Display the first and last name of userdetails welcome message

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• InDesign - prevent breaks between the first and last names in a very long list of names?

  Is there a quick way to do?  Having the list 800 names in a text box and want to prevent the first & last names being split at the end of the line.  Other than choosing each name and apply the rule "no break" (a lot of time).  Any other suggestions?

  This is a more elegant solution:

  (?<=[\l\u]) (?="">

  Apply style: no pause

  It detects all single space between two letters

• To display the first and last date of one month

  I have the date format in 10 Mar 10.
  My requirement is when ever I select the date in the dashboard for all the month it should show results of all the months.
  I had the request for obiee101.blogspot.com.but if I use that sometimes it is not the latest results of the day. Any body please give me the query to display the results for the first day and lastday?
  I select any day from the drop-down menu of the guest, it must display the month of ex: if results
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  It should give results for the month of March.
  Can you please provide me the query for the last month also?
  If I select March date date print want to display the results of March together in a single column, results of the previous months in the other column
  
  Someone help me to achieve this?

  Yes, you are right. Jean SQL for the last day of the month, if the "last day of the previous month" ends on June 30, that "adding a month" will result in the 30th of the following month. But if the next month has 31 days, you don't miss this day here.

  Use it for the last day of the current month.

  TIMESTAMPADD (SQL_TSI_DAY-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, TIMESTAMPADD (SQL_TSI_DAY, 1, TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, CURRENT_DATE))))

  The SQL above will ensure that you will get always the last day of the month "current" no matter how many days during the previous or current month.

• I would like to change the name in my profile my name and my company name, so when my clients receive a signature on the Forms application, my company name is displayed in the email as opposed to my first and last name. How can I change

  I would like to change the name in my profile my name and my company name, so when my clients receive a signature on the Forms application, my company name is displayed in the email as opposed to my first and last name. How can I change this? I tried to edit my profile however my first and last name are not editable fields.

  Hello Laurag92400722,

  You connect with Adobe ID account E-Sign? If Yes, then you can directly connect to your Adobe ID account and can update the name as the name of the company and it will reflect in your E-Sign account as well.

  -Usman

• Changed the display pad and how can I change this back to the first and last frame of the clip in question?

  Hi, when you cut a clip using the standard cursor (not the adjustment tool but just the mouse), the behavior that I was accustomed to is it shows the first and last frame of the clip you're carved, in a 2 - up window. Now in the updated 2015 I'm confused because it's still place 2 window, but instead I see the head or tail of any clip is next to any side of the clip, I'm trying to cut. I can see the utility in this, but I would like to know where I can go to the screen more as I'm used to it...

  Thank you!

  Click on the key in the timeline and in the drop-down the menu uncheck Composite overview over the filling.

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• Can only see the first and last frame of the item in the editing HELP PLEASE

  Hi, my first time and I find an answer, but fails. I first elements 4 and I'm trying to worm. 9. in version 4 clips in the timelin shows all the frames, but in ver 9 it only shows the first and last frame clips. Is it possible to make all the images to display. I mean by "all frames", clips from filling with frames. I wanted to see all of the images in the scenario, it is easier for me to select and cut the pieces on.

  My features are Core 2 Duo 6750, Nvidia 8600GTS, 4 G of Ram and Vista Home Premium. 3 HARD DRIVE 3 TB.

  Thank you for having responded

  Werner

  Werner,

  Welcome to the forum.

  In the header of the video track, there is an icon for Clip thumbnail display. It's a cycle, and you can scroll through the Modes to display the first frame, first & last, all, or none (name of file only). In pre 4.0, it's on the far left in the header of the track. I guess that's about the same place in pre 9.0.

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• Impossible to print the first and last pages of a pdf of the 8 page?

  I have a pdf of 8 pages exported from an InDesign document. I can print it without any problem on my MAC, but when I will forward it to a partner, she is unable to print the first and last pages. Any ideas?

  Hi jimr67163466,

  Could you please let us know the version of Adobe Reader is installed on the machine?

  What operating system is installed on the machine-Windows/Mac?

  The pdf is printing via a network printer?

  This phenomenon happens with a specific document only or with other documents as well?

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• Detect the first and last spark of list items

  Hello

  I have a converter item personalized with a background image for each item in a list. the thing is I'm trying to have a different background for the first and last elements (curved respectively) and I don't know how to do this.

  Any help will be appreciated.

  not sure it's the best solution, but:

  You can override the method to data defined in your itemRenderer. Compare the new data for the first and last items in your list. And you set the background depending on the result.

• Need a query to return the first and last date for a rowset.

  Hello
  
  I have a query which can be simplified to the following data, if
  Assume that it is my dataset, with THE_VALUE of
  Sign (Anum) therefore,-1, 0 or 1.
  
  * (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *
  
  THE_VALUE THE_DATE THE_MEMBER
  1 0 1 January 2007
  1 0 1 February 2007
  1 0 1 March 2007
  1. 1 April 1, 2007
  1 1 1 May 2007
  1 0 1 June 2007
  1. 1 July 1, 2007
  1. 1 August 1, 2007
  1 0 01 - sep - 2007
  2 0 1 January 2007
  2 1 February 1, 2007
  2 0 1 March 2007
  2. 1 April 1, 2007
  2 1 1 May 2007
  2 0 1 June 2007
  -2 1 1 July 2007
  2. 1 August 1, 2007
  2. 1 01-sep-2007
  3 0 1 January 2007
  3. 1 February 1, 2007
  3 0 1 March 2007
  3 0 1 April 2007
  3. 1 May 1, 2007
  3 0 1 June 2007
  3. 1 July 1, 2007
  3. 1 August 1, 2007
  3 0 01 - sep - 2007
  
  I need to get the lines with the THE_MEMBER, the values of the first and the last
  THE_DATE, where the value is - 1, and the date range is the last
  set of lines to the Member, with the same value of THE_VALUE.
  
  I tried the following to get the dates of first and last for a set
  consecutive months with the same value for the Member.
  
  SELECT the_member
  the_value
  the_date
  first_value (the_date)
  in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  last_value (the_date)
  during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
  OF togola
  ORDER BY the_member
  the_date;
  
  At first, it seems to work, but then, when the return value
  an old value, FIRST_DATE will be the first of all the lines containing
  This value for the Member rather than the first of consecutive
  rows with this value for the Member. Apparently the partitioning
  occurs before the order.
  
  THE_MEMBER THE_VALUE THE_DATE FIRST DATE LAST DATE
  1 0 January 1, 2007 January 1, 2007 January 1, 2007
  1 0 1 February 2007 1 January 2007 1 February 2007
  1 0 1 March 2007 1 January 2007 March 1, 2007
  1. 1 April 1, 2007 April 1, 2007 April 1, 2007
  1. 1 May 1, 2007 April 1, 2007 may 1, 2007
  1-0 June 1, 2007 January 1, 2007 June 1, 2007
  1. 1 July 1, 2007 April 1, 2007 July 1, 2007
  1. 1 August 1, 2007 April 1, 2007 August 1, 2007
  1 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  2 0 January 1, 2007 January 1, 2007 January 1, 2007
  2 1 1 February 2007 February 1, 2007 February 1, 2007
  2 0 1 March 2007 1 January 2007 March 1, 2007
  2. 1 April 1, 2007 February 1, 2007 April 1, 2007
  2 1 1 May 2007 February 1, 2007 may 1, 2007
  2-0 June 1, 2007 January 1, 2007 June 1, 2007
  -2 1 1 July 2007 February 1, 2007 July 1, 2007
  2. 1 August 1, 2007 February 1, 2007 August 1, 2007
  2. 1 01-sep-2007 1 February 2007 01-Sep-2007
  
  3 0 January 1, 2007 January 1, 2007 January 1, 2007
  3. 1 February 1, 2007 February 1, 2007 February 1, 2007
  3 0 1 March 2007 1 January 2007 March 1, 2007
  3 0 April 1, 2007 January 1, 2007 April 1, 2007
  3. 1 May 1, 2007 February 1, 2007 may 1, 2007
  3 0 June 1, 2007 January 1, 2007 June 1, 2007
  3. 1 July 1, 2007 February 1, 2007 July 1, 2007
  3. 1 August 1, 2007 February 1, 2007 August 1, 2007
  3 0 01 - sep - 2007 1 January 2007 01-Sep-2007
  
  That's what I need to get in the end.
  
  THE_MEMBER FIRST DAY DATE OF LAST
  July 2 1 2007-01 - Sep - 2007
  
  Any ideas would be really appreciated.
  
  Published by: user10700981 on December 17, 2008 13:57

  Hello

  We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.

  For each value of the_value, we need the first and last values of the_date where
  the last row in the group is good
  (b) the current line is good
  (c) there is a lot of lines from the current line to the end of the Group
  Condition (a) is just a special case of (c).
  Conditions (b) and (c) are similar: (b) if applied to the current line, (c) applies to all lines after him. They can easily be combined into a single test that counts the number of lines after the current line or bad.

  Which produces the results you requested of the sample data that you provided:

  WITH     count_bad     AS
  (
       SELECT     the_member
       ,     the_date
       ,     COUNT     ( CASE
                      WHEN  the_value != -1 -- assuming the_value is never NULL
                      THEN  1
                   END
                 ) OVER     ( PARTITION BY     the_member
                        ORDER BY     the_date     DESC
                      )     AS bad_cnt
       FROM     table_x
  )
  SELECT     the_member
  ,     MIN (the_date)     AS first_date
  ,     MAX (the_date)     AS last_date
  FROM     count_bad
  WHERE     bad_cnt     = 0
  GROUP BY     the_member
  ORDER BY     the_member;
  

• Animate the first and last character

  Hello

  Does anyone have a model may be the way to animate the first and the last character or a tutorial?

  For example, I would like to animate "ABCDEFG".

  AG would be the first thing you see on the screen, then the distance between AG grew and fade the letters in the middle.

  So, the result would be:

  1 frame: AG

  2: A G

  3: ABG

  4: ABCG

  etc.

  http://www.Mylenium.de/_temp/Text_Expand_00.zip

  Mylenium

• Generaiting first and last names using DBMS_RANDOM.

  Hello, I need to generate 1000 lines in the usind DBMS_RANDOM table to generate the first names of family. There are ID first_name and last_name columns column!
  How can I do?
  
  I use 11g 2
  
  THX
  
  Published by: 905194 on January 9, 2012 03:28

  Please change person_id column

  ALTER TABLE PERSONS MODIFY PERSON_ID number(10);
  

• Find the first and last record in a game and the calculation of time

  I have the following table and data below,
  
  CREATE TABLE AAA_CDR
  (ACCTTYPE (1) NUMBER, MSID VARCHAR2(20 BYTE), ACCOUNTSESSION_ID VARCHAR2(64 BYTE), BEGINNINGSESSION NUMBER (1),)
  SESSIONCONTINUE NUMBER (1), ACCT_MULTI_SESSION_ID VARCHAR2(64 BYTE), DATAOCTETCOUNTORIGINATING NUMBER (20), DATAOCTETCOUNTTERMINATING NUMBER (20), ACCTSESSIONTIME NUMBER (20));
  
  -SQL statement that produces these data:
  / * Select msid, accountsession_id, beginningsession, sessioncontinue, ACCTTYPE, acct_multi_session_id,.
  dataoctetcountoriginating, dataoctetcountterminating, acctsessiontime
  OF AAA_CDR
  where msid = "5C4CA98EAC4C."
  ORDER BY acct_multi_session_id, accountsession_id, accttype
  */
  
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '190001E9', 1, 0, '100014E19775F169', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', '190001E9', 0, 0, '100014E19775F169', 47496, 182054, 70);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', ' 290001C 4', 1, 0, '100014E19E21F16C', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', ' 290001C 4', 0, 0, '100014E19E21F16C', 3278162, 17540714, 14152);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', 190001 FC', 1, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', 190001 FC', 0, 1, "100014E1A949316E", 682734, 2935111, 1553);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '190001FD', 0, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', '190001FD', 0, 1, "100014E1A949316E", 1821052, 9585090, 5368);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '190001FE', 0, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', '190001FE', 0, 1, "100014E1A949316E", 42012, 505004, 213);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '19000200', 0, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', 0, '19000200', 1, '100014E1A949316E', 50224, 144566, 729).
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '19000201', 0, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', 0, '19000201', 1, '100014E1A949316E', 62634, 378416, 392);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (1, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 0, 0, 0);
  Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
  Values (2, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 1457286, 9141033, 7574);
  commit;
  
  I need to calculate the sum (dataeoctetcountoriginating) + sum (dataoctetcountterminating) for each session
  It is average, but the beginning of the session and the end of the session, as below,
  for each ACCT_MULTI_SESSION_ID and MSID
  the beginning of the session is when the accttype = 1 and beginningsession = 1
  and the end of the session is at this time the accttype = 2 and SESSIONCONTINUE = 0
  
  
  1. collect the first accounting start CDR generated an event online for a user.
  Collect CDR AcctType is 1 and beginning of Session is 1 according to MSID. In
  also, see the value of the Acct-Multi-Session-ID field in the CDR.
  2. collect all Accountants stop CDRs generated during this event the user online.
  Collect CDR AcctType is 2 according to MSID and Acct-Multi-Session-ID.
  If the value of Session continues on a CD - r accounting stop is 0, it indicates that this CDR
  is the last CDR of accounting judgment that is generated during the event of the user's offline.
  3. calculate the total volume of the user during this event online.
  Add the values of the data fields Byte Count (termination) and data values
  Fields byte (native) Count in the accounts collected stop CDRs together to get
  the total volume of this event the user online.
  
  How can I find each session, then calculate the sum of this session?
  any help please
  
  Published by: user11309581 on July 13, 2011 22:01

  Is that what you are looking for:

  select
     acct_multi_session_id,
     max(ACCTSESSIONTIME)-min(ACCTSESSIONTIME)
  from AAA_CDR
  group by acct_multi_session_id
  

  According to the DDL and DML you provided, this is the output I see:

  ACCT_MULTI_SESSION_ID,MAX(ACCTSESSIONTIME)-MIN(ACCTSESSIONTIME)
  100014E19E21F16C,         14152
  100014E19775F169,         70
  100014E1A949316E,         7574
  

• How to get the first and last record

  Hai All
  
  I have a table called T1 and there are more than 8 lakhs Archives and I have a column named Timestamp, so I need to get the first record value and time stampvalue and last record and time stamp value so that I can conclude that for example
  form June 13 to 15 June data are here
  
  
  Kind regards
  
  SrikkanthM

  What is the problem with:

  select min(timestamp),max(timestamp)
  from T1;
  

  ?

• Confirm: Have 4 snapshots; to remove average snapshots 2, leaving the first and last

  I thought I knew this, but confused me after having looked further. ESXi 5.5 U2. I have a virtual machine that has 4 pictures:

  2015 12-30

  2016 01-04

  2016 01-05-morning

  2016 01-05-night (latest snapshot)

  I like to keep the snapshot from 2015-12-30 and the last 2016-01-05-night. Do not the other 2; We won't be going back to these snapshots, but you may have to return to the State from 30-12-2015 or 2016-01-05-evening.

  So I can just delete 2 snapshots medium, correct? And yet still be able to return to the State from 30-12-2015 or 2016-01-05-night, if necessary?

  But regardless of what order that I remove them? Can I just remove the sequentially (i.e. delete 2016-01-04 and then 2016-01-05-morning)?

  Sorry if this seems to be a newbie question, but I never deleted a few shots, leaving others like this. I've removed all the or just deleted the most recent; I never deleted snapshots in the middle of a sequence like this before.

  Screenshot of snapshots attached.

  Well, let me explain how...

  Created virtual MACHINE Original.vmdk

  2015-12-30 snapshot created.  00001.VMDK - original created for changes.

  2016 01-04 created snapshot.  00002.VMDK - original created for changes.

  2016 01-05-morning snapshot created.  origianl - created 00003.vmdk for the changes.

  2016 01-05-night snapshot created.  00004.VMDK - original created for changes.

  When you remove 04-01-2016 and 2016-01-05-morning snapshots, these changes are rolled in the original - 00004.vmdk, so if return you to this snapshot, it contains everything, instead of having data access between 3 different VMDK.

  That explain better?

• get the first and last day of the year

  and razm.date > = to_date ("' 1.01 ' |: $VDATE |", ' dd.mm.yyyy ") AND razm.date < = to_date ('31.12.2010. ' || (": $VDATE |", ' dd.mm.yyyy ");
  
  but I get:
  ORA-01830: date format picture ends before converting all of the input string
  01830 00000 - "date format picture ends before converting all of the input string.
  * Cause:
  * Action:
  
  
  : $VDATE is entered as 2010 param. I need to get data from range 1.1.2001 to 31.12.2010
  
  THX

  Why don't you use:

  to_char(razm.date,'YYYY') = :VDATE