Data serialisieren / String deserialisieren in LabVIEW7.1 nachbauen

Hallo,

Wie kann ich den in LabVIEW8.0 shipping block 'in the string if"&" String in data if "(en 8.5.1 Daten serialisieren/deserialisieren) in LabVIEW7.1 nachbauen?"» Email sharp für Kommunikation CAN-Bus(betrifft die PCAN WRITE.vi und READ.vi), im Internet published über die. VI´s as 7.1 function nicht, da immer dir Eingange "table-oder Stringgrosse, ByteReihenfolge (LITTLE ENDIAN email) und Fehler digitization available sind nicht. Also HAbe schon versucht uber 8.0 downzugraden auf 7.1, aber wie geschrieben, scheitert an den material block

MFG Holger

Hi Holger,

as I told you before: you don't need these additional contributions of "flatten chain! See the attachment to the use of a simple type conversion...

Tags: NI Software

Similar Questions

  • Is there an easy way to get a Date/time string seconds?

    I have 2 strings of the format depending on whether I would like to convert in seconds (since 1900). I need this value to set the t0 in a field.

    Date: ' 30/06/2014 '.

    "Time: '16:06 ' 08."

    Is there a CVI function that will do this conversion for me? If not, is there an easy way to do it?

    Thank you!

    This code should do what you want:



    static time_t calt;
    struct Shared tm tm;
    public static char msg [64];
    public static int AA, mm, DD, hh, mn ss;

    strcpy (msg, ' 2014/06/30 16:06:08 ');

    Extract the date/time string component
    Scan (msg, "%d [x] %d [x] %d [x] %d [x] [x] %d %d", & mm, dd, and yy, & hh, & mn, &ss);)

    Transfer to a struct tm components
    TM.tm_hour = hh;
    TM.tm_min = mn;
    TM.tm_sec = ss;
    TM.tm_year = yy - 1900;
    TM.tm_mon = mm - 1;
    TM.tm_mday = dd;

    Obrtain calendar
    CALT = 0;
    CALT = mktime (&tm);)

  • date/time string

    Hello

    I would like to retrieve information about the last use (date and time) of a user, but I don't know how.

    In my program, the user enters the name of the person they are looking for. The person sought may be used multiple times in a day, or even in the software of the year Labtech or Adam. I would like to retrieve the date and time of the last use of the program for the person.

    I try with the "format date / Time string" but it returns me the same date of my tests.

    Do you have an example

    Thank you


  • date/time string tabs

    Hello!

    I have a problem with the date/time string format VI. I would like to define the date and time with a tab to see the date and time in different columns so when I opened the data written in excellent... but I can´t! I ve tried with \t in the bar code backslash... (% d/%b\t%H:%M:%S%2u), also with concatenate strings with a constant of the tab in the middle... (as illustrated in attached piece) but the extent of my file the tab written as \09 (14/May\0911:00:20.25) s. The strange thing is that when I use \s (space code) it works fine... Why does only not with the tabs?

    Thank you very much for your answers!

    Hi Mia,.

    as I have LV8 + at the moment I can't dig deep - can someone else check this Express VI (stay away from them )

    You can use simple 'write in the text file' calls instead, just use 'picture to a worksheet string' on your data. That's what I'd do... (Express screws are nice start using LabView or quickly write code running - but they hide all the interesting stuff and won't provide any flexibility for special needs!) And they always need conversion into "dynamic data", which also hides the user's information. Did I mention I don't like screws Express?)

  • Daylight Saving Format Date/Time String vs get time in seconds

    Hi all

    I have developed a real-time application using a cRIO 9074 which has two loops. The first gathers data and records the time using the module of ' string of Format Date/time ' with the following time sting: '%d/%m/%Y % H: %m ". The output is a sting with mouth/day/year hour: minute.

    The second loop Gets the cRIO time using the module "get Date/Time in Seconds ' and the output of timestamp is sent by a shared variable for an application that is running on a local computer.

    The problem started Sunday last with DST. With the help of MAX I am able to see that the time of cRIO is bad (1 hour less) and that him "automatically adjust clock for daylight saving time" is not checked and gray, so I am not able to change it.

    The time of the first loop by using the "Date and time Format string' returns the time elapsed between the cRIO (1 hour late), however the time of the second loop is OK. I have manually corrected time using MAX, so now the first loop is correct, and the second is now over an hour.

    Any ideas?

    Dear RavensFan, thank you very much for your answer.

    However, this was not the problem. Apparently the result with or without the element of DST is the same. I solved the problem, for now, by changing a parameter not on the function "get Date/Time in Seconds" but on the time stamp indicator.

    By right clicing the indicator and go to the display Format and the advanced editing mode, I have changed the Format string to a universal time container of this: %< %="" h:="" %m="">< t="" %="" ^="">< %="" h:="" %m=""><>

    Apparently the time from the 'get time in seconds' is still an hour longer, but now it is correctly displayed.

  • From dynamic data to string

    Hello

    I would like to convert my dynamic data (4 channels and time) to sink chain (I use UDP write).

    I tried to build a table and then use Nnmber to the fractional frequency range, but I can't wire both, because it's 1 d array of string.

    Thanks for your help!

    Sarah

    have you checked Array to string of worksheet function
    ?

  • Get date friendly String

    Hi all

    I try to get Sunday, August 15, 2010-08 - 15. I divided the date and everything works without error when I call myDate.toString (); It does not give the desired result.

    Calendar calendar = Calendar.GetInstance ();
    Calendar.Set (Calendar.DAY_OF_MONTH, Integer.parseInt(second[2]));
    Calendar.Set (Calendar.MONTH, Integer.parseInt(second[1]));
    Calendar.Set (Calendar.YEAR, Integer.parseInt(second[0]));

    Date myDate = calendar.getTime ();

    Can someone tell me what I need to do next to get Sunday, August 15?

    Thank you

    Alex

    Try this,

    This code gives u what you want

            Date date = new Date();
            date.setTime(System.currentTimeMillis());
            String str=date.toString());
    

    -------------------------------------------------------------------------------------------------------

    Press Button Kudoes to say thanks to your help, if got the answer and the press also accept as a Solution button.

  • Orchestrator Timer Date Time String pending

    Using VCenter Orchestrator - I have a workflow that will get kicked off via the REST API but the only option of entry, I have my users POV is a string.

    The entrance to the user should look something like 2:125 9 mai 2016:50 PM or similar.

    Is there a way for me to format the string/pass one string in the workflow and the value of the timer to wait on this entry object?

    Any help would be appreciated.

    Thank you.

    OK, if you want to get a value of the user string and convert it into a Date object to be able to link it to the timer.date of the timer element attribute on hold?

    The string to date conversion can be done easily. Here is a code example:

    var datestr = "May 9, 2016 2:25:50 PM";  // user-provided date string
    var dt = new Date(datestr); // parses the string and creates an object of type Date
    System.log(dt);  // log the Date object value
    
  • Date to string chips

    A string like
    foo#yyyymmdd#.txt
    How regexp_replace can be used to replace the #... token # with a date (e.g. sysdate) in this format? A tried
    regexp_replace(?,'#([^#])+#',to_char(sysdate,'\1'))
    but the replacement for regexp_replace string must be a string, not a function.

    Or maybe forget regexp_replace and wrap the rest of the string in double - quotes * "foo" YYYYMMDD ".txt" * and that move simply as a to_char() and Oracle date format let alone the part in quotation marks.

    Thoughts? Thank you

    Hello

    HELEN wrote:
    A string like

    foo#yyyymmdd#.txt
    

    How regexp_replace can be used to replace the #... token # with a date (e.g. sysdate) in this format? A tried

    regexp_replace(?,'#([^#])+#',to_char(sysdate,'\1'))
    

    but the replacement for regexp_replace string must be a string, not a function.

    Yes, the argument must be a string, but the function returns a string. The above error is that the 2nd argument TO_CHAR is "\1".

    Or maybe forget regexp_replace and wrap the rest of the string in double - quotes * "foo" YYYYMMDD ".txt" * and that move simply as a to_char() and Oracle date format let alone the part in quotation marks.

    Thoughts? Thank you

    If you know the format:

    REGEXP_REPLACE ( str
                , '#[^#]*#'
                , TO_CHAR (SYSDATE, 'YYYYMMDD')
                )
    

    If the format is between the signs #:

    REGEXP_REPLACE ( str
                , '#[^#]+#'
                , TO_CHAR ( SYSDATE
                            , TRIM ( BOTH '#' FROM
                             REGEXP_SUBSTR ( str
                                    , '#[^#]+#'
                                  )
                        )
                    )
                )
    

    Note that, in both cases, the 3rd REGEXP_REPLACE argument is the string returned by a function.

    Published by: Frank Kulash, November 21, 2012 15:14

    I hope that answers your question.
    If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
    Explain, using specific examples, how you get these results from these data.
    Always say what version of Oracle you are using (for example, 11.2.0.2.0).
    See the FAQ forum {message identifier: = 9360002}

  • problems by analyzing a date format string...

    Hi all, I'm having a hard time to convert a date into a string.

    I was using to_char but after much research, I thought that it would be better to use convert so I do:

    SELECT CONVERT (VARCHAR (8), 'November 19, 2012', 112) twice;

    Where the specifications for 112 is YYYYMMDD but I get the error "ORA-00936: lack of expression ', guess is cause Oracle do not know how to read the string to be converted.

    How can I convert a YYYYMMDD string format string of the form dd mmm yyy (as described above)?

    Thanks in advance,

    It seems that your search will lead you to a SQL Server thread. SQL Server uses arbitrary numbers to represent date formats. Oracle does not - the number 112 is irrelevant for Oracle.

    In Oracle, you convert a date to a string using the function TO_CHAR

    SELECT to_char( date '2012-11-19', 'YYYYMMDD' )
      FROM dual
    

    Of course, this assumes that you start with a date (like I do with my date literal). If you start with a string representing a date and you want to convert it to a string that represents the same date in a different format, you will need to use a TO_DATE and a TO_CHAR to convert the original string to a date and date on another string

    SELECT to_char( to_date( '19 Nov 2012', 'DD Mon YYYY' ), 'YYYYMMDD' )
      FROM dual
    

    Justin

  • How to convert the types of RAW data to string

    Is a feature that allows you to convert Raw data channel/CHRA type Hello in 10g env.
    My column has a data type RAW (100 bytes). I need to extract the string equivalent.

    Thanks in advance for any hlp.

    Thank you
    SD

    UTL_RAW.cast_to_varchar2 ();

  • Date to the Date object string

    Hello

    How I'd go on parsing the date in DD/MM/YYYY format strings in a date objects. I'm sure its an easy problem but I can't find a simple way to do as most of the API wants a different format as DD/MM/YYYY

    Thanks for any help

    Hello

    in the actionscript 3.0 Cookbook, there is a class DateFormat described, which allows to parse strings of objects date.

    You can download the code for the dateformat.as from there.

    http://www.rightactionscript.com/ASCB/

    Best regards
    Kcell

  • Date format string SQL Conveting XML

    Hi all
    I have a question where a date that comes as input to a string format must be inserted into a database is Timestamp. Can someone help me on this...

    the date format which I recive is '2008-08-01' where "yyyy-MM-DD" I have to convert it in the format "YYYY-MM-ddTHH" Help with this convert Timestamp would be a great help.

    Hi Sissi,
    Please use the format-dateTime function in xslt and to generate the time portion of the date, use the '00' instead of hh, mm, and ss. This function automatically converts an XML datetime SQL string.

    The function will look like this - dateTime(YYYY-MM-DDT00:00:00) format.

    Concerning
    AYUSH

  • variable presentation changing the data type date to string the Calende

    Hi gurus,

    I'm having a strange problem. I have a Start date and end date fast that aren't on any column presentation for example (in the case where 1 = 0 DATE. DATE other cast ('2100-12-31 Date ') end).
    Now, this prompt, I put 2 startdate and enddate variables presentation to use in my sql filter in the report.i use these variable to calculate the date for these 2 end dates and then I apply between it function with these 2 dates.
    The question is when the dashboard is running for the first time the presentation variable takes the dates as the DATE "' 2009/14/10 and when I change the date and click on the go button, the variables is October 15, 2009" as strings anf so DATE in my SQL filter functions fails and error throughts VD.

    All of the suggestions!

    Nico explain already.

    Select date '' 2009-12-15 of the double - TRUE
    Select date of 2009 '-15-12' of the double - ORA-01843: not one month valid
    Select date ' 10/2009/15 ' of double - ORA-01861: literal does not match the format string

    DATE 'yyyy-mm-dd' does that have this format.

    Concerning
    Goran
    http://108obiee.blogspot.com

  • Sort Date in string model

    My xml data:
    <? XML version = "1.0" encoding = "UTF-8"? >
    < p0 >
    < p1 > < d2 > 11 March 09 < / d2 > < / p1 >
    < p1 > < d2 > 4 August 09 < / d2 > < / p1 >
    < p1 > < d2 > 3 March 09 < / d2 > < / p1 >
    < p1 > < d2 > 22 March 09 < / d2 > < / p1 >
    < / p0 >

    I want to sort the data according to the date, but the xml data in d2 are of type string that I can't change in the source of data due to some restrictions.
    so all that I can to sort out the model only, pls tell me a way to do this.
    I tried the following, but it does not work.


    <?-foreach: p1? > <? fate: to_date(d2,'dd-mon-yy');' ascending '; data-type = "text"? >
    <? D2? > <? end foreach? >

    Clues here?

    Thank you
    Mouly
    
    
    
    
    

Maybe you are looking for