Copy of columns part 2 leaves to find various averages

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  Hi all
  
  I have a requirement to find a way to several columns in a row. The trickiest part is it may or may not be a value in each of the lines and the average must be calculated for those that have a value. Let me give you an example:
  
  col1 col2 col2, col4
  
  1 NULL 3 5-> average will be (1 + 3 + 5) / 3 = 3
  NULL NULL 2 4-> average will be (2 + 4) / 2 = 3.
  
  A (acc to me dump) option is to get the entire file in the variable % ROWTYPE, scan through each of the columns, see if the value is not null and greater than 0, increment the counter (i) and calculate the sum. Finally make a sum / I. An average was 215 columns that it takes on average and having a separate if end seems illogical. There must be a smart solution to find this kind of average. Help, please.
  
  Thank you
  Aristides

  Hey,.

  SELECT (nvl (col1, 0), nvl (col2, 0), nvl (col3, 0) + nvl (col4, 0)) / (nvl2 (col1, 1, 0) + nvl2 (col2, 1, 0) + nvl2 (col3, 1, 0) + nvl2 (col4, 1, 0))
  Table_name FROM

  I hope this helps.

  -Annick