Determine whether an array contains elements of another array

I have an array whose length is not know (TABLE 1)
I have another array whose length is known (TABLE 2)

I have to see if the table 1 contains elements of table 2 and then form another array that contains elements that are not present in the table Array1.
The values that I face is int values. Also I don't know if I should use tables or any other collection.
I tried to go an and compare other but does not know this exceptionas of arrayIndexoutOfBound gives the length of table 1.
Please suggest how to proceed.

Thank you

>
I want to do another painting where I can put the elements that are in array2, but not in the table array1. How to make
>
There are several ways to do so. Where is the best depends on how many items it can be in each table, if the elements, or both, the tables are already in a sorted order, and if these are real berries or instances of a Collection class.

If you want to just brute force, then we forget about loops nested and just do the simple way. Here is pseudocode, which should be enough for you to write correct code. This method is very effective for all but very little evidence of the table

boolen existsInArray1;
ArrayList array3 = new ArrayList;
-for each element (index value) in array2 loop
     -if notExistsInArray1 (array2[index]) then
            array3.add(array2[index]);
     -end if
-end loop

-new method returns true if parameter exists in array1
public boolen notExistsInArray1 (int myInt) {
    - for each element (index value) in array1 loop
           if array1[index] = myInt return true;
    -end loop
    return false;
}

For a larger number of items you could order to each of the tables in the order, then through table array1 array2 looking for the item. You would keep track of each index value of paintings. If the first element of the array array2 is smaller than the first element of the array array1 it cannot therefore in the table because the list is sorted. So you increment the index of table 1 and test again.

This method is similar to the way in which two sorted files are merged or mapped.

Another way is to create a GAME (does not allow duplicates) for the elements of the array array1 and then use the 'contains' to check each element of the array array2 to see if it belongs to the whole.

CollectionUtils Apache Commons Library also has a method "disjunction".
http://Commons.Apache.org/collections/apidocs/org/Apache/Commons/Collections/CollectionUtils.html

disjunction
public static java.util.Collection disjunction(java.util.Collection a,
                                               java.util.Collection b)Returns a Collection containing the exclusive disjunction (symmetric difference) of the given Collections.
The cardinality of each element e in the returned Collection will be equal to max(cardinality(e,a),cardinality(e,b)) - min(cardinality(e,a),cardinality(e,b)).

Tags: Java

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