Difference in size of file in LR and PS

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  Hi team,

  I do view Vsphere 5.2 implementation Horizon. Implementation goes smoothly, but I saw a c disk space difference of Parent and Linked clone.

  Windows 7 with Service pack 1 built with optimization script to disable unwanted services. Free space on the drive c image parent is 3.90 Go. When I put in service a clone related in this snapshot of parent picture I found free space in linked clone vdi is about 6.5 GB.

  Please specify if anyone face the same or it is normal in the linked clone.

  Thank you

  Ravindra.

  You use a disposable disc?    When you use a disk file page flies on this disc which may explain the difference in free space.

• Differences in size of image in PS and email

  Hello

  I received an email with an attachment that was 575 k, and then when I open it in PS, it says it's 3.3 M. Why is - this?

  Thank you for your help in advance.

  Fenny

  Most of the images sent email are jpg and compressed files to save space.  Once you open the file, it is is more compressed and PS shows how the document is large.  Once that save you it as a jpg file, once again, it will show the file size small.

• How can I get rid of the file name, date and size of the photo in the upper left corner of the module develop when I'm not working on the photos?

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• What is the difference between the cat of the IR and IR data files in lightroom it please

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  The.lrcat is the file in your catalog. This is an important safeguard.

  The .lrdata files have previews. These can always be regenerated from the library, but it could take some time a large catalog.

  It is advisable to save them both. But if you are short on disk space, save the .lrcat file.

• What is the difference between size function and aggragate function?

  Hi Experts,
  
  In OBIEE 11.1.1.6.0, what is the difference between size function and aggragate MDB measure column function?
  If it contains material or detail information, I am very grateful to you.

  Hello

  Good example with screenshots-

  http://www.clearpeaks.com/blog/Oracle-BI-EE/aggregation-based-on-dimensions

  Mark this reply / helped.

  Concerning
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• What is the difference between the file httpd.pid and httpd.lock?

  What is the difference between the file httpd.pid and httpd.lock?

  Salvation;

  Apache httpd saves the id of the httpd process parent in the file logs/httpd. PID.

  LockFile

  Sets the path to the lock file used when Oracle HTTP Server is compiled with USE_FCNTL_SERIALIZED_ACCEPT or USE_FLOCK_SERIALIZED_ACCEPT. It is recommended that the default value be used. The main reason for changing it is if the logs directory is NFS mounted, since the lock file must be stored on a local disk.

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• difference between online redolog files and archived log files

  What is the fundamental difference between archived log files and online redo log files? .. .plz keep things simple as m a newbie

  Online redo log:

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  See here,
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  Archived redo log:

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  See here,
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  Thank you

• Pole #1 PC Performance and RAM: quantity, average, maximum size of files Adobe

  Do a little research here regarding the performance of the PC and the main memory/RAM.

  If you all could estimate/Riddle the minimum and maximum amount of files Adobe program, as well as file sizes, by each program (Illustrator, Photoshop etc...) I drop the results into a spreadsheet and provided details to etc. (at least attempt, based on number/quantity of participants, if the top I'll provide statistics at the end).

  Also indicate what is the size of the file you usually launched and how many of them. These averages are expected to produce some very interesting/useful information.

  More people who best meet of course (unless this has been done or his stats there somewhere already).

  Since I work mostly in Illustrator, these are the files that I took to target when looking for my storage by specifying the .ai extension. (both bad operating system couldn't do the math).

  I specifically made the research by entering the generic asterisk before the file extension, for example: * .ai, then by specifying all storage locations (Windows, choose 'My Computer' etc., Mac do not know, I have one, just don't use it often so that if anyone would care to specify it).

  For windows, the status bar at the bottom of the window has provided total number of files. To get out of the category, I've just enlarged screen and first counted the number of files poster by scrolling the window. Then moved/positioned column size of file, you click this header to sort etc. from the bottom up, then began to scroll the window with a simple click of mouse (not by the arrows) and counted the pages for the file/category varies so thought to them.

  My results (rounded):

  Illustrator

  Total files: 900 +.

  Min. size: 3KB

  Maximum size: 300, 00KB (or 300 MB)

  Based on the results of research and my some quantities of products and file sizes, I created 5 file size categories:

  1-0-1, 000 KB(1MB)

  2 1, KB(1MB) - 2, KB(2MB) 000 000

  3 2, KB(2MB) - 10, 000 KB(10MB) 000

  4 10, 000 KB(10MB) - 50, 000 KB(50MB)

  5 200, 000 KB +.

  360 files in category 1

  300 cases in Cat. 2

  220 files Cat. 3

  30 files in Cat. 4

  5 files in Cat. 5

  * There are duplicates

  Average of Adobe programs and files of launched/open all day (or work them)

  Illustrator: 2-5 or 10 files a few cat. 3, 1 in category 5 to 300 000 KB

  Absolute maximum load

  Illustrator, launched with 2,300, 00 KB (300 MB) of files, maybe 5 Cat. 3 and 5 Cat. 4, 850 000 Ko charge total (850 MB)

  If someone elsehas another suggestion of structure for the post categories please, seemed to me these adapted my amount of files.

  The information in it would be very helpful/insightful with regard to material resources and system performance is affected. It will also be interesting to see how the Illustrator compares to Photshop (and other programs).

  I'll also post this in the forum of Photoshop.

  [I wonder why copy what hinders a message from one forum to another formatting, adding of additional places at random]

  THX

  function() {return A.apply (null, [this] .concat ($A (arguments)))}

  150 views, by a global forum, and they can be repeated without participation except one > interesting

  Perhaps 150 users were curious what kind of question can have been displayed on a stick (pole).

  Find "survey."

  JET

• What is FAT, FAT32 & NTFS maximum file size of file systems supported? File system of all the methods of the passage of FAT & FAT32 to NTFS without formatting is appreciated.

  What is FAT, FAT32 & NTFS maximum file size of file systems supported? File system of all the methods of the passage of FAT & FAT32 to NTFS without formatting is appreciated. (IE without deleting the files from a particular disk).

  Difference between material FAT & FAT32?

  I have a disk full of files, and it is in the FAT32 file system. As I can't copy large files (5 GB +) in this player, I intend to fix this by changing the file systems. Apparently, it is not possible to do it without formatting. I am curious about a way to do this without destroying the drive.

  Thanks in advance.

  Eguy

  Tuesday, October 9, 2012 16:55:51 + 0000, Eguy wrote:

  What is FAT, FAT32 & NTFS maximum file size of file systems supported? File system of all the methods of the passage of FAT & FAT32 to NTFS without formatting is appreciated. (IE without deleting the files from a particular disk).

  Difference between material FAT & FAT32?

  First, note that there are three varieties of FAT: FAT12, FAT16, and
  FAT32. Many people call just FAT16 FAT, because before that FAT32 is out.
  FAT16 is the only variety used for hard drives, so just
  The FAT was not enough.

  FAT12 (hardly any more used) had a maximum volume size of 12 MB.
  It has been used almost exclusively for floppy disks.

  FAT16 was used on hard disks (or partitions) up to 4 GB and had a
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  the partition. It serves almost never again, because almost nobody does
  a as small as 4 GB partitions.

  FAT32 FAT16 succeeded and has a maximum drive size of 2 TB. His
  maximum file size is 4 GB, which explains why you can't copy a file of 5 GB to
  it. its cluster size is 4 KB up to an 8 GB partition. Beyond 8 GB the
  cluster size develops up to 32 KB.
  NTFS, that's what almost everyone should use on their hard drives
  today. Its maximum volume size is 2 ^ ^ 64-1 and its maximum file size
  16 × 1024 is ^ ^ 6 bytes (much more than the bigger hard drive available
  today). Cluster size is 4 KB, regardless of the size of the volume.

  I have a disk full of files, and it is in the FAT32 file system. As I can't copy large files (5 GB +) in this player, I intend to fix this by changing the file systems.

  Good! You should.

  Apparently, it is not possible to do it without formatting.

  It's not correct. To convert to NTFS, use you the CONVERT
  command. But first read http://www.aumha.org/a/ntfscvt.htm , because
  There is an important question about the size of cluster that is not obvious.

  Also note that conversion is an important step, touching everything on your
  drive. When you take a big step, no matter how unlikely it is
  always possible that something can go wrong. For this reason, there
  careful to make sure that you have a backup of everything you can not afford to
  lose before you start.

  Ken Blake, Microsoft MVP

• DW shows not sizes correct file in the files Panel

  Hello

  I use DW CC 2015.1 on Mac 10.10.5.

  I notice a difference in file size.

  In the finder if I discover a Quicktime move, it indicates the size of the file is 313.1 MB. DW, said that the same file 298,63 MB.

  DW displays all file sizes smaller than what indicates the operating system.

  I also took a glance on my second Mac that is running 10.11.3 and the same thing. State of Mac OS 313,1, DW on Mac (same versions DW) indicate less large files.

  Anyone else notice this? Is this a bug in DW or a problem with the operating system?

  I did not pay attention as much file size differences to be honest, because I do not transfer or work with files that large in DW sizes.  However, if you're not a Mac user for a long time, there was an update of how Mac computes sizes of files made back in Snow Leopard (10.7).  I suspect that DW used the other method of calculating file size and not the new method that apple used.  I worry too much on this subject.  The only place I would look at is your host if they have a limit to the size of the file.

  Here's an article that explains the change: math new Snow Leopard | Macworld

• DB file sequential read and read of the direct path

  Hello
  
  Could someone please clear my doubts about 'db file sequential read' and ' path direct reading. And help me understand the tkprof report correctly.
  Please suggest if my understanding for scenario below is correct.
  
  We have a 11.2.0.1 ' cluster 2 node rac version + asm' production and environment of his test environment that is a stand-alone database.
  The query performs well in production compared to the test database.
  The table is to have 254 + columns (264) with many lobs coulumns however LOB is not currently selected in the query.
  I read in metalink this 254 table + column a intra-line-chaining, causing "db file sequential read" full table Scan.
  
  Here are some details on the table which is similar to the prod and test, block size is 8 k:
  

  TABLE                             UNUSED BLOCKS     TOTAL BLOCKS  HIGH WATER MARK
  ------------------------------  ---------------  ---------------  ---------------
  PROBSUMMARYM1                               0          17408          17407

  What I understand less tkprof in production environment for a given session is:
  1 - the request resulted in disk 19378 readings and 145164 consistent readings.
  2 19378 disc bed, 2425 reads disc has given rise to the wait event 'db file sequential read'.
  This statement is correct this disc remaining readings were "db file sequential reads" but real quick so didn't wait event tied to it?
  3 - 183 'direct path read' there also. Is it because of the order by clause of the query?
  
  

  SQL ID: 72tvt5h4402c9
  Plan Hash: 1127048874
  select "NUMBER" num 
  from
   smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' 
    order by num asc
  
  
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        1      0.00       0.00          0          0          0           0
  Execute      1      0.00       0.00          0          0          0           0
  Fetch        1      0.53       4.88      19378     145164          0           0
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total        3      0.53       4.88      19378     145164          0           0
  
  Misses in library cache during parse: 0
  Optimizer mode: ALL_ROWS
  Parsing user id: SYS
  
  Rows     Row Source Operation
  -------  ---------------------------------------------------
        0  SORT ORDER BY (cr=145164 pr=19378 pw=0 time=0 us cost=4411 size=24 card=2)
        0   TABLE ACCESS FULL PROBSUMMARYM1 (cr=145164 pr=19378 pw=0 time=0 us cost=4410 size=24 card=2)
  
  
  Elapsed times include waiting on following events:
    Event waited on                             Times   Max. Wait  Total Waited
    ----------------------------------------   Waited  ----------  ------------
    SQL*Net message to client                       1        0.00          0.00
    ges message buffer allocation                   3        0.00          0.00
    enq: KO - fast object checkpoint                2        0.00          0.00
    reliable message                                1        0.00          0.00
    KJC: Wait for msg sends to complete             1        0.00          0.00
    Disk file operations I/O                        1        0.00          0.00
    kfk: async disk IO                            274        0.00          0.00
    direct path read                              183        0.01          0.72
    db file sequential read                      2425        0.05          3.71
    SQL*Net message from client                     1        2.45          2.45

  The same query when ran in no no rac - asm test stand alone database has given below tkprof.
  Does this mean that:
  1-here too, reads happen through "db file sequential read", but they were so fast that has failed to the wait event?
  2. "direct path read," it's because of the order clause in the query. "
  

  SQL ID: 72tvt5h4402c9
  Plan Hash: 1127048874
  select "NUMBER" num 
  from
   smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' 
    order by num asc
  
  
  call     count       cpu    elapsed       disk      query    current        rows
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        1      0.00       0.00          0          0          0           0
  Execute      1      0.00       0.06          0          0          0           0
  Fetch        1      0.10       0.11      17154      17298          0           0
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  total        3      0.10       0.18      17154      17298          0           0
  
  Misses in library cache during parse: 0
  Optimizer mode: ALL_ROWS
  Parsing user id: SYS
  
  Rows     Row Source Operation
  -------  ---------------------------------------------------
        0  SORT ORDER BY (cr=17298 pr=17154 pw=0 time=0 us cost=4694 size=12 card=1)
        0   TABLE ACCESS FULL PROBSUMMARYM1 (cr=17298 pr=17154 pw=0 time=0 us cost=4693 size=12 card=1)
  
  
  Elapsed times include waiting on following events:
    Event waited on                             Times   Max. Wait  Total Waited
    ----------------------------------------   Waited  ----------  ------------
    SQL*Net message to client                       1        0.00          0.00
    Disk file operations I/O                        1        0.00          0.00
    db file sequential read                         3        0.00          0.00
    direct path read                              149        0.00          0.03
    SQL*Net message from client                     1        2.29          2.29

  For trace files in the database Production and Test, I see that 'direct path read' is against the same data file that's stored table.
  Then how come 'this direct path read' because of the order by clause of the query and would have been in sort field size or pga?
  Or this direct path read extracts real PGA disk data, and "db file sequential read" do not extract data?
  I know, it's 'direct path read' is wait event when data are asked in PGA drive or what kind segment or temp tablespace is used.
  
  Here is the example of trace file in the Production database:
  

  *** 2013-01-04 13:49:15.109
  WAIT #1: nam='SQL*Net message from client' ela= 11258483 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278555109496
  CLOSE #1:c=0,e=9,dep=0,type=1,tim=1357278555109622
  =====================
  PARSING IN CURSOR #1 len=113 dep=0 uid=0 oct=3 lid=0 tim=1357278555109766 hv=138414473 ad='cfc02ab8' sqlid='72tvt5h4402c9'
  select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc
  END OF STMT
  PARSE #1:c=0,e=98,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278555109765
  EXEC #1:c=0,e=135,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278555109994
  WAIT #1: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278555110053
  WAIT #1: nam='ges message buffer allocation' ela= 3 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555111630
  WAIT #1: nam='enq: KO - fast object checkpoint' ela= 370 name|mode=1263468550 2=65610 0=1 obj#=-1 tim=1357278555112098
  WAIT #1: nam='reliable message' ela= 1509 channel context=3691837552 channel handle=3724365720 broadcast message=3692890960 obj#=-1 tim=1357278555113975
  WAIT #1: nam='ges message buffer allocation' ela= 2 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555114051
  WAIT #1: nam='enq: KO - fast object checkpoint' ela= 364 name|mode=1263468550 2=65610 0=1 obj#=-1 tim=1357278555114464
  WAIT #1: nam='KJC: Wait for msg sends to complete' ela= 9 msg=3686348728 dest|rcvr=65536 mtype=8 obj#=-1 tim=1357278555114516
  WAIT #1: nam='ges message buffer allocation' ela= 2 pool=0 request=1 allocated=0 obj#=-1 tim=1357278555114680
  WAIT #1: nam='Disk file operations I/O' ela= 562 FileOperation=2 fileno=6 filetype=2 obj#=85520 tim=1357278555115710
  WAIT #1: nam='kfk: async disk IO' ela= 5 count=1 intr=0 timeout=4294967295 obj#=85520 tim=1357278555117332
  
  *** 2013-01-04 13:49:15.123
  WAIT #1: nam='direct path read' ela= 6243 file number=6 first dba=11051 block cnt=5 obj#=85520 tim=1357278555123628
  WAIT #1: nam='db file sequential read' ela= 195 file#=6 block#=156863 blocks=1 obj#=85520 tim=1357278555123968
  WAIT #1: nam='db file sequential read' ela= 149 file#=6 block#=156804 blocks=1 obj#=85520 tim=1357278555124216
  WAIT #1: nam='db file sequential read' ela= 155 file#=6 block#=156816 blocks=1 obj#=85520 tim=1357278555124430
  WAIT #1: nam='db file sequential read' ela= 4826 file#=6 block#=156816 blocks=1 obj#=85520 tim=1357278555129317
  WAIT #1: nam='db file sequential read' ela= 987 file#=6 block#=156888 blocks=1 obj#=85520 tim=1357278555130427
  WAIT #1: nam='db file sequential read' ela= 3891 file#=6 block#=156888 blocks=1 obj#=85520 tim=1357278555134394
  WAIT #1: nam='db file sequential read' ela= 155 file#=6 block#=156912 blocks=1 obj#=85520 tim=1357278555134645
  WAIT #1: nam='db file sequential read' ela= 145 file#=6 block#=156920 blocks=1 obj#=85520 tim=1357278555134866
  WAIT #1: nam='db file sequential read' ela= 234 file#=6 block#=156898 blocks=1 obj#=85520 tim=1357278555135332
  WAIT #1: nam='db file sequential read' ela= 204 file#=6 block#=156907 blocks=1 obj#=85520 tim=1357278555135666
  WAIT #1: nam='kfk: async disk IO' ela= 4 count=1 intr=0 timeout=4294967295 obj#=85520 tim=1357278555135850
  WAIT #1: nam='direct path read' ela= 6894 file number=6 first dba=72073 block cnt=15 obj#=85520 tim=1357278555142774
  WAIT #1: nam='db file sequential read' ela= 4642 file#=6 block#=156840 blocks=1 obj#=85520 tim=1357278555147574
  WAIT #1: nam='db file sequential read' ela= 162 file#=6 block#=156853 blocks=1 obj#=85520 tim=1357278555147859
  WAIT #1: nam='db file sequential read' ela= 6469 file#=6 block#=156806 blocks=1 obj#=85520 tim=1357278555154407
  WAIT #1: nam='db file sequential read' ela= 182 file#=6 block#=156826 blocks=1 obj#=85520 tim=1357278555154660
  WAIT #1: nam='db file sequential read' ela= 147 file#=6 block#=156830 blocks=1 obj#=85520 tim=1357278555154873
  WAIT #1: nam='db file sequential read' ela= 145 file#=6 block#=156878 blocks=1 obj#=85520 tim=135727855515

  Here are the trace file for the test database:
  

  *** 2013-01-04 13:46:11.354
  WAIT #1: nam='SQL*Net message from client' ela= 10384792 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278371354075
  CLOSE #1:c=0,e=3,dep=0,type=3,tim=1357278371354152
  =====================
  PARSING IN CURSOR #1 len=113 dep=0 uid=0 oct=3 lid=0 tim=1357278371363427 hv=138414473 ad='c7bd8d00' sqlid='72tvt5h4402c9'
  select "NUMBER" num from smprd.probsummarym1 where flag ='f' and affected_item = 'PAUSRWVP39486' order by num asc
  END OF STMT
  PARSE #1:c=0,e=9251,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278371363426
  EXEC #1:c=0,e=63178,p=0,cr=0,cu=0,mis=0,r=0,dep=0,og=1,plh=1127048874,tim=1357278371426691
  WAIT #1: nam='SQL*Net message to client' ela= 2 driver id=1650815232 #bytes=1 p3=0 obj#=-1 tim=1357278371426766
  WAIT #1: nam='Disk file operations I/O' ela= 1133 FileOperation=2 fileno=55 filetype=2 obj#=93574 tim=1357278371428069
  WAIT #1: nam='db file sequential read' ela= 51 file#=55 block#=460234 blocks=1 obj#=93574 tim=1357278371428158
  WAIT #1: nam='direct path read' ela= 31 file number=55 first dba=460235 block cnt=5 obj#=93574 tim=1357278371428956
  WAIT #1: nam='direct path read' ela= 47 file number=55 first dba=136288 block cnt=8 obj#=93574 tim=1357278371429099
  WAIT #1: nam='direct path read' ela= 80 file number=55 first dba=136297 block cnt=15 obj#=93574 tim=1357278371438529
  WAIT #1: nam='direct path read' ela= 62 file number=55 first dba=136849 block cnt=15 obj#=93574 tim=1357278371438653
  WAIT #1: nam='direct path read' ela= 17 file number=55 first dba=136881 block cnt=7 obj#=93574 tim=1357278371438750
  WAIT #1: nam='direct path read' ela= 35 file number=55 first dba=136896 block cnt=8 obj#=93574 tim=1357278371438855
  WAIT #1: nam='direct path read' ela= 22 file number=55 first dba=136913 block cnt=7 obj#=93574 tim=1357278371438936
  WAIT #1: nam='direct path read' ela= 19 file number=55 first dba=137120 block cnt=8 obj#=93574 tim=1357278371439029
  WAIT #1: nam='direct path read' ela= 36 file number=55 first dba=137145 block cnt=7 obj#=93574 tim=1357278371439114
  WAIT #1: nam='direct path read' ela= 18 file number=55 first dba=137192 block cnt=8 obj#=93574 tim=1357278371439193
  WAIT #1: nam='direct path read' ela= 16 file number=55 first dba=137201 block cnt=7 obj#=93574 tim=1357278371439252
  WAIT #1: nam='direct path read' ela= 17 file number=55 first dba=137600 block cnt=8 obj#=93574 tim=1357278371439313
  WAIT #1: nam='direct path read' ela= 15 file number=55 first dba=137625 block cnt=7 obj#=93574 tim=1357278371439369
  WAIT #1: nam='direct path read' ela= 22 file number=55 first dba=137640 block cnt=8 obj#=93574 tim=1357278371439435
  WAIT #1: nam='direct path read' ela= 702 file number=55 first dba=801026 block cnt=126 obj#=93574 tim=1357278371440188
  WAIT #1: nam='direct path read' ela= 1511 file number=55 first dba=801154 block cnt=126 obj#=93574 tim=1357278371441763
  WAIT #1: nam='direct path read' ela= 263 file number=55 first dba=801282 block cnt=126 obj#=93574 tim=1357278371442547
  WAIT #1: nam='direct path read' ela= 259 file number=55 first dba=801410 block cnt=126 obj#=93574 tim=1357278371443315
  WAIT #1: nam='direct path read' ela= 294 file number=55 first dba=801538 block cnt=126 obj#=93574 tim=1357278371444099
  WAIT #1: nam='direct path read' ela= 247 file number=55 first dba=801666 block cnt=126 obj#=93574 tim=1357278371444843
  WAIT #1: nam='direct path read' ela= 266 file number=55 first dba=801794 block cnt=126 obj#=93574 tim=1357278371445619

  Thanks & Rgds,
  Vijay

  911786 wrote:

  Direct path readings can be done on the series tablescans in your version of Oracle, but if you have chained rows in the table and then Oracle can read read read the beginning of the line in the path directly, but must make a single block in the cache (the db file sequential read) to get the next part of the line.

  It is possible that your production system has a lot of chained rows, while your test system is not. As corroboration (though not convincing) indicator of what you might notice that if you take (reads disc - db file sequential reads) - who might get you close to all the blocks direct read - the numbers are very similar.

  I'm not 100% convinced that it's the answer for the difference in behavior, but worth a visit. If you can force and indexed access path in the table, do something like "select / * + index (use {pk}) * / max table (last_column_in_table)" and check the number of "table fetch continued lines" could be close to the number of db file sequential reads you. (There are other options for the counting of the chained rows that could be faster).

  Concerning
  Jonathan Lewis

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