Comparison table of the firewall

Similar Questions

• The firewall CISCO ASA not getting connections do not time-out

  Hello

  I see the connections that are established by the ASA are not getting deleted from the table of connection.

  In the world, I set the conn timeout on the firewall, but you see not that idle connections do not timeout & removed from connection table.

  !

  Timeout conn 01:10 half-closed 0:10:00 udp 0:01:00 icmp 0:00:02
  Sunrpc timeout 0:10:00 h323 0:05:00 h225 mgcp from 01:00 0:05:00 mgcp-pat 0:05:00
  Timeout sip 01:30 sip_media 0:02:00 prompt Protocol sip-0: 03:00 sip - disconnect 0:02:00
  Timeout sip-provisional-media 0:02:00 uauth 0:00:00 absolute
  timeout tcp-proxy-reassembly 0:01:00
  Floating conn timeout 0:00:00

  !

  Here are some of the number of connections that are observed more than chronology configured.

  Y.y.y.y:162 UDP dmz1 inside the x.x.x.x:162, slow 227:28:39, bytes 9946115-flags.

  The TCP flags dmz1 z.z.z.z:22 inside the x.x.x.x:64880, slow 243:16:17, byte 13755432, UI

  Y.y.y.y:162 UDP dmz1 inside the x.x.x.x:49962, slow 640:41:09, bytes 1599882-flags.

  A.a.a.a:22 TCP dmz1 inside the x.x.x.x:56750, slow 600:06:46, bytes 148361, flags UIO

  Meet some connections he defined indicator that says his top, but whereas that much are didn't all (empty) set of flags.

  I'm running with 9.1 2 code.

  Hello Sanjay

  The behavior that you note does not seem normal that the device is configured for specific waiting periods.

  I suggest you check the following defect which is reported for ASA.

  Here is a link to default:

  https://BST.cloudapps.Cisco.com/bugsearch/bug/CSCuh13899/?reffering_site...

  It could be that useful...

  Thank you

  RS

• A question about the conservation of fields (hour, min, sec) time DATE type in the table on the changes of NLS_DATE_FORMAT

  Hello

  Oracle version: 12.1.0.1.0 - 64 bit

                    OS:   Fedora Core 17 X86_64

  My question is about the conservation of fields (hour, minute, second) time DATE type in the array on NLS_DATE_FORMAT changes.

  Take the following test case:

  SQL> create table tmptab(dateval date);
  
  Table created.
  
  SQL> alter session set nls_date_format = 'yyyy-mm-dd hh24:mi:ss';
  
  Session altered.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 00:00:00');
  
  1 row created.
  
  SQL> insert into tmptab(dateval) values('2014-01-01 10:00:00');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select * from tmptab;
  
  DATEVAL
  -------------------
  2014-01-01 00:00:00
  2014-01-01 10:00:00
  
  SQL> alter session set nls_date_format = 'yyyy';
  
  Session altered.
  
  SQL> select * from tmptab where dateval > '2014';
  
  no rows selected
  
  SQL>
  

  I don't understand why it returns nothing. The second test case above insert statement inserted a line with 10 as the value for the time of the DATE field column dateval.

  Accordingly, while comparing this with the literal '2014' (which based on the new value of NLS_DATE_FORMAT = "yyyy" is implicitly converted to DATE), shouldn't the above query returns the line 2014-01-01 10:00 ?

  I mean, I changed the NLS_DATE_FORMAT but data from time in the table fields are preserved and that's why they should normally be taken into account in the comparison of date.

  What I'm trying to say is that for me (Please correct me if I'm wrong), no matter what NLS_DATE_FORMAT configuration is the following test

  SQL> select * from tmptab where dateval > '2014';
  

  is the same thing that

  SQL> select * from tmptab where dateval > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss');
  

  And because the line 2014-01-01 10: 00:00 in the tmptab table. The following test

  2014-01-01 10:00:00 > to_date('2014-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
  

  evolves normally true (beucase of TIME = 10 on the left side of the test) and therefore this line must be returned which is not the case in the test above.

  You kindly could you tell me what I misunderstood?

  Thanks in advance,

  This is the price for the use of implicit conversions. Implicit DATE conversion rules are not as direct as it can be assumed. In your case, all you provide is year as date format. In this case date implicit conversion rules assumes that month in the current month, day 1 and time as 00:00:00.

  SQL > alter session set nls_date_format = "yyyy";

  Modified session.

  SQL > select to_char (to_date ('2014 "), ' mm/dd/yyyy hh24:mi:ss') twice;

  TO_CHAR (TO_DATE('20)
  -------------------
  01/08/2014-00:00:00

  SQL >

  So, when you start:

  Select * from tmptab where dateval > '2014 '.

  Oracle implicitly converts date using "YYYY", which translates as August 1, 2014 '2014'. That's why your quesry returns no rows.

  SY.

• Use of the firewall via API Service

  Hello

  looking at the appendix to the API_v_1_5_Reference I noticed that only 10 ComputingResources are listed. There is no reference to the firewall function.

  However, when I generate a report via the GUI, I am able to get the number of networks, Service NAT, DHCP, firewall, external network transfer/receive etc...

  Is it possible to get this information through the API?

  Thanks in advance,

  Marco

  Hi Marco,.

  You have two options: -.

  • You can find the ID of the next computing resource of the database directly. You must watch CB_SERVER_PROPERTY table invCenter chargeback database. Once the computer resource ID are generated for a particular vCenter Chargeback installation they are fixed and will not change.
  1. Number of networks--> SERVER_PROPERTY_NAME = "Count Of Networks", PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you the id
  2. Service NAT--> SERVER_PROPERTY_NAME = "Service NAT", PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you the id
  3. Service DHCP--> SERVER_PROPERTY_NAME = 'Service of firewall', PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you the id
  4. Firewall Service--> SERVER_PROPERTY_NAME = "DHCP Service", PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you the id
  5. External network transfer--> SERVER_PROPERTY_NAME = 'External network Transfer', PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you the id
  6. Network reception external--> SERVER_PROPERTY_NAME = "External network receive", PROPERTY_CATEGORY = "vcloud"--> column SERVER_PROPERTY_VALUE will give you ideas
  • Another option is to find the resource ID computer using APIs (but it's time that an effort, I think that first approach should be better)

  Call APIs "Get, POST /Rechercher", the input xml for appellant file this API will look like

     
         
             
                 
             
             
                 
                      serverPropertyName
                 
             
             
                  0
                  100
             
         
     
  The response will return all properties with category as "vcloud" out of these properties, you can filter the relevant properties to your name (example ' Count of Networks') and get the id of computing resource of the value.
  I hope this helps.
  -Amrainder

• Partitioning of a table in the production

  Hello
  
  Oracle 10.2.0.4
  
  I partitioned a table lines about 100 million (62 GB) in Server DEV source. The target database was created again. It was partioned range on a column of date as follows:

  PARTITION BY RANGE (ENTRY_DATE_TIME)
  (
    PARTITION ppre2012 values less than (TO_DATE('01/01/2012','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
    PARTITION p2012 values less than (TO_DATE('01/01/2013','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
    PARTITION p2013 values less than (TO_DATE('01/01/2014','DD/MM/YYYY')) TABLESPACE WST_LRG_D,
    PARTITION p2014 values less than (MAXVALUE) TABLESPACE WST_LRG_D
  )

  It's every year. Nothing before 2012 to p2013 ppre2012, then 2012, and so on. There are 20 million lines in 2012. and about 75 million lines of ppre2012. We had as well to the tables (partitioned) target DEv and (unpartitioned) source for comparison. Queries are normally on the partition for the current year. Just to say that I am a developer and do not have full visibility to the production instance.
  
  Now that our tests are completed, we would like to promote this production. Of course in production we would not not need source and target tables. In all likelihood, this will be done on a weekend window. This is why I would like to suggest the following.
  
  (1) use expdp export the source table
  (2) remove the table from the source
  (3) create a new source "partitioned" no index table
  (4) use impdp to retrieve data in a table
  (5) create a global index (it's a unique index to enforce the uniquness) and the rest of the clues like local
  (6) run dbms_stats.gather_table_stats (waterfall of the user, 'SOURCE' = > true). It takes about 2 hours by dev
  
  My point is that, if the importation of 100 million lines will cause no issues with segments of cancellation. Can we import data say firstly to the current partition (20 million lines) 2012 first. Any practical advice is appreciated.
  
  Thank you
  
  Published by: 902986 on November 2, 2012 02:08
  
  Published by: 902986 on November 2, 2012 03:10

  >
  -Why do I get "ORA-12838: cannot read/modify an object after edit it in parallel."
  >
  Why don't find you the error and read the cause "that applies?
  http://ORA-12838.ora-code.com/
  >
  ORA-12838: cannot read/modify an object after edit it in parallel
  Cause: In the same transaction, an attempt was made to add instructions for reading or changing on a table once it had been amended at the same time or with a direct charge. This is not allowed.
  >
  Do you have a 'direct charge '? Yes - you can not do anything else under this operation. Do a COMMIT or ROLLBACK first.

• finding duplicate records in the DB table, or the data trasnpose

  Hello
  
  I have a question...
  
  Key | UID. Start Dt | End date. / / DESC
  
  
  --------------------------------------------------------------------------------
  1. 101 | March 12 09 | 30 May 09 | UID101
  
  2. 101 | January 1 09 | February 25 09 | UID101
  
  3. 102. 13 March 09 | 30 March 09 | UID102
  
  4. 103. 13 March 09 | 30 March 09 | UID103
  
  5. 103. 13 March 09 | April 1 09 | UID103
  
  6. 104. 13 March 09 | 30 May 09 | UID104
  
  7. 104. February 25 09 | 29 May 09 | UID104
  
  8. 105. 15 February 09 | March 1 09 | UID105
  
  9. 105. April 1 09 | 30 May 09 | UID105
  
  The query must know UID in duplicate according to the above data, which are stored in the same form in a table. The definition of the UID duplicate is
  
  (1) UID repeating themselves (records by 2) ex are 101,103,104 and 105.
  (2) each UID has two dates and date of end of beginning.
  (3) the UID for which dates are overlaping. For ex: touch #4, 103 UID whose start dates are March 13 09-30-Mar-09 and there also another record, with the # 5 UID 103 key dates are 13 Mar 09 to 1 April 09. Here, there is overlap or intersection in line #4 with key #5 key dates dates of rank. This UID is duplicated UID by def.
  
  What precedes that falls under def and selectable are 103 and 104 only 102 UID has only a single line, UID 105 dates are mutually exclusive or not that overlap and even for the UID.
  
  Is there a function available DB to make use of?
  
  
  Wanted not to delete records or duplicate records.
  
  There is a report to display these duplicate records.
  
  It would be good for me if I can get the data transposed for UID
  
  as
  
  Of
  
  4. 103. 13 March 09 | 30 March 09 | UID103
  
  5. 103. 13 March 09 | April 1 09 | UID103
  
  TO
  UID. Start the t1d. End t1d. Start the T2D. End T2D
  103: |13-Mar-09|30-Mar-091-Apr-09 13 March 09
  
  Any advice or ideas can be useful to gr8
  
  Thank you...

  It can also be done without Analytics:

  WITH test_data AS (
    SELECT  1 AS KEY, 101 AS UD, TO_DATE('03/12/2009','MM/DD/YYYY') AS START_DT, TO_DATE('05/30/2009','MM/DD/YYYY') AS END_DT, 'UD101' AS DSC FROM DUAL UNION ALL
    SELECT  2 AS KEY, 101 AS UD, TO_DATE('01/01/2009','MM/DD/YYYY') AS START_DT, TO_DATE('02/25/2009','MM/DD/YYYY') AS END_DT, 'UD101' AS DSC FROM DUAL UNION ALL
    SELECT  3 AS KEY, 102 AS UD, TO_DATE('03/13/2009','MM/DD/YYYY') AS START_DT, TO_DATE('03/30/2009','MM/DD/YYYY') AS END_DT, 'UD102' AS DSC FROM DUAL UNION ALL
    SELECT  4 AS KEY, 103 AS UD, TO_DATE('03/13/2009','MM/DD/YYYY') AS START_DT, TO_DATE('03/30/2009','MM/DD/YYYY') AS END_DT, 'UD103' AS DSC FROM DUAL UNION ALL
    SELECT  5 AS KEY, 103 AS UD, TO_DATE('03/13/2009','MM/DD/YYYY') AS START_DT, TO_DATE('04/01/2009','MM/DD/YYYY') AS END_DT, 'UD103' AS DSC FROM DUAL UNION ALL
    SELECT  6 AS KEY, 104 AS UD, TO_DATE('03/13/2009','MM/DD/YYYY') AS START_DT, TO_DATE('05/30/2009','MM/DD/YYYY') AS END_DT, 'UD104' AS DSC FROM DUAL UNION ALL
    SELECT  7 AS KEY, 104 AS UD, TO_DATE('02/25/2009','MM/DD/YYYY') AS START_DT, TO_DATE('05/29/2009','MM/DD/YYYY') AS END_DT, 'UD104' AS DSC FROM DUAL UNION ALL
    SELECT  8 AS KEY, 105 AS UD, TO_DATE('02/15/2009','MM/DD/YYYY') AS START_DT, TO_DATE('03/01/2009','MM/DD/YYYY') AS END_DT, 'UD105' AS DSC FROM DUAL UNION ALL
    SELECT  9 AS KEY, 105 AS UD, TO_DATE('04/01/2009','MM/DD/YYYY') AS START_DT, TO_DATE('05/30/2009','MM/DD/YYYY') AS END_DT, 'UD105' AS DSC FROM DUAL
  )
  select  t1.ud,
       t1.key, t1.start_dt, t1.end_dt,
       t2.key, t2.start_dt, t2.end_dt
  from     test_data t1
  ,     test_data t2
  where     t1.ud = t2.ud
    and     t1.key < t2.key
    and     ((t1.end_dt - t1.start_dt) + (t2.end_dt - t2.start_dt)) >
          (greatest(t1.end_dt, t2.end_dt) - least(t1.start_dt, t2.start_dt))
  /
  

  Result:

          UD        KEY START_DT   END_DT            KEY START_DT   END_DT
  ---------- ---------- ---------- ---------- ---------- ---------- ----------
         103          4 13-03-2009 30-03-2009          5 13-03-2009 01-04-2009
         104          6 13-03-2009 30-05-2009          7 25-02-2009 29-05-2009
  

  In addition, you will need to adjust the date a little comparison, depending on whether you set two periods where the first End_date is equal to the start_date in the second, because duplication or not.

  Published by: tijmen on December 21, 2009 06:17

• I forgot to turn on the firewall

  After updating Adobe Flash, I forgot to re - activate my firewall. I checked it after noticing that a number of Web sites, I have visited not appeared in my web browser (Firefox). It was late, so I've re-enabled the firewall, turn off my iMac and went to bed. The next morning, I'm sending you this from my iPhone. How can I tell if there is malicious software on my iMac?

  Oh! I've also been alerted by a friend that she had an email 'me' which of course was not

  Help!

  marsue

  Try to run this program, copy and paste the result in a response. The program was created by Etresoft, a regular contributor.  Use please copy and paste the screenshots can be difficult to read. On the screen with the Options, please open Options and tick the boxes in the bottom 2 before the race. Click on the button "Report share" in the toolbar, select "Copy to Clipboard" and then paste into a response. This will show what is running on your computer. No personal information is shown. Alternatively, you can run Malwarebytes.

  Etrecheck - Information System

  10.8 Malwarebytes Anti-Malware for Mac and later versions

  What should I do if Malwarebytes Anti-Malware for Mac does not solve my problem?

• Firefox 36.0.1 problems with addon and MP sent after notification of the firewall on Win7

  Yesterday, I had a problem after clicking on 2 or 3 times to open the firewall et seq. asked to unlock even if I did a long time ago. I'm not an admin, but I know that the local administrator password that allows me to put things in the control panel. After what's happened alert HitmanPro cannot load on FF opening; PIX downloaded with Picture Picker addon are not saved in the destination folder, even if the message indicates that they are registered and also I can't send pms in some sites. I don't know what other damage is done.

  It seems that the bug in the picture picker is because the new FF updated (it works in it), it is the same with Facebook album downloader. There are numerous answers in their pages. MP is a temporary problem, and IMHO, all the things that I've met are because the update. I would ask some mod to close my question.

• Firefox Beta 36 requires to define the parameters of the firewall to startup every time

  Beta 36 for Firefox from a few days ago asking to add an exception to the OSX Firewall to startup every time. Even if I accept and enter my administrator credentials. Also if I add Firefox to the standing of firewall settings. He never asked me before the latest beta version.

  I use 10.10.2

  FredMcD said

  Some problems occurs when your Internet security program has been implemented.
  trust the previous version of Firefox, but not more acknowledges your
  update as being approved. Now how do I solve the problem: to allow
  Firefox to connect to the Internet

  • Make sure your Internet security software is up-to-date (for example, you are using the latest version).
  • Delete Firefox to list your program of programs approved or recognized. For detailed instructions, see

  Configure the firewall so that Firefox can access the Internet. {web link}

  Thanks for the reply, but it's fixed now with a new beta 37.0

  The previous version of Firefox has not solved even after that I removed and then Firefox again added to the firewall exceptions list.

• Remove the firewall

  Hello

  in the firewall settings is a list of allowed connections.

  As I have latest granted these connections I want to delete them, but no idea how to do that these connections are not in the list of output connection.

  Hint please?

  

  In the case where if you do not want to allow all incoming connections the box block all incoming connections, stealth mode and click ok.

• El Capitan screen sharing does not connect to less than the firewall disabled

  I reinstalled my Mini to El Capitan server and I can not connect via screen sharing. Screen sharing is enabled and the application firewall indicates incoming connections to it are allowed. But the customer never connect unless I turn off the firewall. Sniffing the network says that port 5900 is the problem, but I see no way to specify ports in the application firewall. I do not use the Adaptive firewall, and I don't see anything in the config of pf which would block 5900. This machine is on the public network, I can't throw without a firewall, but I can not understand how to sort goes with her.

  Firewall of Apple's specific app, not specific port

  using a network utility or the wall of the fire out of 3rd?

  If so, uninstall them to test.

  If this isn't something else between your mac and their computer may contribute to cause as the public network itself.

• last version of Firefox can not ensure a secure connection without disabling the firewall, why?

  I've upgraded to the latest version of Firefox and now whenever he goes to a secure connection, it debits far and doesn't connect or said that the connection was refused. I'm under Firewall PC Tools and strangely when I turn off the firewall, it connects. I don't really like it. I tried to remove Firefox to the list of applications and add new, but it did not help.

  One possible cause is security software (firewall) that blocks or limits Firefox or plugin-container process without informing you, possibly after the detection of changes (update) for the Firefox program.

  Delete all rules for Firefox and the plugin-container in the permissions list in the firewall and leave your firewall again ask permission to get full unlimited access to the internet for Firefox and the plugin-container and the update process.

  See:

  • https://support.Mozilla.org/KB/server+not+found
  • https://support.Mozilla.org/KB/firewalls

• By the numbers, how do the list tables on the side?

  By the numbers, how do the list tables on the side? It used to be on the side, now it is on the top which is a huge pain.

  This changed in the transition from Numbers2.x too 3.x.

  Unless you explicitly removed numbers 2.x, it is always installed and usable on your computer.  You can locate it in the folder "/ Applications/iWork ' 09.

  You should be aware, that numbers 2.x cannot open files saved numbers 3.x - you can export files from Numers3.x back to Numbers2.x by using the item of menu numbers 3.x "file > export to > number ' 09»

• cannot access the internet through firefox, IE is ok, checked the firewall settings and network

  Have used firefox for ages w / no problem - this morning, firefox will not have internet access - modem and the router are fine, inernet explore what access very well. Firefox is configured to use the system, not considered proxy settings 'no proxy', has not worked, checked windows and Mcaffey firewalls, not found something that should be blocked. Have restarted/rebooted everything

  This has happened

  Each time Firefox opened

  This moringing - last successfully used there - 3: 00 children asks that they "did nothing...". »

  User Agent

  Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 1.1.4322; .NET CLR 2.0.50727; .NET CLR 3.0.4506.2152 .NET CLR 3.5.30729)

  They did something with firefox 3.6.8, which upsets the McAffee Firewall currently. Since the upgrade, I get the firewall Alerts pop ups. If you click on the block (which could have your children), then Firefox will be blocked completely.

  If you dig in the McAffee Firewall tools-> program authorities, you will likely find that Firefox listed as "blocked."

  On my machine, the entry is for 'Free' only and I now get alerts. I think they will disappear if I switch it to "Full". But I'm reluctant to do this, why a browser should accept incoming connections, why this change has been made and what benefit is it for us as users?

• expand the category drop-down list table in the model of checkbook

  Using version 2.3 of numbers 09.  Try to understand the model section for checkbook and to expand the available categories in the menu drop-down allows to assign a category to an entry in the checkbook.  Where would we go to learn this procedure.

  Hi Robert,.

  This is as good one place as any.

  If you have started using the model and have defined categories for all operations, make changes to the cells in these rows. Fill the pop-up menu edited cells wil also reset the value of each cell filled to the currently selected value in the source cell to this filling.

  Add new categories to a cell in the context menu

  In the Transactions table, click any cell to the row and column reference tabs appear.

  Line control grip (red arrow in the image below) and drag to the bottom to add a new line. The new line will contain a new copy of the cell from the popup menu in the category column. Click this cell to select it.

  In the bar of buttons above the workspace, click the Inspector button to open the Inspector, and then click the format cell [42] button to go to the cell format Inspector.

  You will see the list of the menu items for the selected cell. The list below are a pair of buttons marked + and - (blue arrow). To add a new item to the menu, click on the button +.

  

  The new item appears at the bottom it has the list, with its highlighted text as shown. Type the new category name.

  Repeat for as many new features that you need.

  You can also edit the items already in the list.

  Double-click an existing item to select the text. Type the new name for the item.

  When you are finished, close the Inspector.

  The menu changes are applied immediately and affect only the menu in the modified cell, and cells, this version of the menu is filled in. If you add a new line to the bottom of the table, for example, the edition menu of line 15 will be filled in the new line.

  Add a new category to the account categories table

  The new category is not automatically added to the category table account. When you add it, ensure that there is an exact match between the label of the table and the category in the menu.

  Click any cell in the account categories table to select it.

  Enter the line control handle and drag down to add as many lines as necessary.

  Note that the totals in a footer line moves down and the new lines are added above it.

  Fill in the new lines of the new category (or categories). *

  If you have completed transactions for these categories, these will be totaled in the B column and adds the total in the footer line, but not yet appear on the pie chart.

  

  Add the new categories on the pie chart

  Click the pie chart to select it and show its data source.

  

  Data for the graph comes from the cells defined by the selection (in blue) rectangle. The cells shown in white on a background come from the chart legend labels black in column A of the table in the colors of the wedge can be seen in the box beside the category name (and can be changed by clicking on the box, and then choosing a new color in the fill color in the toolbar).

  To add the new category to the table, place the mouse pointer on the small handful (circle in the lower right corner of the selection rectangle. When the pointer changes into a Black plus sign, click and drag down to lock the new categories, which will be instantly assigned a color and added to the graph.

  Click anywhere outside the objects onscreen to deselect all objects, and then save your work.

  * To ensure matched spelling between the menus and the list of categories, select one of the new cells of menu and copy. Select one (or all) cells new category on the table of the types of accounts and paste. Specify each menu to the new categories, and then select all the cells in the new category. In the format of cell Inspector, use the context menu to change the format of these cells to the text. This removes the attribute from popup menu of the cells, leave the text as it was when the last value.

  Kind regards

  Barry