RegExp_. Using substr

Hi - I need to extract the string after the last ' / ' and everything before the last ' / '. Possible to do using substr and instr but I would like to know how this can be done using regexp_substr.

for example: / Merchants/Retail/ShopBrand/Home/Holidays/Bed

My requirement is to extract 'Reads', which is after the last ' / ' and '' / Merchants/Retail/ShopBrand/Home/Holidays which is before the last ' / '.

Help, please

Could you give the explanation as well to '. * /', '' ?

We receive all the strings until the last ' / ' and substituting null

And my second (not a Cleaver) option would be:

SELECT REGEXP_REPLACE(REGEXP_SUBSTR('/Merchants/Retail/ShopBrand/Home/Holidays/Bed', '.*/'), '.$', '') FIRST_REQUIREMENT FROM DUAL;

Here, we remove the last character. Take a look at the documentation to go further: http://docs.oracle.com/database/121/ADFNS/adfns_regexp.htm#ADFNS1003

Kind regards.

Tags: Database

Similar Questions

How to use substr to search and show as an ouput in oracle 11g

Hi all
Suppose I have oracle.india.com1.1234 in my value line so I need not to show the India as output. I need to display in the .csv (Excel)
Thank you

You can use SUBSTR + INSTR:

with t as)

Select 'oracle.india.com1.1234' union str double all the

Select "oracle.England.com1.1234" from double

)

Select str,

substr (STR, InStr(STR,'.') + 1, instr(str,'.',1,2) - instr(str,'.') - 1) new_str

t

/

STR NEW_STR
------------------------ ------------------------
Oracle.India.COM1.1234 India
oracle.England.com1.1234 England

SQL >

Or use regular expressions:

with t as)

Select 'oracle.india.com1.1234' union str double all the

Select "oracle.England.com1.1234" from double

)

Select str,

regexp_substr (str,'[^.] +', 1, 2) new_str

t

/

STR NEW_STR
------------------------ ---------------------
Oracle.India.COM1.1234 India
oracle.England.com1.1234 England

SQL >

SY.

WE SHOULD NOT USE SUBSTR FUNCTION...

Hello
ex: [email protected] , [email protected] [email protected]
AS THIS HUNDRED PLATE IS HERE.
QUERY:
I DON'T WANT THAT YAHOO, GMAIL LIKE THAT... WE SHOULD NOT USE SUBSTR FUNCTION...
THIS IS AN INTERVIEW QUESTION
Thank you

Try:

Select regexp_replace (' [email protected]',' ^. * @(.*)-.) (. *)', '\1') twice;

How to use substr and instr, where the line of input Multi text

Hi all
with
data in the form of)
Select ' Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..' double val
Union of all the
Select 'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Plaza Falke' of the double
)
Select
regexp_substr (shipping_instructions, "[^ #] +' 1, 1") name
, regexp_substr (shipping_instructions, "[^ #] +' 1, 2") address
, regexp_substr (shipping_instructions, "[^ #] +' 1, 3") city
, regexp_substr (shipping_instructions, "[^ #] +' 1, 4") State
, regexp_substr (shipping_instructions, "[^ #] +' 1, 5") zip
, regexp_substr (shipping_instructions, "[^ #] +' 1, 6") County
FROM (select REGEXP_REPLACE (val, ' \.)) () [^.])', ' #\1 ") data shipping_instructions)
(1)'Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234..'
(2)'Bill Johnson.Apartment 3 b. Sterling.VA.20166.3 Falke Plaza. »
"Mary America. 1234 Southridge Park Dr. Samna Lorie. MO.31234..'
NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Married America 1234 Southridge Park Dr.    Samna Lorie MO 31234 NULL VALUE
"Bill Johnson. Apartment 3B. Sterling. VA. 20166. Falke Plaza 3... "
NAME ADDRESS CITY ZIP County SATE
----------------      -----------------        -------       -----        ---         --------
Bill Johnson apartment 3B Sterling, WILL 20166 3 Falke Plaza.
Problem
---------
(1) if the value, if the County (if null) value then it shows the ZIP with dot's (.) value, in the 31234 above..,.
How to solve this problem?
(2) another possible to fix the code, I want to use substr and InStr.
(3) who is the best approach?
Conditions:
--------------
(1) shipping_instructions column has the value with "Mary America.1234 Southridge Park Dr... Samna Lorie.MO.31234... »
This means it combined all the similar name, address, city, State, zip
(2) we insreted in the table separately.
=========================
/ * Use Substr and Instr * /.
=========================
I used substr and instr, but I'm getting the money results (no point in the address).
"America Mary. 1234 Southridge Park Dr. Samna Lorie.MO.31234..'

NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Mary America 1234 Southridge Park Dr. Samna Lorie MO 31234 NULL VALUE
But I need the results (no point in the address)
NAME ADDRESS CITY ZIP County SATE
---------                  --------                                ------------           ------           -------    -- -----
Mary America 1234 Southridge Park Dr.    Samna Lorie MO 31234 NULL VALUE

Hello

994122 wrote:

Hello

(1) how do to do this, use the substr and instr functions?

Thank you

You can't do all the work with SUBSTR and INSTR; you need regular expressions to obtain a string delimited by a #.

Once you have such a string, then you can use SUBSTR and INSTR (instead of REGEXP_SUBSTR) to get the separate secondary strings:

WITH got_delimited_string AS

(

SELECT REGEXP_REPLACE (val

, '\. ([^ .]| $)'

, '#\1'

) AS delimited_string

FROM the data

)

got_pos AS

(

SELECT delimited_string

, INSTR (delimited_string, "#", 1, 1) AS pos_1

, INSTR (delimited_string, "#", 1, 2), pos_2

, INSTR (delimited_string, "#", 1, 3) AS pos_3

, INSTR (delimited_string, "#", 1, 4) AS pos_4

, INSTR (delimited_string, "#", 1, 5) AS pos_5

, INSTR (delimited_string, "#", 1, 6) AS pos_6

OF got_delimited_string

)

SELECT SUBSTR (delimited_string, 1, pos_1 - 1) AS the name

SUBSTR (delimited_string, pos_1 + 1, pos_2 - (pos_1 + 1)) AS address

SUBSTR (delimited_string, pos_2 + 1, pos_3 - (pos_2 + 1)) AS city

SUBSTR (delimited_string, pos_3 + 1, pos_4 - (pos_3 + 1)) AS State

REPLACE (SUBSTR (delimited_string, pos_4 + 1, pos_5 - (pos_4 + 1))

, '.'

)                                                           AS zip

SUBSTR (delimited_string, pos_5 + 1, pos_6 - (pos_5 + 1)) AS the County

OF got_pos

ORDER BY delimited_string

;

data of cutting using substring and instring, and storage in a new table

Hi all

I have an emp_address 2tables, address as below:
---------------------------------------------------------------
create the table emp_address (emp_id varchar2 (10), address varchar2 (100));

Insert into EMP_ADDRESS
(EMP_ID, ADDRESS)
Values
('101', 'street1 fremont CA 94538');
Insert into EMP_ADDRESS
(EMP_ID, ADDRESS)
Values
("102", "Street.2 fremont, CA 94537');
COMMIT;

create the address table (emp_id varchar2 (10), street varchar2 (20), city varchar2 (15), State varchar2 (10), zip varchar2 (10));

-----------------------------------------------------------------------------
Emp_address data as below:

emp_id address

street1 101 fremont CA 94538

102 fremont, CA 94537 Street.2

------------------------------------------------------------------------------
now I read data emp_address and split the data of the address column and record these data in the address table like as below

emp_id Street City State Zip Code
street1 101 fremont, ca 94538
102 fremont, ca 94537 Street.2

-------------------------------------------------------------------

I'm trying to divide these data using substring and instring. Actually my problem was between the data a few times I have 1tab or 2tabs and sometimes 3tab. If the number of tab spaces is not constant.

So can u help me in this case.

Thanks in adavnce

position of reference BluShadow

WITH emp_address AS (SELECT   '101' emp_id,
                              'street1 fremont CA 94538' address
                     FROM     DUAL
                     UNION ALL
                     SELECT   '102',
                              'street2  fremont CA 94537'
                     FROM     DUAL),
    emp_address_list_temp AS
      (SELECT       emp_id,
                    SUBSTR (
                      address,
                      DECODE (LEVEL,
                              1, 1,
                              INSTR (address, ' ', 1, LEVEL - 1) + 1
                             ),
                      DECODE (
                        INSTR (address, ' ', 1, LEVEL),
                        0,
                        LENGTH (address),
                        INSTR (address, ' ', 1, LEVEL)
                        - DECODE (LEVEL,
                                  1, 0,
                                  INSTR (address, ' ', 1, LEVEL - 1)
                                 )
                        - 1
                      )
                    )
                      address,
                    LEVEL rn
       FROM         emp_address
       CONNECT BY   LEVEL <=
                      LENGTH (address) - LENGTH (REPLACE (address, ' ')) + 1
       GROUP BY     emp_id, address, LEVEL),
    emp_address_list AS
      (SELECT   emp_id,
                address,
                ROW_NUMBER () OVER (PARTITION BY emp_id ORDER BY rn) rn
       FROM     emp_address_list_temp
       WHERE    TRIM (address) IS NOT NULL)
SELECT     emp_id,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 1)
             street,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 2)
             city,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 3)
             state,
           (SELECT   address
            FROM     emp_address_list e2
            WHERE    e2.emp_id = e1.emp_id
                 AND rn = 4)
             zip
FROM       emp_address_list e1
GROUP BY   emp_id

A string into the text and numbers using SUBSTR and INSTR

I have the sample data. I know it's terrible database designed for a combination of text and numbers in the same field, but I can't change the business process.
That's what I have so far:
```
set linesize 5000

WITH table_data
     AS (SELECT 'R: JASON BOURNE 12341560' str FROM DUAL UNION ALL
         SELECT 'R: FATS DOMINO 23432342' str FROM DUAL UNION ALL
         SELECT 'R: MARTIN LUTHER KING 3334156' str FROM DUAL UNION ALL
         SELECT 'R: TOM CRUISE 6547123' str FROM DUAL UNION ALL
         SELECT 'R: TOMMY DE GROOT 1212124' str FROM DUAL UNION ALL
         SELECT 'R: GRIM REAPER 1345245' str FROM DUAL UNION ALL
         SELECT 'R: DOCTOR DEATH THE FIRST SMITH 24356178' str FROM DUAL)
SELECT str
     , TRIM(SUBSTR(str, INSTR(str, ' ', 1, 1), INSTR (str, ' ', 1, 2) - INSTR (str, ' ', 1, 1))) first_name
     , REPLACE(SUBSTR(str, INSTR (str, ' ', 1, 2)+1, 999), SUBSTR(str,LENGTH(str)-6,7), '') last_name
     , SUBSTR(str,LENGTH(str)-6,7) emp_num
  FROM table_data;

STR                                      FIRST_NAME    LAST_NAME                 EMP_NUM
---------------------------------------- -----------------------------------------------
R: JASON BOURNE 12341560                 JASON         BOURNE 1                  2341560
R: FATS DOMINO 23432342                  FATS          DOMINO 2                  3432342
R: MARTIN LUTHER KING 3334156            MARTIN        LUTHER KING               3334156
R: TOM CRUISE 6547123                    TOM           CRUISE                    6547123
R: TOMMY DE GROOT 1212124                TOMMY         DE GROOT                  1212124
R: GRIM REAPER 1345245                   GRIM          REAPER                    1345245
R: DOCTOR DEATH THE FIRST SMITH 24356178 DOCTOR        DEATH THE FIRST SMITH 2   4356178

7 rows selected.
```
I need to:
1 extract the first name - which is always the first name after the 'r' - I've got that little works very well.
2 extract the name - should be the last word before the number, if e.g. for the last night, I wish only that 'SMITH' and 'KING' for the 3rd line and "GROOT" for the 5th line.
3. remove the number at the end, regardless of the length - some of the examples above are 8 long numbers so my attempt above does not work.
I can't use any REGEXP or REGEXP_SUBSTR because they are not registered in the EUL I'm using discoverer, I can only use INSTR AND SUBSTR.
I was wondering if someone might be able to help please?
Any advice much appreciated.
Thank you

AW, go on them, as it's Christmas, I'm feeling generous...

SQL > ed
A written file afiedt.buf

1. WITH table_data (SELECT "r: JASON BOURNE 12341560' DOUBLE UNION ALL STR ')
2. SELECT "r: FATS DOMINO 23432342' str OF DOUBLE UNION ALL.
3. SELECT "r: MARTIN LUTHER KING 3334156' str OF DOUBLE UNION ALL.
4. SELECT "r: TOM CRUISE 6547123' str OF DOUBLE UNION ALL.
5. SELECT "r: TOMMY GROOT 1212124' str OF DOUBLE UNION ALL.
6. SELECT "r: GRIM REAPER 1345245' str OF DOUBLE UNION ALL.
7. SELECT "r: DOCTOR DEATH FIRST SMITH 24356178' FROM DUAL str.
8                     )
9 select substr (str, 1, instr(str,' ')-1) as a first name
10, substr (substr (str, 1, instr(str,' ',-1)-1), instr (substr (str, 1, instr(str,' ',-1)-1),' ', 1) + 1) as last_name
11, substr (str, instr (str, ' ',-1) + 1) as emp_num
12 years of (select replace (str,'R: ') as str)
table_data 13
14*        )
SQL > /.

FIRST_NAME LAST_NAME EMP_NUM
---------------------------------------- ---------------------------------------- ----------------------------------------
JASON BOURNE 12341560
FATS                                     DOMINO                                   23432342
MARTIN                                   KING                                     3334156
TOM                                      CRUISE                                   6547123
TOMMY                                    GROOT                                    1212124
GRIM                                     REAPER                                   1345245
DOCTOR SMITH 24356178

7 selected lines.

using substr in the select statement

Hi all
I'll have a column as below from a table values.
"404-297-9559 UNLISTED."
"123 211 2345 KGTFE".
"123 293 2789 GFT.
OUTPUT should be like below... is it possible in sql oracle and my client uses the 8i version.
404-297-9559
123-211-2345
123-293-2789
Thank you
KBS

2804972 wrote:

I gave only for three values of the column as an example, there are millions of records... hard coding is not possible. Please suggest me other

Thank you

KBS

Where does show that you need to hard no matter what code?

The comment in the code indicates that the WITH clause is just used to provide sample data to the query (so I can't create a table in my database). What keeps you using the same query against your own data table? Do you really understand the basic concept of a SQL selection in a table? Did you even try and understand the code?

Is it really that hard for you to have tried to do:

Select substr (yourcolumname, 1, instr (yourcolumnname,' ', 1)-1) as txt

of yourtablename

In the Select statement using substring comparison

Hello
Based on the requirement of the enterprise, I m trying to get geography_element4 to the hz_geographies table that corresponds to the value of the p_city parameter.
Here, I take p_city from the 4th character value to 8 characters.
For under query, I m not getting the correct result. The statement is true? GE.geography_element4 as substr(:p_city,4,8);
SELECT UPPER (ge.geography_element4)
OF apps.hz_geographies ge
WHERE ge.geography_type = "zip_code".
AND ge.geography_name = SUBSTR(:postal_code,1,5)
AND ge.created_by_module = 'EBTAX_CONTENT_UPLOAD. '
AND ge.country_code = 'en '.
AND ge.geography_element4 like substr(:p_city,4,8);
Thank you.

ef2019c7-080c-4475-9cf4-2cf1b1057a41 wrote:

Can I use something like '% substr(:p_city,4,5) % '.

Yes, you should, but using the correct syntax. Do you understand how AS works? It involves wildcards are used in similar Configuration. Otherwise, it's same as equals. Assume that p_city is "FT LAUDERDALE". Then substr(:p_city,4,5) is 'LAUDE '. Then ge.geography_element4 AND as substr(:p_city,4,5) will compare "FT. LAUDERDALE" "LAUDE", of course, without a game. When wrap you it with jokers '% "| substr(:p_city,4,5) | '%' AS get ge.geography_element4 that contains "LAUDE" and "FT LAUDERDALE" will be a game.

SY.

Using substr / instr to analyze a filepath help

I can't parse a string by saying using sql. I have a full path column. The files are similar to:
C:\Users\Guest\Pictures\example.jp
I want to be ablt to simply enter the name of the image file. I worked on several variants of a query by using the function substr and instr function. I came up with the following query. FILEPATH is the name of the column. So far, it gives me the file name, but has the '-' in front of it. Can someone help me get rid of this. Thanks in advance.
```
Select substr(FILEPATH, (instr(FILEPATH,'\',-1,1)))
from Table_Name
where ID = '101'
```
Hello

Here's one way:

SELECT SUBSTR (FilePath

INSTR (FilePath

, '\'

-1

) T

) + 1 + 1 in the end note

) AS file_name_only

Table_Name FROM

ID WHERE = '101'

;

SUBSTR (str, p) returns the last part of the string str, starting at position p. You place the position of the last '-' p; That's why the ' \' was added. If you add 1 backwards, like this:

SUBSTR (str, p + 1) then you're going to be in the way of the position of the character after the last 1 '-'.

Find key words in a string using substr

Hello

I have following values in a column.

uspa-doj-brnz-INT1_SCS_ASCS_DATA-int-m
uspa-doj-brnz-PRD_SCS_ASCS_APP-int-m
uspa-doj-brnz-DEV1_SCS_ASCS_DATA2-int-m
.
.
.
.

I would like to get help from the following keywords before the the first character "_" and the third "-" character. Something like that.

INT1
PRD
DEV1
.
.
.

I made the next attempt. It seems that it works, but I want to know if there is a better way.

substr(regexp_substr(col1, '[^_]+', 1, 1), 15)

Thank you
-Abe

Published by: abe50 on Sep 10, 2012 15:27

abe50 wrote:
I would like to get help from the following keywords before the the first character "_" and the third "-" character. Something like that.
...
I made the next attempt. It seems that it works, but I want to know if there is a better way.
substr(regexp_substr(col1, '[^_]+', 1, 1), 15)

Your version is based on the fact that the first 3 - indications always take up to 15 characters. If this is not guaranteed, so an expression like that could be better.

with testdata as (select 'uspa-doj-brnz-INT1_SCS_ASCS_DATA-int-m' col1 from dual union all
                  select 'uspa-doj-brnz-PRD_SCS_ASCS_APP-int-m' col1 from dual union all
                  select 'uspa-doj-brnz-DEV1_SCS_ASCS_DATA2-int-m' col1 from dual union all
                  select 'uspa2-doj-brnz-DEV1_SCS_ASCS_DATA2-int-m' col1 from dual )
select col1,
       substr(regexp_substr(col1, '[^_]+', 1, 1), 15) original,
       regexp_replace(col1, '^([^-]+-){3}([^_]+)_.+$', '\2') regexp_only
from testdata

COL1                                     ORIGINAL          REGEXP_ONLY
---------------------------------------- --------------------------
uspa-doj-brnz-INT1_SCS_ASCS_DATA-int-m   INT1                       INT1
uspa-doj-brnz-PRD_SCS_ASCS_APP-int-m     PRD                        PRD
uspa-doj-brnz-DEV1_SCS_ASCS_DATA2-int-m  DEV1                       DEV1
uspa2-doj-brnz-DEV1_SCS_ASCS_DATA2-int-m -DEV1                      DEV1

Or even (using a slightly different logic)

       regexp_substr(col1, '[^-_]+', 1, 4)

Published by: W. Sven 11 Sep, 2012 18:18

Use substring of paragraph < $paratext >?

Hi all
FM (we use version 11) allows any type of expressions in variables in order to extract a substring of a paragraph for use in a M/F run? I studied him this as much as possible and I did a search on the forum and the first reactions look promising, although these responses seem to be for older versions...
An example would be a paragraph that looks like this:
Tropical Island - a wonderful place to be
and we only get out
Tropical Island
for M/F running so that we can take advantage of the automatic filling of FM of the header on left pages similar to a dictionary using < [MyTag] $paratext > and < $paratext [+ MyTag] >, only this MyTag is the substring of the paragraph, not the whole paragraph.
I am very grateful for any help or suggestion.
Thank you!

Using Extendscript (or Framescript) would be the way to go, if you have a way to uniquely identify the fractional part of the paragraph text that you need.

On the feature of expression, how you imagine it works on the FM band? A regex expression any? The content will always be pretty unique to get the desired match?

Note: If you head titles were of the type "point - descriptor", then you might have used two separte paratags in Run-in mode to make it homogeneous, but still allow you to use the building blocks <$paratext[...]>.

Optimize the query using SUBSTR

Hi, I wrote the following to get the string 'abc' in the following input strings

' 2010/abc' and
' 2010/inv/abc '.

I have to get the string ("abc") that is after the last ' / '.
In the entrance of the channels the ' / ' can be 1 or 2

So I tried the following

select substr(substr('2010/abc',(instr('2010/abc','/',1,1)+1),length('2010/abc inst')),
(instr(substr('2010/abc',(instr('2010/abc','/',1,1)+1),length('2010/abc inst')),
'/',1,1)+1),length (substr('2010/abc',(instr('2010/abc','/',1,1)+1),length('2010/abc inst')))) str from dual

The Select query above is even working for the string "abc/2010/inv" (until the 2nd "/" only it works)

Could please minimize the above query, and which may even work you for same 3rd or 4th ' / '.

Thank you

Hello

Alternatively, you can use regexp if you want:

Scott@my10g SQL>l
  1  with data as (
  2  select '2010/abc' str from dual
  3  union all select 'inv/2010/abc' from dual
  4  union all select 'inv/2010/inv/2010/abc' from dual
  5  union all select 'abc' from dual
  6  )
  7* select str, regexp_substr(str,'[^/]+$') sstr from data
Scott@my10g SQL>/

STR                   SSTR
--------------------- ----------
2010/abc              abc
inv/2010/abc          abc
inv/2010/inv/2010/abc abc
abc                   abc

It would be up to the end of the string from the last source / (or early if no / in the source string)

REG USING SUBSTR
I want out put like BOTTOM of BOTTOMBUD using susbtr finction.

Can I use select substr ('BOTTOMBUD', 1, 6) of double; for a single word, but I want that whenever the last 3 letters excluded. in this case, they are BUD.

I hope that I am clear on my question. Please suggest.
TRY this SELECT substr ('BOTTOMBUD', 1, 6) FROM DUAL;

Using SUBSTR to convert part of an IP address to a NUMBER and then sort
Hello!

I have a table in APEX that IP numbers and was looking for a way to be able to sort out them.

I wrote the following script:
SELECT TO_NUMBER (SUBSTR (IP, 11)) y
OF NETWORKINFO y
ORDER BY y

Which produces the results I'm looking for.

However, I use the 'FORM ON A TABLE WITH REPORT' by their SUMMIT. It is perfect for what I need, but here's my question:

How can I go about adding my custom SQL string to be able to use the feature to sort of this 'FORM ON A TABLE WITH REPORT "?

In the above form, it gives the ability to sort by any column. Is there a way I could do a column hidden, associated with the IP column to sort results?

Sorry if I'm not in all this that claire here - let me see if I can be more specific.

I have the IP addresses which of course do not sort numerically. So I wrote the SQL script above to convert a portion of these IP addresses in a number format.

Is it possible to combine the two in the search function in 'Form on a Table with report' so I can get a user sort by IP number, but behind the scenes it sorts using the SUBSTR value from above?

Thank you for pointing me in the right direction on this subject!

-Igor
Hi Igor,.

You can get a custom sort order added to your IP column without needing a second column.

Consider that the sorting is done strictly from left to right across a string in the column. The string can be any content valid HTML. So you can wrap your string in, say, a SPAN tag and add an attribute to the tag that contains the sort order, you need to forward the text that is displayed to the user. As long as the attribute is properly structured (in other words, all instances are the same length, for example), then sort will work correctly. For example:
```
SELECT
'' || IP || '' Y
FROM ...
```
Now you must make sure that the PAD_IP_ADDRESS() function returns the correct values. In IP addresses, you have whatever it is "0.0.0.0" to "255.255.255.255". To sort "digitally", you need fill one or two numbers to get three numbers for each value of - so, "0.0.0.0" becomes "000.000.000.000." You can create a function to do this - something like:
```
CREATE OR REPLACE FUNCTION PAD_IP_ADDRESS
(
 pIP IN VARCHAR2
)
RETURN VARCHAR2
IS
 vIP VARCHAR2(15);
 vTEMP APEX_APPLICATION_GLOBAL.VC_ARR2;
 vSEP VARCHAR2(1);
BEGIN
 vSEP := '';
 vIP := '';
 vTEMP := APEX_UTIL.STRING_TO_TABLE(pIP,'.');
 FOR x IN 1..vTEMP.COUNT
 LOOP
 vIP := vIP || vSEP || TRIM(TO_CHAR(TO_NUMBER(vTEMP(x)),'000'));
 vSEP := '.';
 END LOOP;
 RETURN vIP;
END;
```
The result of this would look like:
```
1.1.1.1
2.255.255.255
10.1.199.098
```
Andy

Using SUBSTR

Hi all
I use Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production.
I have the XML_REC column in a table, and the value is lower.
< placeOrder xmlns = "urn:org.kp.pc.placeOrder" > < delegateMrn >07950359< / delegateMrn > < status orderInfo = "SUCCESSFUL" > < guid > 177275 < / guid > < mOrderNum > 2015092617000025027981 < / mOrderNum > < orderNum > 2015092617000025027981 < / orderNum > < date > 20150927 < / date > < delivery > < type > US_MAIL < / type > < mailingAddress > < line1 > 5607 KIVA DRIVE < / line1 > < City > CARMICHAEL < / City > < State > CA < / State > < > 95608 zip < / zip > < singleUse > false < / singleUse > < / mailingAddress > < defaultAddress > < line1 > 5607 KIVA DRIVE < / line1 > < line2 > < / line2 > < City > CARMICHAEL < / City > < State > CA < / State > < > 95608 zip < / zip > < / defaultAddress > < / delivery > < / orderInfo > < rxData costSource = "historic cost". ': zero ' rc = "000" source = "Epic" statusCode = "00" > < MNR relationship 'auto' = >07950359< / MNR > < rx >2566804902< /RX > < rxPreOrderRxNum > 5915638866 < / rxPreOrderRxNum > < rxPostOrderRxNum > 2566804902 < / rxPostOrderRxNum > < nhinId > 0 < / nhinId > < sOrderNum > 2015092617000025027981 < / sOrderNum > < name > CLONAZEPAM 1 MG TABLETS < / name > < invalid > true < / ineligible items > < rxDispenseLocationCode > 591 < / rxDispenseLocationCode > < displayStatusCodes > PHE: 1000 < / displayStatusCodes > < approxReadyDate > 20151004 < / approxReadyDate > < / rxData > < / placeOrder >
The query should return the value as below for the above values and also the order can vary for each value.
DELEGATE_MRN MNR RXNUMBER
7950359 7950359 2566804902

Please, please help me on this.

Thank you

Maybe

with

As XMLDATA

(select xmltype ('))

0019295803

4792958 Z2015092409004934

Z2015092409004934

20150924

 US_MAIL



 218 N SWEETWATER ST

 ANAHEIM

 CA

 92807

 fake

 218 N SWEETWATER ST



 ANAHEIM

 CA

 92807

 0019295803

 107006733859

 107006733859



 900001070

 Z2015092409004934

 SUMATRIPTAN 100 MG TAB SUNP

 true

 70

 PHE:1000

 0019295802

 175307282783

 175307282783



 900001753

 Z2015092409004934

 RATED 3 MG / 24 H CAP BUDESONIDE

 true

 753

 PHE:1000

donnees_xml ')

of the double

)

Select x.*

of xmldata xd.

XMLTable (xmlnamespaces (default ' urn:org.kp.pc.placeOrder'),

"Let's $po: = /placeOrder."

for $i in $po / rxData

return



 {$po/delegateMrn}

 {$i / MNR}

 {$i / rx}



'

in passing xd.xml_data

path of columns delegate_mrn varchar2 (20) "/ ESA/delegateMrn,"

path of varchar2 (20) MNR "/ ESA/MNR."

path of varchar2 (20) RX ' / ESA/rx '

) x

DELEGATE_MRN MRN RX

0019295803 0019295803 107006733859

0019295803 0019295802 175307282783

Concerning

Etbin

DELEGATE_MRN	MRN	RX
0019295803	0019295803	107006733859
0019295803	0019295802	175307282783

RegExp_. Using substr

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