Connect by - no start Query

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• Understanding "CONNECT BY" and "START WITH".

  OK, I'm trying to update the rows with values determined by lines joined in a recursive relationship of unknown depth. I am told that "CONNECT BY" and "START WITH" can be useful in this, but I don't see how to get the value I'm looking for.
  
  In my case, there are 3 values in my table.
  ID
  ID of the parent
  Invoice
  
  On some lines, the Bill is null. For records, you get the ID of the invoice by searching for the invoice of the parent folder. I'm trying to update the table so that all THE rows in the table have an ID of invoice.
  
  Here is an example of table and the lines.
  

  CREATE TABLE DISTRIBUTION (
  ID            INT,
  INV_NUM       INT,
  PARENT_ID     INT
  )
  
  INSERT INTO DISTRIBUTION 1, 111, NULL;
  INSERT INTO DISTRIBUTION 2, 112, NULL;
  INSERT INTO DISTRIBUTION 3, NULL, 2;
  INSERT INTO DISTRIBUTION 4, 113, NULL;
  INSERT INTO DISTRIBUTION 5, NULL, 4;
  INSERT INTO DISTRIBUTION 6, NULL, 5;
  INSERT INTO DISTRIBUTION 7, NULL, 6;

  What I would do is update the inv_num column in the table so that a select statement * would look like this...
  

  ID        INV_NUM    PARENT_ID
  -----     -------------     ---------------
  1            111           null
  2            112           null
  3            112              2
  4            113           null
  5            113              4
  6            113              5
  7            113              6

  You can provide any help would be greatly appreciated.

  Hello

  Thank you post the CREATE TABLE and INSERT instructions, but please make sure that they work.
  None of the INSERT statements; I think you meant something like the statements shown after the query.

  Here's a way to get the desired results:

  UPDATE  distribution     m
  SET     inv_num = ( SELECT  inv_num
                FROM    distribution
                WHERE   CONNECT_BY_ISLEAF     = 1
                START WITH     id          = m.id
                CONNECT BY     id          = PRIOR parent_id
                         AND     PRIOR inv_num     IS NULL
                 )
  WHERE   inv_num       IS NULL
  ;
  

  This statement is Bottom-Up of subqueries, where we START WITH the lines that need to update, and process to the top of the tree, until you get to an ancestor who was an inv_num.
  In your sample data, only the roots (the lines that have no parents) have inv_num. In this case, it might be a little easier (but only a little) to make a request from top to bottom , where we START WITH the roots and low process in the tree to find their subordinates.
  If we add some data examples where a nonroot has inv_num:

  INSERT INTO DISTRIBUTION (id, inv_num, parent_id) VALUES ( 91, 910,   1);
  INSERT INTO DISTRIBUTION (id, inv_num, parent_id) VALUES ( 92, NULL, 91);
  

  What results would you like?
  Using the UPDATE statement above, id = 92 would get his inv_nuym of the closest ancestor (in the case of thios, parent) who had an inv_num:

  .       ID    INV_NUM  PARENT_ID
  ---------- ---------- ----------
           1        111
          91        910          1
          92        910         91
           2        112
           3        112          2
           4        113
           5        113          4
           6        113          5
           7        113          6
  

  Either the row with id = 92 gets inv_num = 910, no 111.

• WiFi connects immediately after starting

  Hello community,

  I started having Wifi issues after installation LittleSnitch. It would be irrelevant, but that's when the problem appeared. Although I have already removed, the Wifi connection does not seem to operate normally.

  Before that, it would connect immediately after starting, which means instant access to Chrome or any other browser.

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  I tried several solutions spare, change my location, manual settings, DHCP or DNS, wifi diagnostics, reset my router, but all without success. I still can't get it to connect at the same time.

  Any ideas?

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  Please read this message before doing anything.

  This procedure is a diagnostic test. It is unlikely to solve your problem. Don't be disappointed when you find that nothing has changed after you complete it.

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  Disconnect all devices wired except those required to test and remove all the expansion cards from secondary market, as appropriate. Start in safe mode and log on to the account of the problem.

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  Test in safe mode. Same problem?

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• No instant Wlan connection at the start of the Satellite L650

  Hello

  I had connection problems with my Toshiba L650 during the past two months.

  I bought my laptop about a year ago (October 2010), and everything worked perfectly until April 2011.
  The first months, my computer will automatically connect to the internet once it starts.

  From April 2011, my computer takes about 2 minutes to connect to a wireless internet connection when I start it, either my home connection or connection.
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  The problem is not a wireless router because it happens with all wireless connections. Also, I tried to update the drivers for the network card wireless (Broadcom 802.11n) no success at all.

  I would be grateful if someone could provide possible solutions to the problem.
  Thanks in advance.

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  The WiFi network connects well, but it takes two minutes until the connection has been established?
  Right?

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  The game may 17, 2012 03:43:10 + 0000, BIGKEV2257 wrote:

  I am not satisfied by McAfee, three days and three nights, waiting for their technicians to ring me, I get automated emails asking if I'm happy and saying that they can not communicate with me, seems since Mr. McAfee sold his company, that it went to the pack, and I understand not why Microsoft sell McAfee with new computers when mcAfee are not appropriate technical support.

  Two points:

  1. in my opinion and that of many others of us here, McAfee is one of
  the poorest choice of security these days software here. I strongly
  recommend you take and replace with eSet NOD32 or
  Kaspersky, if you are willing to pay for it. If you want a free
  antivirus, I recommend one (do not run more than one antivirus
  program) of three of the following:
   
  Avira AntiVir
  Avast
  Microsoft Security Essentials
   
  You also need anti-spyware software (even if you run a program such as)
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  It). I recommend that you download and install MalwareBytes (freeware)
  AntiMalware
  2 Microsoft isn't selling McAfee with new computers. Microsoft
  is not even do or do not sell computers. If your computer comes with
  McAfee, it's because the manufacturer of your computer (Dell, HP,
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  Can the vcenter server that an ESX host is connected to determine through query of the esx host cmd line?

  All points will be awarded. Thxs.

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• Hierarchical connect by and start with and joined?

  I have an Employees table and a table of identifiers. The table of identifiers is hierarchical, with parents and children. Each employee has one or more identifiers, but that a unique identifier is considered to be the "primary" or root for each employee identifier. Unfortunately, the employee table can point to one of the children identifier lines and not the root. I need a quick query to reach employees with their most recent ID (root).
  
  Here's the code to define the problem.

  create table employees (employeeid varchar2(8), fakeNationalID varchar2(9), empname varchar2(30));
  insert into employees (employeeid, fakeNationalID, empname) values (1,'001000001','John Smith');
  insert into employees (employeeid, fakeNationalID, empname) values (2,'002000002','James Jones');
  
  create table realids (realidkey NUMBER, fakeNationalID VARCHAR2(9) not null, 
     realNationalID VARCHAR2(9) UNIQUE, parent_realidkey number);
  insert into realids (realidkey, fakeNationalID, realNationalID, parent_realidkey) values
     (1,'001000001','111111111',3);
  insert into realids (realidkey, fakeNationalID, realNationalID, parent_realidkey) values
     (2,'002000002','222222222',null);
  insert into realids (realidkey, fakeNationalID, realNationalID, parent_realidkey) values
     (3,'003000003','333333333',null);
  commit;   
  
  create or replace function get_parentid (fakeID in VARCHAR2) return varchar2 is
     tempid VARCHAR2(9);
     begin
        select realNationalID into tempid 
           from (
             select realNationalID, fakeNationalID
                from realids
                start with fakeNationalID = fakeID
                connect by nocycle prior parent_realidkey = realidkey
                order by level desc)
                where rownum = 1;
        return tempid;
        exception 
           when NO_DATA_FOUND then
              return NULL;
           when others then raise;
      end;
  
      
  select get_parentid('001000001') from dual; -- returns 333333333 because its linked to a parent
  select get_parentid('002000002') from dual; -- returns 222222222 because there is only one child
  select get_parentid('003000003') from dual; -- returns 333333333 because it is the parent

  What I want is to put the parent node above realids for each line of employees...
  
  It works, but it is NOT very effective:

  select employeeid, get_parentid(fakeNationalID) realid, empname from employees;
  employeeid   realid       empname
  ----------   -----------  ------------
  1            333333333     John Smith
  2            222222222     James Jones

  You can imagine what it would be like with 100K lines or more. It takes about 3 minutes to run.
  
  It seemed like a good way to do it, but with a sub query.

  select e.employeeid, e.fakenationalid, e.empname, sub.realnationalid
     from employees, 
        (select realidkey, fakenationalid, realnationalid, parent_realidkey
           from realids r
           start with r.fakenationalid = e.fakenationalid
           connect by prior r.parent_realidkey = r.realidkey) sub

  Unfortunately, it produces an invalid identifier on e.fakenationalid (in the beginning with the clause).
  
  Anyone has any ideas on how to get top most parent node of the realids for each row in the employees table? In real life, there are 6 or more employees tables across multiple remote instances of what children in the realids table and how much to the parents. We always want the highest parent of the page realid. Any help would be appreciated.

  Hello

  Thanks for posting the sample data in a convenient form!
  It is always useful to post your version of Oracle, too, especially when it comes with CONNECT BY queries.

  What follows is what you asked for in Oracle 10:

  WITH     got_roots   AS
  (
       SELECT     CONNECT_BY_ROOT     fakenationalid     AS leaf_id
       ,     realnationalid
       FROM     realids
       WHERE     CONNECT_BY_ISLEAF     = 1
       START WITH      fakenationalid IN ( SELECT  fakenationalid
                                            FROM    employees
                             )
       CONNECT BY     realidKEY     = PRIOR parent_realidkey
  )
  SELECT     e.employeeid
  ,     r.realnationalid
  ,     e.empname
  FROM     employees     e
  JOIN     got_roots     r     ON     r.leaf_id     = e.fakenationalid
  ;
  

  In any query, call a function defined by the user for each line is going to be slow. Fortunately, Oracle now has the built-in functions and operators that can take the place of get_parentid. The CONNECT_BY_ROOT operator, which was introduced in Oracle 10, is the key to the problem. In Oracle 9, you can get the same results using SYS_CONNECT_BY_PATH.

  It is generally faster to CONNECT BY query separately, and then join some other tables you need for results.

  You had a good idea in your last query. The problem was that void and employees were equal tables in the FROM clause, and you cannot establish a correlation between equals. You can only correlate a subquery to its Super application. You could make to this general idea work by changing void in a scalar sub-requete, which can be connected to the employees, but I think it would be much less effective than what I posted above.

• Performance issue with connection of a level query

  Hi I have a problem with connection by level in oracle.
  
  My table is:
  
  
  J_USER_CALENDAR
  --------------------------
  
  USER_NAME FROM_DATE TO TO_DATE COMMENTS
  -------------------------------------------------------------------------------------------------
  Comment1 5 November 09 uma Shankar 2 November 09
  Veera 11 November 09 13 November 09 Comment2
  Commnet3 17 December 09 uma Shankar 15 December 09
  Vinod 20 October 09 21 October 09 Comments4
  
  
  The table above is the calendar of user authorization.
  
  Now I need to view the users who are on leave between November 1, 2009 to November 30, 2009
  
  The output should look like:
  
  
  USER_NAME FROM_DATE COMMENTS
  ---------------------------------------------------------------------------------
  Comment1 2 November 09 uma Shankar
  Comment1 3 November 09 uma Shankar
  Comment1 4 November 09 uma Shankar
  Comment1 5 November 09 uma Shankar
  Comment2 Veera 11 November 09
  Comment2 Veera 12 November 09
  Comment2 Veera 13 November 09
  
  For this, I tried with the following query, but it takes too long to run.
  Select FROM_DATE, user_name, comments from (SELECT distinct FROM_DATE, user_name,
  Comments FROM (SELECT (LEVEL) + FROM_DATE-1 FROM_DATE, TO_DATE, FIRST_NAME |) » '|| LAST_NAME
  user_name, COMMENTS OF J_USER_CALENDAR
  where
  and J_USER_CALENDAR.IS_DELETED = 0
  CONNECT BY LEVEL < = TO_DATE - FROM_DATE + 1) has) where ("FROM_DATE = 1st November 2009 ' or FROM_DATE = November 30, 2009")
  or FROM_DATE between November 1, 2009 "-November 30, 2009") order of from_Date, lower (user_name)
  
  Please help me.
  
  Thanks in advance.
  
  Kind regards
  Phanikanth

  I have not tried to analyze the SQL statement.

  Here is a test set in place:

  CREATE TABLE T1(
    USERNAME VARCHAR2(30),
    FROM_DATE DATE,
    TO_DATE DATE,
    COMMENTS VARCHAR2(100));
  
  INSERT INTO T1 VALUES ('Uma Shankar', '02-Nov-09','05-Nov-09','Comment1');
  INSERT INTO T1 VALUES ('Veera','11-Nov-09','13-Nov-09','Comment2');
  INSERT INTO T1 VALUES ('Uma Shankar','15-Dec-09','17-Dec-09','Commnet3');
  INSERT INTO T1 VALUES ('Vinod','20-Oct-09','21-Oct-09','Comments4');
  INSERT INTO T1 VALUES ('Mo','20-Oct-09','05-NOV-09','Comments4');
  
  COMMIT;
  

  Note that I have included an additional line, when the person starts their vacation in the previous month and ends in November.

  You could approach the problem like this:
  Assume that you want to appear every day in a given month:

  SELECT
    TO_DATE('01-NOV-2009','DD-MON-YYYY')+(ROWNUM-1) MONTH_DAY
  FROM
    DUAL
  CONNECT BY
    LEVEL<=ADD_MONTHS(TO_DATE('01-NOV-2009','DD-MON-YYYY'),1)-TO_DATE('01-NOV-2009','DD-MON-YYYY');
  

  Note that the above attempts to calculate the number of days in the month of November - if we know that the month has a certain number of days, 30 for example, you can rewrite the CONNECT BY clause like this:

  CONNECT BY
    LEVEL<=30
  

  Now, he must pick up lines of interest to the table:

  SELECT
    *
  FROM
    T1 T
  WHERE
    (T.FROM_DATE BETWEEN TO_DATE('01-NOV-2009','DD-MON-YYYY') AND TO_DATE('30-NOV-2009','DD-MON-YYYY')
      OR T.TO_DATE BETWEEN TO_DATE('01-NOV-2009','DD-MON-YYYY') AND TO_DATE('30-NOV-2009','DD-MON-YYYY'));
  
  USERNAME        FROM_DATE TO_DATE   COMMENTS
  --------------- --------- --------- ----------
  Uma Shankar     02-NOV-09 05-NOV-09 Comment1
  Veera           11-NOV-09 13-NOV-09 Comment2
  Mo              20-OCT-09 05-NOV-09 Comments4
  

  If join us then both sets of results, we have the following query:

  SELECT
    *
  FROM
    T1 T,
    (SELECT
      TO_DATE('01-NOV-2009','DD-MON-YYYY')+(ROWNUM-1) MONTH_DAY
    FROM
      DUAL
    CONNECT BY
      LEVEL<=ADD_MONTHS(TO_DATE('01-NOV-2009','DD-MON-YYYY'),1)-TO_DATE('01-NOV-2009','DD-MON-YYYY')) V
  WHERE
    (T.FROM_DATE BETWEEN TO_DATE('01-NOV-2009','DD-MON-YYYY') AND TO_DATE('30-NOV-2009','DD-MON-YYYY')
      OR T.TO_DATE BETWEEN TO_DATE('01-NOV-2009','DD-MON-YYYY') AND TO_DATE('30-NOV-2009','DD-MON-YYYY'))
    AND V.MONTH_DAY BETWEEN T.FROM_DATE AND T.TO_DATE
  ORDER BY
    USERNAME,
    MONTH_DAY;
  
  USERNAME        FROM_DATE TO_DATE   COMMENTS   MONTH_DAY
  --------------- --------- --------- ---------- ---------
  Mo              20-OCT-09 05-NOV-09 Comments4  01-NOV-09
  Mo              20-OCT-09 05-NOV-09 Comments4  02-NOV-09
  Mo              20-OCT-09 05-NOV-09 Comments4  03-NOV-09
  Mo              20-OCT-09 05-NOV-09 Comments4  04-NOV-09
  Mo              20-OCT-09 05-NOV-09 Comments4  05-NOV-09
  Uma Shankar     02-NOV-09 05-NOV-09 Comment1   02-NOV-09
  Uma Shankar     02-NOV-09 05-NOV-09 Comment1   03-NOV-09
  Uma Shankar     02-NOV-09 05-NOV-09 Comment1   04-NOV-09
  Uma Shankar     02-NOV-09 05-NOV-09 Comment1   05-NOV-09
  Veera           11-NOV-09 13-NOV-09 Comment2   11-NOV-09
  Veera           11-NOV-09 13-NOV-09 Comment2   12-NOV-09
  Veera           11-NOV-09 13-NOV-09 Comment2   13-NOV-09
  

  Charles Hooper
  IT Manager/Oracle DBA
  K & M-making Machine, Inc.

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