Converting a string to a Date using an insert after trigger.

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• How convert the string in enum by using LabVIEW 7.0

  I learned LabVIEW 8.6, but here at work, so we must use the Solaris workstations built in 95, the more advanced version of LV they will work is version 7.0.  On LV8.6, it was very to change a string to an enum using the format 'text' vi.  On LV7.0, is not available.  I made my own conversion from type vi with a structure of the case, but this is very annoying, because every time I add an element to the enum, I must add something to this vi.  I added the verification code so there is a warning if I add to the enum, but don't forget to update of the conversion of the vi errors.  Is it possible to reproduce the "text format" vi, using LV7.0?

  

  The analysis of primitive string will do the job in LV7.0.  Its a darn good idea to create a control of the enum type-def you use! If the constant and the witness are instances of your type definition, when you change the control (add, delete, rename, swap values) you can press the button to change to apply and PRESTO all your commands, constants and indicators that use the def type are updated with new info.

• [Oracle 8i] How to convert a string (timestamp) in a date?

  I find it difficult to know how to convert a string to a date time stamp (or possibly several).
  
  The timestamp is 20 positions, character (NOT NULL, CHAR (20))
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  Hello

  As Damorgan said, if all you want to do is find which is the earlier or later, then you can just compare the strings: they are in a format where it works.

  If you need to do other things, such as compare to today date or see the difference between two of your lines of days, you will need to convert it to date. (He has no reason to convert them to numbers).

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  (1) ignores the microseconds, or
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  Whatever it is, use TO_DATE to convert the first 14 characters in DATE:

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          )
  

  where txt is your column of type CHAR.
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• Converts a string to a problem posed by the

  Hello!
  
  I get an ORA-01861: "literal does not format string" when you try to convert a string
  on a date.
  
  Currently stored as VARCHAR2
  

  14SEP11

  Should be

  to_date(start_op, 'DD-Mon-YY HH24:MI:SS') AS FORMATTED

  Date format

  NLS_DATE_FORMAT                DD.MM.RR 

  user545194 wrote:
  Hello!

  I select the column name:

  select to_date(start_op, 'DD-MON-YY') AS FORMATTED from table
  

  Column name: start_op

  A conversion problem?

  SQL> create table otn(p_date varchar2(7));
  
  Table created.
  
  SQL> insert into otn values('14SEP11');
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> select to_date(p_date,'DDMONYY') from otn;
  
  TO_DATE(P
  ---------
  14-SEP-11
  
  SQL> 
  
  SQL> alter session set nls_date_format='ddmonyy';
  
  Session altered.
  
  SQL> select to_date(p_date,'DDMONYY') from otn;
  
  TO_DATE
  -------
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  SQL> 
  

• How do to convert the string (with the Hex data) in number?

  Hello

  I use TestStand 3.5 to automate a few test cases associated with boot loader.

  The requirement is that I need to read the value in some places for specific address. The values of these addresses are stored in a hexadecimal format.

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  Try: Val ("0 x" + Locals.Value_Read)

• Converting a string to date

  I run the following select statement in Oracle SQL Developer.
  
  Select I_NOTE_DESIGS. ENDDATE AS END_DATE
  
  However in my results date hows as 1 April 29.
  
  I was wondering if there is a way to convert this course to another date string that is to say: I would like that the date of this column to show 2029-04-01. I'm not bothered if the time out at the end, as I have a program that can remove.
  
  Kind regards
  
  Jon Ditchfield

  948083 wrote:
  I run the following select statement in Oracle SQL Developer.

  Select I_NOTE_DESIGS. ENDDATE AS END_DATE

  However in my results date hows as 1 April 29.

  I was wondering if there is a way to convert this course to another date string that is to say: I would like that the date of this column to show 2029-04-01. I'm not bothered if the time out at the end, as I have a program that can remove.

  Kind regards

  Jon Ditchfield

  [url http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions200.htm#SQLRF06129] TO_CHAR

• How to convert a string and use a rope as a property?

  I have an array in the following format:

  {ownsCar: 'true', ownsBike: 'true', ownsHouse: 'true'}

  {ownsCar: ownsBike 'false',: 'true', ownsHouse: 'true'}

  {ownsCar: 'true', ownsBike: ownsHouse 'false',: 'true'}

  etc ............

  And I need to test against each element, for example

  If...

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  If...

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  How to convert the string (for example, "ownsCar") in a property "myProperty"?

  Thanks in advance

  Chris

  OK, if I got this right what you need to do is introspection.

  The easiest way to do this would be:

  for ( var propertyName:String in myObject ) {
       // Do what you need with this here:
       myObject[ propertyName ];
  }
  

• Converts a string fragment file values

  Function wich use to convert the string fragment values?

  I have this string in the file:

  Instrument: NOR-DAQ; Date: 01-10-2008;
  Quantity: voltage [V];
  Results: 1.23,3.45,5.65,6.89,...;

  And I need to values - 1.23,3.45,5.65,6.89

  Hi crisdragon,

  You must use the native LabVIEW file and the string API.

  I gave you an example.

  Hope this helps.

• Converts a string (float single precision) in decimal

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  I use reading series base and write vi to communicate with a device.  The answer I receive (shown in hexadecimal format) is 4606 8D3B, which from what I understand (this discussion: http://forums.ni.com/t5/LabVIEW/string-to-number-conversion-a-very-interesting-observation/m-p/32170... ) the data is not actually hexadecimal but rather binary and appears just hex for the user.

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  Any help would be appreciated, thanks

  Alex

  Try this:

  

• Spreadsheet string table / why data medium becomes zero

  Hello

  I converted an array of 3 x 2 to 2 x 3 table with table 2D to transpose, then I used "table to a spreadsheet string" vi to convert my table from 2 x 3 to a string. The string format is %f. The table consists of numbers and the text as:

  frequency capacitance resistance
  100                  10                     100

  When I try to write data to the file text the number in the Middle becomes 0. I used probes for debugging. I discovered that the problem is in the output of the 'picture to a worksheet string' vi.  The input data (which are a 2D table) are ok, but out (which is a string), the average data are zero! I can not find the reason.

  Thanks in advance for your help

  The problem lies in the scale of your value.  Primary parameter is 14.5, which rounds to zero because it is rounded to 6 decimal places and pico is too small.  Use %g instead of %f for your format code.

  I do not understand why you generate values at the ends of the empty table.  A lot of this manipulation of cluster and table seems unnecessary.

  I removed the while loop and the agilent Subvi is so I could run this.  But basically your code can be disassembled for this.

  

  PS: because you have attached the code, we could zoom in and see that the problem was with the size of your data, that we couldn't see on the initial partial screenshot of the code.

• Converting a string to an array of integers (ints)

  I need to do ot an app that will read in numbers, or data means, in a text file on an SD card and then convert them in a line graph. Currently I am able to read the contents of a text file and store it as a string with this code

   private String readTextFile(String fName) {
          String result = null;
          FileConnection fconn = null;
          DataInputStream is = null;
          try {
            fconn = (FileConnection) Connector.open(fName, Connector.READ);
            is = fconn.openDataInputStream();
            byte[] data = IOUtilities.streamToBytes(is);
            result = new String(data);
          } catch (IOException e) {
            System.out.println(e.getMessage());
          } finally {
            try {
             if (null != is)
  
              is.close();
             if (null != fconn)
              fconn.close();
            } catch (IOException e) {
             System.out.println(e.getMessage());
            }
          }
          return result;
          }
  

  I am able to print the result of the chain of my test file so it prints something like "1 2 3 12 14 2 42.

  What I want to do convert this string to an array of int that will look like int [] result = {1, 2, 3, 12, 14, 2, 42}.

  I tried to use string.split("") as this seems to be what is generally done when I have the problem of google. When I try this however I get an error "the split (String) method is not defined for the String type.

  I just want to know if there is a way to convert this string to an array of integers (ints), or maybe is it possible to change my readTextFile method so that it will display the data in a table or working with the array of bytes to get distinct integers.

  Hi try this

• AF:convertDateTime converts the year 19xx when you use the format of year 2 figures

  Hello
  
  I have a page with a single inputText field with an oracle.jbo.domain.Date as a value and an af:convertDateTime as a date converter. date converter has a secondary ground of "mmddyy". the problem is that when I type a date using the secondary model, and year to date is after 49, then af:convertDateTime photos 19xx as year-round; not 20xx. It works up until 1950. between 1950 and up to 99 it converts in 19xx.
  
  I have read a document that 1950 is used by default by oracle.adf.view.faces.converter.DateTimeConverter to convert strings to date, but this can be changed in a document called adf-faces - config.Xml. I looked for the document but could not find it. Can someone tell me where is the document or if it has been replaced by something else?
  
  This is where I found the information: [http://download.oracle.com/docs/cd/B31017_01/web.1013/b28967/appendixa011.htm#BABHCEJE]
  
  
  This is the code in the page:
  
  * < af:inputText label = "Label 1" id = "it1' autoSubmit ="true"partialTriggers = value =" #{pageFlowScope.MyPb.date "it1"} "> *.
  <!-af:convertDateTime fails year after 50-> 19xx
  * < af:convertDateTime pattern = "MM/dd/yyyy" secondaryPattern = "MMDDYY" / > *.
  < / af:inputText >
  
  Thank you
  
  Abraham
  
  Published by: Abraham Ciokler, March 17, 2011 09:11
  
  Published by: Abraham Ciokler, March 17, 2011 09:12

  What you hear, you can't find where is adf-faces-config. XML?

  What version of JDeveloper? If you're on 11g, you want to use Trinity - config.XML - documentation you accessed is for 10 g

  http://MyFaces.Apache.org/Trinidad/DevGuide/configuration.html

• How to convert a string literal function function valid

  Hello
  
  I have a situation where I need to get the built-in (sysdate/sysdate-1/sysdate-2) as variables. As the variable is taken as a string, it is considered as a string, not a function. Is it possible to convert the string literal in valid function.
  
  Here is an example for better understanding. I used v_var to store the 'sysdate-1 "in the form of string literal. Try to change the value.
  
  
  */*-------------------------------------------------------------------------------------*/*
  declare
  
  v_var varchar2 (20): = ' sysdate-1';
  date of v_var2;
  
  Start
  
  Select v_var in the double v_var2;
  
  dbms_output.put_line ('v_var2: ' | v_var2);
  
  end;
  
  */*-------------------------------------------------------------------------------------*/*
  
  
  Thanks in advance

  Or

  SQL>  var str varchar2(20)
  SQL>  exec :str := 'sysdate - 1'
  PL/SQL procedure successfully completed.
  
  SQL>  select trim(dbms_xmlgen.getxmltype('select ' || :str || ' s from dual').extract('//text()')) str from dual
  /
  STR
  ------------------------
  15.07.09
  1 row selected.
  

• Convert the string with number of floats a number

  How to convert the string as "- 8.9E - 03" to a number of TestStand?

  Thanks in advance

  Hello

  Try to use the Val() function

  In the expression, it looks like this

  People of the country

  .nValue = val (Locals.strValue)

  Locals.nValue = Val("-8.9E-03")

  Hope this helps

  Jürgen