Display lines of dates in the column

Similar Questions

• How to display rows of data in different columns?

  I'm new to SQL and currently, that's what I try to do:

  Display multiple lines of data in different columns in the same row

  I have a table like this:

  CREATE TABLE TRIPLEG)

  T # NUMBER (10) NOT NULL,

  STEP # NUMBER (2) NOT NULL,

  DEPARTURE VARCHAR (30) NOT NULL,

  VARCHAR (30) DESTINATION NOT NULL,.

  CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (T #, LEG #).

  TRIPLEG_UNIQUE UNIQUE CONSTRAINT (T #, DEPARTURE, DESTINATION).

  CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (T #) REFERENCES TRIP(T#));

  INSERT INTO TRIPLEG VALUES (1, 1, 'Sydney', 'Melbourne');

  INSERT INTO TRIPLEG VALUES (1, 2, 'Melbourne', 'Adélaïde');

  The result should be something like this:

  > T # | ORIGIN | DESTINATION1 |  DESTINATION2

  > 1 | SYDNEY | MELBORUNE | ADELAIDE

  The request must include the ' COUNT(T#) < 3' since I only need to display the records of less than 3. How can I get the results I want to use relational views?

  Thank you!!!

  I replaced the syntax "where" with the syntax 'account '. The reason why I do this is because I want to only display records with a number of travel of less than 3. By defining where the legs #.<=3, the="" result="" will="" be="" all="" the="" records="" of="" the="" tripleg="" table="" since="" each="" record="" could="" also="" have="" leg#="" is="">

  The answer is:

  with t as (SELECT t #,)

  REGEXP_REPLACE)

  LISTAGG (start |) '->' || destination, ' ')

  THE Group (ORDER BY t #, leg #).

  '([^ ]+) \1+',

  "\1") str

  OF tripleg

  HAVING COUNT (T #)<>

  GROUP BY t #)

  Select T #, regexp_substr (str, ' [^->] +', 1, 1) departure

  , regexp_substr (str, ' [^->] +', 1, 2) destination_1

  , regexp_substr (str, ' [^->] +' 1, 3) destination_2

  , regexp_substr (str, ' [^->] +' 1, 4) destination_3

  Thanks to Marty and knani!

• How to remove tabs, several spaces, quotes from data in the column.

  Hello

  How can we remove legs, several spaces, quotes from data in the column.

  Entry:

  H ope you 'are' Ingo w ell

  Output:

  H ope do you everything - there is a tab in hope and double-spaced in the well. This should be replaced by space. (Tab and multi spaces)

  I found myself with below:

  REGEXP_REPLACE (REGEXP_REPLACE (Replace (col, Chr (9),' '), ' () {2,} ', ' '),'[' ""]', ")

  Can we do more efficiently, your contributions are appreciated.

  I tried

  REGEXP_REPLACE (col,'[^ [a - z, A - Z, 0-9, Chr (0) - Chr (127) [: Space:]]] *', ") but the tabs still exist and that my data have German characters I can't go along with this.

  Thank you

  GVK.

  Hello

  Karthik417 wrote:

  Hello

  Thanks for your suggestion. In the above expression, we still missed to replace the double quotes.

  So thought we must use another regular expression instead of REPLACE.

  Select REGEXP_REPLACE (REGEXP_REPLACE (' H ope you "are" d "Ingo ell w ',' [' |])) CHR (9) | + ',' '),'["" "]') twice;

  I suppose we must use at least 2 REGEXP to achieve and cannot get it with a single expression.

  Thank you

  Sorry, I removed single quotes, not double - quote.  (This shows one of the reasons why having a few lines of sample data is very useful).

  I think you don't need 2 separate functions.  I do not think that the two must be REGEXP_REPLACE; You can use TRANSLATE to remove both types of quotation marks in a single function call:

  TRANSLATE (REGEXP_REPLACE (col

  , '[ ' || CHR (9) | ']+'

  , ' '

  )

  , '?'''"',

  , '?'

  )

  Of course, you can use use REGEXP_REPLACE to remove the quotes, if you really want to.

  Powerful they are, regular expressions are basically only 1 thing, things not 2 or more different.  Sometimes, he can watch as they do several things, because they can operate on character classes, like the series containing the and the and a variable number of characters.  For example, the REGEXP_REPLACE function, I used above is simply changing expression expression x y, where x is 1 consecutive or more characters of a given set.  As we both demonstrated, we can have a separate function that changes from p to q, but I know not all built-in function which, in general, can change x to y at the time that it changes from p to q.  TRANSLATE comes close, but TRANSLATE only works if x, y, p and q are single (or NULL), characters not expressions.

• How to assign the text value when the data in the column is null or empty

  Hello guys
  
  I have a small question
  
  I have a column A that half of its value is empty, now the condition is that whenever the column is empty, assign "N/a" in the column... So I wrote a code which is:
  
  <? If: not (column A)? > column a = 'n/a' <? end if? >
  
  However, when I preview the RTF model, the data in the column still has not changed at all, many lines are still empty and did not show 'n/a '... The column is of type text
  
  Please advice
  
  Thank you

  N/A
  

• How to join two tables to retrieve the data from the columns in table two. Tables have primary and foreign key relationships

  Hello

  I want to join the two tables to retrieve the data from the columns of the two table passing parameters to the join query. Tables have primary and foreign key relationships

  Details of the table

  Alert-1 - AlertCode (FK), AlerID (PK)

  2 AlertCode-AlertDefinition-(PK)

  Help, please

  
  

  ----------
  

  Hi Vincent,.

  I think that you have not worked on adf 12.1.3.  In adf 12.1.3 you don't have to explicitly create the association. When you create the EO to your table, Association xxxxFkAssoc, will be created by ADF12.1.3 for you automatically. Please try this and do not answer anything... You can also follow the links below. I solved the problem by using the following link

  Oracle ADF Guide step by step - Oracle ADF tutorial: creating a relationship of the master / detail using Oracle ADF

  ---

• I tried to download a pdf and convert them into excel, but the data in excellent is always to the image format.  How can I get the pdf data into the columns and rows?

  I tried to download a pdf and convert them into excel, but the data in excellent is always to the image format.  How can I get the pdf data into the columns and rows so that I can do the calculations?

  If you start the https://forums.adobe.com/welcome Forums Index

  You will be able to select a forum for the specific Adobe products you use

  Click on the symbol "arrow down" on the right (where it is said to see all our products and Services) to open the drop-down list and scroll

• I need to display tomorrow's date in the format ' yyyy/mm/dd' in Captivate 8.

  I need to display tomorrow's date in the format ' yyyy/mm/dd' in Captivate 8.

  I understand that I must build a tip for this Action. Has someone done something similar and can post a screenshot of the completed tip Action?

  Thanks in advance!

  I think that means Lieve this article:

  http://www.Infosemantics.com.au/Adobe-Captivate/template/02-dynamic-date-functions

• How to divide the data in the column based identifier

  Hello
  
  I use the oracle database.
  I have data in this format in my column 1234 ~ 2345 ~ 3456 ~ 4567.
  
  I need a motion to split the data in the column based on the identifier ' ~', so that I can choose the value after the second occurrence of the identifier.
  
  
  Do I know who can do this.
  
  Published by: 962987 on October 3, 2012 12:11

  Hello

  Welcome to the forum!

  Whenever you have any questions, please post CREATE TABLE and INSERT statements for some examples of data and the results desired from these data. For example, in view of these data

  CREATE TABLE     table_x
  (       my_column     VARCHAR2 (40)
  );
  
  INSERT INTO table_x (my_column) VALUES ('1234~2345~3456~4567');
  INSERT INTO table_x (my_column) VALUES ('just~2 parts');
  

  I think you're asking for these results

  PART_3     MY_COLUMN
  ---------- ----------------------------------------
  3456       1234~2345~3456~4567
             just~2 parts
  

  I suppose that, if the string does not contain at least 2 ' ~ s, you want to return null. It's a good idea to explain what you want like that for special cases and include examples in your sample data and results.

  Not all versions of Oracle are exactly the same. In fact, they are all different. If you want the best solution that works with your version, then say what version it is.
  The following query will work in Oracle 10.1 and higher:

  SELECT  REGEXP_SUBSTR ( my_column
                  , '[^~]+'
                  , 1
                  , 3     -- 3rd occurrence (after 2nd delimiter)
                  )     AS part_3
  ,     my_column          -- if wanted
  FROM    table_x
  ;
  

  See the FAQ forum {message identifier: = 9360002}

  Published by: Frank Kulash, October 3, 2012 15:24
  Adding sample data and results.

• How to group data in the column?

  Hi all
  Anyone can solve the my problem please?
  I have two columns 'Age' and 'employee ID '.
  I want the 'Number of employees' group for the specific AGE group:
  
  Age | Number of employees
  20 to 30 | 06
  31 to 40. 13
  41 to 50. 16
  51 to 60. 03
  
  And the data in the columns are put aside
  
  Age | Employee IDS
  30. 002
  38. 008
  33. 298
  22. 213
  54. 083
  24. 098
  So now.
  Waiting for your HELP.
  In advance thank you very much...
  Take care

  Here you go...

  Drag a column of answers and name as age and in his writing of fx

  case
  When tablename.age between 20 and 30 then 20 to 30'
  When tablename.age between 31 and 40 and 31 to 40'
  When can tablename.age between 41 and 50 41 to 50'
  When tablename.age between 51 and 60 and 51 to 60'
  end

  Drag a column of answers and name it as "Number of employees" and in his writing of fx

  Count (tablename. (EmployeeID)

  That would give you the report of your choice

  I hope that its useful...

  Thank you
  Ashish Gupta

• the data in the column sql colorization

  Please help predict the data in the column of blue and underlined.
  I wanted to add in sql only.
  How can I add

  select 
  decode(TUFF_GENERIC_PKG.adj_status_func(m.billing_key),'Y','<a href="javascript:alert(''This billing period has an open adjustment request currently pending'')">'||  to_char(to_date('01/'||trim(substr(M.REPORT_PERIOD,5,2))||'/'||
  trim(substr(M.REPORT_PERIOD,1,4)),'DD/MM/YYYY'),'Month YYYY') ||'</a>','<a href="f?p=&APP_ID.:5:&APP_SESSION.:BRANCH:NO:
  5:P5_BILLING_KEY:'||m.billing_key||'">'||  to_char(to_date('01/'||trim(substr(M.REPORT_PERIOD,5,2))||'/'||
  trim(substr(M.REPORT_PERIOD,1,4)),'DD/MM/YYYY'),'Month YYYY') ||'</a>')
  from dual;

  Hello

  Adding style to html (a tag) in your query

  Kind regards
  Jari

• SQL queries for reports help: need to reverse the data in the column in columns [O

  Hi all
  
  I'm looking for help in writing SQL, where I need to reverse the data in the columns column.
  
  My data in DB is as below.
  
  VALUE OF NAME OF MONTH
  Jan-10 M1 5
  Jan-10 M2 8
  Jan-10 M3 9
  Feb-10 M1 4
  Feb-10 M2 6
  Feb-10 M3 2
  M4 10 Feb 10
  M1 10 Mar 21
  Mar-10 M2 6
  
  Power required for the declaration will be like:
  
  
  MONTHS M1 M2 M3 M4
  Jan-10 5 8 9
  Feb-10 4 6 2 10
  21 Mar-10 6
  
  How can I do this using SQL. [ORACLE 10g]?
  
  I can make use of server Oracle BI also.
  
  Please help me on this...

  I think this is wrong forum to ask this question. You want to do it in OBIEE or at the DB level. In oBIEE you can do in a table privot view.

  Thnaks,
  Knani

• Transform the data in the column marked in lines

  I've already implemented Tom Kytes solution for dynamic / variant in the list that is found here and on his own works very well when passing a variable.  I'm trying to use it to decode several rows in a table.  Each row has a column of delimited data and I want to turn these data delimited by lines.

  Here is the configuration.

  create table data_source

  (upload_id number not null,

  data_source_id integer not null,

  sources varchar2 (50).

  ERROR_MESSAGE varchar2 (100)

  );

  insert into data_source (upload_id, data_source_id, sources) values (1, 1, 'a');

  insert into data_source (upload_id, data_source_id, sources) values (1,2, 'A:B:C:X');

  insert into data_source (upload_id, data_source_id, sources) values (1, 3, 'c');

  insert into data_source (upload_id, data_source_id, sources) values (1, 4, 'B');

  insert into data_source (upload_id, data_source_id, sources) values (1.5, 'Y');

  create the table data_source_lookup

  (varchar2 (10) sources non-null)

  ;

  insert into data_source_lookup (sources) values('A');

  insert into data_source_lookup (sources) values('B');

  insert into data_source_lookup (sources) values('C');

  My goal is to update the table data_source for lines where there is an invalid data source, in the example above that would be 2 and 5 lines.  I can do this individually using the in_list solution:

  Select * from table (in_list ('A:B:C:X',' :'))))

  If column_value not in (select data_source_lookup sources)

  Returns 'X' as expected.

  What I am struggling with is a method to make it through all the lines for a given loading ID:

  Update data_source

  ERROR_MESSAGE = "Source of data" is not a valid value

  where upload_id = 1 and...

  I tried to create a join cross- like this:

  Select ds.data_source_id, ds.sources, x.column_value

  DS data_source cross join (select column_value in the table (in_list (ds.sources,' :'))) x)))

  but as you can imagine passing in the function ds.sources has failed, returning "ORA-00904:"DS".» "SOURCES": invalid identifier.

  I'm sure I can solve this problem in a loop, but that seems inefficient.  Anyone know of a method by which I can pass the content of the column to the table function (in_list ()) for each line?

  For someone else it may call a function table in several lines, here's what I came with.  First of all, I changed my data to test a bit to add some very incorrect values.

  setting a day from sources set data_source = 'A:B:C:X:Y' where data_source_id = 1;

  This query will not return a list of lines that contain invalid values, including their wrong value:

  Select the rowid, sources, column_value

  de)

  Select the rowid, data_source sources)

  x cross table junction (utils.in_list (x.sources,' :'))))

  where column_value is not null

  and not exists (select null from data_source_lookup l where l.sources = column_value)

  AABk3MAAjAAAKd8AAA A:B:C:X:Y X

  AABk3MAAjAAAKd8AAA A:B:C:X:Y Y

  AABk3MAAjAAAKd8AAB A:B:C:X X

  AABk3MAAjAAAKd8AAE Y Y

  With this work, I can then modify cela a little bit to turn it back in a delimited list bad values that I can put in the error column.

  Update data_source x 2

  ERROR_MESSAGE = value

  (by selecting bad_value in)

  Select RID, "Invalid Data Source - ' |" listagg(column_value,':') within the Group (column_value control) bad_value

  de)

  Select the rowid RID, data_source sources)

  x cross table junction (utils.in_list (x.sources,' :'))))

  where column_value is not null

  and not exists (select null from data_source_lookup l where l.sources = column_value)

  (Group of RID) where rid = x 2 .rowid)

  where x 2 .upload_id = 1

  and x2.rowid in (select RID)

  de)

  Select the rowid RID, data_source sources)

  x cross table junction (utils.in_list (x.sources,' :'))))

  where column_value is not null

  and not exists (select null from data_source_lookup l where l.sources = column_value))

  ;

  It works well, and I find myself with:

  Error sources

  Source of invalid data in A:B:C:X:Y - x: y

  Invalid Data Source - X A:B:C:X

  C

  B

  Valid source of data Y - Y

• transpose the data in the column to the line

  I want to change the columns in lines, my data is

  TYPE	RANK
  1	A
  1	AA
  1	AAA
  2	B
  2	BB

  I want it in

  RANK (1)	RANK (2)
  A	B
  AA	BB
  AAA

  Please help me

  Thanks for the response guys, in the meantime, I found the solution too

  SELECT MAX(CASE WHEN ID=1 THEN RATING ELSE NULL END) AS RC,

  MAX(CASE WHEN ID=2 THEN RATING ELSE NULL END) LAUGHED

  FROM (SELECT ID, RATING, ROW_NUMBER() over (ORDER BY rowid ID PARTITION) RN)

  OF RANK_TEST) X

  GROUP BY RN;

  Thank you very much

• display the data in the column as column name

  in this column of query names are hard coded, I need to display the column name dynamically (based on sysdate). Please help me on this?

  with test_emp as

  (select 100 empno, 1st February 2014 ' hiredate, SAL union 1000 double all the)

  Select 200 empno, February 3, 2014 ", 2000 union SAL double all the"

  Select empno 300, 4 February 2014 ", 3000 union SAL double all the"

  Select 400 empno, 5 February 2014 ", 4000 SAL double

  )

  -Select * from test_emp

  SELECT EmpNo,

  Sum (decode (HireDate, trunc (sysdate), SAL, 0)) as '4 February 2014. "

  Sum (decode (HireDate, SAL, trunc(sysdate-1), 0)) as "February 3, 2014.

  Sum (decode (HireDate, trunc (sysdate)-2, SAL, 0)) as 'February 2, 2014.

  Sum (decode (HireDate, trunc (sysdate)-3, SAL, 0)) as 'February 1st, 2014. "

  Sum (decode (HireDate, trunc (sysdate)-4, SAL, 0)) as 'January 31, 2014.

  OF test_emp

  Group by empno stopped by 1

  expected results:

  EMPNO February 4, 2014 3 February 2014 2 February 2014 February 1, 2014 January 31, 2014

  100                     0                    0                       0                   1000               0

  200                     0                   2000                    0                   0                   0

  300                 3000                    0                       0                   0                   0

  400                     0                       0                       0                 0                    0

  Hello..

  We cannot manage dynamic crossover into a sql. So what I did just create a function with refcursor and get results. It will work for your case only. Try the code below and let me know in case of any problems

  FUNCTION to CREATE or REPLACE dyn_row_colum

  RETURN SYS_REFCURSOR

  AS

  v_sqlstr VARCHAR2 (32767): = ' SELECT empno, SUM (DECODE (hiredate,'|)) '''|| Trunc (sysdate) | " ((' |', sal, 0))' | ' '||'"'|| TRUNC (SYSDATE) |' » ' || «, » ;

  v_rfcur SYS_REFCURSOR;

  BEGIN

  FOR j_rec IN (SELECT col_val FROM test_emp TRUNC(SYSDATE-ROWNUM))

  LOOP

  v_sqlstr: = v_sqlstr | » '||' SUM (DECODE (hiredate,'|)) '''|| j_rec.col_val | " ((' |', sal, 0))' | ' '||'"'|| j_rec.col_val |'"' | ',';"

  END LOOP;

  v_sqlstr: = RTRIM (v_sqlstr, ','). » '||' OF test_emp GROUP BY empno';

  V_rfcur OPEN FOR v_sqlstr;

  RETURN v_rfcur;

  EXCEPTION

  WHILE OTHERS THEN

  LIFT;

  END dyn_row_colum;

  VARIABLE v_cur REFCURSOR

  EXEC: v_cur: = dyn_row_colum;

  PRINT v_cur;

  SELECT dyn_row_colum FROM dual;

  Unit tests: -.

  ----------------

  Scott@ORCL > dyn_row_colum FUNCTION to CREATE or REPLACE

  2 SYS_REFCURSOR RETURN

  3 AS

  4 v_sqlstr VARCHAR2 (32767): = ' SELECT empno, SUM (DECODE (hiredate,'|)) '''|| Trunc (sysdate) | " ((' |', sal, 0))' | ' '||'"'|| TRUNC (SYSDATE) |' » ' || «, » ;

  5 v_rfcur SYS_REFCURSOR;

  6 BEGIN

  7 FOR j_rec IN (SELECT col_val FROM test_emp TRUNC(SYSDATE-ROWNUM))

  8 LOOP

  9 v_sqlstr: = v_sqlstr | » '||' SUM (DECODE (hiredate,'|)) '''|| j_rec.col_val | " ((' |', sal, 0))' | ' '||'"'|| j_rec.col_val |'"' | ',';"

  10 END OF LOOP;

  11 v_sqlstr: = RTRIM (v_sqlstr, ','). » '||' OF test_emp GROUP BY empno';

  12 v_rfcur OPEN FOR v_sqlstr;

  13 RETURN v_rfcur;

  14 EXCEPTION

  15 SO THAT OTHERS THEN

  16 RAISE;

  17 END dyn_row_colum;

  18.

  The function is created.

  Scott@ORCL > v_cur VARIABLE REFCURSOR

  Scott@ORCL > EXEC: v_cur: = dyn_row_colum;

  PL/SQL procedure successfully completed.

  Scott@ORCL > v_cur PRINT;

  EMPNO 5 FEBRUARY 14 FEBRUARY 4, 14 3 FEBRUARY 14 FEBRUARY 2 14 1 FEBRUARY 14

  ---------- ---------- ---------- ---------- ---------- ----------

  100          0          0          0          0       1000

  400       4000          0          0          0          0

  300          0       3000          0          0          0

  200          0          0       2000          0          0

  Scott@ORCL > dyn_row_colum SELECT FROM dual;

  DYN_ROW_COLUM

  --------------------

  CURSOR STATEMENT: 1

  CURSOR STATEMENT: 1

  EMPNO 5 FEBRUARY 14 FEBRUARY 4, 14 3 FEBRUARY 14 FEBRUARY 2 14 1 FEBRUARY 14

  ---------- ---------- ---------- ---------- ---------- ----------

  100          0          0          0          0       1000

  400       4000          0          0          0          0

  300          0       3000          0          0          0

  200          0          0       2000          0          0

• copy the data from the columns box

  Hi all, I have multicolumn listbox and I deleted all the lines both vertical and horizontal lines and columns headers.when while, I run my vi, some string data are introduced into the list box. However when I try to copy a line of string in the drop-down list, I am unable to do (I can't select a line,... the idea is to select a row in the list box so that I can paste it somewhere else... That's how am supposed to allow some feature of the list box to be able to do this... any help? Thanks already

  Hello

  If I understand your problem, you want to copy the values of time and the description at once and paste the entire line in a txt for example, no? Unfortunately, the listbox is as an array of 2D channels and each field is a different value of this table 2D. You can copy a value at the time when the VI does not RUN otherwise you can use a property node to display the name of items and that the copy and paste values (always a time value) also using the VI.

  I hope the information is useful for your application

  Concerning

  Mario