Correct the e-mail validation

I have a textfield that accepts an email address.

I want to check for validation as soon as the focus of the text is lost.

Check the settings should be:

1. for example,[email protected]. Someemail here is the local part of the address, which typically identifies the user.

2. the local part cannot contain spaces (except if it is cited, which is rare, as in ' robert mitchell"@yahoo.com").

3. the local party also cannot contain special characters various, as the following: () <> , ' @:; \\ [ ].  If anyone tries to create an e-mail address that looks like <(([[))>@yoursite.com I want to reject outright.

4. the local part can and often it contains characters period, as in [email protected], but the periods must be preceded and followed by alphanumeric characters (that is, I can't use an email address for example[email protected]).

5. the domain may contain more than one period, as in [email protected], but it cannot begin or end with a period (as in [email protected]). [Finally, the guidelines permit but discourage a domain literal, as in robert@[192.168.33.12].

These are the criteria I want to check in my validation code.

I used this area at the present time. A label of the E-mail: and a box to contain input (editfield)

I know there is a

EmailAddressEditField

But it has very limited validation. If someone can guide in each of these methods, I would be grateful.

//Add box next to field for containing input of email
       HorizontalFieldManager hfm2 = new HorizontalFieldManager();
       LabelField lbl2 = new LabelField(" Email:                  ");

       final EditField TextField3 = new EditField()
       {

            protected void layout(int maxWidth, int maxHeight)
            {
                super.layout(Math.min(maxWidth, 300), Math.min(maxHeight, 20));
            }
            protected void paint(Graphics g)
                {
                         g.clear();
                        g.drawRect(0,0, 50, 50);
                        int oldColor = g.getColor();
                        g.setColor(Color.WHITE);
                        g.fillRect(0, 0, this.getPreferredWidth(), this.getPreferredHeight());
                        g.setColor(oldColor);
                        g.drawRect(100, 100, 50, 50);
                        super.paint(g);
                 }
        };
       TextField3.setBorder(BorderFactory.createRoundedBorder(new XYEdges(6,6,6,6)));
       hfm2.add(lbl2);
       hfm2.add(TextField3);
       add(hfm2);

Thank you.

Hi Tech

Try this function. may be useful for you.

public static boolean Emailval(String email)
    {
        if (email == null || email.length() == 0 || email.indexOf("@") == -1 || email.indexOf(" ") != -1) {
            return false;
        }
        int emailLenght = email.length();
        int atPosition = email.indexOf("@");

        String beforeAt = email.substring(0, atPosition);
        String afterAt = email.substring(atPosition + 1, emailLenght);

        if (beforeAt.length() == 0 || afterAt.length() == 0) {
            return false;
        }
        if (email.charAt(atPosition - 1) == '.') {
            return false;
        }
        if (email.charAt(atPosition + 1) == '.') {
            return false;
        }
        if (afterAt.indexOf(".") == -1) {
            return false;
        }
        char dotCh = 0;
        for (int i = 0; i < afterAt.length(); i++) {
            char ch = afterAt.charAt(i);
            if ((ch == 0x2e) && (ch == dotCh)) {
                return false;
            }
            dotCh = ch;
        }
        if (afterAt.indexOf("@") != -1) {
            return false;
        }

        for (int i = 0; i < afterAt.length(); i++) {
            char ch = afterAt.charAt(i);
            if (!((ch >= 0x30 && ch <= 0x39) || (ch >= 0x41 && ch <= 0x5a) || (ch >= 0x61 && ch <= 0x7a)
                    || (ch == 0x2e) || (ch == 0x2d) || (ch == 0x5f))) {
                return false;
            }
            if ((ch == 0x2e) && (ch == dotCh)) {
                return false;
            }
            dotCh = ch;
        }

        dotCh = 0;
        for (int i = 0; i < beforeAt.length(); i++) {
            char ch = beforeAt.charAt(i);
            if (!((ch >= 0x30 && ch <= 0x39) || (ch >= 0x41 && ch <= 0x5a) || (ch >= 0x61 && ch <= 0x7a)
                    || (ch == 0x2e) || (ch == 0x2d) || (ch == 0x5f))) {
                return false;
            }
            if ((ch == 0x2e) && (ch == dotCh)) {
                return false;
            }
            dotCh = ch;
        }
        return true;
    }

Thank you

Pawan

Tags: BlackBerry Developers

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