Count occurrences of matched words

Similar Questions

• Add the signature field to the second occurrence of two words (nieme Word) on the page

  
  I have a script that searches for two words ("APP ENG") on a page and adds a digital signature field.

  The trick is that there are two occurrences of these words and place the script in the field of digital signature on the first ocurrance of the two words.

  
  I need the digital signature script to add to the second occurrence of these two words.

  There was a counter added the script, but this place then the field on the word ("ENG"), it might have to do with the meter to count one word instead of two.

  
  If someone can help me to modify the script to count the words and the occurrences of two words instead of one word it would be most appreciated.

  Script as follows:

  
  var ckWords; pair of words to test

  var number = 0;

  numWords = this.getPageNumWords (0); number of words on the page

  loop through the words on the page

  for (var j = 0; j < numWords-1; j ++) {}

  get the pair of words to test

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (0, j + 1); test words

  If (ckWords == "ENG APP") {}

  Count += 1;

  If (count == 2) {}

  var q = this.getPageNthWordQuads (0, j);

  convert quads in the rotation by default user space

  Userspace used by links

  m = (new Matrix2D).fromRotated(this,0);

  mInv = m.invert)

  r = mInv.transform (q)

  r = r.ToString)

  r = r.split(",");

  var m = this.addField ("EngSignature", "signature", 0,

  ([r [0], [1] r, r [2], r [5]]) ;

  }

  }

  }

  Thank you.

  You must use the left coordinates of the first table and the right of the second table.

• How will I know what search fuzzy matching word

  I tried to find something about my problem, but research has resulted in no relevant thread. I do not use fuzzy to search text, but the names and I use it mainly to work even if the user misspelled the name of a resource.
  
  In order to set the search I want to know what the fuzzy search word was actually and what was the outcome for this match.
  
  So if I search for 'sumer' I get hit for "hot summer" and the relationship is clear. But if I get soon "swimming is not possible that the Summit ends" the blow is not clear more.

  You can use fuzzy with weight and use the partition function for the score. You can use ctx_doc.highlight to get the positions (offsets and length) of the matching words and then use it in a function in pipeline to return these words and this function in your query. Please see the demo below.

  -data and index table:

  SCOTT@orcl_11gR2> CREATE TABLE test_tab
    2    (test_col  VARCHAR2(46))
    3  /
  
  Table created.
  
  SCOTT@orcl_11gR2> INSERT ALL
    2  INTO test_tab VALUES ('warm summer')
    3  INTO test_tab VALUES ('soon swimming is not possible as summit closes')
    4  INTO test_tab VALUES ('other data')
    5  SELECT * FROM DUAL
    6  /
  
  3 rows created.
  
  SCOTT@orcl_11gR2> CREATE INDEX test_idx
    2  ON test_tab (test_col)
    3  INDEXTYPE IS CTXSYS.CONTEXT
    4  /
  
  Index created.
  

  -function

  SCOTT@orcl_11gR2> create or replace function get_words
    2    (p_idx          in varchar2,
    3       p_rid          in rowid,
    4       p_query      in varchar2,
    5       p_col          in varchar2)
    6    return          sys.odcivarchar2list
    7    authid          definer
    8    pipelined
    9  as
   10    v_hightab     ctx_doc.highlight_tab;
   11  begin
   12    ctx_doc.set_key_type ('rowid');
   13    ctx_doc.highlight (p_idx, p_rid, p_query, v_hightab);
   14    for i in 1 .. v_hightab.count loop
   15        pipe row
   16          (dbms_lob.substr
   17            (p_col,
   18             v_hightab(i).length,
   19             v_hightab(i).offset));
   20    end loop;
   21    return;
   22  end get_words;
   23  /
  
  Function created.
  
  SCOTT@orcl_11gR2> show errors
  No errors.
  

  -Research:

  SCOTT@orcl_11gR2> VARIABLE search_string VARCHAR2(100)
  SCOTT@orcl_11gR2> EXEC :search_string := 'sumer'
  
  PL/SQL procedure successfully completed.
  
  SCOTT@orcl_11gR2> COLUMN words FORMAT A15
  SCOTT@orcl_11gR2> SELECT SCORE(1), x.column_value words, t.test_col
    2  FROM   test_tab t,
    3           TABLE
    4             (get_words
    5            ('test_idx',
    6             t.ROWID,
    7             'FUZZY (?' || :search_string || ', 1, 5000, W)',
    8             t.test_col)) x
    9  WHERE  CONTAINS
   10             (t.test_col,
   11              'FUZZY (?' || :search_string || ', 1, 5000, W)',
   12              1) > 0
   13  ORDER  BY SCORE(1) DESC
   14  /
  
    SCORE(1) WORDS           TEST_COL
  ---------- --------------- ----------------------------------------------
          36 summer          warm summer
          12 summit          soon swimming is not possible as summit closes
  
  2 rows selected.
  

• Find the occurrence of the word in a list separated by commas

  Hello
  
  I need to find the first occurrence of a word in a list separated by commas.
  
  Example list:

  monster,daemon,shark,bambi,sky

  Now I'm looking for the word: bambi
  Result should be the first calculation of the event: 4
  
  Now I'm looking for the word: Monster
  Result should be the first calculation of the event: 1
  
  Hope you can help.
  
  Tobias

  Hi, Tobias,.

  This can be more efficient, because it does not use CONNECT BY or regular expressions. Instead of splitting the string to the level of every comma, just find the target string and count how many commas occur in front of her.

  WITH     got_found_pos          AS
  (
       SELECT     list_txt
       ,     INSTR ( ',' || list_txt || ','
                  , ',bambi,'
                  )          AS found_pos
       FROM    table_x
  )
  SELECT     list_txt
  ,     found_pos + 1
              - LENGTH ( REPLACE ( SUBSTR (list_txt, 1, found_pos)
                                    , ','
                           )
                    )          AS item_num
  ,     found_pos
  FROM    got_found_pos
  WHERE     found_pos     > 0
  ;
  

  Delimited lsits storage is usually a bad idea in a relational database. It is best to store each item in the list on a separate line.

• Get all occurrences of a Word.

  Hello
  
  Is it possible to find all occurrences of a word in a single document using Oracle text?
  
  Or maybe a count of how many times a word appears in a document?
  
  I had a glance at the documentation and the web and don't think it is, could anyone suggest a way to do this?
  
  Thank you very much
  
  Darren.

  Hello

  You can, as Roger said to use ctx_doc.tokens. This works if you already have a clue (text) on the document. You also have the option to use ctx_doc.policy_tokens. This does not have a clue, but needs a policy. The two proceedings are with examples in the Manual: [url http://download.oracle.com/docs/cd/E11882_01/text.112/e16593/cdocpkg.htm#CEGCIDAJ] package CTX_DOC.

  Herald tiomela
  http://htendam.WordPress.com

• Find the first occurrence of a Word

  I have a script which detects and counts all occurrences of a Word.

  I need the script to find the FIRST occurrence of a Word only.

  Can any advise please how do I change the script to find the first occurrence of the word?

  Script as follows:

  {

  numWords = this.getPageNumWords var (0);

  for (var i = 0; i < numWords; i ++)

  {

  var ckWord = this.getPageNthWord(0,i);

  If (ckWord is 'MATERIAL')

  {

  / * Script going here based on the finds the first occurrence of the word 'MATTER ' * /.

  }

  }

  }

  I tried var CKWord = this.getPageNthWord (0,0); but reports from the rear console is UNDEFINED?

  numWords = this.getPageNumWords var (0);

  var number = 0;

  for (var i = 0; i)
  var ckWord = this.getPageNthWord(0,i);
  If (ckWord == "ISSUED") {}
  Count ++;
  If (count == 2) {}
  var = this.mouseX Coord.

  var annot = this.addAnnot({)
  page: 0.
  type: "Stamp."
  name: "AppStamp."
  Rect: [coord + 1000, 2300, 30, 2820]
  rotation: 90,.
  ({AP: '#C94cHAFFa42U1gTH5Tug5C'});
             
  break;
  / * this.flattenPages (); */
  }
  }
  }

• Replace the last occurrence of a word in a string

  Hello

  I need to replace the last occurrence of a word in the string. Example of form:

  "I like fruits and vegetables as" need to replace the last occurrence of 'like' that is just before the vegetables and not 'as' before the fruit.

  Something like that!

  SELECT
      REGEXP_REPLACE('I like fruits and also like vegetables','like','hate',1,2) data_col
  FROM dual;
  

• How can I add a style "BOLD" grep on the first occurrence of a Word?

  Hi all

  I need help on adding a style "BOLD" grep on the first occurrence of a Word.

  I can add the "BOLD" to the word, but it adds to all occurrences, see below:

  GREP style (Incorrect)

  Apply Style: "BOLD"

  Text: \ < Lorem Ipsum\ >

  Nam Lorem Ipsum semper pellentesque tincidunt. UT nisi sit amet arcu nulla tristique dictum. SED commodo total non mauris cursus pretium. Lorem Ipsum Aliquam erat volutpat. Morbi id pretium justo. Nam lorem quis facilisis molestie risus fermentum. Vestibule ut sem elit. Nunc eget neque Sed elementum augue EU outbound.

  I need only the "BOLD" to add to the first occurrence of the word, as below:

  Nam Lorem Ipsum semper pellentesque tincidunt. UT nisi sit amet arcu nulla tristique dictum. SED commodo total non mauris cursus pretium. Lorem Ipsum Aliquam erat volutpat. Morbi id pretium justo. Nam lorem quis facilisis molestie risus fermentum. Vestibule ut sem elit. Nunc eget neque Sed elementum augue EU outbound.

  
  

  Thanks in advance for the help!
  

  This should do it for you

  Apply style

  "BOLD"

  text (? i) ^(.+?) Lorem Ipsum

  apply the stye

  Book

  text: ^. * ? (? = Lorem Ipsum)

  

  The first expression search all the text from the beginning of the parapgrah through the Lorem Ipsum

  The other defines the rest of the text before the Lorem Ipsum to the base style (book, novel, or whatever your basic style)

• Replacing the occurrences of a Word by links

  Hello

  I'm writing a Javascript script that should replace all occurrences of a word given in an Indesign CS3 document by a hyperlink pointing to a given URL.

  I am very new to Indesign scripting, and I don't know where to start. I tried searching this forum, but couldn't find the answer to my problem.

  If anyone can help...

  Thank you

  Bertrand

  You can use my findAndDo Script (the blog is in German): http://www.indesignblog.com/?p=7

  for a hyperlink, you need to change:

  app.changeGrepPreferences = NothingEnum.nothing;
  app.findGrepPreferences = NothingEnum.nothing;
  app.findGrepPreferences.findWhat = "SEARCH";
  var erg = app.activeDocument.findGrep ();     
  
  for (var i = erg.length - 1; i >= 0; i--) {
      var _hlinkSource = app.activeDocument.hyperlinkTextSources.add(erg[i]);
      var _destination = app.activeDocument.hyperlinkURLDestinations.add("http://www.google.de");
      app.activeDocument.hyperlinks.add(_hlinkSource, _destination);
  }
  

• Grep for styling the second occurrence of a Word

  Hi all

  I'm putting a dictionary for children.

  name of the bicycle

  a vehicle with two wheels in tandem, usually propelled by pedals attached to the rear wheel by a chain and have the handlebars for steering and a saddlelike seat. • Some find it faster to ride a bicycle and weaving through cars to take the bus or drive a private car.

  I managed to match the first occurrence of the bicycle to the second (underlined below) using the following grep.

  (?:^( \w+).+\r.+(\r.+)?) (\1)

  bike noun

  a vehicle with two wheels in tandem, usually propelled by pedals attached to the rear wheel by a chain and having the steering handlebars and a seat saddlelike. • some found it quicker to mount a bike and weaving through cars to take the bus or drive a private vehicle.

  This grep (that which) works as expected in the dictionary, but now I need to be able to select only the second word (in italics and in red in the example above) to be able to give him the correct character style.

  Any help would be greatly appreciated.

  Thanks in advance.

  Stephen

  GOAL!

  

  

• Firefox's search function seems to have become the HATS or caps-no specific, so that typing a word in non-caps will not find matching words with one or more uppercase letter.

  Find seems to have changed in Firefox. Before, when making a (CTRL + F) to find, research was not specific or non-specific to the caps CAPS. "In other words, if I typed in"firefox"(without ceiling), it will find the words"firefox,"Firefox", or "FIREFOX", regardless of capitalization. Now, however, the function finds will only match exact same capitalization. Totally, this undermines the usefulness of the service and is a major concern. Please fix.

  This has happened

  A few times a week

  == I noticed in during the two or two weeks.

  Make sure that the "match case" box in the find (Ctrl + F) bar is not activated.

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of your modules is causing your problem (switch to the DEFAULT theme: Tools > Modules > themes).
  See the extensions, themes and problems of hardware acceleration to resolve common troubleshooting Firefox problems and troubleshooting questions with plugins like Flash or Java to solve common Firefox problems

• match Word between two table

  Hello

  I want to retrieve those records where full word of the 'text' column does not match with the word in the column 'object' of another table.

  for example

  for id 101 table abc, it contains the Word as "Air Blow" which is exactly with 101 id of table of bcd. I don't want the case

  With abc as

  (

  Select 101 as id, "Air Blow" as double union text

  Select 102, 'Air' Union double

  Select 103, 'Sink' double union

  Select 104, 'Air press' Union double

  Select 105, 'Putting out fires' double

  ),

  BCD as

  (

  Select 101 as id, "Air blown near the mount" as subject, 'WE' as a double union countries

  Select 102, "Air breath seen here," 'China' of the double union

  Select 103, 'Throughput', 'canada' to double union

  Select 104, 'air pressure', 'UK' Union double

  Select 105, 'Fire engine', 'Ubdy' from dual

  )

  Select * from abc, bcd

  where abc.id = bcd.id

  and upper (abc.text) <>(bcd.subject) upper

  OUTPUT

  ID	TEXT	ID_1	Object	COUNTRY
  102	Air blown	102	Blowing air saw	China
  103	Water flow	103	Water flow	Canada
  105	Putting out fires	105	Firefighter	Ubdy

  Another corresponding original solution post results...

  SQL > ed
  A written file afiedt.buf

  1 with abc as)
  2. Select 101 as id, "Air BLOW" as double union text
  3. Select 102, 'Air' Union double
  4. Select 103, 'Sink' double union
  5. Select 104, 'Air press' Union double
  6 select 105, 'Fire extinguish' from dual
  7    ),
  8 bcd as
  9    (
  10. Select 101 as id, "Air blown near the mount" as subject, 'WE' as a double union countries
  11. Select 102, "Air breath seen here," 'China' of the double union
  12. Select 103, 'Throughput', 'canada' to double union
  13. Select 104, 'air pressure', 'UK' Union double
  14 select 105, 'Fire engine', 'Ubdy' from dual
  15)
  16. Select *.
  17 ABC join bcd on (abc.id = bcd.id)
  18 * where no regexp_like (bcd.subject, abc.text, 'i')
  SQL > /.
  TEXT ID COUNTR OBJECT ID
  ---------- --------------- ---------- ----------------------- ------
  102 air blowing here view China 102
  103 103 water flow flow of water canada
  Fire 105 105 fire Ubdy

  3 selected lines.

• Array of string to search for the exact match words

  I need to create a search feature.

  There is a textfield where the user will enter one or more words.

  Then I need to check if are any reference in the array of names.

  namesArray ["ocean in the sky", "cean on sky", "cean is white"];
  keywordsArray ["cean", "sky"];
  matchCounter = 0;
  

  If I entered the word "cean" I don't want in my results 'ocean in heaven', 'cean's heaven

  I have the following code:

  for (var j:int = 0; j < namesArray.length; ++j)
  {
       var tempStr:String = namesArray[j];
  
       for (var k:int = 0; k < keywordsArray.length; ++k)
       {                    
            if (tempStr.indexOf(arrayKeywords[k]) != -1)
            {
                matchCounter++;
            }
       }
  
       if(lengthKeywords == matchCounter)
                                {
            trace("yeahhh... there's a match!!");
       }
  
       matchCounter = 0;
  }
  

  Is there a better way? How can I do this?

  There are little things, but the main problem is that 'new RegExp()' needs double escapes ("\")

  ...
              var namesArray:Array = ["ocean in the sky", "cean on sky", "cean is white"];
              var keywordsArray:Array = ["cean", "sky"];
  
              for (var j:int = 0; j < namesArray.length; j++){
                  var matchCounter:uint = 0;
                  var tempStr:String = namesArray[j];
  
                  for (var k:int = 0; k < keywordsArray.length; k++){
                      var regExp:RegExp = new RegExp("(\\s+|^)" + keywordsArray[k] + "(\\s+|$)");  
  
                      if (tempStr.search(regExp) > -1){
                          matchCounter++;
                      }
                  }
  
                  if(keywordsArray.length == matchCounter){
                      trace("\"" + namesArray[j] + "\" matched all the keywords");
                  }
              }
  ...
  

  Traces:

  'cean on Sky' set match all keywords

• Procedure with the DML statements that insert values from 1 to 100 in only one table and it is matching word equivalent in the other

  Can someone help me create a procedure with the DML statements that insert values from 1 to 100 in a table "abc" and the procedure must connect the numbers into words in another table "xyz" without doing a commit explicitly. "."

  Currently on trial...

  SQL > create table abc (num number);

  Table created.

  SQL > create table xyz (num varchar2 (100));

  Table created.

  SQL > ed
  A written file afiedt.buf

  1. insert all
  2 values of 1 = 1 then in abc (num) (l)
  3 when the values of 1 = 1 then in xyz (num) (to_char (to_date(l,'j'), 'jsp'))
  4 * Select the level from dual connect by level<=>
  SQL > /.

  200 rows created.

  And the result...

  SQL > select * from abc;

  NUM
  ----------
  1
  2
  3
  4
  5
  6
  7
  8
  9
  10
  11
  12
  ..
  ..
  ..
  98
  99
  100

  100 selected lines.

  SQL > select * from xyz;

  NUM
  ----------------------------------------------------------------------------------------------------
  one
  two
  three
  four
  five
  six
  seven
  eight
  nine
  ten
  Eleven
  twelve
  ..
  ..
  ..
  98
  Nineteen eighty
  Cent

  100 selected lines.

• How to count the number of words in a string?

  It is only possible by counting the number of white spaces in the string?

  You can use the String.Split method to divide the string into an array using the character space as delimiter, and then check the length property of the resulting table.