error handle output line 45 / column 9 / errors/warnings - tag must be associated, missing: [< /li > < /li > < /li > < /li >]

Similar Questions

• I get an error code when saving my page. He said: 'error on line 39 column 8:unbal. head tag

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; Charset = UTF-8 "/ >"

  <!-TemplateBeginEditable name = "head"--> <! - TemplateEndEditable - >

  < / head >

  <!-TemplateBeginEditable name = "doctitle"-->

  < title > NextBest Fest: new < /title >

  <! - TemplateEndEditable - >

  < style type = "text/css" >

  < / style >

  "" < link href = "... / stylesheets/nfb_styles.css" rel = "stylesheet" type = "text/css" / >

  < script type = "text/javascript" >

  <!--

  function MM_swapImgRestore() //v3.0 {}

  var i, x = offline. MM_sr; for (i = 0; a & & I <.) Length & & (x = a [i]) & & x.oSrc; i ++) x.src = x.oSrc;

  }

  function MM_preloadImages() {//v3.0

  var d = document; If (d.images) {if(!d.MM_p) d.MM_p = new Array();

  var i, j is d.MM_p.length, a = MM_preloadImages.arguments; for (i = 0; i <.) Length; i ++)

  If (a [i].indexOf("#")! = 0) {d.MM_p [j] = new Image; d.MM_p [j ++] .src = a [i] ;}}

  }

  function MM_findObj (n, d) {//v4.01

  var p, i, x;  if(!d) d = document; If ((p = n.IndexOf ("?")) > 0 & & parent.frames.length) {}

  d = parent.frames [n.Substring(p+1)] .document; n = n.Substring (0, p) ;}

  If (!) () x = d [n]) & & copyrights) x = d.all [n]; for (i = 0;! x & & i < d.forms.length; i ++) x = d.forms [i] [n];

  for (i = 0;! x & & d.layers & & I < d.layers.length; i ++) x = MM_findObj (n, d.layers [i] .document);

  If (! x & & d.getElementById) x = d.getElementById (n); Return x;

  }

  function MM_swapImage() {//v3.0

  var i, j = 0, x, a = MM_swapImage.arguments; document. MM_sr = new Array; for (i = 0; i <(a.length-2); I += 3).

  If ((x = MM_findObj (a [i]))! = null) {document. MM_sr [j ++] = x; if(!x.oSrc) x.oSrc = x.src; x.SRC = a [i + 2] ;}

  }

  ->

  < /script >

  < / head >

  < onload of the body = MM_preloadImages('..) "(/ graphics/nb_logo_over.png ')" > ".

  "" "< div id ="container"> < a href ="... / index.html "MM_swapImgRestore" onmouseover = "MM_swapImage ('logo_rollover',",'... / graphics/nb_logo_over.png ', 1) "> < img src =" "... / graphics/nb_logo.png" alt = name "NextBest Fest Logo and link to the home page" = "logo_rollover" width = "205" height = "110" border = "0" class = "logostyle" id = "logo_rollover" / > < / has > "

  "" "< div id ="content"> < span id ="nav"> < a href ="... / about.html "" > on < /a > < a href = "... / lineup.html" > range < /a > < a href = "... / schedule.html" "> annex < /a > < a href ="... / tickets.html "> tickets < /a > < a href ="... / contact.html "> contact < /a > < / span >"

  < h1 > < / h1 >

  <!-TemplateBeginEditable name = "page_head"->

  Heading < h1 > < / h1 >

  <! - TemplateEndEditable - >

  < table width = "100%" border = "0" cellspacing = "0" cellpadding = "0" >

  <!-Name = 'content'-> TemplateBeginRepeat

  < b >

  < td > <!-TemplateBeginEditable name = "EditRegion4"-> Add content here <!-TemplateEndEditable--> < table >

  < /tr >

  <! - TemplateEndRepeat - >

  < /table >

  < h2 > < / h2 >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  < p > < / p >

  <!-closing happy tag-->

  < / div >

  < div id = "footer" > <!-#BeginLibraryItem "/ Library/nb_footer.lbi"-->

  < a href = "mailto: " [email protected] ' > & copy; Copyright NextBest Fest 2012 < /a > <!-#EndLibraryItem--> < / div >

  <! - container tag closing - > < / div >

  < / body >

  < / html >

  Line 6, you closed yourtag. Then close it again you.

  Remove the 6 line.

• How to convert (multiple) output lines (multi-column)

  
  HII
  
  
  I have a weird request. But not sure how to get results out of it!
  
  
  My query returns two rows to a query I asked.
  
  
  
  Current result
  10
  20
  
  Expected result
  
  10 20
  
  My problem here is that I wanted two values above to be stored in two variables in a single select statement.
  
  
  
  If I use a cursor that my problem will be solved. But I'm not much interested in using a cursor for a simple select statement.
  
  
  
  is there a possibility that I can convert the output of two lines to two columns?
  
  
  
  I use Oracle Release 10.1.0.2.0
  
  
  
  Windows Xp operating system.
  
  
  
  People here will not appreciate the tags 'Urgent '. I know that :-(.
  
  
  
  But some how I'm forced to use this tag "urgent." Sorry for that.
  
  
  
  If no response, I will in another way can go to the slider :-(
  
  
  
  Any help will be appreciated.
  
  
  
  Thank you
  Pavan
  
  

  ??? WITH the clause is just a quick way to produce one on the fly table with your sample data. I think you should do a lot of reading material. In any case, use:

  select  dept,
          max(decode(rn,1,location,null)) location_1,
          max(decode(rn,2,location,null)) location_2
    from  (
           select  dept,
                   location,
                   row_number() over(partition by dept order by location) rn
             from  (
                    your-query
                   )
          )
    group by dept
  /
  

  SY.

• Cannot install the debugging for bb10 token: error in tag hr

  After having successfully generated a debugging token, jcdebug.bar, I tried to install it using blackberry - deploy and got a fatal system error.  My entry of order/.output line is below.  What am I doing wrong now?

  Token of debugging C:\Users\Jacquelyn\Documents\Jacquie\Blackberry\bb10 > "C:\Program Fil".

  are (x 86) \Research in Motion\BlackBerry 10 SDK WebWorks 1.0.4.7\dependencies\tool

  s\bin\blackberry - deploy"installDebugToken - jcdebug.bar - 192.168.1.10/24 device

  -password mypassword

  [Fatal error]: 5:3: the element type "hr" must end with the corresponding end

  -tag «»

  Error: Authentication failed due to system error

  DOH!  I forgot to put my (dev alpha B) device in development mode.  Also used the IP address specified for the development.

  Fixed a problem.

  Now we'll see if I can put the debug token...

• Model Dreamweaver, renounce the error 'instancebegineditable tag inside the editable region.

  I searched the internet and no matter what forum I can find about Dreamweaver and find the solutions that they don't did not help me, but there was a problem of command for many people. I created a template by following the steps via a tutorial from helpvid.net and the website looked very good to be pretty basic but since last night when I try save the model gives the error message "there is an error in line 8, column 47 (absolute position 789) of 'address of the file': InstanceBeginEditable tag inside the editable region.» Now from what I have read on the forums that means usually there is a spelling error or something placed inside the area when should not be, but there are only 50 odd lines on it and can't see any problem. When I view the files it gives error on, replicas of the editable 'start' there are has a number of times, but they shouldn't be there because they are not on the model. IM also conclusive that until this error came pages went well when downloaded, but now the footer height that has been set to 20px is 200px when downloaded and I check all coding for it so the Divs see but still no error. I downloaded my tempalete and some of the pages that mistakes about donations to see if that help, do not know if its better just stick wall of coding so sick message links to the files and if the code must be pasted here ill do it. http://dublinmoulding.com/ <-work im site, one can see the footer is very large. Should be 20px height but inspect element shows his 200px - #wrapper #footer {color: #FFF;}     height: 200px; The model is #wrapper #footer {color: #FFF;}     text-align: center;     margin: 0px;     do-size: 18px;     make-style: normal;     make-weight: lighter;     do-family: Arial, Helvetica, without serif.     padding-top: 5px;     padding-right: 0px;     padding-bottom: 5px;     padding-left: 0px;     height: 20px; http://dublinmoulding.com/dreamweaver/temp1.dwt <-my error tempalate is abandoned on pages created by using the template

  
  

  * Update * I've edited file names of some of the pages I used the template on so now it shows as coding.

  
  

  http://dublinmoulding.com/Dreamweaver/index.html6 <-my index page

  http://dublinmoulding.com/Dreamweaver/about.html6 <-on the page
  

  I've recreated the model and its not waive errors and the layout seems well, hurt that mark as resolved thank you for help

• ORA-06550: line 1, column 7: PLS-00306: wrong number or types of arguments

  Hi all
  Here is the error:
  ORA-06550: line 1, column 7: PLS-00306: wrong number or types of arguments
  The following code generates the error:
  create or replace PROCEDURE AMENDNUMBER_UPDATE
  (
  SHIP_NUMBER IN VARCHAR2,
  AMEND_NO ON SYS_REFCURSOR)
  AS
  BEGIN
  UPDATE CSPS_SHIPMENT_INFO_TL
  SET AMENDMENT_NO =
  (SELECT AMENDMENT_NO + 1
  OF CSPS_SHIPMENT_INFO_TL
  WHERE SHIPMENT_NUMBER = SHIP_NUMBER
  )
  WHERE SHIPMENT_NUMBER = SHIP_NUMBER;
  
  AMEND_NO OPEN FOR SELECT AMENDMENT_NO FROM CSPS_SHIPMENT_INFO_TL WHERE SHIPMENT_NUMBER = SHIP_NUMBER;
  
  -VALIDATION;
  END AMENDNUMBER_UPDATE;
  
  now when I try to run the under statement I get the above error:
  exec amendnumber_update (ship_number);
  
  
  Please suggest how to manage...

  Hello

  TCSBPMUSER wrote:
  Hi all
  Here is the error:
  ORA-06550: line 1, column 7: PLS-00306: wrong number or types of arguments

  It's one of these error messages that actually means what he says.

  The following code generates the error:
  create or replace PROCEDURE AMENDNUMBER_UPDATE
  (
  SHIP_NUMBER IN VARCHAR2,
  AMEND_NO ON SYS_REFCURSOR)
  AS...

  now when I try to run the under statement I get the above error:
  exec amendnumber_update (ship_number);

  The procedure requires 2 arguments.
  You try to call with only 1 argument. It's the wrong number of arguments.

  To call the procedure from SQL * Plus, you can do something like this:

  VARIABLE   rc  REFCURSOR
  
  EXEC  amendnumber_update (123, :rc);
  

  The 1st argument is an argument IN, so you can pass any kind of digital expression. (I used a literal above.)
  The 2nd argument is an OUT argument, so you must pass a variable. (I used a variable link above.)

• ORA-06550: line 21, column 5: PLS-00306: wrong number or types of arguments

  Dear Sir
  
  can someone help what is the problem?
  I get the error message:
  ORA-06550: line 21, column 5: PLS-00306: wrong number or types of arguments in the call to 'STRONG_PASSWORD_VALIDATION' ORA-06550: line 21, column 5: PL/SQL: statement ignored
  
  code is:
  ---
  DECLARE
  l_username varchar2 (100);
  l_password varchar2 (100);
  l_old_password varchar2 (100);
  l_workspace_name varchar2 (30);
  l_min_length_err boolean;
  l_new_differs_by_err boolean;
  l_one_alpha_err boolean;
  l_one_numeric_err boolean;
  l_one_punctuation_err boolean;
  l_one_upper_err boolean;
  l_one_lower_err boolean;
  l_not_like_username_err boolean;
  l_not_like_workspace_name_err boolean;
  l_not_like_words_err boolean;
  BEGIN
  l_username: =: P29_CURR_USER;
  l_password: =: P29_NEW_PW;
  l_old_password: =: P29_PW;
  l_workspace_name: = APEX_UTIL. GET_DEFAULT_SCHEMA;
  APEX_UTIL. () STRONG_PASSWORD_VALIDATION
  p_username = > l_username,.
  p_password = > l_password,
  p_old_password = > l_old_password,
  p_workspace_name = > l_workspace_name,
  p_use_strong_rules = > false,
  p_min_length_err = > l_min_length_err,
  p_new_differs_by_err = > l_new_differs_by_err,
  p_one_alpha_err = > l_one_alpha_err,
  p_one_numeric_err = > l_one_numeric_err,
  p_one_punctuation_err = > l_one_punctuation_err,
  p_one_upper_err = > l_one_upper_err,
  p_one_lower_err = > l_one_lower_err,
  p_not_like_username_err = > l_not_like_username_err,
  p_not_like_workspace_name_err = > l_not_like_workspace_name_err,
  p_not_like_words_err = > l_not_like_words_err
  );
  
  IF l_min_length_err THEN
  return ('Kennwort ist zu kurz');
  END IF;
  
  IF l_new_differs_by_err THEN
  return ("' muss sich vom alten Kennwort unterscheiden Kennwort");
  END IF;
  
  IF l_one_alpha_err THEN
  return ('wenigstens einen letter included muss Kennwort');
  END IF;
  
  IF l_one_numeric_err THEN
  return ('wenigstens eine Ziffer included muss Kennwort');
  END IF;
  
  IF l_one_punctuation_err THEN
  return ('wenigstens ein Sonderzeichen included muss Kennwort');
  END IF;
  
  IF l_one_lower_err THEN
  return ('wenigstens einen Kleinbuchstaben included muss Kennwort');
  END IF;
  
  IF l_one_upper_err THEN
  return ('wenigstens einen Grossbuchstaben included muss Kennwort');
  END IF;
  
  IF l_not_like_username_err THEN
  return ('Kennwort darf nicht den included Nick');
  END IF;
  
  IF l_not_like_workspace_name_err THEN
  return ('Kennwort darf nicht den Namen-Workspace included');
  END IF;
  
  IF l_not_like_words_err THEN
  Return ("' contains unerlaubten term Kennwort") End Function
  END IF;
  Returns a null value.
  END;
  ---
  Any help is welcome.
  Kind regards
  Lorenz

  Look in your version of apex_util. Your code certainly doesn't look like using STRONG_PASSWORD_VALIDATION, which has very different parameters.

  My version (4.0) of STRONG_PASSWORD_CHECK has 16 parameters, your code has 15.

• ORA-06550: line 1, column 34: PLS-00103 in Validation element with 4 APEX

  Hello
  I use 4 APEX?
  I created ths program to validate an element
  DECLARE
  LONGEUR1 NUMBER;
  BEGIN
  Select the LENGTH IN LONGEUR1 OF the BOOK WHERE code_ouvrage = (select code_ouvrage from the book where language =: P6_CODE_OUVRAGE);
  IF: P6_PK < 0 or: P6_PK > LONGEUR1 THEN
  RETURN FALSE;
  ON THE OTHER
  RETURN TRUE;
  END IF;
  END;
  
  I had thir error message when you run the page:
  ORA-06550: line 1, column 34: PLS-00103: symbol "DECLARE" met instead of one of the following symbols: () - + new case mod not null to other table avg current County exists max min prior sql stddev sum variance run the two main merger year forall multiset months DAY_ hour minute second stimezone_minute timezone_region timezone_abbr time end date interval timestamp timezone_hour
  
  ERR-1025 expression PLSQL treatment error. DECLARE LONGEUR1 NUMBER; START LENGTH Select INTO LONGEUR1 FROM BOOK WHERE code_ouvrage = (select code_ouvrage from the book where language =: P6_CODE_OUVRAGE); IF: P6_PK < 0 or: P6_PK > LONGEUR1 THEN RETURN FALSE; ELSE RETURN TRUE; END IF; END;
  
  
  All siggestion please?

  Rob wrote:
  Hello
  I use 4 APEX?
  I created ths program to validate an element
  DECLARE
  LONGEUR1 NUMBER;
  BEGIN
  Select the LENGTH IN LONGEUR1 OF the BOOK WHERE code_ouvrage = (select code_ouvrage from the book where language =: P6_CODE_OUVRAGE);
  IF: P6_PK < 0="" or="" :p6_pk=""> LONGEUR1 THEN
  RETURN FALSE;
  ON THE OTHER
  RETURN TRUE;
  END IF;
  END;

  I had thir error message when you run the page:
  ORA-06550: line 1, column 34: PLS-00103: symbol "DECLARE" met instead of one of the following symbols: () - + new case mod not null to other table avg current County exists max min prior sql stddev sum variance run the two main merger year forall multiset months DAY_ hour minute second stimezone_minute timezone_region timezone_abbr time end date interval timestamp timezone_hour

  ERR-1025 expression PLSQL treatment error. DECLARE LONGEUR1 NUMBER; START LENGTH Select INTO LONGEUR1 FROM BOOK WHERE code_ouvrage = (select code_ouvrage from the book where language =: P6_CODE_OUVRAGE); IF: P6_PK < 0="" or="" :p6_pk=""> LONGEUR1 THEN RETURN FALSE; ELSE RETURN TRUE; END IF; END;

  All siggestion please?

  What is the Validation Type? It seems you are trying to use the code for validation of Boolean function return in one of type PL/SQL Expression.

  Make sure that the Validation Type is function to return a Boolean.

• Help: java.sql.SQLException: ORA-06550: line 1, column 7:, PLS-00201:

  Who can give me a hand to settle the question below? I use the db 11G for two or three days. This works. But now it displays information below, it blocks my server needs to be in place. Can anyone help to take a look? And explain to me what is meaning with below question?
  
  Thank you
  
  
  java.sql.SQLException: ORA-06550: line 1, column 7:
  PLS-00201: identifier ' INVALIDHTOMEH. KEEP ' should be declared
  
  oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:138)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:316)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:282)
  11/08/05 02:18:17-oracle.jdbc.driver.T4C8Oall.receive(T4C8Oall.java:639)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CCallableStatement.doOall8(T4CCallableStatement.java:184)
  11/08/05 02:18:17-oracle.jdbc.driver.T4CCallableStatement.execute_for_rows(T4CCallableStatement.java:873)
  11/08/05 02:18:17-oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1161)
  11/08/05 02:18:17-oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3001)
  11/08/05 02:18:17-oracle.jdbc.driver.OraclePreparedStatement.execute(OraclePreparedStatement.java:3093)
  11/08/05 02:18:17-oracle.jdbc.driver.OracleCallableStatement.execute(OracleCallableStatement.java:4286)
  11/08/05 02:18:17-com.agile.pc.cmserver.util.OracleIDGenerator.pinSequence(OracleIDGenerator.java:245)
  11/08/05-02:18:17-com.agile.pc.cmserver.util.OracleIDGenerator. < init > (OracleIDGenerator.java:62)
  11/08/05 02:18:17-com.agile.pc.cmserver.util.CMUtilReflection.getOracleIDGenerator(CMUtilReflection.java:79)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getNewInstance(IDGenerator.java:78)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getInstance(IDGenerator.java:66)
  11/08/05 02:18:17-com.agile.util.dao.IDGenerator.getNextID(IDGenerator.java:91)
  11/08/05-02:18:17-com.agile.util.AppServerId. < clinit > (AppServerId.java:14)
  11/08/05 02:18:17-com.agile.startup.PCMStartupImpl.start(PCMStartupImpl.java:115)
  11/08/05 02:18:17-com.agile.ui.pcm.InitServlet.init(InitServlet.java:63)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.loadServlet(HttpApplication.java:2379)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.findServlet(HttpApplication.java:4830)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.findServlet(HttpApplication.java:4754)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.initPreloadServlets(HttpApplication.java:4942)
  11/08/05 02:18:17-com.evermind.server.http.HttpApplication.initDynamic(HttpApplication.java:1144)
  11/08/05-02:18:17-com.evermind.server.http.HttpApplication. < init > (HttpApplication.java:741)
  11/08/05 02:18:17-com.evermind.server.ApplicationStateRunning.getHttpApplication(ApplicationStateRunning.java:431)
  11/08/05 02:18:17-com.evermind.server.Application.getHttpApplication(Application.java:586)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite$ HttpApplicationRunTimeReference.createHttpApplicationFromReference (HttpSite.java:1987)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite$ HttpApplicationRunTimeReference. < init > (HttpSite.java:1906)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite.initApplications(HttpSite.java:643)
  11/08/05 02:18:17-com.evermind.server.http.HttpSite.setConfig(HttpSite.java:290)
  11/08/05 02:18:17-com.evermind.server.http.HttpServer.setSites(HttpServer.java:270)
  11/08/05 02:18:17-com.evermind.server.http.HttpServer.setConfig(HttpServer.java:177)
  11/08/05 02:18:17-com.evermind.server.ApplicationServer.initializeHttp(ApplicationServer.java:2493)
  11/08/05 02:18:17-com.evermind.server.ApplicationServer.setConfig(ApplicationServer.java:1042)
  11/08/05 02:18:17-com.evermind.server.ApplicationServerLauncher.run(ApplicationServerLauncher.java:131)
  
  Published by: user774630 on November 4, 2008 18:57

  # com.agile.pc.cmserver.util.OracleIDGenerator.pinSequence(OracleIDGenerator.java:245)

  This method tries to pin a sequence in the Shared Pool so that it is not recharged. Reloading can cause sequence numbers to be ignored, if I remember correctly.
  Pinning is done using packed the INVALIDHTOMEH procedure. KEEP. The error is reported because either the package INVALIDHTOMEH is not created in the database (the $ORACLE_HOME/rdbms/admin/dbmspool.sql script creates) or the user who connects to the database have not run privilege for the package.

  Note that the package has access to the shared swimming pool. Execute privilege to grant only trusted users.

  -Sergiusz

• Sort sort the columns number of lines n columns in the RTF PivotTable but hide them.

  Hello

  I'm trying to sort on the columns number of sort for lines n columns in the PivotTable but hide them. Any help appreciated.

  Attached model RTF, XML and output required. Thank you

  Please check your email that I have forwarded to update the model.

  by default, it performs a sort on the column, we used to pivot rows and columns. If we need custom sort, we must specify that column in the logic that was present in the C form field.

  by default, you are as below

  Custom sort

  {INDUSTRY_sort, o = a, t = n} « ; » MONTHS {Month_sort, o = a, t = n} '; SALES '; "' sum '? >

• Write a SQL query with lines in columns

  All the

  I need help in writing a SQL query with lines in columns, let give u an example...

  drop table activity;

  CREATE TABLE 'ACTIVITY '.

  (

  "PROJECT_WID" NUMBER (22.0) NOT NULL,

  VARCHAR2 (150 CHAR) "PROJECT_NO."

  VARCHAR2 (800 CHAR) 'NAME '.

  );

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1683691, '10007', 12-121');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1684994, '10008', 12-122');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (1686296, '10009', 12-123');

  Insert in the ACTIVITY (PROJECT_WID, PROJECT_NO, NAME) values (2225222, '9040', 12-124');

  drop table lonet;

  CREATE TABLE 'LONET.

  (

  VARCHAR2 (150 CHAR) "NAME."

  NUMBER OF THE "ROOT."

  VARCHAR2 (150 CHAR) "ENTRYVALUE".

  );

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("GAC", 1683691, "LDE");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('NAM', 1683691, 'LME');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('BAG', 1683691, 'ICE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1683691, 'IKE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('NAM', 1686291, "QTY");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1686291, 'MAX');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("GAC", 1684994, "MTE");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('PAP', 1684994, 'MAC');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('FMT', 1684994, 'NICE');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('FMR', 1684994, 'RAY');

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ('BAG', 1686296, "CAQ");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("PAP", 1686296, "QAQ");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("VANESSA", 1686296, "THEW");

  INSERT INTO LONET (NAME, ROOT, ENTRYVALUE) VALUES ("ANDR", 1686296, "REYL");

  commit;

  Link: activity.project_wid = lonet.root

  look like output

  Project_wid	Project_no	NAME	GAC	NAM	BAG	RAC
  1683691	10007	12-121	LDE	LME	LCE	LKE
  1684994	10008	12-122	MTE	null	null	MAC
  1686296	10009	12-123	null	null	CAQ	QAQ
  2225222	9040	12-124	null	null	null	null

  two problems, in that I am running

  1. I dono how simply we can convert rows to columns

  2. for root = 1683691, there are double NAM and RAC in lonet table... ideally these data should not be there, but since its here, we can take a MAX so that it returns a value

  3. There are undesirables who should be ignored

  Once again my thought process is that we join the activity and 4 alias table lonet.

  ask for your help in this

  Thank you

  Hello

  This is called pivoting.

  Here's a way to do it:

  WITH relevant_data AS

  (

  SELECT a.project_wid, a.project_no, b.SID

  , l.name AS lonet_name, l.entryvalue

  Activity one

  LEFT OUTER JOIN lonet l.root = a.project_wid l

  )

  SELECT *.

  OF relevant_data

  PIVOT (MAX (entryvalue)

  FOR lonet_name IN ("GAC" IN the gac

  "NAM" AS nam

  'BAG' IN the bag

  "RAC" AS cars

  )

  )

  ORDER BY project_wid

  ;

  Output:

  PROJECT_WID PROJECT_NO GAC NAM BAG RAC NAME

  ----------- ---------- ---------- ---------- ---------- ---------- ----------

  1683691 12 - 10007 121 LDE LME LCE LKE

  1684994 MAC MTE 10008 12-122

  1686296 12 - 10009 123 QAC QAQ

  2225222 9040 12 - 124

  To learn more about swivel, see the FAQ in the Forum: Re: 4. How can I convert rows to columns?

  Thanks for posting the CREATE TABLE and INSERT statements; It's very useful!

• AWK print 1st line of column 2

  hope I can get help with awk unix guys here

  trying to get the line 2, column 1 leaving an output of l - esxcfg-vswitch

  basically by train to get the ID of dvport vmnic0

  esxcfg-vswitch - l | grep vmnic0 | AWK '{print $1} '.

  column 1 shows

  and

  esxcfg-vswitch - l | grep vmnic0 | AWK 'NR == 2'

  line 2 shows

  How to show a line of column 1 2 only?

  AWK 'NR is 2 {print $1}'

• How to view the line of columns without using the pivot keyword

  Hello
  could someone help me how to display lines in columns without using the keyword pivot and actuall is my scenario, iam having two tables with names and examples of data is shown below
  
  MIDDLE MINAME TASKID TASKNAME IDENTIFICATION PROJECT
  
  1 PROJ1 1 AA 100 PR1_TASK1
  1 PROJ1 3 CC PR1_TASK3 102
  1 PROJ1 DD 4 103 PR1_TASK4
  1 PROJ1 EE 5 104 PR1_TASK5
  1 PROJ1 6 105 FF PR1_TASK6
  2 PROJ2 EE 5 114 PR2_TASK1
  2 PROJ2 6 115 FF PR2_TASK2
  2 PROJ2 GG 7 116 PR2_TASK3
  2 PROJ2 HH 8 117 PR2_TASK4
  2 PROJ2 9 118 PR2_TASK5 JJ
  2 PROJ2 KK 10 119 PR2_TASK6
  2 PROJ2 1 AA PR2_TASK7 120
  
  
  The output should show the project and County of tasks at a given stage as shown below
  
  project AA BB CC DD EE FF GG HH JJ KK
  1 2 0 1 5 3 2 0 2 1 0
  2 1 2 0 2 1 0 2 4 3 1
  
  
  Thanks in advance,
  VVR

  CREATE TABLE pivot_test (
  ID           NUMBER,
  PROJECT      VARCHAR2(10),
  MID          NUMBER,
  MINAME       VARCHAR2(5),
  TASKID       NUMBER,
  TASKNAME     VARCHAR2(10)
  );
  
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 1,  'AA', 100, 'PR1_TASK1');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 3,  'CC', 102, 'PR1_TASK3');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 4,  'DD', 103, 'PR1_TASK4');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 5,  'EE', 104, 'PR1_TASK5');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 6,  'FF', 105, 'PR1_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 5,  'EE', 114, 'PR2_TASK1');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 6,  'FF', 115, 'PR2_TASK2');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 7,  'GG', 116, 'PR2_TASK3');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 8,  'HH', 117, 'PR2_TASK4');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 9,  'JJ', 118, 'PR2_TASK5');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 10, 'KK', 119, 'PR2_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 1,  'AA', 120, 'PR2_TASK7');
  
  SELECT ID as PROJECT,
         SUM(DECODE(miname, 'AA', 1, 0)) AS AA,
         SUM(DECODE(miname, 'BB', 1, 0)) AS BB,
         SUM(DECODE(miname, 'CC', 1, 0)) AS CC,
         SUM(DECODE(miname, 'DD', 1, 0)) AS DD,
         SUM(DECODE(miname, 'EE', 1, 0)) AS EE,
         SUM(DECODE(miname, 'FF', 1, 0)) AS FF,
         SUM(DECODE(miname, 'GG', 1, 0)) AS GG,
         SUM(DECODE(miname, 'HH', 1, 0)) AS HH,
         SUM(DECODE(miname, 'JJ', 1, 0)) AS JJ,
         SUM(DECODE(miname, 'KK', 1, 0)) AS KK
  FROM   pivot_test
  GROUP BY ID;
  
  PROJECT AA BB CC DD EE FF GG HH JJ KK
  ------- -- -- -- -- -- -- -- -- -- --
        1  1  0  1  1  1  1  0  0  0  0
        2  1  0  0  0  1  1  1  1  1  1 
  

• Lines in columns

  Hello
  
  I'm currently stuck with a problem when trying to convert some lines in columns, but the solutions I've found don't quite give me the result I want.
  
  Here's an example of how the transactional system stores its information.
  

  TRANS_REF   TRANS_LINE  ITEM_CODE   SUPP_DESCR                      PURCH_QTY
  PPI-026166  1           TELE1       Teléfono Celular Bmobile QW101  7000
  PPI-026166  2           TELE1       Teléfono Celular Motorola Spic  300
  PPI-026166  3           -           e                               0
  PPI-026166  4           TELE1       Teléfono Celular Huawei 6150 3  3777.7777
  PPI-026166  5           -           G, color azul/negro, Manos lib  0
  PPI-026166  6           -           res, manual inglés/español, Mi  0
  PPI-026166  7           -           cro SD de 2GB. Version SW: U61  0
  PPI-026166  8           -           50CAMB100                       0

  As you can see the transaction system is not any kind of ID for each item and each spans several lines, but the desired report would need the description be concatenated into a single description, like that I should only be left with 3 rows. The "good" is to identify the start of an element by the "TELE1' ITEM_CODE and not knowing how many lines the description will take.
  
  Concerning

  Hello

  vacadude wrote:
  Thanks much for the tips on how to post!

  Well, I use Oracle 11g,

  There is no Oracle 11f or 11 o'clock, so it is a bit ridiculous to say that you are using 11g. Say something like 'I'm using Oracle 11.2.0.1.0'.

  and the results you've posted, that's exactly what I'm looking for. I guess it would be with the LISTAGG function but I can't quite grasp its use, could you help me a bit with her?

  Here's a way to get these results using the LISTAGG:

  WITH     got_grp_id     AS
  (
       SELECT     transactions.*
       ,     COUNT (CASE WHEN item_code = 'TELE1' THEN 1 END)
                OVER ( PARTITION BY  trans_ref
                        ORDER BY        trans_line
                      )       AS grp_id
       FROM    transactions
  )
  SELECT       trans_ref
  ,       MIN (trans_line)          AS first_trans_line
  ,       LISTAGG (supp_descr) WITHIN GROUP (ORDER BY trans_line)
                                        AS supp_descr
  ,       MAX (purch_qty)          AS purch_qty
  FROM       got_grp_id
  GROUP BY  trans_ref
  ,            grp_id
  ORDER BY  trans_ref
  ,            grp_id
  ;
  

  LISTAGG guess the order of the concatenated elements is always important, so he always requres «...» In the BOSOM OF THE GROUP (SOMETHING)". This differs from the more common aggregate functions (including MIN and MAX), where the order of the entries lines dioesn can't issue, and there is nothing to sort on an output, so these functions have «...» In the BOSOM OF THE GROUP (SOMETHING)".
  (Besides, if, for some reason, you really want to exit in a random order, you would have to say something like)

  LISTAGG (supp_descr)  WITHIN GROUP (ORDER BY  0)
  

  ).

  You always need a subquery as got_grp_id, because you need to GROUP BY something like grp_id, being derived from an anlalytic function, and GROUP BY is done before the analytical functions are calculated.
  With LISTAGG, you do not need a subquery as got_r_num. Using CONNECT BY, something very ordinary (such as integers consectuive) was necessary to get the lines in the order. LISTAGG using, what can go in a cllause ORDER BY is good enough.

• Matrix - vector lines and columns

  M1 (3,2) gives the element of line 3, column 2

  M1 (2) gives the second row of a matrix (as a vector line)

  Is there a way to return a column (other than transpose, store again and using the method above on the transposed matrix)?

  Tim Wessman wrote:
  

  Assuming that first here...

  Col(M1,1)

  Row(M1,1)

  @ Tim,.

  As Mmmm - created a post on the 39gii and commented on a post on the 39gii, this one is perhaps more likely to be on the 39gii?

  I think that your presumption re - expresses my presumption that the 39gii becomes brother forgot the premium?

  @ Mmmm.

  Try M1 (-c), where C is desired column number. For example M1(-2) for column 2.