Conversion of 3 bytes in an I32

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• conversion of 4-byte float

  Hi all

  I work with microcontrollers PIC (slaves masters + 6) RS485 network. I intend to replace the master with some hardware which would be installed LabVIEW. I already managed to put together test vi on PC with adapter USB-FTDI-RS485 WE, who is able to communicate with a slave. Slave is responsible for the consumption of electricity and water meassuring in my house.

  The problem is in the conversion of data from recived tabular byte float form, it is not precise enough. Attached photo shows what aro bytes for each variable and also shows what is correct values for kWh, but also for the m3. Please check also part VI, where conversion takes place. Juice have in mind that Microchip has diferent IEEE754 standard, where the sign bit is shifted with the Exhibitor in one place.

  Any suggestions or advice would be very appreciated.

  Best regards, Vlado

  California_J wrote: instead, it is used Microchip conversion where the side MSB eight bits are used for exponent, then a sign bit and rest of 23 as before same bits for the mantissa.

  So this should work for you, once you get the 4 bytes.

  

• String equal?

  I have an instrument that communicate with the PC via RS232. So I use VISA write, read...

  It works OK, but have the following problem

  I want to compare two strings, one is constant other out by VISA read. If I use the indicator, this is the show "hexagonal"(par exemple 3E04 4B73) the value of VISA, but if I use the same wire to the 'equality?' to compare two strings is strange... return values ".

  We see them all together to see what my problem is:

  

  A string is an array of bytes interpreted as text characters.

  If the string that appears as '3E04 4B 73' mode normal consists of the characters '3' ASCII '0' ' E' '4' '' '4' 'B' '7' '3 '. The hexadecimal values in the ASCII characters are "3345 3034 2034 4237 33.  ASCII 3 = 33 hex.  ASCII E = 45 hexagonal.

  If you want to type in the hexadecimal values to a control of the chain or the constant, you must assign to the hex display.

  To see what is in a thread of string in a string to the conversion of primitive bytes and the wire table then said to a table indicator output.  This will show the numerical values of each byte of the string.  You can set the digital display to decimal, hexadecimal, octal, or binary.

  Lynn

• change the representation of the Golden Gate entries

  Hello

  I have a pair of enums U16 in my code I want to spend in a golden door. Is it possible to change the representation of the U16 GOLD door entry so that I do not need to use a conversion function or the forced to I32?

  Dave

  I don't know why it converts in I32, but if you explicitly convert enums U16, then there is no constraint, and the output is U16. The value should not be changed, because enums are already U16.

• NULL padded string

  I need to create a completed chain so by 0x00 if the length is not met.

  sample

  length = 30

  entry = 123456

  should look like this in hexadecimal

  0 x 3132 3334 3536 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000

  display or ' / '.

  123456\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00\00

  tried to "format string" either won't work for padding with 0x00 or I'm not formatting correctly

  Jeff· Þ· Bohrer says:

  Paul good idea!

  Very good idea.  Except, I just use instread replace substring of the conversion of a byte array and vice versa.

  

• float to bytes conversion using c code in labview

  Mr President, I made the taste of the float to bytes conversion using type cast in labview. now I want that conversion using the code c. means I want to know that how labview can suport code c. farmula node is not suporting my code which is working wel in labwindows. kindly help me on this subject so that my skil can be improved using labview

  The node of the formula as its name suggests is to facilitate the access of the algebraic formulas in text form and uses a C like syntax, but is in no way a fully featured parser/compiler. It supports only a subset of the syntax of C for obvious reasons. Why would you need to implement entire code C in LabVIEW for LabVIEW program supports the same functions and to do it with LabVIEW nodes, you will always have better performance you can get in the formula node.

  If you have real C code you wish to call in LabVIEW you use the node form but create a DLL from it and call it via the node library call.

• conversion of existing databases to code on several bytes

  We have existing database facilities and because we'd spend our forms application on several bytes for the support of the Chinese characters, we understand that the database must be changed to manage them as well. Is there a way to 'upgrade' of existing databases to multibyte ability or you have to do a new installation of database software? In addition, we plan to 11g R2 ranging from 10g R2 databases. What would be the best order to do these two things in? We do the first multibyte character conversion, or can we take a standard database configuration export and import directly into an installation of 11g multibyte characters? Suggestions for the documentation to read would be greatly appreciated!
  
  Thank you for your help.
  Stacey

  Hello

  You can find some information on the Migration of the character value on the link below:

  http://download.Oracle.com/docs/CD/E11882_01/server.112/e10729/ch11charsetmig.htm#NLSPG011

  And Upgrade Guide:

  http://download.Oracle.com/docs/CD/E11882_01/server.112/e10819/TOC.htm

  Otherwise, it is possible to migrate to Unicode and Oracle 11.2 in a step by export/import.

  It is recommended to use DataPump instead of the utility former import/export. More, if you migrate to Unicode, the character AL32UTF8 set is better rather than the UTF8.

  Hope this helps.
  Best regards
  Jean Valentine

• float to bytes conversion using labview

  in the project of the University to number of float serialy using labview. I don't know how to convert his individual bytes actualy I want to encode float in its float bytes. kindly help me in this regard

  Send "bytes" is usually done in the form of strings. Just use catalogued with the disconnected type entry (or use "flatten chain").

  To get started, simple would be to use the finder example in LabVIEW and search for serial communications.

• Binary 8-bit digital conversion to a string of bytes 1

  Hello..

  I want to convert a binary number to 8 bits for hex string.

  Examples;

  binary - 00000000-> 00 (Hex)

  binary - 11110000-> F0 (Hex)

  binary - 01110000-> 70 (Hex)

  And the STRING of the hexagon is 1 byte.

  I tried but its not showing the exact as string above.

  Help, please.

  I have attached the VI.

  Hi Pascal,.

  Cannot open your VI here, but your question translates this excerpt:

  

• convert I32 U8

  Hello

  I have a problem during the conversion from my table.

  I have a table 1 d of 32-bit integers for a long time.

  I would like to convert a table 1 d of the 8-bit byte unsigned integers.

  I try to use the conversion u8 block, but the result I get is a 1 d table that I accepted, but all my item values are transformed into zero rather than keep the original.

  can someone help me?

  Hi koekie,.

  (1) you will have problems to convert I32 numbers greater than 255 (or smaller than 0) U8 values, both get forced to the U8 line possible!

  (2) you don't say you are trying to convert the values.

  (3) are you really want to convert your table instead of convert? What kind of result data do you really need?

• Conversion of QuickTime is eating hard drive space?

  So I thought I'd go through some old video files on an external drive, so when I found and tried to open them by default - open with Quicktime Player because they were .mov files. But when opening them that forced me to convert first, which took some time, but it was very good. After viewing the file, I have it closed and he could be invited to record the conversion, but I said no every time.

  Dozens of video clips later, I received a warning that my hard drive is running out of space even though I was not downloading anything. Of course, I'm up to 1 GB, even if I don't know I got a lot more than this, perhaps 20, but at least 10gbs before starting. I don't know Quicktime is somehow to blame, and whenever I try to open a .mov file and it begins to convert, I actually see my free disk space down a bit like 1.35 GB GB 1.06 to 53KO to zero bytes. However, now it crashes towards the end by saying: he can't open the clip, even if the conversion is almost over, and then my disk space back to about 1.35 GB. However, on my most recent test it is simply suspended zero byte. I quit the program and am currently stuck at zero-byte and get the impossible to open again message clip.

  I was able to open the same .mov files in VLC without problem. I tried to use OmniDiskSweeper to find where these ghosts files could be but nothing extraordinary appears. I can't find all the physical files that QuickTime can be created on my hard drive, unless I'm looking in the wrong places...

  I'm currently under OSX Yosemite v10.10.5 and Quicktime v10.4.

  If someone could help me please understand this point, I would be very happy. Thanks for reading this.

  If someone could help me please understand this point, I would be very happy.

  To start, I remember not where temporary files of conversion are stored by the system or if this location varies for different operating systems from the user. Basically, the problem is self-inflicted. When you refuse to save the file after the conversion, the reference of the source file ends up stored in your list of 'Récent' without for as much free disk space used to store the converted data. Try to access the data already converted via the "open the recent item" option will restart just another conversion of the same file. On the other hand, you had actually stored the converted file, you may have deleted or moved to an external drive for future use. Fortunately, if your system works like mine, there may be another way to reclaim the space for temporary storage consumed by conversions without having to know where temporary data is stored. Simply try to empty your "Récent" list by pressing the option "delete". Then watch the space window of Finder reading for a short period, while to see if the OS is recover storage space that has been allocated to the converted data. It worked for me under El Capitan, when I reset my normal 'None' setting return to the default value of '10' and ran some tests to try to reproduce your problem.

  

• BUG: Split then join reverse byte order - sometimes

  I created a simple to serialize an array of bytes I32 and fell VI on this interesting bug. This code runs in 32-bit SP1 of LabVIEW in 2014, fully patched. Save the parts two attached and run TestI32ToByteArray.vi. Note that the 6 and 7 at the end of the table are reversed. If you explore the data around, everything looks good except the string split on the last low word is reversed. Any ideas?

  More details on the installation program:

  LabVIEW 2014 SP1 32-bit

  AMD FX - 6300 3.5 GHz processor hexagonal

  Windows 7 64 - bit, fully patched

  8 GB RAM

  Check your wiring, 6 is connected to a lower bound of the join, and 7 is wired to the top.

• Visa reading reads all bytes to the port

  I have a camera that I communicate via the Serial Port. I have a standard communications protocol. For a particular command, I know that the exact number of bytes expected in return. I send my order. I see the correct number and exepcted to bytes in the port. I then read the number of bytes in the port. However, the VISA read returns only the first two bytes.

  I contacted success with this camera and this Protocol for more than 130 commands unique and different. There are only about 6 orders in which the read visa does not read all the bytes in the port. Anyone know why that would happen?  I expect to see 6 bytes. I see 6 bytes. I have visa read the command with 6 bytes. The visa read returns only the first 2 bytes. It's very very frustrating. I can do this exact process even with a different command. I expect 45 bytes of this command. I see 45 bytes with this command and I read 45 bytes with this command.

  I don't think that it is device connected as I can converse with success with the same camera on the same computer with the same cable of connector using non-LabView. It seems to be a problem strictly related to labview and VISA read the order. If someone could help that would be greatly apprecicated.

  Thank you.

  What is the exact byte stream that await you in return with this command?

  Instead of opening VISA, use the configuration Serial Port VI.  In this way, you can override the default values.  It looks that your instrument using all the defaults VISA of speed in baud rate, start and stop bits, etc.  However, in the VISA software, there is a failure to use a termination character, and this character is 10 (0x0A).  If you use the configure Serial Port, you can tell the pilot VISA do not use the stop character.

• Divide the 16-bit words in his HI and LO bytes, then convert it to ASCII?

  Hello

  I'm doing the mentioned action:

  Divide the 16-bit words in his HI and LO bytes, then convert it to ASCII

  I downloaded the .zip file and got the files .lks and .l4t... I don't know what are these files?  Where can I find just a VI for what I want to do?

  If someone has one, let me know!

  Thank you

  Danny

  Danny,

  Look at the sections of Data Manipulation and Conversion of the Digital Palette. Burst and array of bytes to a string number are your friends.

  

  In regards to the files, you will need to know the file formats. I never heard of one of those, and a search in the file don't produce something useful.

  Lynn

• How to reverse a byte?

  What I want to do sounds just so far, but I can not find a solution that can be as simple as that...

  I have a byte array, for example: 1101 1010 and I would reverse like this: 1011 0101

  I have not found the VI to do. I think this isn't a Big/Little - endian issue. I have an idea on the conversion of byte in a string and use the string changes VI. Then return to byte, but it is not optimized.

  You have any ideas?

  Thanks for the help!

  xela75,

  Looks like you want to reverse the order of the bits of a U8?  If so, try this.