count the pixel values in an array

Similar Questions

• Charger changes the pixel value after loading as bitmap

  Hi all

  My goal is to load two images and compare its color pixel-by-pixel information. For this I used "flash.display.Loader' class to load the images, and once the load finished I catalogued the content loaded bitmap object (loaderObj.content as Bitmap). Finally, I'll get the bitmapdata of the bitmap of the two images and compare the pixels.

  Now the problem is the color of the original image information and the loaded bitmap is slightly different. For example, the color value of the pixels of the image attached image1.jpg is 0xDDDDDD for full 1366 x 768. And for the image even when it is loaded as bitmap color value of pixels are different from the original value (for a few pixels only, not all pixels are different).

  I gave you the source code and sample images.

  Please can someone help me how to solve this problem?

  <? XML version = "1.0" encoding = "utf-8"? >

  " < = xmlns:fx s:WindowedApplication ' http://ns.Adobe.com/MXML/2009 "

  xmlns:s = "library://ns.adobe.com/flex/spark".

  xmlns:MX = "library://ns.adobe.com/flex/mx".

  width = "1376" height = "800."

  ShowStatusBar is kept = "false" >

  < fx:Declarations >

  <! - Place non-visual elements (e.g., services, items of value) here - >

  < / fx:Declarations >

  < fx:Script >

  <! [CDATA]

  private function loadBtn_ClickHandler (): void {}

  var file:File = new queue (File.desktopDirectory.nativePath);

  file.addEventListener (Event.SELECT, onFileSelectionHandler);

  file.browseForOpen ('open image', [new FileFilter ("Images", "*.gif, *.jpg; *.JPEG; *.png")]);

  }

  private void onFileSelectionHandler(ev:Event):void {}

  var loadedFilePath:String = (ev.target as a file) .nativePath;

  loadImageAsBitmap (loadedFilePath);

  }

  / * Load the bitmap image using the loader * /.

  private void loadImageAsBitmap(url:String):void {}

  var loader: Loader = new Loader();

  load the content as a bitmap

  loader.contentLoaderInfo.addEventListener (Event.COMPLETE, onContentLoadComplete);

  loader.contentLoaderInfo.addEventListener (IOErrorEvent.IO_ERROR, onContentLoadFail);

  Loader.Load (new URLRequest (url));

  }

  private void onContentLoadComplete(ev:Event):void {}

  var loaderInfo:LoaderInfo = ev.target as LoaderInfo;

  var bitmap: Bitmap = loaderInfo.content as Bitmap;

  printPixelValue (bitmap.bitmapData);

  container_ID. AddChild (bitmap);

  }

  private void onContentLoadFail(ioe:IOErrorEvent):void {}

  trace ("Image Load Failed");

  }

  private void printPixelValue(bmData:BitmapData):void {}

  var initPixelValue:Number = - 1;

  for (var countI:int = 0; countI < bmData.height; countI ++) {}

  var countI:int = 1;

  for (var countJ:int = 0; countJ < bmData.width; countJ ++) {}

  var pixelValue:Number = bmData.getPixel32 (countJ, countI);

  If (pixelValue! = initPixelValue) {}

  initPixelValue = pixelValue;

  Print pixel value for a single line

  trace ("value of Pixel to" + countI + "x" + countJ + "is:" + pixelValue);

  }

  }

  trace ("value of Pixel to" + countI + "x" + countJ + "is:" + pixelValue);

  //}

  }

  []] >

  < / fx:Script >

  < s:Button id = "loadBtn_ID" label = "Load!" click = "loadBtn_ClickHandler ()" "

  x = '5' y = "5" height = "20" / >

  < mx:UIComponent id = 'container_ID' x '5' = y = "30" width = "1366" height = "768" / >

  < / s:WindowedApplication >

  Sample image:

  

  Thank you all,

  Update the sdk to 4.6.0 fixed the problem

• Find the minimum value in digital array that is greater than 0

  So far I have;

  $pfpp = min ($pflist);

  $pflist is the array of digital values and contains about 0.

  I need to change to $pfpp = min ($pflist); to return the lowest number which is greater than zero.

  I am stuck, can anyone help?

  Thank you

  Change the values in the table so I can't sort them in ascending order.

  Of course you can.  Or you can copy the table into a temporary array.

  $temp = $pflist;

  sort ($temp, SORT_NUMERIC)

  foreach ($temp as $value) {}

  If $value > 0; $number = $value; break;

  }

  echo "entry of zero smaller in pflist is $number";

• count the pixels?

  I am new to scripting and is so confusing. I was wondering if someone here would know where I could find a script for the export of histogram information? Basically, I have hundreds of files with 30 + layers in each file. I need to know how many pixels is present on each layer. manually, I do this by selecting each layer and check the pixels of the layer selected in the Histogram palette and write it down. If, instead, I could export this info to the database or file of a Word, that would allow me to save a lot of time. I'm working on with CS2. grateful for any help!

  You can try this, it will write the number of name and pixel in the layer to a csv file on the desktop with the same name as the opened document.

  if(documents.length){
  doc=activeDocument;
  var area = activeDocument.histogram;
  var Results=[];
  var Name = app.activeDocument.name.replace(/\.[^\.]+$/, '');
  var CSV=File("~/desktop/"+Name+".csv");
  findLayers(doc);
  Results = Results.reverse();
  CSV.open("w");
  for(var a in Results){
  CSV.writeln(Results[a][0]+","+Results[a][1]);
   }
  CSV.close();
  }
  function findLayers(obj){
   if(obj.artLayers.length>0){
   for(var z = 0;z 0){
    for(var l=0;l		   

• Count the horizontal value and generating date

  using oracle 9i.
  
  I have a table named test which presents
  

  Eno     pct1     pct2     pct3     pct4     pct5     sal_date
  101     0     100     0     100     100     03/01/2010
  102     0     0     100     100     100     14/02/2010
  103     0     100     100     100     100     24/01/2010

  for the first line, we have two zeros for pct1 pct3, so two records to be generated for the 01/03/2010 and as well next week
  

  Eno     pct1     pct2     pct3     pct4     pct5     sal_date
  101     0     100     0     100     100     03/01/2010 (2 Zeros,two weeks to b generated
  101     0     100     0     100     100     10/01/2010
  102     0     0     100     100     100     14/02/2010(2 Zeros,two weeks to b generated
  102     0     0     100     100     100     21/02/2010
  103     0     100     100     100     100     24/01/2010(one Zero,one week to b generated

  create table test
  ( eno number,
    pct1 number,
    pct2 number,
    pct3 number,
    pct4 number,
    pct5 number,
    sal_date date);
  
  insert into test values
  (101,0,100,0,100,100,to_date('03/01/2010','DD/MM/YYYY');
  
  
  insert into test values
  (102,0,0,100,100,100,to_date('04/02/2010','DD/MM/YYYY');
  
  insert into test values
  (103,0,100,100,100,100,to_date('24/01/2010','DD/MM/YYYY');

  Can u pls help out me
  
  Thanks in advance
  
  Published by: user12093849 on 28-Sep-2010 00:13

  Kaila Mahesh wrote:

  select ENO, PCT1, PCT2, PCT3, PCT4, PCT5,SAL_DATE + (cnt - 1) * 7 SAL_DATE  from
  (
  select ENO, PCT1, PCT2, PCT3, PCT4, PCT5, SAL_DATE,
  sum(
  case when PCT1 = 0 then 1 else 0 end +
  case when PCT2 = 0 then 1 else 0 end +
  case when PCT3 = 0 then 1 else 0 end +
  case when PCT4 = 0 then 1 else 0 end +
  case when PCT5 = 0 then 1 else 0 end
  ) over (partition by (eno)) cnt
  from test
  ) 
  

  Kind regards
  Kaila Mahesh

  Hmm, produces only 3 lines, rather than the required 5...

  SQL> select ENO, PCT1, PCT2, PCT3, PCT4, PCT5,SAL_DATE + (cnt - 1) * 7 SAL_DATE  from
    2  (
    3  select ENO, PCT1, PCT2, PCT3, PCT4, PCT5, SAL_DATE,
    4  sum(
    5  case when PCT1 = 0 then 1 else 0 end +
    6  case when PCT2 = 0 then 1 else 0 end +
    7  case when PCT3 = 0 then 1 else 0 end +
    8  case when PCT4 = 0 then 1 else 0 end +
    9  case when PCT5 = 0 then 1 else 0 end
   10  ) over (partition by (eno)) cnt
   11   from test
   12  )
   13  /
  
         ENO       PCT1       PCT2       PCT3       PCT4       PCT5 SAL_DATE
  ---------- ---------- ---------- ---------- ---------- ---------- -------------------
         101          0        100          0        100        100 10/01/2010 00:00:00
         102          0          0        100        100        100 11/02/2010 00:00:00
         103          0        100        100        100        100 24/01/2010 00:00:00
  
  SQL>
  

• I can move the position of the pixel-values (browser-filling) background image?

  I want to design a landing with Muse page. To insert a background image that fills the screen on the top and to the left and right of the browser window edges, I think the best way is to put a picture as the fill "browser" (I this translated from the German term 'Navig-deflectors', then choose suitable size ('scale Passend").

  Unfortunately, if I'm having a menu bar on top of this image, it will always hide the upper part of the image. Can I therefore change the background a little image?

  There may be several ways to achieve this goal within the Muse.

  -Use composition to create the menu, where the menu will only appear on mouse click or hover.

  -Use any image editor and add a rectangle empty start of image where menu will be rendered.

  -Apply the scroll on the Menu so that the menu only to scroll page should appear on the page.

  -Make the homepage with only the picture fill and the link to get inside the site with sub-pages, which should include a menu.

  Thank you

  Sanjit

• PES 10 suddenly refuses the pixel dimensions

  Hi, I never use anything other than sizes of pixels for resizing. Without any warning, today PSE refuses to allow me. I checked the preferences/units & leaders: leaders and type have the pixel value as they always have been. But now when I try to resize, it gives me the option only per cent, inches, cm, mm, points, picas, and columns; I'm not allowed to use more pixels.

  What has been reached? And how can I work in pixels and this continues?

  First of all, resampling is turned on?

  If it is and you still do not see the pixels, try to delete the preferences: exit the editor and then restart it by pressing ctrl + alt + shift (command + option + shift on a mac). Keep the key down until you see a window asking if you want to delete the settings file. You do.

• return the minimum value from a table

  Hi all, how can I output the lower value within an array of numbers?

  I have this but it does not work, it is always the first number in the table.

  function minF(a:Array):Number {var min:Number = [0];      for (var i: Number = 1; i >.) Length; i ++) {if (a [i] > min) {min = a [i];}           } else {trace ("buahMin!");           return min}}; }

  Thanks to you all.

  This is because you have the sign on your conditional loop wrong.

  You must make the comparison for all I less than your length of array.

  function minF(a:Array):Number {}

  var min:Number = [0];

  for (var i: Number = 1; i

  min (min =

  }

  return min;

  }

• Scripting: Count the number of selected pixels (non-quadrangle) or alternative approach

  Is it possible to count the number of pixels in a selection that is not a quadrilateral? For example, if I have cntl - click on the thumbnail of a text layer, I would like to know how many pixels is selected.

  This application, if anyone has another approach to try...

  

  My goal is the place the text at some point where it covers do not all lines (or, Alternatively, the place where it covers the smallest number of pixels line). My approach is to insert a text in red to the desired location, apply a BlendMode.Multiply to the text. The number of Red pixels always on the screen will show how many pixels line I'm concealing. Then I move the text into a region and check the histogram in 76 index (which is 255,0,0), find the point with the highest number of red (meaning concealing pixels less line) and finally move the text at that location. See the code snippet below:

  var bestCX = cX;

  var bestCY = cY;

  var bestPixelDensity = - 1;

  var pixelDensity = 0;

  var searchRegionWidth = 3000;

  var searchRegionHeight = 2000;

  loop through an area 3000 x 2000 around where you want

  for (var x = cX - searchRegionWidth/2; x < cX + searchRegionWidth/2; x ++)

  {

  for (var y = cY - searchRegionHeight/2; y < cY + (searchRegionHeight/2); y ++)

  {

  textItemRef.position = new Array (x, y);

  pixelDensity = myDocument.histogram [76]; index of 255,0,0 (red)

  If this point is greater than the previous highest density, use it instead.

  if(pixelDensity > bestPixelDensity)

  {

  bestCX = x;

  bestCY = y;

  bestPixelDensity = pixelDensity;

  }

  }

  }

  move text in the best location found

  textItemRef.position = new Array (bestCX, bestCY);

  The problem is that the images I use are very large ((7000x7000px) for each histogram control takes a few seconds and I really need to move in a fairly large region (3000 x 2000) to find the best place.) I think that it is perhaps faster if I'm not using the histogram at all, and instead each time that I move the text, I select the text and see how many points is in the selection. Any help or alternative approaches would be great!

  I don't know the answer, the only thing I can think is the whole of the histogram to the selection and treatment of the histogram of the selected area.

• Count the boxes, color Format according to value

  Searched for how to count the boxes in a PDF form. Found this link and have renamed my boxes so that they share the same initial letters.  Added the script below in the section of a body of numbers custom calculation script.  Nothing happens not even.  What should I know to set up correctly?  Also, I need to add a table more so it adds another section to the meter.  These boxes begin with cbxSAP.  Once the number of box is working, is there a way to tell if the sum is = or greater than 14 to the green color of the border/field and the default value would be red?  Hope that makes sense, thank you.

  // Custom calculate script
  
  (function () {
  
  
  
      // Get an array of the PO checkbox fields
  
      var fa = getField("cbxPO").getArray();
  
  
  
      // Initialize counter
  
      var sum = 0;
  
  
  
      // Loop through the fields and update counter
  
      for (var i = 0; i < fa.length; i += 1) {
  
          sum += fa[i].value !== "Off" ? 1 : 0;
  
      }
  
  
  
      // Set this field's value to the sum
  
      event.value = sum;
  
  
  
  })();
  

  You have get an error and it's why the JavaScript console opens and displays the lines of information.

  The first line indicates there is an eorror.

  The code is a custom calculation script.

  The code cannot locate the Group of fields named "cbxPO". Verify that the field whose name "cbxPO. ' # ' exist. The ' # ' is the name or number of subfield.

  The code actually works if there are no errors.

  For hierarchical fields, there must be "." separates levels. You field names must be:

  cbxPO.Dest

  cbxPO.Tax

  cbxPO.Pay

  cbxPO.Status

  cbxPO.Freight

  And it is not important what was once the value of exports.

• How to get the RGB value of a pixel in a psd document using scripting Photoshop

  Hi, guys!    Does anyone know how to get the RGB value of a pixel in a psd document using scripts in Photoshop?  I myself have missed for a long time and could not resolve. I am very happy to hear your voice as soon as possible!

  Here is an example...

  var originalUnits = app.preferences.rulerUnits;
  app.preferences.rulerUnits = Units.PIXELS;
  var doc = activeDocument;
  var Colour1 = GetHexColour(eyeDropperRGB(1,doc.height-1));
  var Colour2 = GetHexColour(eyeDropperRGB(20,doc.height-5));
  var Colour3 = GetHexColour(eyeDropperRGB(40,doc.height-14));
  alert("Colour 1 = " +Colour1 + "\rColour 2 = " +Colour2 + "\rColour 3 = " +Colour3);
  var decColour = eyeDropperRGB(40,doc.height-14);
  alert("Red = " +decColour[0] + "\rGreen = " +decColour[1] + "\rBlue = " +decColour[2]);
  app.preferences.rulerUnits = originalUnits;
  function GetHexColour(reqHex){
  var out='';
  for(No in colours = reqHex){
   out = out.concat(zeroPad(d2h(reqHex[No]),2));
   }
  return out;
  };
  function eyeDropperRGB(x,y) {
   var x2 = x + 1;
   var y2 = y + 1;
   var out = new Array(3);
   activeDocument.selection.select([[x,y], [x2,y], [x2,y2], [x, y2]], SelectionType.REPLACE, 0, false);
   for(ch in list = ["Red", "Green", "Blue"]) {
   histogram = activeDocument.channels[list[ch]].histogram;
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     if (histogram[i]) {
      out[ch] = i;
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    }
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    return out;
  };
  function d2h(d) {return d.toString(16);}
  function zeroPad(n, s) {
     n = n.toString();
     while (n.length < s)  n = '0' + n;
     return n;
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• How re - initialize an array with the new values at run time?

  Hello

  In this application of particluar I want to change the value of a particular index (Ex: 4th move in a 1 d table) and store the changed value (Inremented) in the same index position.

  I wrote a program, can someone tell what I am doing wrong?

  LabVIEW version: 8.6

  Screenshot kindly updated instead of .vi

  Two things.

  First of all:

  You must initialize the table (via the feedback loop).

  Click with the right button on the wire of the array and create constant.  Move the index of item 99.  Initialize element 0.  This thread up to the lower part of the feedback node.

  Second:

  You use an Insert in the table VI, but it's not describe what you try to do.  While he places an element in the position shown is also increases the size of the table.

  This change to a subset of table replace VI.

• Where can I find the numerical value for GenICam standard pixel formats?

  I am putting in place a structure of case for the reconstruction of image formats using the pixel as IMAQdx output format. Confirmed the consistent property of 'Pixel Format' numeric U32 in id IMAQdx from camera to camera, but it's just a number, and I don't see that the number of image formats used by the cameras I (I need code for other formats I've yet to see). The GenICam standard 1.1 supports 52 image formats, and no doubt IMAQdx has a corresponding U32 value for each format. Where can I find this list? The .pdf for the GenICam standard lists the formats available in name only and does not have a corresponding numerical value.

  Hey Nasgul

  The attribute 'PixelFormat' is actually a list of name/value pairs. For GenICam cameras (such as GigE Vision) these names and these values are determined by the camera, no IMAQdx XML file. The names themselves are normalized by the part of the "Standard feature Naming Convention" of GenICam (but aren't their values).

  I think you speak for the Format of Pixel property node. I think you are right that it is a digital. It's probably because the available modes can not be known before you actually run the code and the LabVIEW enumeration values must be known when editing, no compilation. The node itself as a digital is probably as a relic of the firewire interface. It would be probably more useful as a string, I imagine.

  You probably want to use the generic way of manipulating the attributes instead. You initially set the property 'Attribute Active' in 'PixelFormat' and then you can then query a list of name/value pairs available or simply set the value. IMAQdx allows you to set the value directly as a string (using the standard names) rather than having to translate it into a numeric value.

  Eric

• How can you specify the default value for the undefined array elements

  According to aid LV, the tables have two default values, the normal default value and the default value for the undefined array elements.

  I assume that there must be a way to specify the default value for later, but I can't find it anywhere.  Any ideas?

  I know that you can drag the item out of the table container.  Change the default value on this scalar element.  Then drag the item in table tank.

• extract the positive values of a 2D array

  Hello

  I have a table 2D with positive value in column 2.

  What I want to do is to find the positive value of each column.

  For example, I have this table

  A        B

  -1        1

  2         -2

  3         9

  5         4

  -5        6

  6         7

  and I want to get the following

  A          B

  3          9

  5          4

  6          7

  I managed to have the positve in each case, but the value do not match (I have all the positive values of each column) as

  A AND B

  2 1
  3 9
  5 4
  6 6
  7

  can you help me please?

  Just to be clear: you want the output array to contain all rows in the input table that have positive values in the two column A and column B?  Are you using strictly positive (> 0) comparisons or not negative (> = 0)?  Are integers of values?

  RIF answers: Yes and strictly positive, this will do what you want.

  Lynn