Duplicate values in the union

Similar Questions

• How to find duplicates of a field value? For example - in a field, I have values like {123,345,346,123}, now I want to remove the duplicate value in the field so that my output looks like {123,345,346}

  How to find duplicates of a field value? For example - in a field, I have values like {123,345,346,123}, now I want to remove the duplicate value in the field so that my output looks like {123,345,346}

  If it's an array you want to deduplicate then here is a script [for use in the Script Processor] I prepared earlier:

  var result = new Array();

  var added = new Object();

  If (input1 [0]! = null)

  {

  for (var i = 0; i)< input1[0].length;="">

  {

  var point = input1 [0] [i];

  If (! added [item])

  {

  added [item] = 1;

  result [result. Length] = item;

  }

  }

  }

  Output 1 = result;

  Kind regards

  Nick

• Check all the duplicate values in the column COUNT()

  Hello
  
  I'll do some tests, and for this I need to retrieve data based on a single column for example test_data_col, which-
  1 to 3 or more count (test_data_col) for a given set of columns for example grp_col1, grp_col2, grp_col3 group
  2. overall recovered lines, this particular column has some duplicate values. I don't need displayed duplicates, just whether or not duplicates exist.
  
  Which could explain what I'm trying to do -
  
  grp_col1, grp_col2, grp_col3, test_data_col
  
  1, A, xyz, HELLO
  1, A, xyz, HELLO
  1, a, xyz, BYE
  1, A, xyz, goodbye
  
  2, C, pqr, WELCOME
  2, C, pqr, GOOD MORNING
  2, C, pqr, BAD MORNING
  
  So for condition 1, I do something like that.
  

  SELECT COUNT(test_data_col) cnt, grp_col_1, grp_col2, grp_col3
  FROM test_tab
  GROUP BY grp_col_1, grp_col2, grp_col3
  HAVING COUNT(test_data_col) >= 3;

  In this request, I want to do something that will tell me if the aggregate COUNT (test_data_col) has all the duplicate values it contains. Yet once, display the duplicates is not important here.
  

  SELECT COUNT(test_data_col) cnt, grp_col_1, grp_col2, grp_col3,
  /*some logic*/ dup_val
  FROM test_tab
  GROUP BY grp_col_1, grp_col2, grp_col3
  HAVING COUNT(test_data_col) >= 3;

  With the correct to replace coding / * some * logic /, I have following values.
  
  CNT, grp_col_1, grp_col2, grp_col3, dup_val
  
  4, 1, a, xyz, Y
  3, 2, C, pqr, N
  
  I have dup_val column to explain what I'm trying to achieve... Another way to know the existence of duplicates in the aggregate count will be fine.
  
  My version of Oracle's Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0
  
  Do you like the answer!

  Your somewhere logical can be like that

  case when COUNT(test_data_col) != COUNT(distinct test_data_col) the 'Y' else 'N' end dup_val
  

• Values in the list by the order of table in SELECT Union

  Version: 11.2
  
  Apparently a very basic thing. But I couldn't do it :)
  
  In the UNION example below automatic sorting in is based on alphabetical order. I want to get rid of this sort and list the values according to the order of the table in the SELECT.
  
  Test data

  create table test1 (name1 varchar2(10));
  
  create table test2 (name2 varchar2(10));
  
  create table test3 (name3 varchar2(10));
  
  
  insert into test1 values ('EARTH');
  insert into test1 values ('TAURUS');
  insert into test2 values ('YELLOW');
  
  insert into test2 values ('ALPHA');
  insert into test2 values ('TANGO');
  
  
  insert into test3 values ('BRAVO');
  
  
  select name1 from test1
  union
  select name2 from test2
  union
  select name3 from test3;
  
  NAME1
  ----------
  ALPHA
  BRAVO
  EARTH
  TANGO
  TAURUS
  YELLOW
  
  6 rows selected.

  In the above example, I want the values in the first array SELECT listed first, then all the values of the second table in SELECT it and so on.
  
  Basically my requirement will be
  

  Return all values from test1 (alphabetically sorted)
  then
  Return all values from test2 (alphabetically sorted)
  then
  Return all values from test3 (alphabetically sorted)

  Expected results:

  NAME1
  ----------
  EARTH  ------------> from the first table in the SELECT
  TAURUS ------------> from the first table in the SELECT
  ALPHA  ----------------------> from the second table in the SELECT
  TANGO  ----------------------> from the second table in the SELECT
  YELLOW ----------------------> from the second table in the SELECT
  BRAVO  ------------------------------> from the third table in the SELECT

  Hello

  Union made a distinct in terms of the line. From the line "ALPHA", 2 and the line 'ALPHA', 3 are different, they both show in the result set.

  Further, you are all just lucky, that you get the results you want with the order clause:

  order by 2
  

  This performs a sort on the second column (1,2,3)
  Also, you want to sort on the first column (name1, name2 and Name3). The order clause should be (as already shown correctly abbove):

  order by
    2, 1
  

  Kind regards

  Peter

• Returns all the duplicate values in object lookup (PHP, drop-down list)

  Hi, I have a PHP page I designed as a search page. I have a number of drop-down lists that get their dynamic values from the fields in a MySQL database.

  At present, if there are any entries that have duplicate values in a certain area, they are all listed, in the order of the index database. For example:

  City:

  Derby

  Stoke

  Stafford

  Stoke

  Derby

  Derby

  Stoke

  etc...

  Now, I want to do is be able to show all results for a given city. In the find what drop-down list box, I would than each of the cities to appear only once rather than every time it is registered. included in this, I would like the page of results to then display ALL results that match this search criteria.

  Thus, in the example above, "Derby" appears only once, but when the user has selected 'Derby', it would return all three results in the results page.

  My results page is built on a dynamic form, so I am confident that the results page would make it according to the needs. However, how can I get the drop-down list box to ask him?

  > 'SELECT DISTINCT table1.champ1, table1.champ2, table1.champ3 FROM Table1 ";

  Duplicate rows to remove the DISTINCT keyword strength SQL. In other words, that it will only return the unique combinations of fields in your selection list. If you examine your results set, you will see that each line is separate, although there may be duplicates in a particular area. Because you want to populate a drop-down list, you must include a field in your select list only, otherwise you get of the dupes.

• Customize alert messages to check the duplicate value and alert success

  Hi all
  
  I want to show two alert against the button 'Submit' even at -.
  
  1 the attention of messages to check the duplicate value and show the duplicate value found alert and
  2 alert if successful the form's success to commit no duplicate values found.
  
  I did all the thing but what alert-1 show and I pressed the ok button of the alert, then the second alert also shows that I don't want to show.
  
  Who can I do about it? Have someone to help me!
  
  Arif

  Use the folliwng in PRE-INSERT-TRIGGER.

  There is not a lot of changes with the exception

  where CANCELLATION_USERID =: CANCELLATION_USERID;

  and

  If valExists > 0 then

  declare
  
   valExists number;
  
  begin
  
   select count(*) into valExists
   from USERDELETION
   where CANCELLATION_USERID = to_char(:CANCELLATION_USERID);
  
   if valExists > 0 then
    message('Duplicate value found !');
    -- show_alert('ERROR_ALERT');
   else
    message('All is well');
    -- show_alert('All is well ');
   end if;
  
  end;
  

• How to get the values in a single line, without the help of the union

  Hello
  
  I have a table with the structure and the following data
  
  EmpID address phoneno emailid
  1001 xyz
  1001 1234234
  1001 [email protected]
  1002 23434
  1002 [email protected]
  1003 abcd
  1003 [email protected]
  1004 [email protected]
  
  
  
  I need to get a result in this format.
  
  
  EMP id address phoneno emailid
  1001 xyz 1234234 [email protected]
  1002 23434 [email protected]
  1003 abcd [email protected]
  1004 [email protected]
  
  
  I can do this by using the union, but who gives a performance of questions with a large table. I want to do it using any other way using lead or something, but with the relative to data complexity, I couldn't do it.
  
  Can someone help me please?
  
  
  Natarajan
  
  Published by: Nikita on December 3, 2009 15:50

  Select employee_id, max(address), max(phone), max(email)
  from emp
  group by employee_id;
  

  Max

• ORA-06550: PLS-00394: wrong number of values in the list INTO a mesh FETCH

  Dear friends,
  I ask you a suggestion:
  
  The following code inserts a table errors (errori_work), the IDS of the records repeat (in the work of the table), but gives me this error:
  ORA-06550: PLS-00394: wrong number of values in the list of a FETCH statement INTO.
  
  The work of the table has the 78 columns: the problem of the fields used in the slider flew against the 78% ROWTYPE fields?
  I could use a record declared as the cursor (rec_tabwork cu_tabwork % ROWTYPE;), but in the MANUAL I need a field (ID_WORK) is not present in the cursor.
  
  declare
  CURSOR cu_tabwork IS
  SELECT CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, likelihood
  Work
  CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, applications GROUP
  HAVING COUNT (rowid) > 1
  UNION ALL
  SELECT CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, likelihood
  Work
  CD_STRUTTURA, CD_SUB_STRUTTURA, NR_PRATICA, applications GROUP
  After HAVING COUNT (rowid) > 2.
  rec_tabwork work % ROWTYPE;
  BEGIN
  Open cu_tabwork;
  loop
  extract the cu_tabwork in rec_tabwork;
  If FOUND then % cu_tabwork
  dbms_output.put_line (rec_tabwork. (ASL); -test
  INSERT INTO errori_work
  (cd_errore, note, ID_WORK)
  )
  VALUES ("ACC", "Record ripetuto nella table work", rec_tabwork.ID_WORK)
  );
  end if;
  EXIT WHEN cu_tabwork % NOTFOUND;
  end loop;
  close cu_tabwork;
  end;
  
  Can you help me?
  Thank you
  Leo

  Hello

  I loaded your data and ran the query. It's coz the NR_RICETTA contains a null value, so your State A.NR_RICETTA = B.NR_RICETTA will fail when it checks for NULL = NULL. Here is your output from the query

  PRAZY@orcl> select count(ID_AMBS) FROM WORK A
    2  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
    3  WHERE A.CD_PRESIDIO        =B.CD_PRESIDIO
    4  AND A.GGMM_CONTATTO        =B.GGMM_CONTATTO
    5  AND A.NR_RICETTA   =B.NR_RICETTA
    6  AND A.CD_CONT_PRESCR       =B.CD_CONT_PRESCR
    7  AND A.NR_PROG_INT  =B.NR_PROG_INT
    8  AND A.DESTINAZIONE =B.DESTINAZIONE)
    9  /
  
  COUNT(ID_AMBS)
  --------------
              48
  
  Elapsed: 00:00:00.00
  

  Therefore, I have included NVL to A.NR_RICETTA, which will produce true when it finds null checking 0 = 0 and you will get your result. and this is what you are looking for

  PRAZY@orcl> select count(ID_AMBS) FROM WORK A
    2  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
    3  WHERE A.CD_PRESIDIO        =B.CD_PRESIDIO
    4  AND A.GGMM_CONTATTO        =B.GGMM_CONTATTO
    5  AND NVL(A.NR_RICETTA,0)    =NVL(B.NR_RICETTA,0)
    6  AND A.CD_CONT_PRESCR       =B.CD_CONT_PRESCR
    7  AND A.NR_PROG_INT  =B.NR_PROG_INT
    8  AND A.DESTINAZIONE =B.DESTINAZIONE)
    9  /
  
  COUNT(ID_AMBS)
  --------------
              61
  
  Elapsed: 00:00:00.01
  

  If you want to insert the duplicate ID in a Table of errors, do an insert with the following select statement.

  INSERT INTO errori_work(cd_errore, note, ID_AMBS)
  SELECT 'CAC', 'Record ripetuto nella tabella Work',ID_AMBS FROM WORK A
  WHERE A.ROWID > ANY (SELECT B.ROWID FROM WORK B
  WHERE A.CD_PRESIDIO     =B.CD_PRESIDIO
  AND A.GGMM_CONTATTO     =B.GGMM_CONTATTO
  AND NVL(A.NR_RICETTA,0)     =NVL(B.NR_RICETTA,0)
  AND A.CD_CONT_PRESCR     =B.CD_CONT_PRESCR
  AND A.NR_PROG_INT     =B.NR_PROG_INT
  AND A.DESTINAZIONE     =B.DESTINAZIONE);
  

  Hope that solves your problem.

  See you soon!

• How to replace the value of a column in a table based on the value in the second column?

  Hi, I would like to find in a table 2D for values that meet certain criteria (for example, a column< 0.98).=""  based="" on="" which="" rows="" meet="" this="" criteria,="" i="" want="" to="" replace="" the="" values="" in="" a="" different="" column="" of="" the="" array="" (change="" to="" 'nan'="" so="" that="" the="" values="" will="" not="" be="" included="" in="" any="" calculations="" on="" that="" column,="" for="" example="" the="" finding="" the="" mean).=""  i've="" attached="" a="" sample="" .csv="" file.=""  if="" the="" values="" in="" column="" 3="" (index="" 2)="" are="" less="" than="" 0.980="" (or="" some="" other="" user="" defined="" value),="" then="" the="" value="" in="" column="" 2="" (index="" 1)="" should="" be="" replaced="" with="" nan.=""  can="" someone="" help="" out="" with="" this="" search="" and="" replace="">

  Thank you

  Keith

  (using LV 2009 SP1)

  A few quick hits.

  You can merge the two for loops

  You have not need one of the constants 1 and 2 in the index table.  They will solve automatically when you expand on the index picture, once you have wired to 0 in the column index.

  It seems a lot of handling additional table spent unnecessarily.

  See below.  I did not try to duplicate your code to see how it actually works, but I believe that I have attached will give the same result with less steps.

  

• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

• Range between unbounded preceding: default value of the windowing clause: question

  from online article down: https://oracle-base.com/articles/misc/analytic-functions

  question relates to the part I have in bold below.

  

  There are two things to note here.

  • The addition of the order_by_clause without a windowing_clause means that the query is now return an average race.
  • The default value for windowing_clause is "RANGE BETWEEN UNBOUNDED PRECEDING AND LINE CURRENT", not "ROWS BETWEEN UNBOUNDED PRECEDING AND LINE CURRENT. The fact that it is the BEACH means no LINES, it stops at the first occurrence of the value of the current row, even if it's several lines earlier. Accordingly, the duplicated lines are included in the average when the value of the wage. You can see in the two last records of the 20 Department and the records of the second and the third Department 30

  
  

  
  

  He mentions including duplicates if the salary is changed. I do not notice a salary in duplicates to change the display of the output, not in salary or individual pay on average (last two documents of the Department 20 for example, both treatments show 3000 respectively). Could someone please clarify this part of the article says it all.

  
  

  
  

  Watched again and I think I understand...

  Display duplicate is included only once in the average running not twice. What is he trying to tell me?

  I think it is correct but would not rather a bad assumption.

  AVG is not a good example. Just use count:

  SQL > select empno,.

  2 deptno,

  3 sal,

  4 count (*) on rows_cnt (partition by deptno stopped by rows of sal between prior 0 and 0 preceding).

  5 count (*) on range_cnt (partition by deptno arrested by sal ranged from 0 preceding and 0 preceding)

  6 of PEM

  7.

  EMPNO DEPTNO SAL ROWS_CNT RANGE_CNT

  ---------- ---------- ---------- ---------- ----------

  7934 10 1300 1 1

  7782 10 2450 1 1

  7839 10 5000 1 1

  7369 20 800 1 1

  7876 20 1100 1 1

  7566 20 2975 1 1

  7788 20 3000 1 2

  7902 20 3000 1 2

  7900 30 950 1 1

  7654 30 1250 1 2

  7521 30 1250 1 2

  EMPNO DEPTNO SAL ROWS_CNT RANGE_CNT

  ---------- ---------- ---------- ---------- ----------

  7844 30 1500 1 1

  7499 30 1600 1 1

  7698 30 2850 1 1

  14 selected lines.

  SQL >

  We hope now that you see the difference.

  SY.

• values based on the following logic 'values after the first values of two '_' and before last '_' values '.

  Hi all

  I need the values according to below 2logics in a single select query using instring and substring

  1 values based on the following logic 'values after the first values of two '_' and before last '_' values '.

  2 values based on the following logic 'values after the first values of two '_' and before last'-'values '.

  EXM:

  Entry: ABCD_EFGH_IJKLM - NOPQ_XYZ output: IJKLM - NOPQ

  Entry:. ABCD_EFGH_IJKLM - NOPQ output:IJKLM

  Thank you.

  Check the following

  WITH DATA1 AS

  (SELECT "ABCD_EFGH_IJKLM - NOPQ_XYZ" double val)

  UNION ALL

  SELECT 'ABCD_EFGH_IJKLM - NOPQ' double val

  )

  SELECT SUBSTR (VAL, INSTR(VAL,'_',1,2) + 1, DECODE (BIGGER (INSTR (VAL, '_',-1, 1), INSTR(VAL,'-',-1,1)), INSTR (VAL,'-', - 1, 1), LENGTH (VAL) + 1, INSTR (VAL, '_',-1, 1))-(INSTR (VAL, '_', 1, 2) + 1))

  OF DATA1;

  Concerning

  Salim

• update of NULL in the column with the values of the adjacent column

  Examples of data

  with test_data as
  (select 1 as one, null as two, 2 as three,5 as four, 6 as five, null as six from dual
  union all
  select 1 as one, null as two, 2 as three,5 as four, 6 as five, null as six from dual)
  select * from test_data;
  

  This is one of those cases, the case may be where any value of a column can be null

  or two similar columns can be null. If the column is null then I want to update the adjacent column

  average value of the column, if the first column is null so I want to take the next non-null column and update, if the last column is null

  so I want to take prev not zero column and to update.

  In this case would be my expected output

  Un	Two	Three	Four	Five	Six
  1	1.5	2	5	6	6
  1	2	3	5	6	6

  Prospects for the future the suggesion or advice.

  Or, using Analytics:

  SQL> with test_data (id, one, two, three, four, five, six) as (
    2    select 1, 1   , null, 2   , 5, 6, null  from dual union all
    3    select 2, 1   , null, 3   , 5, 6, null  from dual union all
    4    select 3, 1   , null, null, 5, 6, null  from dual union all
    5    select 4, null, null, null, 5, 6, null  from dual
    6  )
    7  select *
    8  from (
    9    select id
   10         , cell
   11         , case when next_nn is not null and prev_nn is not null
   12             then (next_nn + prev_nn)/2
   13             else nvl(next_nn, prev_nn)
   14           end val
   15    from (
   16      select id
   17           , cell
   18           , val
   19           , last_value(val) ignore nulls over(partition by id order by cell) as prev_nn
   20           , first_value(val) ignore nulls over(partition by id order by cell range between current row and unbounded following) as next_nn
   21      from test_data
   22      unpivot include nulls (val for cell in (one as 1, two as 2, three as 3, four as 4, five as 5, six as 6) )
   23    )
   24  )
   25  pivot ( min(val) for cell in (1 as "ONE", 2 as "TWO", 3 as "THREE", 4 as "FOUR", 5 as "FIVE", 6 as "SIX") )
   26  ;
  
          ID        ONE        TWO      THREE       FOUR       FIVE        SIX
  ---------- ---------- ---------- ---------- ---------- ---------- ----------
           1          1        1,5          2          5          6          6
           2          1          2          3          5          6          6
           3          1          3          3          5          6          6
           4          5          5          5          5          6          6
  

• Use the value of the sum and compare

  I have a table with data below

  T1

  ID, amount

  12,20

  13,10

  14.5

  create table T1 (ID number, amount);

  Insert into T1

  Select double 12.20;

  Union

  Select 13,10 double;

  Union

  Select double 14.5;

  I need the sum of the quantity and the value of the sum compares the values as flat > display then 10 0 otherwise amounted

  output

  ID, amount, derived

  12,20,20

  13,10,10

  14,5,5

  If my table has a

  T1

  12.0

  13.5

  It should be

  T1

  12,0,0

  13,5,0

  You can use the analytic function SUM

  select id, amount, case when sum(amount) over() > 10 then amount else 0 end derived from t1
  

• How to upgrade are the value of the column and the new column value created

  Hi all

  create the table xxc_temp

  as

  Select donnees_1 'AB103', 'AAA' data_2 data_3 '123', 'RED' data_4, NULL status in all the double union

  Select donnees_1 'AB105', 'BBB' data_2, '222' data_3, data_4 'BLUE', NULL status in all the double union

  Select donnees_1 'AB106', 'CCC' data_2, '333' data_3, data_4 'BLUE', the double NULL status

  create the table xxc_base

  as

  Select donnees_1 'AB103', 'AAA' data_2, '123' data_3 data_4 'RED', 'Inactive' status of Union double all the

  Select donnees_1 'AB105', 'BBB' data_2, '222' data_3 data_4 'BLUE' status 'Active' of all the double union

  Select donnees_1 'AB106', 'CCC' data_2, '333' data_3, data_4 'BLUE', 'Inactive' status of double

  I need to update the status column xxc_temp with xxc_base value of the status column and also if the user tries to insert new values/lines in the xxc_temp

  So how can I update the status column? I mean automatically set to day and also new values/lines

  I need to update only that are Inactive then these lines should be updated in the temporary table

  We can do this by using the stored function, but I need to update the new status of lines also

  Please help me

  Here's another way to do it, using VIRTUAL function column as expression to get the status of the other table

  CREATE or REPLACE FUNCTION GET_STATUS (pDATA_1 IN TANK) RETURN VARCHAR2 DETERMINISTIC

  AS

  vstatus VARCHAR2 (8);

  BEGIN

  SELECT status in vstatus FROM xxc_base WHERE donnees_1 = pDATA_1;

  RETURN vstatus;

  END;

  /

  DROP TABLE 'XXC_TEMP ';

  CREATE TABLE 'XXC_TEMP '.

  ('DONNEES_1' CHAR (5),

  "DATA_2" TANK (3).

  "DATA_3" TANK (3).

  "DATA_4' VARCHAR2 (4).

  'STATUS' VARCHAR2 (8) GENERATED ALWAYS AS (SUBSTR (GET_STATUS (DATA_1), 1, 8)) VIRTUAL

  ) ;

  INSERT INTO 'XXC_TEMP' (data_3, donnees_1, data_2, data_4))

  Select "AB103' donnees_1, data_2 'AAA', '123' data_3, 'RED' data_4 of any double union

  Select donnees_1 'AB105', 'BBB' data_2, '222' data_3 data_4 'BLUE' of all the double union

  Select donnees_1 'AB106', 'CCC' data_2 data_3 '333', 'BLUE' double data_4);