match Word between two table

Hello

I want to retrieve those records where full word of the 'text' column does not match with the word in the column 'object' of another table.

for example

for id 101 table abc, it contains the Word as "Air Blow" which is exactly with 101 id of table of bcd. I don't want the case

With abc as

(

Select 101 as id, "Air Blow" as double union text

Select 102, 'Air' Union double

Select 103, 'Sink' double union

Select 104, 'Air press' Union double

Select 105, 'Putting out fires' double

),

BCD as

(

Select 101 as id, "Air blown near the mount" as subject, 'WE' as a double union countries

Select 102, "Air breath seen here," 'China' of the double union

Select 103, 'Throughput', 'canada' to double union

Select 104, 'air pressure', 'UK' Union double

Select 105, 'Fire engine', 'Ubdy' from dual

)

Select * from abc, bcd

where abc.id = bcd.id

and upper (abc.text) <>(bcd.subject) upper

OUTPUT

IDTEXTID_1ObjectCOUNTRY
102Air blown102Blowing air sawChina
103Water flow103Water flowCanada
105Putting out fires105FirefighterUbdy

Another corresponding original solution post results...

SQL > ed
A written file afiedt.buf

1 with abc as)
2. Select 101 as id, "Air BLOW" as double union text
3. Select 102, 'Air' Union double
4. Select 103, 'Sink' double union
5. Select 104, 'Air press' Union double
6 select 105, 'Fire extinguish' from dual
7    ),
8 bcd as
9    (
10. Select 101 as id, "Air blown near the mount" as subject, 'WE' as a double union countries
11. Select 102, "Air breath seen here," 'China' of the double union
12. Select 103, 'Throughput', 'canada' to double union
13. Select 104, 'air pressure', 'UK' Union double
14 select 105, 'Fire engine', 'Ubdy' from dual
15)
16. Select *.
17 ABC join bcd on (abc.id = bcd.id)
18 * where no regexp_like (bcd.subject, abc.text, 'i')
SQL > /.
TEXT ID COUNTR OBJECT ID
---------- --------------- ---------- ----------------------- ------
102 air blowing here view China 102
103 103 water flow flow of water canada
Fire 105 105 fire Ubdy

3 selected lines.

Tags: Database

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    INSERTION of REM in SEND_BILLS

    TOGETHER TO DEFINE

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

    Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

    I match all records of send_bills and received_bills with a status of 'SUCCESS' There is no single column in the table.

    Correspondence held payment of columns, the code and the scratch cards, but it may also duplicate records. But even if there are duplicates, I also need those records in the query results

    the query I wrote is this:

    SELECT SEND.*

    REC received_bills, send_bills send

    WHERE send.datum = rec.datum

    AND send.payment = rec.payment

    AND send.code = rec.code

    AND 'rec.status =' SUCCESS

    ;

    The query results give me this

    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 25 A5
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 25 A5

    The result of the correct application would be

    OCTOBER 10, 15 19 A1
    OCTOBER 10, 15 25 A5
    OCTOBER 10, 15 19 A1

    The select statement that I need I want to use a loop to insert records in another table.

    Can someone help me please?

    Thanks in advance.

    Best regards

    Caroline

    Want to get answers that work?  Then make sure that the CREATE TABLE and INSERT statements you post too much work.  Test (and, if necessary, correct) your statements before committing.  You have a stray "." in the first INSERT statement for received_bills and receikved_bills.status is defined as VARCHAR2 (5), but all values are 6 characters long.

    There are 5 lines in send_bills that are similar to the

    10 OCTOBER 2015 19 A1

    Why do you want that 2 rows like this in the output, not 1 or 3, or 4 or 5?  Is it because there are 2 matching rows in received_bills?  If so, you can do something like this:

    WITH rec AS

    (

    SELECT the reference, payment, code

    , ROW_NUMBER () OVER (PARTITION BY datum, payment, code)

    ORDER BY NULL

    ) AS r_num

    OF received_bills

    Situation WHERE = 'SUCCESS'

    )

    send AS

    (

    SELECT the reference, payment, code

    , ROW_NUMBER () OVER (PARTITION BY datum, payment, code)

    ORDER BY NULL

    ) AS r_num

    OF send_bills

    )

    SELECT send.datum, send.payment, send.code

    REC, send

    WHERE send.datum = rec.datum

    AND send.payment = rec.payment

    AND send.code = rec.code

    AND send.r_num = rec.r_num

    ;

    Note that the main request is very similar to the query you posted, but the last condition has changed.

    If you need to insert these lines in another table, you can use this query in an INSERT statement. There is no need of a loop, or for any PL/SQL.

  • Left join between two tables using two different conditions

    I have following three tables with their data, as shown below.

    CREATE TABLE TIREMASTERPROCESS_TEMP
    (
    PRODUCTIONCODE TANK (12 BYTES),
    FIELDNAME CHAR (12 BYTES),
    DATACHR VARCHAR2 (60 BYTE),
    REVISIONNO TANK (3 BYTES),
    DATANUM NUMBER (9.4)
    )
    Whether the table c. and its sample data are like

    FIELDNAME DATACHR REVISIONNO DATANUM PRODUCTIONCODE
    AB No. Nch 1 100 0
    AB No. Nch 1 108 0
    AB No.-of-Nch 1 1 0
    Ass42 teased dishes 1 0
    Ass42 BTDrumNo1 BTD-051 1 0
    AB53 BTDrumNo1 BTD-051 104 0


    CREATE TABLE materialcode
    (
    UPPERMATERIALCODE CHAR (20),
    PROCESSNO TANK (3),
    PROCESSADOPTDATE TANK (9)

    )
    Whether the table b. and its sample data are like

    UPPERMATERIALCODE PROCESSNO PROCESSADOPTDATE
    Ass42 1 20120717
    AB53 108 20121121
    111 20111104 AS05
    104 20120928 AS30


    CREATE TABLE BUILDINGSCHEDULEMASTER
    (
    BUILDINGSIZE TANK (5 BYTES),
    GTCODE FLOAT (4 BYTES),
    TIREPERCART NUMBER (3.0).
    BUILDINGLOT NUMBER (3.0)
    )
    Whether table and its sample data are like

    BUILDINGSIZE GTCODE TIREPERCART BUILDINGLOT
    AB42A 4 12 ass42
    AB53A 4 88 AB53
    AS30A AS30 4 80
    BF03A 1 90 BF03


    Now, I need to get some data in these fields by using the suite of mappings.

    « PR_ » || Trim (a.BUILDINGSIZE) | ' / MPL2' Processid,--PRIMARY KEY
    TO_DATE (substr (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') starteff, to_date (SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 7, 2) |) » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 5, 2) | » /'|| SUBSTR (NVL(b.PROCESSADOPTDATE,'19800101'), 1, 4). (' 01:00:00 ',' dd-mm-yyyy hh24:mi:ss') startDate.
    b.PROCESSNO revisioncodeid,
    a.BUILDINGLOT tirepercart ,
    CASE WHEN c.FIELDNAME = 'BTDrumNo1' then c.DATACHR end drumtype1.
    BOX WHEN (trim (C.DATACHR) = '1' and trim (C.FIELDNAME) = "No. Nch") and THEN click 'YES '.
    ANOTHER 'NO '.
    END may-BUG,
    case
    When c.FIELDNAME = 'Wavy'
    AND c.DATACHR = 'Use' THEN on 'YES '.
    When c.FIELDNAME = 'Wavy'
    AND c.DATACHR <>'Use' THEN 'NO '.
    fine wavy


    Now for the tables A and B I have the simple join as condition

    a.GTCODE = b.UPPERMATERIALCODE

    But I have to use two different left join conditions to join the table B and C to calculate the RESP fields according to the condition.
    Now, I have to use

    (trim (b.UPPERMATERIALCODE)). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)

    condition to get the data for the WAVY and DRUMTYPE1 fields.

    But at the same time, I have to use

    substr (Trim (b.UPPERMATERIALCODE), 1, 2). » -'|| Trim (b.PROCESSNO) = Trim (c.PRODUCTIONCODE) | » -'|| Trim (c.REVISIONNO)

    conition to derive the CHAFER field.

    And for this reason I am come so many duplicates and do not correct results for JUNEBUG, WAVY, DRUMTYPE1, and STARTDATE field.

    I need some advice as how can I do so that I get the correct results without duplicates for the PRIMARY KEY.

    Thank you

    Mahesh

    It would have been easier to answer if you gave us your example query that gives incorrect results - which both show us what you are doing and give us a starting point.
    Insert instructions for data, rather than only the data would have helped too, making it more quick to test this point.
    You do not show what you have done with your two outer join criteria, but I think you need to list TIREMASTERPROCESS_TEMP in your query twice, with alias names. Here's what I did:

    select a.BUILDINGSIZE, a.GTCODE, b.PROCESSNO ,  c1.FIELDNAME, c1.DATACHR, C2.FIELDNAME, C2.DATACHR
, CASE WHEN c1.FIELDNAME='BTDrumNo1' then c1.DATACHR end drumtype1
, CASE WHEN (trim(c2.DATACHR) = '1' and trim(c2.FIELDNAME) = 'No-of-Nch') THEN 'YES' ELSE 'NO' END CHAFER
, case when c1.FIELDNAME='Wavy' AND c1.DATACHR='Use' THEN 'YES'
       when c1.FIELDNAME='Wavy' then 'NO' else null end wavy
from BUILDINGSCHEDULEMASTER        A
join materialcode b on a.GTCODE=b.UPPERMATERIALCODE
left outer join TIREMASTERPROCESS_TEMP c1
   ON trim(b.UPPERMATERIALCODE)||'-'||trim(b.PROCESSNO) = trim(c1.PRODUCTIONCODE)||'-'||trim(c1.REVISIONNO)
left outer join TIREMASTERPROCESS_TEMP c2
   ON substr(trim(b.UPPERMATERIALCODE),1,2)||'-'||trim(b.PROCESSNO) = trim(c2.PRODUCTIONCODE)||'-'||trim(c2.REVISIONNO)

    C1 is an alias for the TIREMASTERPROCESS_TEMP line which is necessary for drumtype1 and wavy, c2 is an alias for the TIREMASTERPROCESS_TEMP line required for JuneBug. There was some minor errors in your calculations of field I tried to correct.

    The results are:

    BUILD GTCO PRO FIELDNAME    DATACHR    FIELDNAME    DATACHR    DRUMTYPE1  CHA WAV
----- ---- --- ------------ ---------- ------------ ---------- ---------- --- ---
AB53A AB53 108                         No-of-Nch    1                     YES
AB42A AB42 1   BTDrumNo1    BTD-051    No-of-Nch    1          BTD-051    YES
AB42A AB42 1   Wavy         NotUse     No-of-Nch    1                     YES NO
AS30A AS30 104                                                            NO

    Hope this helps,
    David

  • connect before between two tables

    I have this table structure

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    create table OBJECT_LIST
(
  cal_objid   NUMBER(4) not null,
  obj_name    VARCHAR2(100),
  obj_type    VARCHAR2(20),
  obj_title   VARCHAR2(20),
  description VARCHAR2(50)
);
alter table OBJECT_LIST
  add constraint OBJECT_LIST_PK primary key (CAL_OBJID);
  
  
  create table CAL_ERD
(
  obj_child    NUMBER(5) not null,
  obj_parent   NUMBER(5) not null,
  obj_rel_type VARCHAR2(50)
);
alter table CAL_ERD
  add constraint CAL_ERD_PK primary key (OBJ_CHILD, OBJ_PARENT);
    
  alter table CAL_erd
  add constraint cal_parent_FK foreign key (obj_parent)
  references object_list (CAL_objid);
  
  
   alter table CAL_erd
  add constraint cal_child_FK foreign key (obj_child)
  references object_list (cal_objid);
 
 
insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1192,
                                'MainObject',
                                'Form');
                                
                                
             insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1193,
                                'SecondObject',
                                'Form');  
                                
                                
             insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1194,
                                'ThirdObject',
                                'Form');    
                                
                                
              insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                          values(1195,
                                'FourthObject',
                                'Form');  
                                
                                
    insert into object_list (cal_objid,
                             obj_name,
                             obj_type)
                      values(1196,
                             'FirthObject',
                             'Form');
                             
                         
                             
                             
                              insert into cal_erd values(1193,1192,null);
                              insert into cal_erd values(1194,1193,null);
                              insert into cal_erd values(1195,1194,null);

    in the first table values

    CAL_OBJID OBJ_NAME, OBJ_TYPE OBJ_TITLE DESCRIPTION
    1192 MainObject form
    1193 SecondObject form
    1194 ThirdObject form
    1195 FourthObject form
    1196 FirthObject form

    the second value of the table
    OBJ_CHILD OBJ_PARENT OBJ_REL_TYPE
    1192 1193
    1194 1193
    1195 1194

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    WITH t AS 
    (SELECT li.obj_name,
            li.obj_type,
            li.obj_title,
            li.DESCRIPTION, 
            LEVEL AS lvl,
            SYS_CONNECT_BY_PATH(li.obj_name, '/')paths 
    FROM object_list li,cal_erd er
     where li.cal_objid = er.obj_parent(+)
         START WITH obj_parent IS NULL
         CONNECT BY
                  NOCYCLE PRIOR obj_child = obj_parent)
  SELECT obj_name,
         LEAD(obj_name) OVER(ORDER BY paths) AS child_name,
         obj_type ,
         obj_title ,
         DESCRIPTION ,
         substr(paths,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) + 1 , 
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl END)                    
                      - INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) - 1 ) AS parent_name
    FROM t;


    get value

    OBJ_NAME, OBJ_TYPE OBJ_TITLE DESCRIPTION PARENT_NAME CHILD_NAME
    FirthObject FourthObject form
    FourthObject form

    I what like to be like that

    OBJ_NAME, OBJ_TYPE DESCRIPTION OBJ_PARENT OBJ_TITLE OBJ_CHILD

    SecondObject MainObject form

    ThirdObject SecondObject form MainObject

    fourthObject ThirdObject shape SecondObject

    I would like if possible show the id of ojb_name

    Hello

    Here's a way to achieve the expected results, you want to:

    WITH t AS
    (SELECT obj_parent
          , li.obj_name
          , li.obj_type
          , li.obj_title
          , li.DESCRIPTION
          , LEVEL AS lvl
          , SYS_CONNECT_BY_PATH(li.obj_name, '/')paths
    FROM object_list li
         LEFT JOIN cal_erd er ON (li.cal_objid = er.obj_child)
         START WITH obj_parent IS NULL
         CONNECT BY
                  NOCYCLE PRIOR cal_objid = obj_parent),
t2 AS (
  SELECT LEAD(obj_name) OVER(PARTITION BY substr(paths, 1
                                                      , CASE WHEN INSTR(paths, '/', 1, 2)> 0
                                                             THEN INSTR(paths, '/', 1, 2)-1
                                                             ELSE LENGTH(paths)
                                                        END)
                                 ORDER BY paths) AS child_name
       , obj_name
       , obj_type
       , obj_title
       , DESCRIPTION
       , substr(paths,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) + 1 ,
                       INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl END)
                      - INSTR(paths, '/', 1, CASE WHEN lvl > 1 THEN lvl-1 END) - 1 ) AS parent_name
    FROM t)
SELECT *
  FROM t2
 WHERE child_name IS NOT NULL;

    Result:

    CHILD_NAME OBJ_NAME, OBJ_TYPE OBJ_TITLE PARENT_NAME DESCRIPTION

    SecondObject MainObject form

    ThirdObject SecondObject form MainObject

    FourthObject ThirdObject shape SecondObject

    Kind regards

    Steve

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