Download file via a Servlet
Hi allI am trying to download a file via a servlet, so there are two different codes. One in the desktop application, where the user selects the file and click on download, which is below to:
public void actionPerformed (ActionEvent e) {}
Con URLConnection;
try {}
JFileChooser selector = new JFileChooser();
chooser.setDialogTitle ("attachments" "+ jwin.getTitle () +" ' "");
Return int = chooser.showOpenDialog (null);
if(returnVal == JFileChooser.APPROVE_OPTION) {}
File sourceFile = new queue (chooser.getSelectedFile () .getPath ());
DestPath string = "/ var/www/html/pub/ewbattach";
String fileName = sourceFile.getPath ();
destPath += ' / ' + sourceFile.getName ();
attachFile.add (sourceFile.getName ());
FileInputStream end = new FileInputStream (sourceFile);
URL url = new URL("http://"+host+":"+port+"/ewb/servlet?mode="+URLEncoder.encode("transferFile") + "" & name = "+ URLEncoder.encode (fileName) +"& path ="+ URLEncoder.encode (destPath));"
con = url.openConnection ();
con.setDoInput (true);
con.setDoOutput (true);
con.setUseCaches (true);
con.setRequestProperty ("Content-Type", "multipart-formdata");
DataOutputStream dataOut = new DataOutputStream (con.getOutputStream ());
int c = 35720;
Byte b [] = new ubyte [c];
for (int i = fin.read (b, 0, c); I > = 0; I = fin.read (b, 0, c))
{
dataOut.write (b, 0, i);
}
dataOut.flush ();
dataOut.close ();
end. Close();
InputStream input = con.getInputStream ();
BufferedReader br is new BufferedReader (new InputStreamReader (input));.
String strRes = null;
While ((strRes = br.readLine ())! = null) {}
Input.Close ();
Br. Close();
}
} catch (Exception ex) {ex.printStackTrace () ;}
Finally
{
con = null;
}
}
};
And the other part of the code, which is underneath, is inside the servlet:
{if (mode.equalsIgnoreCase ("transferFile"))}
String fileName = req.getParameter ("name");
String destIP = req.getParameter ("path");
attachPath = destIP;
res.setContentType("text/plain");
System.out.println ("queue:" fileName "is ready to be transferred to" + destIP);
File destFile = new queue (destIP);
DataInputStream dataIn = new DataInputStream (req.getInputStream ());
BufferedOutputStream buffOut is new BufferedOutputStream (new FileOutputStream (destFile));.
int c = 30720;
Byte b [] = new ubyte [c];
Try
{
for (int j = dataIn.read (b, 0, c); j > = 0; j = dataIn.read (d, b, c))
{
buffOut.write (b, 0, j);
c += j;
}
}
catch (System.Exception e)
{
System.out.println ("Servlet error:" + e.getMessage ());
}
dataIn.close ();
buffOut.close ();
System.out.println ("now complete...");
}
But I get the error below:
java.io.FileNotFoundException: /var/www/html/pub/ewbattach/two.txt (no such file or directory)
INFO | JVM 1 | 08/24/2011 15:46:57 | at java.io.FileOutputStream.open (Native Method)
INFO | JVM 1 | 08/24/2011 15:46:57 | in java.io.FileOutputStream. < init > (FileOutputStream.java:179)
INFO | JVM 1 | 08/24/2011 15:46:57 | in java.io.FileOutputStream. < init > (FileOutputStream.java:131)
INFO | JVM 1 | 08/24/2011 15:46:57 | at SoldLogs.service (Servlet.java:635)
Which refers to the line of servlet:
BufferedOutputStream buffOut is new BufferedOutputStream (new FileOutputStream (destFile));.
Anyone know how to fix this?
Kind regards
Any help is appreciated.
Thanks in advance
There is no such thing as the path named in the exception.
Tags: Java
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