Cubic hermite

Hello

LV help says 1D.vi to interpolate, used with the cubic Hermite method, should give the same results as the Interpolation of hermit 1D.vi. However, I find a problem with the latter as soon as the spacing of the Xi is not equidistant.

I've attached an example of simple monotonous curve be interpolated. A 'swap' button swap X and Y, by which the Xi not equidistant. Thus, the first VI always does the work, while the second is completely going off the track.

Can anyone tell me what I'm doing wrong, or is this a bug?

The real app is that I would take a calibration curve, let's say the wavelength vs engine position and use these screws in both directions of reading (position-> wavelength) and control (wavelength required-> position). For speed, I wanted to use pre-calculated polynomials by pieces of the 1D.vi of the Interpolation of hermit.

Thank you

Dirk

SRY Ben, I forgot

CAR number: #372390

The CAR connection

Stefan

Tags: NI Software

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