Condition in the order by clause?
Hellomy version of db is,
Oracle9i Enterprise Edition Release 9.2.0.8.0 - Production
select a,b,c,d,sum(e) from f group by a,b,c,d order by a,b,c,d
select a,b,c,d,sum(e) from f group by a,b,c,d order by b,a,c,d
How to get there?
Good help will be appreciated.
Concerning
Sankar MN
Published by: SankarMCA on October 5, 2010 04:51
Hello
You can use CASE expressions in the ORDER BY clause.
For example:
ORDER BY CASE
WHEN a = 1 THEN b
ELSE c
END
, CASE
WHEN a = 1 THEN c
ELSE b
END
, d
Tags: Database
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I was expecting this:
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SET VARIABLE QUERY_SRC_CD = "report"; SELECT s_0, s_1, s_2, s_3, s_4 s_5, (FROM s_6)
SELECT
s_0 0,.
CAST (NULL AS VARCHAR s_1 (1)).
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1 s_0
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HI mbengue,.
Check the report you are running any column presentation sorted in the user interface (in which case the order by clause will creep into generated sqls Physics). Also, I think that its worth it to check the settings of the hierarchy you have configured and if the installation program for the calculation of the measured column (number of students in this case), has been done correctly.
Kind regards
Arko
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How does the order by clause in oracle 10G?
Hi This is my table called Master.I want to order by sno. so I run the below mentioned query.
SNO DESC STIME, ETIME CCODE ADD SID
11 11 11 1 10 s11
1 1 s1 09:00 12:00 10
2 2 s2 06:00 07:00 9
3 3 S3 9:00 23:00 0
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SNO DESC STIME, ETIME CCODE ADD SID
1 1 s1 09:00 12:00 10
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I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.user10566312 wrote:
I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.It is a good point that many developers are not so aware. As far as I understand it the way it works.
Some analytical functions do not need an order by or windowing clause (SUM, COUNT, MIN, etc.). If there is no specified window, then the full score is the window.
As soon as you add a command also add you a windowing clause. This window has the default value of 'rank ofrowsbetween unbounded preceding and current_row. So as soon as you add an order by clause, you get a sliding window.Documentation: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm
windowing_clause
...
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Hello
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Select r.firstname, r.lastname, (e.distance/e.duration) from Runner r Inner Join r.event e Order BY (e.distance/e.duration) Desc;
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javax.servlet.ServletException: java.lang.IllegalArgumentException: an exception occurred while creating a query in EntityManager:
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DB version: 10 gr 2
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For the below SQLs' schema SCOTT, result sets are always classified according to the first column ename. When I added use asc and desc of employment, does not change the result set.
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SQL> create table test_order (name varchar2(10), surname varchar2(10), age number); Table created. SQL> insert into test_order values('Kamran','Agayev',26); 1 row created. SQL> insert into test_order values('Kamran','Taghiyev',26); 1 row created. SQL> insert into test_order values('John','Kevin',23); 1 row created. SQL> select * from test_order; NAME SURNAME AGE ---------- ---------- ---------- Kamran Agayev 26 Kamran Taghiyev 26 John Kevin 23 SQL> select * from test_order 2 order by age; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Agayev 26 Kamran Taghiyev 26 SQL> select * from test_order 2 order by age asc, surname desc; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Taghiyev 26 Kamran Agayev 26 SQL>When in the second query, I sorted out only for age, you saw it there two 26 years old Keita, there was first Agayev, then Taghiyev. But if I want to get the family names in descending order when there are two very old person, then I will add the second column in the order by clause
- - - - - - - - - - - - - - - - - - - - -
Kamran Agayev a. (10g OCP)
http://kamranagayev.WordPress.com -
process of execution of the order by clause
What is the process of execution of the order clause in the sql statement and how it will affect the performance of the query.Siddharth Singh says:
What is the process of execution of the order clause in the sql statementDepends on. First of all, that you mean "alrogithmically, how Oracle data products ordered"? There are a number of different approaches. Data can be ordered as you pick up sequentially from an index. Or it can be explicitly materialized and sorted.
and how it will affect the performance of the query.
Depends on. There could be no impact because it relies on the index to classify the data and index is the most effective path independently of the presence of an ORDER BY. Or it could require a huge amount of time to materialize and sort several GB of data.
Justin
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Problem in the SQL because of the order by clause
Hi all
I am facing a problem in a sql query. I use Oracle 10 g 2.
Query is given below:
The query Plan is:SELECT t1.ename FROM T1, T2 WHERE T1.EMPNO = 1234 AND T1.ACCOUNTNO = T2.ACCOUNTNO AND T1.SEQ = T2.SEQ ORDER BY T2.SEQ
Now, I want to reduce the time of this request..---------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ---------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 2 | 218 | 11716 (1)| 00:00:41 | |* 1 | TABLE ACCESS BY INDEX ROWID | T1 | 1 | 89 | 1 (0)| 00:00:01 | | 2 | NESTED LOOPS | | 2 | 218 | 11716 (1)| 00:00:41 | |* 3 | TABLE ACCESS BY INDEX ROWID| T2 | 2 | 40 | 11715 (1)| 00:00:41 | | 4 | INDEX FULL SCAN | PK_T2_SEQ | 58752 | | 122 (5)| 00:00:01 | |* 5 | INDEX RANGE SCAN | FK_ACCOUNTNO | 3 | | 0 (0)| 00:00:01 | ----------------------------------------------------------------------------------------------------
If I remove order by clause query that the query performance is quite perfect, but with order by clause its take time.
I already set SORT_AREA_SIZE, but still nothing improves.
Welcome and thank you for your suggestions.
Thank you
Published by: BluShadow on June 23, 2011 07:55
addition of {noformat}{noformat} tags and formatted explain plan to make it readable. Please see {message:id=9360002} for details on how to post code and dataHey, a quick test, try:
select ename from ( SELECT t1.ename, T2.SEQ FROM T1, T2 WHERE T1.EMPNO = 1234 AND T1.ACCOUNTNO = T2.ACCOUNTNO AND T1.SEQ = T2.SEQ and rownum > 0) ORDER BY SEQAmiel Davis
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WITH the ORDER BY clause and bug SDO_GEOMETRY?
I'm having a problem using SDO_GEOMETRY in a WITH clause. Specifically with ORDER BY. I'll show a shortened version of SQL here. I'm doing something wrong or is this a bug?
It works:
After the statement select in a with clause, this does not work, which gives an identifier not valid "SDO_GEOMETRY" ORA-00904:SELECT loc.location_id, SDO_GEOM.SDO_DISTANCE(cent.lat_long, MDSYS.SDO_GEOMETRY ( 2001, -- SDO_GTYPE attribute: 2 in 2001 specifies dimensionality is 2. '4326', SDO_POINT_TYPE(-78.6386145, 35.772096, NULL), NULL, NULL ), 0.01, -- tolerance 'unit=mile') result_center_distance FROM location loc JOIN centroid cent ON loc.centroid_id = cent.centroid_id ORDER BY result_center_distance
If I duplicate the function of the distance in the ORDER BY, it works:WITH location_distance AS ( SELECT loc.location_id, SDO_GEOM.SDO_DISTANCE(cent.lat_long, MDSYS.SDO_GEOMETRY ( 2001, -- SDO_GTYPE attribute: 2 in 2001 specifies dimensionality is 2. '4326', SDO_POINT_TYPE(-78.6386145, 35.772096, NULL), NULL, NULL ), 0.01, -- tolerance 'unit=mile') result_center_distance FROM location loc JOIN centroid cent ON loc.centroid_id = cent.centroid_id ORDER BY result_center_distance ) SELECT * from location_distance
WITH location_distance AS ( SELECT loc.location_id, SDO_GEOM.SDO_DISTANCE(cent.lat_long, MDSYS.SDO_GEOMETRY ( 2001, -- SDO_GTYPE attribute: 2 in 2001 specifies dimensionality is 2. '4326', SDO_POINT_TYPE(-78.6386145, 35.772096, NULL), NULL, NULL ), 0.01, -- tolerance 'unit=mile') result_center_distance FROM location loc JOIN centroid cent ON loc.centroid_id = cent.centroid_id ORDER BY SDO_GEOM.SDO_DISTANCE(cent.lat_long, MDSYS.SDO_GEOMETRY ( 2001, -- SDO_GTYPE attribute: 2 in 2001 specifies dimensionality is 2. '4326', SDO_POINT_TYPE(-78.6386145, 35.772096, NULL), NULL, NULL ), 0.01, -- tolerance 'unit=mile') ) SELECT * from location_distanceThis is a bug. But it is set to 11g R2. Note that this is not a space bug, but a bug in generic compilation.
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passing parameters in the order by clause of the cursor
Hi friends,
I am facing a strange problem
I have a cursor with an order by clause.
OPEN FOR Cursor_nomrpt
SELECT DISTINCT
CAST (plano.desc3 AS VARCHAR2 (50)) category
plano.name plan_name
, chip nvl (CAST (plano.desc6 AS VARCHAR2 (50)), 'not applicable')
, nvl (trunc(plano.value18,2), 0) nominal_slm
, nvl (trunc(plano.value19,2), 0) blm
plano.dbdateeffectivefrom date_live
,
Plano.DBKEY pog_id
, case when plano.value47 < 0 THEN 0 when plano.value47 IS NULL THEN 0 ELSE plano.value47 END as parent_id
Of
Plano dplapro1.ix_spc_planogram
INNER JOIN dplapro1.ix_spc_performance ON plano.dbkey = perf.dbparentplanogramkey perf
Produces INNER JOIN dplapro1.ix_spc_product ON perf.dbparentproductkey = product.dbkey
INNER JOIN dplapro1.ix_spc_product_key ON product.dbkey2 = prodkey.dbkey prodkey
AND prodkey.keylevel = 2
WHERE
Plano.value50 = 0
AND plano.dbkey4 = p_subcatkey
ORDER BY ltrim (rtrim (p_orderby)) CSA;
p_orderby is the parameter that is passed. But the result is not sorted. But when I run the cursor to hardcode the value of parameter, that it works fine...
Need your help on thisHello
When you use a local variable in a cursor, it's as if you had hard-coded literal in its place, you cannot use a variable to a column name.
If you know all the possible values for p_orderby, you can do something like this:
... ORDER BY TRIM ( CASE p_orderby WHEN 'DESC' THEN plano.desc WHEN 'VALUE' THEN plano.value ... END ) ASC;If you don't know not all possible values, you can use dynamic SQL statements.
By the way
TRIM (x)Returns the same results as
LTRIM ( RTRIM (x)) -
Error because the ORDER BY clause
Hi gurus
I have this formula for a formula column
function CF_PREVIOUS_QUANTITY returns the number is
quantity number;
Start
SELECT QUANTITY_REMAINING IN the amount
Of
(
SELECT
QUANTITY_REMAINING
Of...
WHERE THE...
-ORDER BY trx_date DESC
)
WHERE rownum = 1;
return quantity;
end;
Copy the following code compiles only if COMMAND LINE is commented out, otherwise I get this:
Met the ORDER symbol when waiting for him...
The code compiles ok in SQLDeveloper. I want to just get the first record in a recordset.
What's not here?
I use 6-speed
Thanks in advance
OscarA problem of M - to-1.
try either:
... (- preferred)
for (SELECT in c
QUANTITY_REMAINING
Of...
WHERE THE...
ORDER BY trx_date DESC) loop
Return c.QUANTITY_REMAINING;
end loop;... (- awkwardly)
SELECT QUANTITY_REMAINING IN the amount
Of
(SELECT QUANTITY_REMAINING
(
SELECT
QUANTITY_REMAINING
Of...
WHERE THE...
ORDER BY trx_date DESC
)
WHERE rownum = 1
); -
How to use the order by clause
Hi Al
order_tracker1 is a tabular_block that I use this to search I want to order by when I search by serch_value
Please guide
The code given is used to find
declare
l_where varchar2 (4000);
Start
If: search_type = "ALL" then
l_where: = ' id | party_name | COMMENT1 | del_date like "%' | : serch_value | » %''' ;
on the other
l_where: =: search_type |' as "%' | : serch_value | » %''';
end if;
set_block_property ('order_tracker1', default_WHERE, l_where);
go_block ('order_tracker1');
execute_query;
end;
Thanks and greetings
Vikas SinghalHai,
Change the line set_block_property ('order_tracker1', default_WHERE, l_where); TO
set_block_property ('order_tracker1', default_WHERE, l_where |) "order by serch_value");
or in time design, you can give in the palette of the ORDER BY Clauesproperty.
or you can write to set_block_property (ORDER_BY, 'order_tracker1', 'serch_value');
Kind regards
Manu.
If this answer is useful or appropriate, please mark. Thank you.
-
That's what I'm trying to someone can help me with that: -.
create table test (env varchar (05), dbname varchar (08), priority varchar (05))
Insert into test values ('prod', 'proddb1', 'C');
Insert into test values ('train', 'traindb1', 'C');
Insert into test values ('train', 'traindb1', 'H');
Insert into test values ('prod', 'proddb1', 'W');
Insert into test values ('test', 'testdb1', 'C');
Insert into test values ('test', 'testdb1', 'W');
Insert test values ('prod', 'proddb1', ' don't);
Insert into test values ('dev', 'devdb1', 'H');
Insert into test values ('dev', 'devdb1', 'C');
Insert into test values ('prod', 'proddb1', 'H');
Insert test values ('train', 'traindb1', ' don't);
Insert into test values ('dev', 'devdb1', 'W');
Insert test values ('test', 'testdb1', ' don't);
Insert into test values ('train', 'traindb1', 'W');
Insert test values ('dev', 'devdb1', ' don't);
I'm trying to get an output format like this below someone can help me: -.
PRIORITY OF THE ENV
----- --------
prod C
Test C
C train
Dev C
prod W
train W
test W
dev W
prod:
train:
H-test
dev:
prod N
N train
test N
dev Nselect env, priority from test order by decode(priority,'C',1,'W',2,'H',3,'N',4);You could order env also by a decoding, but I do not see a specific sequence in the output.
Once 'test' is before 'train', another time 'train' is of 'test '.
If you want to 'train' before 'test', it looks like this:select env, priority from test order by decode(priority,'C',1,'W',2,'H',3,'N',4), decode(env,'prod',1,'train',2,'test',3,'dev',4);When there are other values for env or priority scheduling of these values would be undefined for the latter.
Published by: hm on 06.10.2011 02:23
-
How to use the "Order by" clause dynamically on values LOV Forms 10g r2
Hello
I have following requirement, please guide me.
1. create a list of values with 2 fields, Code and Description
2. do not use the command clause contained in the registration request Group
3. fix this LOV on a form field
4. when the user calls the user LOV will see two fields in LOV with header as Code and Description
5. when the user clicks the column header "Code" then LOV should be arranged on Code
6 and if the user clicks on the header of the column "Description" then LOV must be sorted on the Description
Thanks in advance.Please post this problem in this forum->
[Formulas Forum | http://forums.oracle.com/forums/forum.jspa?forumID=82]
And close this thread by he scored as replied. ;)
Kind regards.
LOULOU.
-
order by clause based on the value of the parameter
Hello
I use reports 6i with db 10 g
I need to create a report sorted in the order of four fields. There is a field selection parameter which should come first in the order by clause.
IE the user has available to display the report in a sorted order selected
Assume that the four fields are emp_id, name, dept_id desig.
If the user selects dept_id, then the order by clause should be in order of dept_id emp_id, name, desig
Please help solve this scenario.
Thank youHi Clement,.
Use the query as follows:
select column_name1, column_name1, .... from table_name &order_by_clauseNow in the trigger AFTER-PARAMETER-SHAPE has the order by clause below according to requirements:
if :sort_column = dept_id then :order_by_clause := 'order by dept_id,emp_id,name,desig'; else :order_by_clause := 'order by emp_id, dept_id, name,desig'; end if;Here's sort_column setting user who will be selected by the user, provide the list of values for it.
Hope this helps
Best regards
Arif Khadas
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