InDesign - prevent breaks between the first and last names in a very long list of names?

Is there a quick way to do? Having the list 800 names in a text box and want to prevent the first & last names being split at the end of the line. Other than choosing each name and apply the rule "no break" (a lot of time). Any other suggestions?

This is a more elegant solution:

(?<=[\l\u]) (?="">

Apply style: no pause

It detects all single space between two letters

Tags: InDesign

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Need a query to return the first and last date for a rowset.
Hello

I have a query which can be simplified to the following data, if
Assume that it is my dataset, with THE_VALUE of
Sign (Anum) therefore,-1, 0 or 1.

* (Sorry for crushed registration. "I can't understand this website's rich text formatting.) *

THE_VALUE THE_DATE THE_MEMBER
1 0 1 January 2007
1 0 1 February 2007
1 0 1 March 2007
1. 1 April 1, 2007
1 1 1 May 2007
1 0 1 June 2007
1. 1 July 1, 2007
1. 1 August 1, 2007
1 0 01 - sep - 2007
2 0 1 January 2007
2 1 February 1, 2007
2 0 1 March 2007
2. 1 April 1, 2007
2 1 1 May 2007
2 0 1 June 2007
-2 1 1 July 2007
2. 1 August 1, 2007
2. 1 01-sep-2007
3 0 1 January 2007
3. 1 February 1, 2007
3 0 1 March 2007
3 0 1 April 2007
3. 1 May 1, 2007
3 0 1 June 2007
3. 1 July 1, 2007
3. 1 August 1, 2007
3 0 01 - sep - 2007

I need to get the lines with the THE_MEMBER, the values of the first and the last
THE_DATE, where the value is - 1, and the date range is the last
set of lines to the Member, with the same value of THE_VALUE.

I tried the following to get the dates of first and last for a set
consecutive months with the same value for the Member.

SELECT the_member
the_value
the_date
first_value (the_date)
in the first_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
last_value (the_date)
during the last_date (PARTITION the_member, ORDER BY the_member the_value, the_date)
OF togola
ORDER BY the_member
the_date;

At first, it seems to work, but then, when the return value
an old value, FIRST_DATE will be the first of all the lines containing
This value for the Member rather than the first of consecutive
rows with this value for the Member. Apparently the partitioning
occurs before the order.

THE_MEMBER THE_VALUE THE_DATE FIRST DATE LAST DATE
1 0 January 1, 2007 January 1, 2007 January 1, 2007
1 0 1 February 2007 1 January 2007 1 February 2007
1 0 1 March 2007 1 January 2007 March 1, 2007
1. 1 April 1, 2007 April 1, 2007 April 1, 2007
1. 1 May 1, 2007 April 1, 2007 may 1, 2007
1-0 June 1, 2007 January 1, 2007 June 1, 2007
1. 1 July 1, 2007 April 1, 2007 July 1, 2007
1. 1 August 1, 2007 April 1, 2007 August 1, 2007
1 0 01 - sep - 2007 1 January 2007 01-Sep-2007

2 0 January 1, 2007 January 1, 2007 January 1, 2007
2 1 1 February 2007 February 1, 2007 February 1, 2007
2 0 1 March 2007 1 January 2007 March 1, 2007
2. 1 April 1, 2007 February 1, 2007 April 1, 2007
2 1 1 May 2007 February 1, 2007 may 1, 2007
2-0 June 1, 2007 January 1, 2007 June 1, 2007
-2 1 1 July 2007 February 1, 2007 July 1, 2007
2. 1 August 1, 2007 February 1, 2007 August 1, 2007
2. 1 01-sep-2007 1 February 2007 01-Sep-2007

3 0 January 1, 2007 January 1, 2007 January 1, 2007
3. 1 February 1, 2007 February 1, 2007 February 1, 2007
3 0 1 March 2007 1 January 2007 March 1, 2007
3 0 April 1, 2007 January 1, 2007 April 1, 2007
3. 1 May 1, 2007 February 1, 2007 may 1, 2007
3 0 June 1, 2007 January 1, 2007 June 1, 2007
3. 1 July 1, 2007 February 1, 2007 July 1, 2007
3. 1 August 1, 2007 February 1, 2007 August 1, 2007
3 0 01 - sep - 2007 1 January 2007 01-Sep-2007

That's what I need to get in the end.

THE_MEMBER FIRST DAY DATE OF LAST
July 2 1 2007-01 - Sep - 2007

Any ideas would be really appreciated.

Published by: user10700981 on December 17, 2008 13:57
Hello

We'll call the lines whose the_value =-1 'good' lines and lines with the_value! =-1 ranks of 'bad '.

For each value of the_value, we need the first and last values of the_date where
the last row in the group is good
(b) the current line is good
(c) there is a lot of lines from the current line to the end of the Group
Condition (a) is just a special case of (c).
Conditions (b) and (c) are similar: (b) if applied to the current line, (c) applies to all lines after him. They can easily be combined into a single test that counts the number of lines after the current line or bad.

Which produces the results you requested of the sample data that you provided:
```
WITH     count_bad     AS
(
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                    THEN  1
                 END
               ) OVER     ( PARTITION BY     the_member
                      ORDER BY     the_date     DESC
                    )     AS bad_cnt
     FROM     table_x
)
SELECT     the_member
,     MIN (the_date)     AS first_date
,     MAX (the_date)     AS last_date
FROM     count_bad
WHERE     bad_cnt     = 0
GROUP BY     the_member
ORDER BY     the_member;
```

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Find the first and last record in a game and the calculation of time
I have the following table and data below,

CREATE TABLE AAA_CDR
(ACCTTYPE (1) NUMBER, MSID VARCHAR2(20 BYTE), ACCOUNTSESSION_ID VARCHAR2(64 BYTE), BEGINNINGSESSION NUMBER (1),)
SESSIONCONTINUE NUMBER (1), ACCT_MULTI_SESSION_ID VARCHAR2(64 BYTE), DATAOCTETCOUNTORIGINATING NUMBER (20), DATAOCTETCOUNTTERMINATING NUMBER (20), ACCTSESSIONTIME NUMBER (20));

-SQL statement that produces these data:
/ * Select msid, accountsession_id, beginningsession, sessioncontinue, ACCTTYPE, acct_multi_session_id,.
dataoctetcountoriginating, dataoctetcountterminating, acctsessiontime
OF AAA_CDR
where msid = "5C4CA98EAC4C."
ORDER BY acct_multi_session_id, accountsession_id, accttype
*/

Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '190001E9', 1, 0, '100014E19775F169', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', '190001E9', 0, 0, '100014E19775F169', 47496, 182054, 70);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', ' 290001C 4', 1, 0, '100014E19E21F16C', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', ' 290001C 4', 0, 0, '100014E19E21F16C', 3278162, 17540714, 14152);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', 190001 FC', 1, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', 190001 FC', 0, 1, "100014E1A949316E", 682734, 2935111, 1553);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '190001FD', 0, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', '190001FD', 0, 1, "100014E1A949316E", 1821052, 9585090, 5368);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '190001FE', 0, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', '190001FE', 0, 1, "100014E1A949316E", 42012, 505004, 213);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '19000200', 0, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', 0, '19000200', 1, '100014E1A949316E', 50224, 144566, 729).
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '19000201', 0, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', 0, '19000201', 1, '100014E1A949316E', 62634, 378416, 392);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (1, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 0, 0, 0);
Insert into AAA_CDR (ACCTTYPE, MSID, ACCOUNTSESSION_ID, BEGINNINGSESSION, SESSIONCONTINUE, ACCT_MULTI_SESSION_ID, DATAOCTETCOUNTORIGINATING, DATAOCTETCOUNTTERMINATING, ACCTSESSIONTIME)
Values (2, '5C4CA98EAC4C', '19000202', 0, 0, '100014E1A949316E', 1457286, 9141033, 7574);
commit;

I need to calculate the sum (dataeoctetcountoriginating) + sum (dataoctetcountterminating) for each session
It is average, but the beginning of the session and the end of the session, as below,
for each ACCT_MULTI_SESSION_ID and MSID
the beginning of the session is when the accttype = 1 and beginningsession = 1
and the end of the session is at this time the accttype = 2 and SESSIONCONTINUE = 0

1. collect the first accounting start CDR generated an event online for a user.
Collect CDR AcctType is 1 and beginning of Session is 1 according to MSID. In
also, see the value of the Acct-Multi-Session-ID field in the CDR.
2. collect all Accountants stop CDRs generated during this event the user online.
Collect CDR AcctType is 2 according to MSID and Acct-Multi-Session-ID.
If the value of Session continues on a CD - r accounting stop is 0, it indicates that this CDR
is the last CDR of accounting judgment that is generated during the event of the user's offline.
3. calculate the total volume of the user during this event online.
Add the values of the data fields Byte Count (termination) and data values
Fields byte (native) Count in the accounts collected stop CDRs together to get
the total volume of this event the user online.

How can I find each session, then calculate the sum of this session?
any help please

Published by: user11309581 on July 13, 2011 22:01
Is that what you are looking for:
```
select
   acct_multi_session_id,
   max(ACCTSESSIONTIME)-min(ACCTSESSIONTIME)
from AAA_CDR
group by acct_multi_session_id
```
According to the DDL and DML you provided, this is the output I see:
```
ACCT_MULTI_SESSION_ID,MAX(ACCTSESSIONTIME)-MIN(ACCTSESSIONTIME)
100014E19E21F16C,         14152
100014E19775F169,         70
100014E1A949316E,         7574
```

To display the first and last date of one month
I have the date format in 10 Mar 10.
My requirement is when ever I select the date in the dashboard for all the month it should show results of all the months.
I had the request for obiee101.blogspot.com.but if I use that sometimes it is not the latest results of the day. Any body please give me the query to display the results for the first day and lastday?
I select any day from the drop-down menu of the guest, it must display the month of ex: if results
If I select either 1 mar mar 10.2 10,30 mar 10...
It should give results for the month of March.
Can you please provide me the query for the last month also?
If I select March date date print want to display the results of March together in a single column, results of the previous months in the other column

Someone help me to achieve this?
Yes, you are right. Jean SQL for the last day of the month, if the "last day of the previous month" ends on June 30, that "adding a month" will result in the 30th of the following month. But if the next month has 31 days, you don't miss this day here.

Use it for the last day of the current month.

TIMESTAMPADD (SQL_TSI_DAY-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, TIMESTAMPADD (SQL_TSI_DAY, 1, TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, CURRENT_DATE))))

The SQL above will ensure that you will get always the last day of the month "current" no matter how many days during the previous or current month.

How to get the first and last record
Hai All

I have a table called T1 and there are more than 8 lakhs Archives and I have a column named Timestamp, so I need to get the first record value and time stampvalue and last record and time stamp value so that I can conclude that for example
form June 13 to 15 June data are here

Kind regards

SrikkanthM
What is the problem with:
```
select min(timestamp),max(timestamp)
from T1;
```
?

InDesign - prevent breaks between the first and last names in a very long list of names?

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