RECORD (
      var_num    NUMBER(6),
      var_char1  VARCHAR2(30),
      var_char2  VARCHAR2(30));
    TYPE outrecset IS TABLE OF outrec_typ;
  

  to include all the columns you need. Unfortunately, you have to manually list all the columns in the draw. The REQUESTOR table. If you think you need this same structure in other places you must create them as SQL types instead of PL/SQL types.

  This example should be enough to show you how to modify your code to do something similar.

• Type of user to the Shared Services

  All,
  I'm on 9.3.1
  So far I have users only to the planning application.
  Now, most of the users above have need to access an application native essbase (with planning).
  In shared services, under project-> AnalyticServer-> AnalytciServer, only users are listed (no groups) and their Type 'user' is planning.
  Now I have to change them to "Planning, Essbase" for each user.
  I found no "user Type" in the corresponding section in the export of the CSSImportExport utility.
  have many users, is it possible to automate?
  
  Thank you
  Krishna

  You could look at using maxl

  For example

  ALTER user user_name add application_access_type Essbase;

  or

  ALTER user user_name add application_access_type planning;

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• How to upgrade the user defined material cost type of cost specific org

  Hello
  
  We need to update material cost sub-elements of something to an org specific and defined by the user type of cost.
  I inserted a line of example in the CST_ITEM_CST_DTLS_INTERFACE and open interface "mass update material operating costs", but the program does not deal with all the lines, the rest 1 Process_flag.
  
  insert into cst_item_cst_dtls_interface
  (inventory_item_id,
  organization_id,
  id_ressource,
  usage_rate_or_amount,
  cost_element_ID,
  Process_Flag,
  last_update_date,
  last_updated_by,
  CREATION_DATE,
  created_by
  )
  values
  (96023,
  343,
  52538,
  0.00208012,
  1,
  1,
  SYSDATE,
  fnd_global.user_id,
  SYSDATE,
  fnd_global.user_id
  )
  
  Can someone help me with this, thanks.
  
  Concerning
  Yohan

  I think that there is some confusion.
  "Edit material costs of mass" program is used to apply the new rate of activity to the issue of costs. To do this, you don't have to insert records in the interface. You should define/update activity rates new use of the screen.

  To process the records in the interface of cost tables, you must run the program of 'importation cost process.

  For more details, see http://download.oracle.com/docs/cd/A60725_05/html/comnls/us/cst/settas06.htm

  Hope that answers your question
  Sandeep Gandhi
  OMKAR Technologies Inc.
  Techno-Functional consultant

• access a type of user to another schema (collection)

  Hello
  
  In my scheme of production, I created a user type:

  CREATE TYPE T_my_row  OID '4711'
  IS OBJECT(field1 varchar2(10), field2 number(10));
  /
  
  CREATE TYPE TT_my_table  OID '0815'
  IS TABLE OF T_my_row;
  /

  I use the TT_my_table collection as a parameter of a procedure type.
  
  Intended to test, I would like to call this procedure from another schema (SQL-developers UT repository). This is why I need 'access' to the collection type of this test pattern.
  
  What are the rights I give to achieve?
  
  Good bye
  DPT
  
  Edited by: T.PD the 29.06.2010 10:40

  Dear T.PD,

  I think that under query will work for you;

  SQL > GRANT EXECUTE, DEBUG ON TYPE_NAME TO SCHEMA_NAME.

  It will be useful,

  Ogan

• prompt user with write to measure file VI

  Hello

  I have a Labview VI who is writing data to a file, currently the file name (path) is written in the section "Filename" of writing on a file measure VI.
  Is it possible that a user can be prompetd for a file name?

  As in,.

  time each time I run the VI a diaglog box appears, which allows the user to type a specific file name (say Run1 or Run 2, etc...). The user types the name of the file must match the name of the file where the data is written (using writing to the file as VI)

  I enclose my vi of the trial.

  Thank you

  lana89

  There is a function of file dialog box, which you can use.  Can be found in the Express-> entry-level or advanced-> palettes files IO.