Count of the number of days in a calendar month according to the year

Similar Questions

• Function to return the number of days in a month?

  In one of my rules, I need to allocate an amount of benefits based on the number of days remaining in the calendar month.
  
  OPM does have a function that can provide me with the number of days in a calendar month?
  
  Thank you very much
  Isamu

  It is not a direct function to do this, however, it can be done with a bit of messing around. The following rules you will get the number of days of the month of the date of the date

  Basically, you get the first day of the month, add a month to the first day of the following month and then get the number of days between them, which will give you the number of days of the month of the date

  the month = ExtractMonth(the date)
  the year = ExtractYear(the date)
  the start of the month =MakeDate(the year, the month, 1)
  the start of the next month = AddMonths(the start of the month, 1)
  The number of days in the month = DayDifference(the start of the month, the start of the next month)
  

  These rules can be a little more compact, but it is basically how to do it.

• Count the number of days of previous instance entity

  Hello

  My context, global and one of many relationship which is a list of contracts.

  I think I can explain my problem with an example:

  Contract 1:

  Start date: 01/01/2013

  End date: 31/03/2013

  2 contract:

  Start date: 05/01/2013

  End date: 31/08/2013

  Contract 3:

  Start date: 11/01/2013

  End date: 31/03/2014

  I want to do this:

  For contract 3, calculate the number of days for contract 1 + contract 2 + 3 contract

  For the market 2, calculate the number of days for the 2 + 3 on contract market

  To contract 1, calculete number of days for contract 1

  Moreover, I would calculate the number of days limited to 28 months before the date of the end of each contract.

  For contract 3 calculate the number of days until the 31/03/2014 but on 30/11/2011.

  Means that

  -If a contract of 4 ends before 30/11/2011-> not taken

  -If a contract of 4 begins on 11/01/2011 and ends on 15/12/2011, the days of the 12/01/2011 to 15/12/2012 are taken into account.

  For contract 2 calculate the number of days until the 31/08/2013, but since 30/04/2011.

  Means that

  -If a contract of 4 ends before 30/11/2011-> not taken

  -If a contract of 4 begins on 11/01/2011 and ends 15/12/2011-> not taken

  Hope my explanation is clear.

  I don't know how mixt:

  temporal reasoning

  reasoning of entities

  through the reasoning of entities

  as

  -for a contract, I have to see all deals before and not one after (cross entities reasoning)

  -I have to count a number of days, but if there is a period without a contract that I have to ignore days (temporal reasoning)

  Then I am quite lost.

  If anyone can help me in this situation aprehendate the appropriate.

  Thank you.

  Hey guys I think I found the solution, here my idea in french (sorry my client is franco-french):

  the contract if course of est en

  Temporelencoursouapres (contract start date)

  and

  TemporelEnCoursOuAvant (date of end of contract)

  a contract is being so

  Exists (employment of the applicant, the contract is ongoing)

  the value of the number of days to count pour the contract to determine the last date of end of contract to take into account
  0	TemporelAvant (InstancesMinimum (employment of the applicant, the start date of the contract))
  0	TemporelAvant (the start date of the contract to determine the last date of end of contract to take into account)
  0	Temporelapres (InstancesMaximum (employment of the applicant, the end date of the contract))
  0	Temporelapres (date of end of contract)
  0	Temporelapres (the end date of the contract to determine the last date of end of contract to take into account)
  3	the day is the last day of February and Temporelencoursouapres (the start date of the contract to determine the last date of end of contract to take into account) and a contract is underway
  1	No (the day is the last day of February) and Temporelencoursouapres (the start date of the contract to determine the last date of end of contract to take into account) and a contract is underway
  0	otherwise

  the value of the number of days through contracts pour prescribe the last contract end date to take into account = Temporeldatedepuisdebut (all jobs of the applicant, the date (the number of months to be taken into account for the period affiliation) months before the end date of the contract, the value of the number of days from paying the contract to determine the last date of end of contract to take into account)

  the duration of contracts from pour prescribe the last contract end date to take into account = IntervalleSommeQuotidienne (the start date of the contract to determine the last date of end of contract to be taken into account; AddDays (InstancesMaximum (employment of the applicant, the end date of the contract) 1); the value of the number of days through contracts pour prescribe the latest end date of contract to take into account)

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• SQL to count the number of days of January with a range of dates

  I have data like this, how to calculate the number of days with January in this date range.

  BEGINNING	END	DAYS OF JAN
  12/12/2013	20/01/2014	20
  21/01/2014	02/02/2014	11

  Hello

  So, you want to count the number of days between

  (a) either start_dt, or January 1, 2014 (prevailing later) and

  (b) or end_dt or January 31, 2014 (whichever comes first).

  However, if start_dt and end_dt are prior to January 2014 (or both are later) which will result in a number negative if you take the difference or 0, if it is higher.

  This looks like a job for the GREATER and LESS than functions.

  SELECT start_dt - START is not a column name good

  , end_dt - is neither END

  BIGGER (1 + LESS (end_dt, DATE ' 2014-01-31'))

  -Most GREAT (start_dt, DATE '' 2014-01-01)

  * v

  ) AS jan_days

  FROM table_x

  ;

  If you would care to post CREATE TABLE and INSERT instructions for some examples of data, then I could test it.

• Is it possible to do it in a table? (Count the number of days from a certain date)

  Hello
  
  I did yesterday a data base to make my job easier. I could make it even more effective if I could understand this delicate piece of business.
  
  What I have is in my table has a column called "Date completed". This column contains the date when the project was completed. Then, I would like to have another column in the table called "number of days elapsed since completion. This column would have simply taken the date in column "Date completed" and count the number of days since that day and show them in a numeric value (i.e. 28). This way I could do a select and display everything is over for a number of days where I need complete my report (s).
  
  Thanks for any help. If you know a way to do that is completely different from what I'm trying to please do not hesitate to propose a solution, I'm a complete newbie to this. I took a basic SQL course at the College a few years ago, but never learned to do anything as advanced as this.
  
  Thanks again

  Your number of days can be easily calculated as trunc (sysdate) - date you completed column.

  You probably don't want to store the number of days in the table (since his will change daily)-instead it calculate on the fly that you query the data (or if you have 11 g you could watch the virtual to make columns persistent calculation rather than the value in the table).

• In Firefox you get 4 how changing the expiry of browser history. It was easy until there was a counter to set the number of days to keep a history? Lizzie

  In tools, under the protection of personal information, I was able to set the number of days during which the browser history... Very handy when you need to keep a record of sites visited. Now in Firefox4 I have "Remember history" option. How will I know how the newspaper story is saved for the moment?

  In Firefox 4 you can no longer set the number of days of historic preservation. The method used by Firefox to store history has changed, for more details on the changes, see http://blog.bonardo.net/2010/01/20/places-got-async-expiration

• Number of days worked if the criteria of

  I'm looking for a formula counting the number of days, I worked my last day of rest, sheet 1, if it meets the date displayed in cell D2 in sheet 2, which is the Start Date and time after my rest day.

  sheet 1 has the info.

  D = 'Date' Date and time format

  E = "Duration" personalized hr: mm (start time)

  F = "Duration" hr: mm custom (arrival time)

  G = "Duration" hr: customized mm (total length)

  sheet 2

  D2 has a sum which adds the sheet 1::Table 1::D2 + 1::Table Sheet 1::E2 equals 03/12/16 17:50.  Format: Custom, Date & time, Format custom: 05/01 07:08 drag token or text etc.

  Any ideas how I can do this please.

  Thanks David

  Hi David,

  I don't get a clear idea of what you're trying to do. Can clarify you, perhaps with a screenshot showing examples of the values in the cells involved?

  Kind regards

  Barry

• Number of days where the value > a certain amount

  Hello

  I have a table named named MSR_3423:

  

  I want to count the number of days where the VALID_VALUE is > to 0.001

  I made this request, but it gives me that result a count of every time that this value has been found in a day:

  select trunc(valid_date), count(*) from MSR_3423 
  where raw_value > 0.001
  and   VALID_DATE IS NOT NULL
  group by trunc(VALID_DATE)
  order by 1
  

  It gives me this result:

  

  But I want the number of days when this value has been reached. In this example, the result should be: 5 (for 5 days)

  I think there must be a dower to do, but I'm not experienced enough to achieve this goal. Could you help her?

  Thank you.

  You almost have it. Just put another county around your account.

  select count(*) from (
  
    select trunc(valid_date), count(*)
    from MSR_3423
    where raw_value > 0.001
    and  VALID_DATE IS NOT NULL
    group by trunc(VALID_DATE)
  );
  

  or shorter but sometimes confusing

  
    select count(count(*))
    from MSR_3423
    where raw_value > 0.001
    and  VALID_DATE IS NOT NULL
    group by trunc(VALID_DATE) ;
  

  Logic of Alvertos did the same thing. He's just using SEPARATE instead of GROUP BY. But since I do not SEPARATE, I wanted to show a different way.

• calculate the number of days excluding non-working days

  11.2.0.4

  theres a fairly common request over the years to get the diff between 2 dates, excluding weekends, theres many ways to to do, however, I would like to go a step further and exclude everything not professional

  day.

  We have a company function that calculates whether a date is a holiday for our Organization.  We can pass a date and we have a Y or N back.     In the example below, the l' appel call function shows there for Saturday to show how we can identify the non-working day.

  Can anyone think of a way that we could use to get a sum of N s between 2 date fields in a line using this function?   IM thinking if we get the right formula/function to create a virtual column with calculating pre built as it can start to get expensive if she had to loop through every possible day between 2 dates to see it is a business day, all by a count.

  create the table t1_count

  (identification number,

  date of TS1,

  date of TS2)

  insert into t1_Count

  values (1, sysdate, sysdate - 7);

  insert into t1_Count

  values (2, sysdate, sysdate - 4);    -Saturday

  commit;

  SELECT id, ts1 ts2, .isholiday (ts1), isholiday (ts2) of t1_count;

  1	06/03/2015-14:30:51	27/05/2015 14:30:51	N	N
  1	06/03/2015-14:32:29	30/05/2015 14:32:29	N	THERE

  That fold to my brain...

  ABS (trunc (sysdate - 40) + level - 1 - trunc (sysdate)) that's equivalent to the abs (level - 41)...

  Why not just level<=>

• Is it possible to send a document through EchoSign, but not allow the recipient to sign in fact that a certain number of days later?

  Is it possible to send a document through EchoSign, but not allow the recipient to sign in fact that a certain number of days later? I often send contracts which have a period of seven days - if the recipient is not allowed to sign until seven days have elapsed since the date I send the contract. I was wondering if there is a way to fight against this automatically or if I should tell them that they cannot sign up to a certain date and count on them to follow my instructions.

  Hi Jamie,

  From now on, once the document is sent to the signatories that they can esign it at any time and it is not possible to delay or set the least number of days before they can not esign.

  Although EchoSign does not have this feature currently, but we can send your request to our team of developers to integrate the requested feature becomes available in the future.

  You can also put your ideas on our page of ideas (http://ideas.echosign.com/forums/21617-echosign-general ) where your feature request will go directly to our development team.

  Kind regards

  -Usman

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• Number of days between two Dates in the Correct month

  I am trying to write a SELECT statement that returns the number of days spent on a project.
  
  Here's my problem. I have a table with several columns of date (start_date, end_date, etc.) as well as several other columns. Here is an example of the table.
  
  PROJECT... START_DATE... END_DATE
  123 ................. 1ST JANUARY 13... 15 JANUARY 13
  456 ................. 25 JANUARY 13... FEBRUARY 5, 13
  789 ................. 30 JANUARY 13... FEBRUARY 5, 13
  999 ................. 1ST FEBRUARY 13... FEBRUARY 8, 13
  
  I'm counting the number of days spent on projects in each month. For example, with the above data, I would come back...
  
  MONTHS... PROJECT_DAYS
  Jan ............. 24
  Feb ............. 18
  
  I tried to use a CASE statement, but I'm having a hard time to understand. Any help would be greatly appreciated!
  
  Published by: 987079 on February 8, 2013 13:12

  An option would be something like

    1  with project as (
    2    select 123 project_id, date '2013-01-01' start_date, date '2013-01-15' end_date from dual union all
    3    select 456, date '2013-01-25', date '2013-02-05' from dual union all
    4    select 789, date '2013-01-30', date '2013-02-05' from dual union all
    5    select 999, date '2013-02-01', date '2013-02-08' from dual
    6  ),
    7  all_days as (
    8    select start_date + level - 1 dt
    9      from (select min(start_date) start_date,
   10                   max(end_date) end_date
   11              from project)
   12   connect by level <= end_date - start_date + 1
   13  )
   14  select trunc(dt,'MM'),
   15         count(*)
   16    from all_days ad
   17         join project p on (ad.dt between p.start_date and p.end_date)
   18   group by trunc(dt,'MM')
   19*  order by trunc(dt,'MM')
  SQL> /
  
  TRUNC(DT,'MM')        COUNT(*)
  ------------------- ----------
  2013-01-01 00:00:00         24
  2013-02-01 00:00:00         18
  

  Justin

• SQL query to get the number of days monthwise

  Hello
  I'm new to sql, can someone please tell me query to find the number of days between the two dates months wise.
  say
  FIRSTDATE last date
  21/03/2011-25/06/2011
  
  March April May June
  9 22 23 18

  Hello

  Welcome to the forum!

  Here's one way:

  WITH     all_dates     AS
  (
       SELECT     start_date + LEVEL - 1     AS a_date
       FROM     (
                 SELECT     TO_DATE ('21/03/2011', 'DD/MM/YYYY')     AS start_date
                 ,     TO_DATE ('25/06/2011', 'DD/MM/YYYY')     AS end_date
                 FROM     dual
            )
       CONNECT BY     LEVEL     <= end_date + 1 - start_date
  )
  SELECT       TO_CHAR ( TRUNC (a_date, 'MONTH')
              , 'fmMonth YYYY'
              )               AS month
  ,       COUNT (*)               AS num_days
  FROM       all_dates
  WHERE       a_date - TRUNC (a_date, 'IW')     < 5
  GROUP BY  TRUNC (a_date, 'MONTH')
  ORDER BY  TRUNC (a_date, 'MONTH')
  ;
  

  What is a 'working day '? I guess you mean every day except Saturday or Sunday, but the query aboveare sometimes figures less than you have asked:

  MONTH             NUM_DAYS
  --------------- ----------
  March 2011               9
  April 2011              21
  May 2011                22
  June 2011               18
  

  Are a few days working on Saturday or Sunday? How do you get the 22 working days in April 2011 and 23 in may?

  SQL is good at obtaining results with a variable number of rows, but you have to say exactly the desired number of columns when you write the query.
  If you really need the output of the way you said, with any number of columns, then watch in swing or a grouping of the chain . See the FAQ forum
  https://forums.Oracle.com/forums/Ann.jspa?annID=1535
  "4. How can I convert rows to columns.

• number of days in the month

  Dear members,
  
  I have available dates,
  Let's say date1 = January 1, 2011"
  and date2 = April 15, 2011"
  
  My goal is to calculate the sum of the no. of days between this range.
  
  i.e.
  
  month = 01 days = 22
  month = 02 days-28
  month = 03 days = 31
  month = 04 days = 15
  
  so total days = 22 + 28 + 31 + 15 = 96 between individuals because of the date range.
  My goal is to have the figure 96 days that is the sum of the days of the month.
  
  
  
  Kind regards
  
  
  
  Teefu
  Developer
  
  Published by: teefu on July 21, 2011 10:09

  Hello

  If all you want is the total number of days, then you can simply subtract the earlier DATE of the last one, like this:

  SELECT     TO_DATE ( '15-04-2011'
            , 'DD-MM=YYYY'
            ) + 1 - TO_DATE ( '10-01-2011'     -- Jan. 10; '01-10-' would be Oct. 1
                      , 'DD-MM-YYYY'
                      )     AS days_diff
  FROM     dual;
  

  If you want to see a breakdown by month, here's one way:

  WITH     parameters     AS
  (
       SELECT     TO_DATE ( '10-01-2011'
                 , 'DD-MM-YYYY'
                 )     AS start_dt
       ,     TO_DATE ( '15-04-2011'
                 , 'DD-MM-YYYY'
                 )     AS end_dt
       FROM     dual
  )
  SELECT       TO_CHAR ( start_dt + LEVEL - 1
              , 'FMMonth YYYY'
              )     AS month
  ,       COUNT (*)     AS days
  FROM       parameters
  CONNECT BY     LEVEL <= 1 + end_dt - start_dt
  GROUP BY  TO_CHAR ( start_dt + LEVEL - 1
              , 'FMMonth YYYY'
              )
  ORDER BY  MIN (LEVEL)
  ;
  

  Output:

  MONTH                      DAYS
  -------------------- ----------
  January 2011                 22
  February 2011                28
  March 2011                   31
  April 2011                   15
  

  Published by: Frank Kulash, July 21, 2011 01:10