Example of the queue to hit

Similar Questions

• HP 8500 of print jobs stuck in the queue, diagnostic control OK

  HP 8500 A909g connected by USB cable to the Windows 7 desktop. Everything was going well until Verizon gave me a new DSL modem/router after which all print jobs are stuck in the print queue. Printing/scanning doctor told me "printer not connected to the homegroup. Nothing I've tried fixed. Downloaded the recent HP patch for network HP printers in Win7. Complete with a mistake any but installed at the next computer startup and scanning and printing has worked very well. Since then, the print jobs again get hit in the print queue and scanner does not work. Has made clear the queue, stop/start the spooler and the computer restarted. Still no printing or scanning. Print/ASNA doctor says everything is OK. Upgrades of the pilot research suggests that I already have the best driver. Printer is checked OK in the control/material Panel, is checked by default, port is OK etc etc. Before uninstall/reinstall the printer with no guarantee that will solve this problem, can someone tell me what could be wrong and how to fix it? Please help as this is really frustrating. Thanks in advance.

  Hi abuonag,

  We need clean completely the previous attempts of software to get a good setup for this printer.

  Follow the steps below and let me know what happens?

   

  First step: clear temp directory

  1. Type %temp% term or search programs and files of field
  2. Select all the files in this folder, and then press the delete key to remove. If you receive a message that the file is in use, you will need to ignore this file (s).
  3. Proceed to step 2 below

  Second step: downloaded and extracted to your system:

  1 download the drivers and full software features

  http://h10025.www1.HP.com/ewfrf/wc/softwareDownloadIndex?softwareitem=MP-88604-2&cc=us&DLC=en&LC=en&OS=4063&product=3752459&sw_langis.

  2. once the download is complete, double-click the file to extract the software.

  3. when the installation window opens, press the Cancel button to stop the installation

  4. tap folder in the race or search programs and files of field

  5. Locate and open the folder starting with 7z (example: 7zS2356)

  6. right click on the folder and select copy

  7. close this window and all open windows, and then in the Middle the desktop right click your mouse and select Paste. This will move the 7z folder on your desktop.

  8 open the 7z, that you just copied on your desktop

  9 open the Util folder

  10 open the CCC folder

  11. start the L4uninstall.exe

  12. once the uninstall is complete, restart the computer

  13. run disk cleanup from the tools Accessories\ system under all programs folder

  14. download and install the latest version of Adobe flash player

  http://www.Adobe.com/support/flashplayer/downloads.html

  15 open the 7z folder and then double-click the Setup.exe file that will be towards the bottom of the open window. Follow the instructions on the screen to reinstall your printer.

  Let me know if you are able to successfully install the software and driver and are able to print & scan?

• M127fw MFP: How to delete the print jobs in the queue?

  When I get an error message when trying to print, I keep trying to print.  This means that I can hit 'print' five times for the same document, because I hit 'print' whenever I think I might finally have something fixed.

  The problem is that HP never forget any of these applications - when it finally starts printing - it always prints every single job - meaning that I get multiple copies of jobs for which I got an error message.

  Where is the interface to view and delete these jobs? I can't find it on the printer itself.  Is there an interface where I can delete jobs in the queue?

  Go to devices and printers and double click on the printer icon. Now click on something like seeing what is printing a list of documents should appear and you can pass by and remove whatever ones you want.

• Size of the queue for Signal form write XNET

  Hello

  I am using the XNET library to play a preset on an output signal waveform. I work with LabVIEW 2014 SP1, 14.5 XNET on a W7 Pro 32-bit operating system. I use an NI PCI-8512 map. This is my first app using the xnet library.

  In my test application, I give the user the ability to set the waveform to play. The total duration and the sampling frequency can be set. The output MAY report is cyclical, with a cycle time of 0.01 s (10 Hz). I chose to use the same frequency for example my wave form and writing of the CAN.

  I have difficulty working with the size of the queue. In this example, it's good but I did not really why. I tested different values in the size of the queue and 100000 seems to be good up to 60 seconds. But for the longest (about 5 minutes), this method is not good...

  

  What is the right way to work in this mode and how use efficiently the property size queue? Information and example of using software and hardware OR XNET are not very convincing...

  Thank you in advance!

  You can add several items at the end of the queue until the queue is empty.  So if you want to write 10,000 points, and your buffer is only 1000 points, then wait and monitor the number of messages remaining in the buffer, and once it is less than 100 say adds an another 900.

  I used this method for flashing on CAN and LIN.  I needed a way to watch specific at specified times images, and a single point of frame link would not repeat (which could write the same byte twice what would be bad) I could have made the rivers and used avoiding, but a better solution was to use queue and add more pictures at the end of the queue to try to keep it as complete as possible.

• Writing in the spreadsheet with the queue

  Hello

  I am a beginner with queues and I have a few questions.  I have attached a simple example of code that I wrote to better implement a consumer who can queue data and write on a worksheet after running the code.

  First of all, I noticed that the queue still has residual remaining after the code ends.  It then writes this element to the file to run the vi.  I can't figure how to get rid of this element.

  Second, anyone have any suggestions to improve this code?  I've been playing with it for quite some time and I finally got to work like that, but it is certainly configured differently from the other examples I've seen.

  Thirdly, I am reading the number of items in the queue, but the two in the loop of the producer and the consumer, told me that there is no element.  How can this be?  My output file seems to work and I certainly put items in the queue.

  Finally, in the future I'll use data from the queue in two places.  Here I've implemented a notifier to do the job.  This is the best method?

  Thanks for your help!

  Jason

  The reason why you do not get the last element of the queue (at least not until you restart the VI) is that you have your automatic indexation tunnel that collects all the data to send to the writing on file SS service cable for moving to register.  So this last piece of data from the queue to get into the shift register, but it is not getting into the 2-D chart by the tunnel of automatic indexing up to the next iteration of the loop.  When you rerun the VI, as the shift register is not initialized, it is already there and became the first point of your next data execution.

  Why did you put the register shift in?  Just remove and just use the tunnel of automatic indexation.

  I don't know what you really want to do with the 2nd loop to say if the Notifier is correct or not.  But if you do not want to lose data in the other loop, then you need to use a second queue and have your producer loop enqueue data in the two queues, a queue for each consumer loop.

  With regard to the elements draws in the queue, seeing how your code is configured, the queue will almost always empty because the dequeue function will be ready to pull out the element immediately after the enqueue function puts in.  Unless you have your loop producer much faster than your consumer loop running, you will not see a build up of the elements.  (Try putting an expectation of more of 100 msec in your loop of consumer.  Then you will see elements accumulate in the queue.)

  I don't know why you put the spreadsheet feature writing after the loop.  Normal use for queues in an architecture of producer/consumer must transmit the data to a separate loop that contains the functions write file.  This way he can work at his own pace, but write the data and make sure that you do not lose it.  As you have now, if your code runs a long time, you may run out of memory when at the tunnel of automatic indexing table becomes too large.  And if your application crashes before you complete it with your stop button, then all data are lost because you did not it writes the file.

• Problem with the queues

  I have two sensors on a conveyor that will determine whether an object should be rejected or not. Another sensor is located at 80 cm distance where the object will be launched the conveyor. I learned to use the queues, but have had no luck so far. Could someone explain to me how they work and if possible, post an example of code pretty much my conveyor system? Thank you!

  Think of a queue as a line in the film. People come, they get online. When the person who sells tickets is ready they get the first person online and sell a ticket. Like many arive, they will get at the end of the line. This process will continue until there is nobody left online. The ticket seller will always be the person at the front of the line and new people will be placed at the end of the line.

  There are provided with LabVIEW examples that illustrate the use of queues. Use the finder of the example and the search for queues.

  With regard to your situation in more detail would be necessary in order to give the best advice.

• Examples for the new reference value of data with LVOOP

  Hello

  I'm looking for examples on how to use the new function of data with the LV class reference to achieve access to the ByRef objects.

  I would be very grateful for some codes.

  Greetings

  Hello

  a reall call by reference is not possible in LabVIEW. A good method is to use a queue with the size of a single element - then you can always move the reference to the queue and to read and write the new items in there.

  Or you use a FGV to store your object, which would work as well.

  

  RMathews

• Prevent the structure elements of the queue of the event?

  Is there a way to prevent a record structure and the queues of the events of the event?

  I have a state machine with a structure of the event in one of the States - the State is waiting for user input before continuing - and I wish that the structure of the event to recognize the events only when the program is in this State. I understand that the current method to catch all events is sometimes (usually) the desired behavior... Heck, I use it to my advantage most of the time. However, this is not one of those times.

  Here is a small example of my configuration:

  

  (See attachment. I guess that's too big for an extract VI, so it is a standard PNG image)

  The question that I have, is that the Structure of the continuous event of events Records even after pass to the next State. This means that if 'String' is changed at any time, the next time the queue of event happens in the state machine, all updates of the "chain" will run.

  So, how can I implement the code in such a way so that the events will be only intercepted and queue when the structure of event loop is running?

  
  

• Why "limit maximum instances of this event in the queue" in the dialog box change events?

  Why I "would limit the maximum instances of this event in the queue" in the dialog box change events?

  

  I think that this is new for LV 2014, but I couldn't find an explanation for an instance of good use. A research on OR displays only the 2014 help text, which explains what it does, but not why?

  Does anyone know good arguments to use this option?

  Thanks in advance.

  Justin Tyme

  

  It is useful for user interface elements that can enqueue actions as quickly as they can be made.

  For example, say it takes takes 1 second to take a picture and save it. The user presses the button "Take a photo", but they do not see a new image file again after a wait of 250 ms (human beings humans can be impatient) so they press twice. Finally, they see a new file image... and then another... and then another... To get rid of this possibility, check this box.

  Or that you have a cursor to adjust some settings. Moving the cursor updates very fast! If the user swipes from 0 to 1 then the program might try to send all the rest as a parameter to your instrument, which takes some time. Instead of sending all of these values, it is probably better if the software can keep up with the cursor and send a value of about 1 at the same time, the cursor said 1. If you do not check this box, the user can be 1, but the unit will continue to receive values from 0.53, 0.54, 0.55...

• Buffer could replace the queue in the design of producer/consumer model

  Hello

  I have a question to which the task of buffer to store the data and the queue is also of the same thing so we could use the inplace queue buffer in a design of producer/consumer model.

  No, these examples of buffer not almost equal to a queue, and never "replaces" queue at the producer/consumer.

  The advantage the most important of the queues for the producers/consumers (which none of the other mechanics buffer sharing), it is that it works activities to warn the reader that the data is available. So if you would simply replace the queue by mechanics of tampon too developed that you have attached to your last post, you will lose a large part of the object using producer/consumer.

  Thus, to compare the two mechanics:

  -Tail works activities, while the example of the buffer is not.

  -Tail must allocate memory during execution if several items are written in that corresponding queue. This also applies to the buffer (must be resized).

  -Given that the buffer is actually simply a table with overhead, memory management becomes slow and messy with the increase in fragmentation of memory. Queues to play much better here (but have their limitations, there also).

  -Overload of the buffer (the table manipulation) must be implemented manually. The queue functions encapsulate all the necessary features that you will need. So the queues have a simple API, while the buffer is not.

  -Given that the buffer is simply a table, you will have a hard time sharing the content in two parallel running loops. You will need to implement an additional charge using data value references to manage the buffer or lose a lot of memory using mechanics as variables. Lose the memory, you will probably encounter racing conditions so don't think not even on this subject.

  This led to four '+' for the queue and only a single point where 'buffer' is equal to the queue.

  Hopefully, this clears things up a bit.

  Norbert

• Get Queue Status output / empty the queue

  Hey everybody,

  I am trying to create the program that will record all the data in a queue after a number / deadline is met.

  However, when you try to save the output of the Flush queue / status of the queue, I'm not sure how to proceed. My original entry is a group of 4 elements.

  The output shows that it is "an array of clusters of 4 elements..."

  My initial approach was to: change of the table to a group (of 8 items)-> separate each element in another group 4 elements-> merge each specific item to get a unique flow of each of the 4 original elements.

  Result: 1 table-> 1 cluster-> 8 clusters-> 4 data streams, each stream of data representing one of my pieces of original entry (my goal).

  However, this seems to be a long process and I can't help but feel that I'm on in a much simpler way to do.

  I would now like to know if it's the only way I can save each of the indivudual 4 elements in the original 'picture of clusters of 4 elements' produced from the Flush queue / status of the queue?

  Also, is there a way to save/log ALL the data directly from the Flush queue / get an output of status of the queue (jump cutting/splitting of process data)?

  Thank you!

  What you really want to do, is use Dequeue item inside a FOR loop.  Inside the loop, ungroup you your cluster and the output values of the wire.  Let the loop FOR the autoindexing and you will have a different picture for each item in your cluster.

  See the example I did here: http://forums.ni.com/t5/LabVIEW/TDMS-File-starts-recording-data-at-20Hz-but-after-a-short-time/m-p/3...

• Reference the queue and sub - VI

  Hey everybody.

  Hope you can help me once again. What I need is actually advice, because my code works, it's just that the examples I see around the internet reminds that I could do better.

  So I use QMD inspired by the very nice guide to http://expressionflow.com/2007/10/01/labview-queued-state-machine-architecture/. My question is how to create queue references so that the queue name in the beam by name. The only way I can make it work is by using the function queue to get then turning the queue to a package by name, with this strategy than the unbundle name said only: "queue outside. See attachment (1 VI and two typedefs that are required for the VI to run). Since I have 5 different queues it is tedious to remember in what order I closed the...

  In addition, in my example I didn't a sequence around my Subvi as they do in the guide. Just because my code works fine without. Can someone explain the usefulness of the structure of sequence?

  I hope you can help

  Atamsih

  Hello

  I couldn't open your VI I did not LV 2011. However, I checked the image you posted.

  some of the answers for you:

  the structure of sequence around the slot screws (bottom of photo) is to ensure that the two sub start screw chasing the value False is written in the local output variable. in other words, when the output is initialized with the value false, the while loop and two void screws begin to run.

  to get the names of queue in the cluster, the name just constants reference queue to the function of bundle with the names you want

  to get the structure of package on the front right of the image, simply create constants of all the items you want to group and wire bundle as

• What is a good way to use the queues for the model of consumers/producers?

  Hi all

  I am following the model of consumers/producers to use the queue to synchronize the following process: the producer is a loop to produce a number N, I will put each number generated in a table and after each 5 numbers generated, I put the table in the queue and pass it on to the consumer. I have to wait the use by consumers of the data and it will then remove the item from queue so that producers will have the chance to produce another 5 numbers. As I put the maximum size of the queue one, I expect that the producer and the consumer turns to produce / consume all five numbers and the opportunity to another. Here is my code

  

  When the checkbox is false, the code will be

  

  For the first 5 numbers, product will generate every thing right and put it in the table, and it's going to pass the array to the quere so that the consumer will have the chance to loop through the table. I except the procude loop will continue only when the queue is available (i.e. all items are deleted), but it seems that once the consumer starts the loop loop of the product will continue (if the indicator x + 1 and x 2 will be changed to numbers). But this isn't what I want, I know there must be something wrong, but I can't say it is.

  dragondriver wrote:

  As you say in 1, sequency structure to enforce the order of execution, that's why I put it here, in this example, the simple question, I replace the complete code with increase in the number, in the real case, the first markers + 1 and + 2 must be performed in this order.

  Mikeporter says:
  1. get rid of all the structures of the sequence. None of them are nothing but apply a work order which would have been the same without them.

  So even if you delete the sequence structure, there will be a fixed & defined order and it is because LabVIEW follows the MODEL of FLOW OF DATA.

  Data flow model (more precisely in the context of LabVIEW): a block diagram node runs when it receives the required inputs. When a node is running, it produces output data and transmits data to the next node in the path of the data stream. The flow of data on the nodes determines the order of execution of the VIs and functions on the block diagram (click here for reference).

  Now in your code, just remove the sequence structure will not make you order will be going to stay the same, but you need to do some very minor changes (as thread of the error in loop, before that he go to the node "Élément Dequeue").

  Come to the main point: it's a good way to use the queue for the consumer/pmodel that?
  The model you are using (and qualifying as consumer/pmodel) is much too deviated from the original consumer/pmodel which model.

  dragondriver wrote:

  For the second, Yes, it's my fault for delete, though. I'm actually the example of model of producer/consumer design pattern, but I do not pay attention to the while loop in the part of the consumer.

  While loops (two producers & consumers) are the essential part of this architecture and cannot be deleted. You can start your code using standard model.

• example of network queue.lvproj.

  It is an example of lines 'queue.lvproj network' in 2011, which I believe is in error.

  It shows two Clients TCP work outside the same queue, which means that both get the same data for work outside.

  I think that the code in this example works because the queue depth is of one and two clients at the same time

  access the queue which also indicates that the queue is not locked when a process is accessing/queue.

  At the same time the attached example "LabVIEW Queuing.llb" makes more sense as a separate queue is open for each customer.

  If one of you smart people can put me right on this I would be grateful.

  Thank you

  Mark

  Hey Mark,

  While the queue.lvproj of network seems to send the same data to both receivers, the queue is actually slightly different times by two customers. You can observe this behavior by placing a VI waiting in the server and wiring while loop in a constant (I used 1000 ms). This will cause an element must be queued per second (if 1000ms is used). You can see the gap between the indicators of customer as they access the queue at different times. This is due to the fact that the queue is only to have an element added to every second while the withdrawal does not have a time constraint. Indeed, they work in the same queue, but they are not identical data, rather each of them removed about half of the elements that go into the queue.

  Depending on the application, it may be desirable to have this behavior or the behavior shown by your EIS.

  Hope this helps,

  Luke W

• Too much time in the queue empty in the loop of consumption

  I'm working on a VI used to screen analog converters above temperatures from room temperature to 175 C.  I have it set in place with a producer and a consumer loop.  The loop of producer makes all the measures, while consumer loop allows you to write tests that all measures in a spreadsheet file. There are 23 steps taken and recorded every second.  The test is run for about 60 minutes.

  Initially, I had trouble with data in the queue being lost when I stopped the VI.  I fixed that by ensuring that the queue was completely empty before you stop the VI.  Now my VI will continue to work long after I pressed the stop button.  I let it run for up to an hour and finally abandoned the operation and still lost a large number of measures on the end of the queue.  From my reading on the forums, it's because of the overload to write to a file of measure.  Opening and closing of the file every second is any slowdown.

  I've seen examples of creating a table of measured data and only writing every 100 samples or more.  Can someone help me see how I could implement something like this in my code?  Is there another reason, it takes so long to write all my test data?

  Thank you

  Matt

  You must use the real file i/o functions.  That made the express VI to write files to measure opens the file, writing the data and then close it.  When you do this several times, you get a really slow performance.  If you must open the file before you consumer loop and close it after the loop.  You will then be able to write as much as you want inside the loop.  But now, you need to format the data yourself.