difference between 2 dates

Similar Questions

• How to calculate the difference between a Date column and the Date yesterday in the analysis (in the formula in the column)

  . For example, I need to calculate the difference between a date column, 'Table_Name '. "' Column_Name ' and (Current_Date-1). I tried different ways to do this. But nothing seems to work.

  Try the below formula.

  Replace "Time". "" Date "with your column.

  TIMESTAMPDIFF (SQL_TSI_DAY, "Time". "Date", TIMESTAMPADD (SQL_TSI_DAY-1, CURRENT_DATE))

  Thank you!

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• Difference between 2 dates using PHP

  Hello

  Having some problems with the calculation of the difference between 2 dates.

  I noticed that about half of the results output 552 months... where is should be approximately 24 months...

  I also noticed that records that display this incorrect calculation having the month following the date less than the current month, it fixed $date2 as 01/01/1970

  This is the code:

  <? PHP

  Calculate the remaining months

  $date1 = date('d/m/Y');

  $date2 = $renewal_row ["enddate"];

  $date2 = date (a/m/Y ", strtotime (str_replace ('. ', ' ' ', $renewal_row [' enddate ']', $renewal_row ['enddate']))");

  $diff = abs (strtotime ($date2) - strtotime ($date1));

  $years = floor ($diff / (365 * 60 * 60 * 24));

  $months = floor (($diff-$years * 365 * 60 * 60 * 24) / (30 * 60 * 60 * 24));

  $days = floor (($diff-$years * 365 * 60 * 60 * 24-$months * 30 * 60 * 60 * 24) / (60 * 60 * 24));

  printf ("%d years, %d months, %d days\n", $years, $months, $days);

  $months_remaining = ($years * 12) + $months;

  ? >

  <? PHP echo "$date1 ='.strtotime ($date1).» ('. $date1.) ") date2 = '.strtotime ($date2).' ('. $date2.) ('') = Difference'. $diff;? >

  The date correct difference between these dates:

  $date1 = 1452038400 (06/01/2016) date2 = 1520035200 (03/03/2018) difference = 67996800

  Day with incorrect difference:

  $date1 = 1452038400 (06/01/2016) date2 = 1452038400 difference =(20/11/2016)

  Note that if the $date2 month exceeds the month current (June) it messes up.

  Any help would be appreciated!

  Assuming that this ["enddate"] $renewal_row is stored in a MySQL/MariaDB DATE, DATETIME, or TIMESTAMP column.

  $now = new DateTime();

  $end = new DateTime ($renewal_row ['enddate']);

  $time_remaining = $now-> diff ($end);

  echo $time_remaining-> format (' %m month %d days ");

• How do the time difference between two dates?

  Hi all
  
  I use this query to get the time difference between two dates.
  
  Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;
  
  but do not get the correct result.
  
  Thank you

  Left KEY... Left Padding of tanks.

• differences between the Data Pump to back up the database and use RMAN?

  What are the differences between the Data Pump to back up the database and use RMAN? What is DISADVANTAGES and BENEFITS?
  
  Thank you

  Search for the backup of the database in

  http://docs.Oracle.com/CD/B28359_01/server.111/b28318/backrec.htm#i1007289

  In brief

  RMAN-> physical backup. (copies of the physical database files)

  DataPump-> logical backup. (logical data such as tables, procedures)

  Docs for RMAN-

  http://docs.Oracle.com/CD/B28359_01/backup.111/b28270/rcmcncpt.htm#

  Datapump docs

  http://docs.Oracle.com/CD/B19306_01/server.102/b14215/dp_overview.htm

  Published by: Sunny kichloo on July 5, 2012 06:55

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to know the difference between the Dates in Oracle.

  Hello
  
  Suppose we have two Dates say November 5, 2005 and October 12, 2007.
  
  Is it possible to know the total difference between these Dates in Oracle.
  
  Thank you

  You can subtract date-objects. The result is the difference in days.

  select  to_date('12-10-2007','DD-MM-YYYY') -  to_date('05-11-2005','DD-MM-YYYY')   from dual;
  

  In your example: 706 days

  Published by: hm on 25.10.2010 12:33

  Please look also for "Oracle Date arithmetic" in the Oracle Documentation or Google.

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• Calculation of the difference between the dates.

  All,
  I have a requirement where I need to calculate the difference between the dates. If the given date is less than the current date, it should return '0' (zero) other wise should return 1. How can I do this?
  
  Kind regards
  Vinciane

  and with a CASE statement...

  SQL> ed
  Wrote file afiedt.buf
  
    1  select case when to_date('01/11/2008','DD/MM/YYYY') /
  
    DATECOMP
  ----------
           0
  
  SQL>
  

• Difference between two data aquistion

  Hello

  I got a data aquistion system that is supposed to keep data acquisition selection until the difference between two points a lot. For example, I get voltage (mv) as 2.31, 2.32, 2.34. 2.33 2.32, 2.33 2.32. the data up to a point, say 0.1V higher or lower than the first. Thewhole procss stop. Thank you for your suggestions.

  Try this... (Labview 8.2)

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• Difference between two dates

  Hello

  I have two columns both of them date data types.

  I would like to know the difference between these two dates.

  SELECTION INTERVAL ' + 2342 23:23:23 ' DAY (4) TO THE SECOND - INTERVAL ' + 102 13:13:13 ' DAY (4) SECOND FROM DUAL;

  But, I get this:

  '+ 2240 10:10:10.000000'

  I'd like to see the result in a year-month and jour-deuxieme groups. I can't do anything with + 2240 days...

  Thanks in advance!

  Hello Adme12

  You can use it.

  SET LINESIZE 110 PAGESIZE 20

  COLUMN today FORMAT A20

  COLUMN TOMORROW FORMAT A20

  COLUMN YEAR_MONTHS FORMAT A15

  COLUMN DAY_SEC FORMAT A30

  SET ECHO ON

  SELECT TO_CHAR (today, ' JJ.) MR. HH24:MI:SS' YYYY) LIKE TODAY

  , TO_CHAR (tomorrow, ' JJ.) MR. HH24:MI:SS' YYYY) TOMORROW

  NUMTOYMINTERVAL (MONTHS_BETWEEN (TOMORROW, TODAY), 'MONTHS') AS YEAR_MONTHS

  , NUMTODSINTERVAL (TOMORROW - ADD_MONTHS (TODAY, TRUNC (MONTHS_BETWEEN (TOMORROW, TODAY))), 'DAY') AS DAY_SEC

  Of

  (SELECT SYSDATE + INTERVAL ' + 102 13:13:13 ' DAY (4) ON THE SECOND THAT TODAY ' HUI)

  , SYSDATE + INTERVAL ' + 2342 23:23:23 ' DAY (4) ON THE SECOND TOMORROW

  OF THE DOUBLE

  )

  ;

  TODAY TOMORROW YEAR_MONTHS DAY_SEC

  -------------------- -------------------- --------------- ------------------------------

  23.04.2014 04:49 10.06.2020 14:59:10 + 000000006-02 + 000000018 10:10:10.000000000

  Of course, it is not so good that you have so many 0, but you can convert the result to a char (TO_CHAR) and you can enter.

  I hope this helps you!

  Kind regards

  David

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• Difference between two dates in the server behaviors

  Hello all,.

  I am trying to create a Recordset by using server behaviors and that I'm not an expert in php, I'm completely lost...

  The problem is this: I want to find in a table of all the records where the difference between today's date and date of creation (stored in this table, although course) is superior to, say 30 days. How can I specify the variable field?

  Thank you very much in advance for your help!

  You must use a sql like query below:

  SELECT * FROM table WHERE creationDate< date_sub(now(),="" interval="" 30="">

  'table' is the name of the table that you want to select the information of and 'creationDate' being the column 'date' in the database